{"pkgId":"26","subjectId":"754","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":"Bahrain Curriculum Full Access","PACKAGE_SLUG":"bahrain-full","PACKAGE_IMG":"file_387203896_1592480631.png","ADMCOURSE_ID":"143","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","STANDARD_NAME":"Bahrain","ADMSUBJECT_ID":"754","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","CAT_NAME":"\u0645\u062c\u0645\u0648\u0639 \u0627\u0644\u0645\u062a\u062a\u0627\u0644\u064a\u0627\u062a \u0627\u0644\u062d\u0633\u0627\u0628\u064a\u0629","CONT_ID":"748","CONT_TITLE":"Sum of Arithmetic Progression","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETo find the sum of all the n terms of an arithmetic progression, apply the formula for sum of n terms, Sn= (n \/ 2)(2 a + (n - 1) d). the arithmetic mean between two numbers a and b is (a + b) \/ 2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic means between a and b.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the term arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of an arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Insert arithmetic means between two numbers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the nth term formula.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the sum of terms in an arithmetic 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Progression","CONT_SLUG":"sum-of-arithmetic-progression","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETo find the sum of all the n terms of an arithmetic progression, apply the formula for sum of n terms, Sn= (n \/ 2)(2 a + (n - 1) d). the arithmetic mean between two numbers a and b is (a + b) \/ 2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic means between a and b.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the term arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of an arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Insert arithmetic means between two numbers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the nth term formula.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the sum of terms in an arithmetic progression.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vm000007","TOPIC_ID":"vm000007","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vm000007.jpg","PUBLIC_BANNER_IMG":"vm000007.jpg","PUBLIC_VIDEO":"en_us_pvideo_vm000007.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 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\u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"747","CATEGORY_ID":"1","CONT_TITLE":"Arithmetic Progressions","CONT_SLUG":"arithmetic-progressions","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn arithmetic sequence is a sequence in which the successive terms have common differences. With the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, a\u003Csub\u003En\u003C\/sub\u003E= a + (n - 1) d.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognise arithmetic progressions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the nth term of an arithmetic progression.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vm000006","TOPIC_ID":"vm000006","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vm000006.jpg","PUBLIC_BANNER_IMG":"vm000006.jpg","PUBLIC_VIDEO":"en_us_pvideo_vm000006.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;An arithmetic sequence is a sequence in which the successive terms have common differences. 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\u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn integer is a whole number that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, and 97. Examples of numbers that are not integers are: -1.43, 1 3\/4, 3.14. To multiply or divide integers with positive or negative signs, always multiply or divide the absolute values and then determine the sign of the answer. The product of two positive integers or two negative integers is positive. The product of a positive integer and a negative integer is negative.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Multiply and divide signed integers.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vm000029","TOPIC_ID":"vm000029","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vm000029.jpg","PUBLIC_BANNER_IMG":"vm000029.jpg","PUBLIC_VIDEO":"en_us_pvideo_vm000029.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;An integer is a whole number that can be positive, negative, or zero. 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The property lets you multiply a sum by multiplying each addend separately and then add the products.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the distributive property.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Simplify problems using the distributive property.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300391","TOPIC_ID":"ms300391","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300391.jpg","PUBLIC_BANNER_IMG":"ms300391.jpg","PUBLIC_VIDEO":"pvideo_ms300391.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/2MAYPl-SRCM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Distributive property is one of the most frequently used properties in math. 