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It occurs when greenhouse gases such as water vapors, carbon dioxide and methane present in the atmosphere absorb the infrared radiations and re-emit the thermal energy in all the directions. This thermal energy warms the Earth\u2019s surface.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- List various greenhouse gases. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of greenhouse gases in the atmosphere. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the glasshouse effect.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms100172.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms100172","TOPIC_ID":"ms100172","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS100172.jpg","PUBLIC_BANNER_IMG":"MS100172.jpg","PUBLIC_VIDEO":"pvideo_ms100172.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/HjKEzlbeD7A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"6","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Greenhouse effect is a natural process that maintains the Earth\u0026#039;s temperature at an average constant. It occurs when greenhouse gases such as water vapors, carbon dioxide and methane present in the atmosphere absorb the infrared radiations and re-emit the thermal energy in all the directions. This thermal energy warms the Earth\u2019s surface.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- List various greenhouse gases.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the effect of greenhouse gases in the atmosphere.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the glasshouse effect.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"The Greenhouse Effect","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"Higher Education"},{"CONT_ID":"505","CATEGORY_ID":"1","CONT_TITLE":"The Difference Between Compounds and Mixtures","CONT_SLUG":"difference-between-compounds-and-mixtures","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Sort compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify compounds and mixtures on the basis of molecular view.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200418.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200418","TOPIC_ID":"hs200418","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200418.jpg","PUBLIC_BANNER_IMG":"HS200418.jpg","PUBLIC_VIDEO":"pvideo_hs200418.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hlxxUVnlQzE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Differentiate between compounds and mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Sort compounds and mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Classify compounds and mixtures on the basis of molecular view.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Difference between Compounds and Mixtures","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"491","CATEGORY_ID":"1","CONT_TITLE":"Stable and Unstable Atoms","CONT_SLUG":"stable-and-unstable-atoms","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAtoms become chemically stable by losing or gaining to fill up their outermost electron shell to a configuration nearest to that of a noble gas. Atoms which attain noble gas configuration are non reactive in nature and are called stable atoms. 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Atoms which attain noble gas configuration are non reactive in nature and are called stable atoms. Atoms which do not attain noble gas configuration are reactive in nature and are called unstable atoms.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the conditions for an atom to be stable.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe how an atom can be made stable or unstable.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify stable and unstable atoms.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Stable and Unstable Atoms","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"487","CATEGORY_ID":"1","CONT_TITLE":"Phase Changes: Boiling, Evaporation and Condensation","CONT_SLUG":"phase-change-boiling-evaporation-and-condensation","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe change in state of liquid into gas is called vaporization. The process in which the vaporization occurs from the surface of a liquid is called evaporation. Whereas the process in which vaporization occurs within the surface of the liquid is called boiling. The change in state of gas into liquid is called condensation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define evaporation, boiling and condensation. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how liquid state and gaseous state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200285.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200285","TOPIC_ID":"ms200285","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200285.jpg","PUBLIC_BANNER_IMG":"MS200285.jpg","PUBLIC_VIDEO":"pvideo_ms200285.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/B6ArYhP2pRY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The change in state of liquid into gas is called vaporization. The process in which the vaporization occurs from the surface of\u0026amp;nbsp; a liquid is called evaporation. Whereas the process in which vaporization occurs within the surface of the liquid is called boiling. The change in state of gas into liquid is called condensation.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define evaporation, boiling and condensation.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain how liquid state and gaseous state of matter can be interchanged.