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\u0646\u0638\u0631\u064a\u0629 \u0627\u0644\u062e\u0644\u064a\u0629\u060c \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0648\u0645\u0643\u0648\u0646\u0627\u062a\u0647\u0627\u060c \u0627\u0644\u0645\u062c\u0627\u0647\u0631\u060c \u0627\u0644\u0637\u0627\u0642\u0629 \u0648\u0627\u0644\u062e\u0644\u0627\u064a\u0627\u060c \u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0641\u064a \u062c\u0633\u0645 \u0627\u0644\u0625\u0646\u0633\u0627\u0646\u060c \u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0627\u0644\u0646\u0628\u0627\u062a\u064a\u0629\u060c \u0627\u0644\u062a\u0643\u0627\u062b\u0631 \u0648\u0627\u0644\u062c\u064a\u0646\u0627\u062a\u060c \u062a\u062d\u0648\u064a\u0644\u0627\u062a \u0627\u0644\u0635\u0641\u0627\u062a \u0627\u0644\u0648\u0631\u0627\u062b\u064a\u0629. \u062a\u062d\u062a\u0648\u064a \u0627\u0644\u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0639\u0644\u0649 \u0648\u0635\u0641 \u0645\u0641\u0635\u0651\u064e\u0644 \u0644\u062e\u0635\u0627\u0626\u0635 \u0648\u062a\u0635\u0646\u064a\u0641\u0627\u062a \u0627\u0644\u062d\u064a\u0648\u0627\u0646\u0627\u062a\u060c \u062a\u0643\u064a\u0641 \u0627\u0644\u0637\u064a\u0648\u0631\u060c \u0648\u062a\u0635\u0646\u064a\u0641 \u0627\u0644\u062b\u062f\u064a\u0651\u064a\u0627\u062a\u060c \u0648\u063a\u064a\u0631\u0647\u0645. \u062a\u0648\u0641\u0651\u0650\u0631 \u0643\u0644 \u0648\u062d\u062f\u0629 \u062a\u0641\u0627\u0639\u0644\u064b\u0627 \u0633\u0644\u0633\u064b\u0627 \u0645\u0639 \u0623\u062c\u0647\u0632\u0629 \u0627\u0644\u0643\u0645\u0628\u064a\u0648\u062a\u0631\u060c \u0648\u062a\u0632\u064a\u062f \u0645\u0646 \u0634\u063a\u0641 \u0627\u0644\u0637\u0644\u0627\u0628 \u0648\u062f\u0631\u062c\u0629 \u0641\u0647\u0645\u0647\u0645 \u0644\u0644\u0638\u0648\u0627\u0647\u0631 \u0648\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"559","CATEGORY_ID":"1","CONT_TITLE":"Distance on a Number Line","CONT_SLUG":"distance-on-a-number-line","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn this topic, we will determine the distance between integers by examining absolute value and number lines. For example, the absolute value of \u22123 is written |\u22123| which equals 3. Therefore, the distance of -3 from 0 is 3.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain number line. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Perform addition and subtraction on number line. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Find distance on number line.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300388","TOPIC_ID":"ms300388","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300388.jpg","PUBLIC_BANNER_IMG":"MS300388.jpg","PUBLIC_VIDEO":"pvideo_ms300388.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/E4nrqAAhXD8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In this topic, we will determine the distance between integers by examining absolute value and number lines. For example, the absolute value of \u22123 is written |\u22123| which equals 3. Therefore, the distance of -3 from 0 is 3.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain number line.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Perform addition and subtraction on number line.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Find distance on number line.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0633\u0627\u0641\u0629 \u0639\u0644\u0649 \u062e\u0637 \u0627\u0644\u0627\u0639\u062f\u0627\u062f","ADMSUBJECT_ID":"754","ADMCOURSE_ID":"143","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"\u0639\u0650\u0644\u0652\u0645 \u0627\u0644\u0623\u062d\u064a\u0627\u0621: \u0647\u0648 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\u0623\u062c\u0647\u0632\u0629 \u0627\u0644\u0643\u0645\u0628\u064a\u0648\u062a\u0631\u060c \u0648\u062a\u0632\u064a\u062f \u0645\u0646 \u0634\u063a\u0641 \u0627\u0644\u0637\u0644\u0627\u0628 \u0648\u062f\u0631\u062c\u0629 \u0641\u0647\u0645\u0647\u0645 \u0644\u0644\u0638\u0648\u0627\u0647\u0631 \u0648\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u0639\u0650\u0644\u0652\u0645 \u0627\u0644\u0623\u062d\u064a\u0627\u0621: \u0647\u0648 \u062f\u0631\u0627\u0633\u0629 \u0623\u0634\u0643\u0627\u0644 \u0627\u0644\u062d\u064a\u0627\u0629\u060c \u0648\u0627\u0644\u0639\u0645\u0644\u064a\u0627\u062a \u0627\u0644\u062d\u064a\u0648\u064a\u0629. \u062a\u062a\u0639\u0627\u0645\u0644 \u0648\u062d\u062f\u0627\u062a \u0627\u0644\u0623\u062d\u064a\u0627\u0621 \u0644\u0644\u0635\u0641 \u0627\u0644\u0633\u0627\u0628\u0639 \u0645\u0639 \u0645\u0648\u0636\u0648\u0639\u0627\u062a\u061b \u0645\u062b\u0644: \u0646\u0638\u0631\u064a\u0629 \u0627\u0644\u062e\u0644\u064a\u0629\u060c \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0648\u0645\u0643\u0648\u0646\u0627\u062a\u0647\u0627\u060c \u0627\u0644\u0645\u062c\u0627\u0647\u0631\u060c \u0627\u0644\u0637\u0627\u0642\u0629 \u0648\u0627\u0644\u062e\u0644\u0627\u064a\u0627\u060c \u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0641\u064a \u062c\u0633\u0645 \u0627\u0644\u0625\u0646\u0633\u0627\u0646\u060c \u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0627\u0644\u0646\u0628\u0627\u062a\u064a\u0629\u060c \u0627\u0644\u062a\u0643\u0627\u062b\u0631 \u0648\u0627\u0644\u062c\u064a\u0646\u0627\u062a\u060c \u062a\u062d\u0648\u064a\u0644\u0627\u062a \u0627\u0644\u0635\u0641\u0627\u062a \u0627\u0644\u0648\u0631\u0627\u062b\u064a\u0629. \u062a\u062d\u062a\u0648\u064a \u0627\u0644\u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0639\u0644\u0649 \u0648\u0635\u0641 \u0645\u0641\u0635\u0651\u064e\u0644 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\u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"556","CATEGORY_ID":"1","CONT_TITLE":"Histogram","CONT_SLUG":"histogram","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA histogram is a graph that is formed by using rectangles whose area is proportional to the frequency of a variable and whose width is equal to the class interval. It is similar to a bar graph. The only difference is that there is no gap in the class intervals or we can say, the intervals are continuous here.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a histogram.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the use of histograms in real life situations.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Interpret a histogram.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Create a histogram.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms300200.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300200","TOPIC_ID":"ms300200","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300200.jpg","PUBLIC_BANNER_IMG":"ms300200.jpg","PUBLIC_VIDEO":"pvideo_ms300200.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/moUWon8HrF0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A histogram is a graph that is formed by using rectangles whose area is proportional to the frequency of a variable and whose width is equal to the class interval. It is similar to a bar graph. 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To subtract like fractions, simply subtract the numerators and write their difference divided by the common denominator.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify like fractions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Subtract like fractions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms300150.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300150","TOPIC_ID":"ms300150","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300150.jpg","PUBLIC_BANNER_IMG":"MS300150.jpg","PUBLIC_VIDEO":"pvideo_ms300150.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/la9DeGZYE8g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Like fractions are fractions with the same denominator. 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\u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"544","CATEGORY_ID":"1","CONT_TITLE":"Identify and Graph Integers","CONT_SLUG":"identify-and-graph-integers","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe set of integers includes zero, negative and positive numbers without any decimal or fractional parts. To graph integers, we take a number line with 0 in the middle and place all the positive integers on the right side of 0 and all the negative integers on the left side of 0. The integers are placed at equal spaces.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe positive integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe negative integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Locate positive and negative integers on a number line.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms300149.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300149","TOPIC_ID":"ms300149","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300149.jpg","PUBLIC_BANNER_IMG":"MS300149.jpg","PUBLIC_VIDEO":"pvideo_ms300149.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/L8d9fCkltgY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The set of integers includes zero, negative and positive numbers without any decimal or fractional parts. 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The integers are placed at equal spaces.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe positive integers.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe negative integers.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Locate positive and negative integers on a number line.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u062d\u062f\u064a\u062f \u0648\u0631\u0633\u0645 \u0627\u0644\u0623\u0639\u062f\u0627\u062f \u0627\u0644\u0635\u062d\u064a\u062d\u0629","ADMSUBJECT_ID":"754","ADMCOURSE_ID":"143","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"\u0639\u0650\u0644\u0652\u0645 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To add like fractions, simply add the numerators and write the sum divided by common denominator.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Identify like fractions. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Add like fractions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300141","TOPIC_ID":"ms300141","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300141.jpg","PUBLIC_BANNER_IMG":"MS300141.jpg","PUBLIC_VIDEO":"pvideo_ms300141.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BjTi9wmzxsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Like fractions are fractions with the same denominator. 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\u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"534","CATEGORY_ID":"1","CONT_TITLE":"Addition and Subtraction of Unlike Fractions","CONT_SLUG":"add-and-subtract-unlike-fractions","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EUnlike fractions are the fractions with different denominators. To add or subtract the unlike fractions, first find the least common multiple of the denominators. This gives the equivalent fractions with the same denominators. Then add or subtract the numerators of equivalent fractions having the same denominators.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Identify unlike fractions. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Add unlike fractions. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Subtract unlike fractions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300127","TOPIC_ID":"ms300127","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300127.jpg","PUBLIC_BANNER_IMG":"MS300127.jpg","PUBLIC_VIDEO":"pvideo_ms300127.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/WvHK9dm5kRI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Unlike fractions are the fractions with different denominators. To add or subtract the unlike fractions, first find the least common multiple of the denominators. This gives the equivalent fractions with the same denominators. Then add or subtract the numerators of equivalent fractions having the same denominators.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify unlike fractions.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Add unlike fractions.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Subtract unlike fractions.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062c\u0645\u0639 \u0648\u0637\u0631\u062d \u0627\u0644\u0643\u0633\u0648\u0631 \u063a\u064a\u0631 \u0627\u0644\u0645\u062a\u0634\u0627\u0628\u0647\u0629","ADMSUBJECT_ID":"754","ADMCOURSE_ID":"143","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"\u0639\u0650\u0644\u0652\u0645 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\u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"533","CATEGORY_ID":"1","CONT_TITLE":"Integers and Absolute Value","CONT_SLUG":"integer-and-absolute-value","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe absolute value of an integer is the numerical positive value without considering the negative or positive sign. On a number line, it is the distance between the number and zero.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify an integer in real life situations.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between positive and negative integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define absolute value.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300126","TOPIC_ID":"ms300126","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300126.jpg","PUBLIC_BANNER_IMG":"MS300126.jpg","PUBLIC_VIDEO":"pvideo_ms300126.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/2B_bQ5idEfs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The absolute value of an integer is the numerical positive value without considering the negative or positive sign. 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When one variable increases the other decreases in proportion, so that the product does not change. If we say, b is inversely proportional to a, the equation is of the form b = k\/a (where k is a constant).\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the concept of variation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize indirect variation.\u003C\/div\u003E","CONT_DESC_AR":"Indirect variation is a relationship between two variables in which the product is a constant. When one variable increases the other decreases in proportion so that the product is unchanged. 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An equation in one variable gives a straight line when plotted on a graph.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Express a linear equation in the form of ax = b.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write a linear equation in one variable to represent a given statement.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Simplify a linear equation in one variable.\u003C\/div\u003E","CONT_DESC_AR":"An equation in one variable gives a straight line when plotted on a graph.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; express the linear equation in the form of ax = b\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write a linear equation in one variable to represent a given statement\u0026lt;br \/\u0026gt;\n\u0026amp;bull; simplify the linear equation in one variable","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300054","TOPIC_ID":"hs300054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300054.jpg","PUBLIC_BANNER_IMG":"hs300054.jpg","PUBLIC_VIDEO":"pvideo_hs300054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/uohuOst-4-8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;A linear equation in defined as the equation of the form ax = b where a is not equal to zero. An equation in one variable gives a straight line when plotted on a graph.\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Express a linear equation in the form of ax = b.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Write a linear equation in one variable to represent a given statement.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Simplify a linear equation in one variable.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0639\u0627\u062f\u0644\u0629 \u0627\u0644\u062e\u0637\u064a\u0629 \u0641\u064a \u0645\u062a\u063a\u064a\u0631 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The curved surface area of a cylinder is the area of its curved surface excluding the base, while total surface area is calculated by adding the areas of curved surface and two circular bases. The volume of a cylinder is calculated by multiplying the area of the base with the height of the cylinder.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive the formula for the curved surface area of a right circular cylinder.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive the formula for the total surface area of a right circular cylinder.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive the formula for the volume of a right circular cylinder.