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Phase change: Boiling, Evaporation and Condensation","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"480","CATEGORY_ID":"1","CONT_TITLE":"Ions-Gaining or Losing Electrons","CONT_SLUG":"ions-gaining-or-losing-electrons","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWhen an atom loses or gains an electron to attain a stable octet configuration, it gets converted to an ion, which is a charged particle, unlike a neutral atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define ions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the type of ion formed by a neutral atom according to its place in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify ions as anions or cations.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Categorize ions as monovalent, divalent, or trivalent.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200031","TOPIC_ID":"hs200031","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200031.jpg","PUBLIC_BANNER_IMG":"HS200031.jpg","PUBLIC_VIDEO":"pvideo_hs200031.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/NvMs_SpFQXs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;When an atom loses or gains an electron to attain a stable octet configuration, it gets converted to an ion, which is a charged particle, unlike a neutral atom.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define ions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the type of ion formed by a neutral atom according to its place in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Classify ions as anions or cations.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Categorize ions as monovalent, divalent, or trivalent.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Ions- Gaining or Losing Electrons","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"383","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Using Evaporation","CONT_SLUG":"separating-mixtures-using-evaporation","CONT_TITLE_AR":"Separating Mixtures: Using Evaporation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the evaporation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solutions that can be separated using the evaporation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\n\u0026lt;ol\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;explain the process of evaporation method of separation\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;identify solutions that can be separated using evaporation method of separation\u0026lt;\/li\u0026gt;\n\u0026lt;\/ol\u0026gt;\n","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200064","TOPIC_ID":"ms200064","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200064.jpg","PUBLIC_BANNER_IMG":"MS200064.jpg","PUBLIC_VIDEO":"pvideo_ms200064.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XT6vdYq4BaA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of the evaporation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify solutions that can be separated using the evaporation method of separation.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Separating Mixtures: Using Evaporation","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"367","CATEGORY_ID":"1","CONT_TITLE":"Distillation","CONT_SLUG":"distillation","CONT_TITLE_AR":"Distillation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDistillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling points, by heating them to a temperature at which one or more fractions of the compound will vaporize.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of distillation to separate miscible liquid mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify liquids that can be separated by distillation.\u003C\/div\u003E","CONT_DESC_AR":"Distillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling point by heating them to a temperature at which one or more fractions of the compound will vaporize.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the process of distillation to separate miscible liquid mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify liquids that can be separated by distillation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200015","TOPIC_ID":"ss200015","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200015.jpg","PUBLIC_BANNER_IMG":"SS200015.jpg","PUBLIC_VIDEO":"pvideo_ss200015.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0CyfkKB5KG4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Distillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling points, by heating them to a temperature at which one or more fractions of the compound will vaporize.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of distillation to separate miscible liquid mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify liquids that can be separated by distillation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Distillation","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"357","CATEGORY_ID":"1","CONT_TITLE":"Methods of Separation","CONT_SLUG":"methods-of-separation","CONT_TITLE_AR":"Methods of Separation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u003C\/div\u003E","CONT_DESC_AR":"Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the separation of ammonium chloride from a mixture of sodium chloride-ammonium chloride by sublimation method\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the separation of acetone from acetone-water solution by distillation method","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200076","TOPIC_ID":"ms200076","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200076.jpg","PUBLIC_BANNER_IMG":"MS200076.jpg","PUBLIC_VIDEO":"pvideo_ms200076.