\u003C\/div\u003E","CONT_DESC_AR":"Formula for curved surface area, total surface area and volume of a right circular cylinder.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be able to find that the\u0026lt;br \/\u0026gt;\n\u0026amp;bull; Curved surface area = 2\u0026amp;pi;rh\u0026lt;br \/\u0026gt;\n\u0026amp;bull; Total surface area = 2\u0026amp;pi;r(r+h)\u0026lt;br \/\u0026gt;\n\u0026amp;bull; Volume = \u0026amp;pi;r\u0026amp;sup2;h \u0026amp;nbsp;\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nWhere r is the radius and h is the height of the cylinder.","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300016","TOPIC_ID":"hs300016","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300016.jpg","PUBLIC_BANNER_IMG":"HS300016.jpg","PUBLIC_VIDEO":"pvideo_hs300016.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Pasy8gpnPP0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A right circular cylinder is a closed solid that has two circular bases connected by a curved surface. The curved surface area of a cylinder is the area of its curved surface excluding the base, while total surface area is calculated by adding the areas of curved surface and two circular bases. The volume of a cylinder is calculated by multiplying the area of the base with the height of the cylinder.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive the formula for the curved surface area of a right circular cylinder.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive the formula for the total surface area of a right circular cylinder.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive the formula for the volume of a right circular cylinder.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062d\u062c\u0645 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It is often written as f(x), where x is the input value.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the domain of a square root function.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the domain and range of a function from the algebraic form.\u003C\/div\u003E","CONT_DESC_AR":"A function is a relationship between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output.\u0026lt;br \/\u0026gt;\nAn example is the function that relates each real number x to its square x\u0026lt;sup\u0026gt;2\u0026lt;\/sup\u0026gt;.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; find the domain of a square root function\u0026lt;br \/\u0026gt;\n\u0026amp;bull; find the domain and range of a function from the algebraic form","BACKING_FILE":"ss300081.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300081","TOPIC_ID":"ss300081","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300081.jpg","PUBLIC_BANNER_IMG":"SS300081.jpg","PUBLIC_VIDEO":"pvideo_ss300081.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ln5podNizPU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;A function is a special relationship where each input has a single output. 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\u0644\u0644\u0638\u0648\u0627\u0647\u0631 \u0648\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"271","CATEGORY_ID":"1","CONT_TITLE":"Composite Functions","CONT_SLUG":"composite-functions","CONT_TITLE_AR":"Composite Functions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFunction Composition is the applying of one function to the results of another.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003E(g \u00ba f)(x) = g(f(x)),\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFor representing this, we substitute f(x) in place of x in g(x) and the resultant function is composite function. Some functions can be decomposed into two (or more) simpler functions.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the composition of two functions.\u003C\/div\u003E","CONT_DESC_AR":"Function Composition is applying one function to the results of another. (g \u0026amp;ordm; f)(x) = g(f(x)),\u0026lt;br \/\u0026gt;\nFor representing this , we substitute f(x) in place of x in g(x) and the resultant function is composite function.\u0026lt;br \/\u0026gt;\nSome functions can be de-composed into two (or more) simpler functions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify the composition of two functions","BACKING_FILE":"ss300048.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300048","TOPIC_ID":"ss300048","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300048.jpg","PUBLIC_BANNER_IMG":"SS300048.jpg","PUBLIC_VIDEO":"pvideo_ss300048.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ZXaDs07rbYE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Function Composition is the applying of one function to the results of another.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;(g \u00ba f)(x) = g(f(x)),\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For representing this, we substitute f(x) in place of x in g(x) and the resultant function is composite function. Some functions can be decomposed into two (or more) simpler functions.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the composition of two functions.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u062f\u0648\u0627\u0644","ADMSUBJECT_ID":"754","ADMCOURSE_ID":"143","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"\u0639\u0650\u0644\u0652\u0645 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\u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"263","CATEGORY_ID":"1","CONT_TITLE":"Rate of Change","CONT_SLUG":"rate-of-change","CONT_TITLE_AR":"Rate of Change","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ERate of change is defined as the value that results from dividing the change in a function of a variable by the change in the variable. The average rate of change in any function calculates the amount of change in one item divided by the corresponding amount of change in another.