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XFqLqtNsjDQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u0026lt;\/div\u0026gt;- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Methods of Separation","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"270","CATEGORY_ID":"1","CONT_TITLE":"Boyle\u2019s Law","CONT_SLUG":"boyles-law","CONT_TITLE_AR":"Boyle\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Boyle\u0027s Law","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"268","CATEGORY_ID":"1","CONT_TITLE":"Charles\u2019s Law","CONT_SLUG":"charles-law","CONT_TITLE_AR":"Charles\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECharles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the temperature and volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate Charles\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Charles\u0026#039;s law in practical problems.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Charles\u0027s Law","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"173","CATEGORY_ID":"1","CONT_TITLE":"Valence Electrons","CONT_SLUG":"valence-electrons","CONT_TITLE_AR":"Valence Electrons","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the outermost shell of an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Count the number of valence electrons present in an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u003C\/div\u003E","CONT_DESC_AR":"Valence electrons are the electrons present in the outermost shell of an atom. The number of valence electrons in the atoms of groups 1,2 and 13 to 18 equals the ones digit of the group members.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- identify outermost shell of an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- count valence electrons present in an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- predict the number of valence electrons in the atoms of groups 1, 2 and 13 to 18 using periodic table\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"hs200070.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200070","TOPIC_ID":"hs200070","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200070.jpg","PUBLIC_BANNER_IMG":"HS200070.jpg","PUBLIC_VIDEO":"pvideo_hs200070.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ksLodK-mJ8c","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Valence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify the outermost shell of an atom.\u0026lt;br\u0026gt;- Count the number of valence electrons present in an atom.\u0026lt;br\u0026gt;- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Valence Electrons","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"167","CATEGORY_ID":"1","CONT_TITLE":"Isoelectronic Species","CONT_SLUG":"isoelectronic-species","CONT_TITLE_AR":"Isoelectronic species","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsoelectronic species have the same number of electrons or a similar electronic configuration, and similar structure. Isoelectronic species can be atoms, ions or molecules. Neon (Ne) atoms and Sodium ion (Na\u207a) are isoelectronic, as both contain 10 electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isoelectronic species.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isoelectronic species of different elements.\u003C\/div\u003E","CONT_DESC_AR":"Isoelectronic species have the same number of electrons or a similar electronic configuration and similar structure. Isoelectronic species can be atoms, ions or molecules. Ne atoms and Na+ ions are isoelectronic, as both contain 10 electrons.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation, you will be able to:\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isoelectronic species\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isoelectronic species of different elements","BACKING_FILE":"hs200052.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200052","TOPIC_ID":"hs200052","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200052.jpg","PUBLIC_BANNER_IMG":"HS200052.jpg","PUBLIC_VIDEO":"pvideo_hs200052.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/IJ7J0l0OUZg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isoelectronic species have the same number of electrons or a similar electronic configuration, and similar structure. Isoelectronic species can be atoms, ions or molecules. Neon (Ne) atoms and Sodium ion (Na\u0026lt;span style=\u0026quot;color: rgb(38, 50, 56); font-family: Roboto, sans-serif;\u0026quot;\u0026gt;\u207a\u0026lt;\/span\u0026gt;) are isoelectronic, as both contain 10 electrons.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isoelectronic species.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isoelectronic species of different elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Isoelectronic Species","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"165","CATEGORY_ID":"1","CONT_TITLE":"Isotones","CONT_SLUG":"isotones","CONT_TITLE_AR":"Isotones","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsotones are atoms that have the same number of neutrons but a different number of protons. Boron-12 and carbon-13 are isotones, as both of them contain 7 neutrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAt the end of this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isotones.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isotones of different elements.\u003C\/div\u003E","CONT_DESC_AR":"Isotones have the same number of neutrons but a different number of protons. Boron-12 and carbon-13 are isotones, as both of them contain 7 neutrons.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isotones\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isotones of different elements","BACKING_FILE":"hs200050.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200050","TOPIC_ID":"hs200050","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200050.jpg","PUBLIC_BANNER_IMG":"HS200050.jpg","PUBLIC_VIDEO":"pvideo_hs200050.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RNhrWFaUeqQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isotones are atoms that have the same number of neutrons but a different number of protons. Boron-12 and carbon-13 are isotones, as both of them contain 7 neutrons.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;At the end of this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isotones.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isotones of different elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Isotones","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"162","CATEGORY_ID":"1","CONT_TITLE":"Isobars","CONT_SLUG":"isobars","CONT_TITLE_AR":"Isobars","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsobars are atoms that have the same mass number, but a different atomic number. Hence isobars have the same number of nuclides, but a different number of protons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isobars.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isobars of different elements.\u003C\/div\u003E","CONT_DESC_AR":"Isobars have the same mass number, but a different atomic number. Hence isobars have the same number of nuclides, but a different number of protons.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isobars\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isobars of different elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of protons and neutrons in different isobars","BACKING_FILE":"hs200025.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200025","TOPIC_ID":"hs200025","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200025.jpg","PUBLIC_BANNER_IMG":"HS200025.jpg","PUBLIC_VIDEO":"pvideo_hs200025.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/LOlP2PuVudo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isobars are atoms that have the same mass number, but a different atomic number. Hence isobars have the same number of nuclides, but a different number of protons.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isobars.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isobars of different elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Isobars","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"159","CATEGORY_ID":"1","CONT_TITLE":"Isotopes","CONT_SLUG":"isotopes","CONT_TITLE_AR":"Isotopes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: hydrogen, deuterium and tritium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isotopes. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isotopes of different elements. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of protons and neutrons in different isotopes.\u003C\/div\u003E","CONT_DESC_AR":"Isotopes of an element have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: \u0026amp;nbsp;hydrogen, deuterium and tritium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isotopes\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isotopes of different elements\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of protons and neutrons in different isotopes","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200024","TOPIC_ID":"hs200024","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200024.jpg","PUBLIC_BANNER_IMG":"HS200024.jpg","PUBLIC_VIDEO":"pvideo_hs200024.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/f4sZdLZU03k","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes:\u0026amp;nbsp; hydrogen, deuterium and tritium.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isotopes.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isotopes of different elements.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the number of protons and neutrons in different isotopes.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Isotopes","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"157","CATEGORY_ID":"1","CONT_TITLE":"Synthesis Reactions","CONT_SLUG":"synthesis-reactions","CONT_TITLE_AR":"Synthesis reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a synthesis reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the synthesis reaction of magnesium oxide.\u003C\/div\u003E","CONT_DESC_AR":"A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic. An example of a synthesis reaction is the formation of water from hydrogen and oxygen.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a synthesis reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate the synthesis reaction of magnesium oxide","BACKING_FILE":"hs200021.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200021","TOPIC_ID":"hs200021","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200021.jpg","PUBLIC_BANNER_IMG":"HS200021.jpg","PUBLIC_VIDEO":"pvideo_hs200021.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5RK8BgMSqAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a synthesis reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the synthesis reaction of magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Synthesis Reactions","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"150","CATEGORY_ID":"1","CONT_TITLE":"Double Displacement Reactions","CONT_SLUG":"double-displacement-reaction","CONT_TITLE_AR":"Double displacement reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is double displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what is double displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Double Displacement Reaction","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"144","CATEGORY_ID":"1","CONT_TITLE":"Electron Distribution in Different Shells","CONT_SLUG":"electron-distribution-in-different-shells","CONT_TITLE_AR":"Electron Distribution in Different Shells","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EElectrons are arranged in energy levels, or shells, around the nucleus of an atom. The shell nearest to the nucleus has the least energy and subsequent shells have progressively more energy. Electrons first occupy lowest-energy shell, subsequent shells are occupied according to increasing order of energy. The maximum number of electrons that can be accommodated in any energy level is given by 2n\u00b2 where n is the number of the energy level, such as 1, 2, 3, 4...