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the rate of change of a function from the given table and graph.\u003C\/div\u003E","CONT_DESC_AR":"Slope and Rate of Change.\u003C\/br\u003E\r\nThe word slope (gradient, incline, pitch) is used to describe the measurement of the steepness of a straight line.\u003C\/br\u003E\r\nThe higher the slope, the steeper the line.\u003C\/br\u003E\r\nThe slope of a line is a rate of change\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this topic you will be able to:\u003C\/br\u003E\r\n\u2022 calculate the rate of change of a linear function from the given information as set of ordered pairs, a table, or a graph","BACKING_FILE":"ss300050.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300050","TOPIC_ID":"ss300050","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300050.jpg","PUBLIC_BANNER_IMG":"SS300050.jpg","PUBLIC_VIDEO":"pvideo_ss300050.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/-lYGscxM51k","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Rate of change is defined as the value that results from dividing the change in a function of a variable by the change in the variable. The average rate of change in any function calculates the amount of change in one item divided by the corresponding amount of change in another.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the rate of change of a function from the given table and graph.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0639\u062f\u0644 \u0627\u0644\u062a\u063a\u064a\u0651\u064f\u0631","ADMSUBJECT_ID":"754","ADMCOURSE_ID":"143","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - 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\u062a\u0648\u0641\u0651\u0650\u0631 \u0643\u0644 \u0648\u062d\u062f\u0629 \u062a\u0641\u0627\u0639\u0644\u064b\u0627 \u0633\u0644\u0633\u064b\u0627 \u0645\u0639 \u0623\u062c\u0647\u0632\u0629 \u0627\u0644\u0643\u0645\u0628\u064a\u0648\u062a\u0631\u060c \u0648\u062a\u0632\u064a\u062f \u0645\u0646 \u0634\u063a\u0641 \u0627\u0644\u0637\u0644\u0627\u0628 \u0648\u062f\u0631\u062c\u0629 \u0641\u0647\u0645\u0647\u0645 \u0644\u0644\u0638\u0648\u0627\u0647\u0631 \u0648\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u0639\u0650\u0644\u0652\u0645 \u0627\u0644\u0623\u062d\u064a\u0627\u0621: \u0647\u0648 \u062f\u0631\u0627\u0633\u0629 \u0623\u0634\u0643\u0627\u0644 \u0627\u0644\u062d\u064a\u0627\u0629\u060c \u0648\u0627\u0644\u0639\u0645\u0644\u064a\u0627\u062a \u0627\u0644\u062d\u064a\u0648\u064a\u0629. \u062a\u062a\u0639\u0627\u0645\u0644 \u0648\u062d\u062f\u0627\u062a \u0627\u0644\u0623\u062d\u064a\u0627\u0621 \u0644\u0644\u0635\u0641 \u0627\u0644\u0633\u0627\u0628\u0639 \u0645\u0639 \u0645\u0648\u0636\u0648\u0639\u0627\u062a\u061b \u0645\u062b\u0644: \u0646\u0638\u0631\u064a\u0629 \u0627\u0644\u062e\u0644\u064a\u0629\u060c \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0648\u0645\u0643\u0648\u0646\u0627\u062a\u0647\u0627\u060c \u0627\u0644\u0645\u062c\u0627\u0647\u0631\u060c \u0627\u0644\u0637\u0627\u0642\u0629 \u0648\u0627\u0644\u062e\u0644\u0627\u064a\u0627\u060c \u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0641\u064a \u062c\u0633\u0645 \u0627\u0644\u0625\u0646\u0633\u0627\u0646\u060c \u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u062e\u0644\u0627\u064a\u0627 \u0627\u0644\u0646\u0628\u0627\u062a\u064a\u0629\u060c \u0627\u0644\u062a\u0643\u0627\u062b\u0631 \u0648\u0627\u0644\u062c\u064a\u0646\u0627\u062a\u060c \u062a\u062d\u0648\u064a\u0644\u0627\u062a \u0627\u0644\u0635\u0641\u0627\u062a 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\u0644\u0644\u0638\u0648\u0627\u0647\u0631 \u0648\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0628\u064a\u0648\u0644\u0648\u062c\u064a\u0629.","SUBJECT_IMG":"754.jpg","SUBJECT_BANNER_IMG":"754.jpg","SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 7","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"243","CATEGORY_ID":"1","CONT_TITLE":"Linear Equations in Two Variables","CONT_SLUG":"linear-equations-in-two-variables","CONT_TITLE_AR":"Linear Equations in Two Variables","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA linear equation in two variable is defined as a first-degree equation that can be written in the form ax + by = c, where both a and b are not equal to zero and a, b, and c are real numbers. The graph of any equation of this form is a straight line.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Express a linear equation in the form of ax + by + c = 0.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write a linear equation in two variables to represent a given statement.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Match a graph with its equation.\u003C\/div\u003E","CONT_DESC_AR":"Solving systems of equations with two variables.A system of a linear equation is comprised of two or more equations, used to find a common solution to the equations.