\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the rules for filling electrons in different atomic shells.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Arrange electrons in different atomic shells up to first 20 elements.\u003C\/div\u003E","CONT_DESC_AR":"Electrons are arranged in energy levels, or shells, around the nucleus of an atom. The shell nearest the nucleus has the least energy and subsequent shells have progressively more energy. The electron first occupy the lowest-energy shell, subsequent shells are occupied according to increasing order of energy. The maximum number of electrons that can be accommodated in any energy level is given by 2n2 where n is the number of the energy level, such as 1, 2, 3, 4...\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning objectives\u0026amp;nbsp;\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the rules for filling different atomic shells with electrons\u0026lt;br \/\u0026gt;\n\u0026amp;bull; arrange electrons in different atomic shells for the first 20 elements","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200004","TOPIC_ID":"hs200004","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200004.jpg","PUBLIC_BANNER_IMG":"HS200004.jpg","PUBLIC_VIDEO":"pvideo_hs200004.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/rzCLxuiGR_A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Electrons are arranged in energy levels, or shells, around the nucleus of an atom. The shell nearest to the nucleus has the least energy and subsequent shells have progressively more energy. Electrons first occupy lowest-energy shell, subsequent shells are occupied according to increasing order of energy. The maximum number of electrons that can be accommodated in any energy level is given by 2n\u00b2 where n is the number of the energy level, such as 1, 2, 3, 4...\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the rules for filling electrons in different atomic shells.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Arrange electrons in different atomic shells up to first 20 elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Electron Distribution in Different Shells","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"93","CATEGORY_ID":"1","CONT_TITLE":"Homogeneous Mixtures","CONT_SLUG":"homogeneous-mixtures","CONT_TITLE_AR":"Homogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is homogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is homogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200054","TOPIC_ID":"ms200054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200054.jpg","PUBLIC_BANNER_IMG":"MS200054.jpg","PUBLIC_VIDEO":"pvideo_ms200054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/elFGPE_TZxk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the properties of homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify whether a mixture is homogeneous or not.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Homogeneous Mixtures","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"85","CATEGORY_ID":"1","CONT_TITLE":"Heterogeneous Mixtures","CONT_SLUG":"heterogeneous-mixtures","CONT_TITLE_AR":"Heterogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is heterogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is heterogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200053","TOPIC_ID":"ms200053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200053.jpg","PUBLIC_BANNER_IMG":"MS200053.jpg","PUBLIC_VIDEO":"pvideo_ms200053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BrPP-a75tI0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe heterogeneous mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of heterogeneous mixtures.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a mixture is heterogeneous or not.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Heterogeneous Mixtures","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"64","CATEGORY_ID":"1","CONT_TITLE":"Separation by Filtration","CONT_SLUG":"separation-by-filtration","CONT_TITLE_AR":"Separation by Filtration","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWater-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure of filtration using filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated by filtration.\u003C\/div\u003E","CONT_DESC_AR":"Liquid mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand water mixture as sand cannot permeate filter paper.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- describe the procedure of filtration using filter paper\u0026lt;br \/\u0026gt;\n- identify mixtures that can be separated by filtration\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200051","TOPIC_ID":"ms200051","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200051.jpg","PUBLIC_BANNER_IMG":"MS200051.jpg","PUBLIC_VIDEO":"pvideo_ms200051.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RZS1h0l5xjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Water-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the procedure of filtration using filter paper.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated by filtration.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Separation by Filtration","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"59","CATEGORY_ID":"1","CONT_TITLE":"Phase Change: Melting and Freezing","CONT_SLUG":"phase-change-melting-and-freezing","CONT_TITLE_AR":"Phase Change-Melting and Freezing","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIf a solid matter gains enough heat, it changes its state from solid to liquid, causing melting. On the other hand, when a solid matter loses heat, it causes a process called freezing. In freezing, the motion of atoms or molecules slows down.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define melting and freezing.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid state and liquid state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"If solid matter gains enough heat, it changes state from solid to liquid, causing melting. The inverse of melting is called freezing, changing from a liquid state to solid, in which atoms and molecules lose heat and come together, slowing down motion.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- Define melting and freezing\u0026lt;br \/\u0026gt;\n- Explain how a solid state and liquid state of matter can be interchanged","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200018","TOPIC_ID":"ms200018","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200018.jpg","PUBLIC_BANNER_IMG":"MS200018.jpg","PUBLIC_VIDEO":"pvideo_ms200018.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/_wM6VCKEABQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:54:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;If a solid matter gains enough heat, it changes its state from solid to liquid, causing melting. On the other hand, when a solid matter loses heat, it causes a process called freezing. In freezing, the motion of atoms or molecules slows down.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define melting and freezing.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how solid state and liquid state of matter can be interchanged.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Phase Change: Melting and Freezing","ADMSUBJECT_ID":"1331","ADMCOURSE_ID":"380","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 9","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"}],"levelObject":["Greenhouse Gases","Greenhouse Effect","Solar Radiation","Infrared Radiation","Water Vapours","Carbon Dioxide","Methane","Glaas House"],"contData":{"CONT_ID":"510","CATEGORY_ID":"1","CONT_TITLE":"The Greenhouse Effect","CONT_SLUG":"the-greenhouse-effect","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGreenhouse effect is a natural process that maintains the Earth\u0026#039;s temperature at an average constant. It occurs when greenhouse gases such as water vapors, carbon dioxide and methane present in the atmosphere absorb the infrared radiations and re-emit the thermal energy in all the directions. This thermal energy warms the Earth\u2019s surface.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- List various greenhouse gases. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of greenhouse gases in the atmosphere. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the glasshouse effect.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms100172.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms100172","TOPIC_ID":"ms100172","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS100172.jpg","PUBLIC_BANNER_IMG":"MS100172.jpg","PUBLIC_VIDEO":"pvideo_ms100172.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/HjKEzlbeD7A","DIST":"AF,AX,AL,DZ,AS,AD,AO,AI,AQ,AG,AR,AM,AW,AU,AT,AZ,BS,BH,BD,BB,BY,BE,BZ,BJ,BM,BT,BO,BQ,BA,BW,BV,BR,IO,BN,BG,BF,BI,KH,CM,CA,CV,KY,CF,TD,CL,CN,CX,CC,CO,KM,CG,CK,CR,CI,HR,CU,CW,CY,CZ,CD,DK,DJ,DM,DO,EC,EG,SV,GQ,ER,EE,ET,FK,FO,FJ,FI,FR,GF,PF,TF,GA,GM,GE,DE,GH,GI,GR,GL,GD,GP,GU,GT,GG,GN,GW,GY,HT,HM,HN,HK,HU,IS,IN,ID,IR,IQ,IE,IM,IT,JM,JP,JE,JO,KZ,KE,KI,XK,KW,KG,LA,LV,LB,LS,LR,LY,LI,LT,LU,MO,MK,MG,MW,MY,MV,ML,MT,MH,MQ,MR,MU,YT,MX,FM,MD,MC,MN,ME,MS,MA,MZ,MM,NA,NR,NP,NL,NC,NZ,NI,NE,NG,NU,NF,KP,MP,NO,OM,PK,PW,PS,PA,PG,PY,PE,PH,PN,PL,PT,PR,QA,RE,RO,RU,RW,BL,SH,KN,LC,MF,PM,VC,WS,SM,ST,SA,SN,RS,SC,SL,SG,SX,SK,SI,SB,SO,ZA,GS,KR,SS,ES,LK,SD,SR,SJ,SZ,SE,CH,SY,TW,TJ,TZ,TH,TL,TG,TK,TO,TT,TN,TR,TM,TC,TV,UG,UA,AE,GB,US,UM,UY,UZ,VU,VA,VE,VN,VG,VI,WF,EH,YE,ZM,ZW","SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"6","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2017-10-06 04:21:02","CREATED_BY":"0","UPDATED_ON":"2024-10-08 09:18:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Greenhouse effect is a natural process that maintains the Earth\u0026#039;s temperature at an average constant. It occurs when greenhouse gases such as water vapors, carbon dioxide and methane present in the atmosphere absorb the infrared radiations and re-emit the thermal energy in all the directions. This thermal energy warms the Earth\u2019s surface.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- List various greenhouse gases.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the effect of greenhouse gases in the atmosphere.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the glasshouse effect.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"The Greenhouse Effect","DISPLAY_NAME":"NGSS New - Middle School - Life Science","DISPLAY_NAME_AR":"NGSS New - Middle School - Life Science","SUBJECT_IMG":"566.jpg","ADMSUBJECT_ID":"566","SUBJECT_NAME":"Life Science","SUBJECT_NAME_AR":"Life Science","ADMCOURSE_ID":"191","COURSE_NAME":"Middle School","COUNTRY_ID":"287","STANDARD_ID":"287","SHORT_NAME":"NGSS","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"Higher Education","DOMAIN_DESC":"Higher Education"},"checkLang":["English - US","\u4e2d\u6587","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Portugu\u00eas ","Ti\u1ebfng Vi\u1ec7t"],"devices":["UmetyVR","WebXR"]}