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; express the linear equation in form of ax+by+c=0\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write linear equation in two variable to represent given statement\u0026lt;br \/\u0026gt;\n\u0026amp;bull; match the graph with it\u0026amp;rsquo;s equation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300027","TOPIC_ID":"hs300027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300027.jpg","PUBLIC_BANNER_IMG":"hs300027.jpg","PUBLIC_VIDEO":"pvideo_hs300027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/960TQM0oUso","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A linear equation in two variable is defined as a first-degree equation that can be written in the form ax + by = c, where both a and b are not equal to zero and \u0026amp;nbsp;a, b, and c are real numbers. 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\r\n\u003Cdiv\u003EA number line is defined as a line on which numbers are marked at regular intervals. The mid of the number line is represented by a zero. The numbers written on the left of zero with negative sign are known as negative numbers and the number written on the right side of zero are known as positive numbers.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Indicate a whole number on a number line.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Indicate an integer on a number line.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Indicate a decimal on a number line.\u003C\/div\u003E","CONT_DESC_AR":"Number line: Writing numbers down on a number line makes it easy to tell which numbers are bigger or smaller.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this topic you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; indicate a whole number on a number line\u0026lt;br \/\u0026gt;\n\u0026amp;bull; indicate an integer on a number line\u0026lt;br \/\u0026gt;\n\u0026amp;bull; indicate a fraction on a number line\u0026lt;br \/\u0026gt;\n\u0026amp;bull; indicate a decimal on a number line","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300040","TOPIC_ID":"ms300040","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300040.jpg","PUBLIC_BANNER_IMG":"MS300040.jpg","PUBLIC_VIDEO":"pvideo_ms300040.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/lQru3vSIa3o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A number line is defined as a line on which numbers are marked at regular intervals. The mid of the number line is represented by a zero. The numbers written on the left of zero with negative sign are known as negative numbers and the number written on the right side of zero are known as positive numbers.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Indicate a whole number on a number line.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Indicate an integer on a number line.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Indicate a decimal on a number line.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0637 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\r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define sector and pie chart.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the parts of a pie chart.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Examine pie chart presented in examples.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize that pie chart provide a visual representation of the whole and its parts.\u003C\/div\u003E","CONT_DESC_AR":"A Pie chart is a type of graph in which a circle is divided into sectors and each sector represents a proportion of the whole.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this topic you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define circle graph, sector, and pie chart\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the parts of a circle graph\u0026lt;br \/\u0026gt;\n\u0026amp;bull; examine circle graphs presented in examples\u0026lt;br \/\u0026gt;\n\u0026amp;bull; recognize that circle graphs provide a visual presentation of the whole and its parts\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ms300039.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300039","TOPIC_ID":"ms300039","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300039.jpg","PUBLIC_BANNER_IMG":"ms300039.jpg","PUBLIC_VIDEO":"pvideo_ms300039.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/GAUfxh48fsU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A pie chart is a graph in which a circle is divided into sectors and each sector represents a proportion of the whole.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define sector and pie chart.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the parts of a pie chart.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Examine pie chart presented in examples.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Recognize that pie chart provide a visual representation of the whole and its parts.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0637\u0637 \u0627\u0644\u062f\u0627\u0626\u0631\u064a","ADMSUBJECT_ID":"754","ADMCOURSE_ID":"143","DISPLAY_NAME":"Bahrain - Grade 7 - Mathematics","DISPLAY_NAME_AR":"Bahrain - Grade 7 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"\u0639\u0650\u0644\u0652\u0645 \u0627\u0644\u0623\u062d\u064a\u0627\u0621: \u0647\u0648 \u062f\u0631\u0627\u0633\u0629 \u0623\u0634\u0643\u0627\u0644 \u0627\u0644\u062d\u064a\u0627\u0629\u060c \u0648\u0627\u0644\u0639\u0645\u0644\u064a\u0627\u062a \u0627\u0644\u062d\u064a\u0648\u064a\u0629. \u062a\u062a\u0639\u0627\u0645\u0644 \u0648\u062d\u062f\u0627\u062a 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Counting","CONT_SLUG":"fundamental-principle-of-counting","CONT_TITLE_AR":"Fundamental Principle of Counting","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe Fundamental Counting Principle is the method to find out the number of outcomes in a probability problem. It is of two types: the multiplication principle which states that if one event has (m) possible outcomes and a second independent event has (n) possible outcomes, then there are (mn) total possible outcomes for the two events together. Another one is the addition principle which states that if there are two events which can occur independently by (m) and (n) ways, then either of the two events can occur in (m+n) ways. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and use the fundamental principle of multiplication.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and use the fundamental principle of addition.\u003C\/div\u003E","CONT_DESC_AR":"The Fundamental Counting Principle is of two types: the Multiplication Principle which states that if one event has (m) possible outcomes and a second independent event has (n) possible outcomes, then there are (mn) total possible outcomes for the two events together.\u0026lt;br \/\u0026gt;\nAnother one is the Addition Principle which states that if there are two events which can occur independently by (m) and (n) ways, then either of the two events can occur in (m+n) ways.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the fundamental principle of multiplication\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the fundamental principle of addition","BACKING_FILE":"ss300011.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300011","TOPIC_ID":"ss300011","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300011.jpg","PUBLIC_BANNER_IMG":"SS300011.jpg","PUBLIC_VIDEO":"pvideo_ss300011.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/O8YlkaAEQKo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;The Fundamental Counting Principle is the method to find out the number of outcomes in a probability problem. It is of two types: the multiplication principle which states that if one event has (m) possible outcomes and a second independent event has (n) possible outcomes, then there are (mn) total possible outcomes for the two events together.\u0026amp;nbsp; Another one is the addition principle which states that if there are two events which can occur independently by (m) and (n) ways, then either of the two events can occur in (m+n) ways.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and use the fundamental principle of multiplication.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and use the fundamental principle of 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Series","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn arithmetic sequence is a sequence in which the successive terms have common differences. With the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, an = a+(n-1)d. Arithmetic mean between two numbers is a+b\/2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic mean between a and b.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assess arithmetic sequence and series.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply a formula for arithmetic sequence and series.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the concept of arithmetic sequence and series.\u003C\/div\u003E","CONT_DESC_AR":"An arithmetic sequence is a sequence in which the successive terms have common differences.\u0026lt;br \/\u0026gt;\nWith the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, an = a+(n-1)d. Arithmetic mean between two numbers is a+b\/2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic mean between a and b.\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nLearning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; assess arithmetic sequence and series\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply a formula for arithmetic sequence and series\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the concept of arithmetic sequence and series\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ss300002.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300002","TOPIC_ID":"ss300002","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300002.jpg","PUBLIC_BANNER_IMG":"ss300002.jpg","PUBLIC_VIDEO":"pvideo_ss300002.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/A8TSAmwj-ac","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;An arithmetic sequence is a sequence in which the successive terms have common differences. With the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, a\u0026lt;span style=\u0026quot;font-size: 9.75px; line-height: 0; position: relative; vertical-align: baseline; bottom: -0.25em; color: rgb(0, 77, 64); font-family: \u0026amp;quot;Open Sans\u0026amp;quot;, \u0026amp;quot;Lucida Sans\u0026amp;quot;, sans-serif; text-align: justify;\u0026quot;\u0026gt;n\u0026lt;\/span\u0026gt;\u0026amp;nbsp;= a+(n-1)d. Arithmetic mean between two numbers is a+b\/2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic mean between a and b.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assess arithmetic sequence and series.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply a formula for arithmetic sequence and series.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the concept of arithmetic sequence and series.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0642\u062f\u0645\u0629 \u0644\u0644\u0645\u062a\u062a\u0627\u0628\u0639\u0627\u062a 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For 4 \u00d7 4 = 16, the square root of 16 will be 4. Similarly, the cube root of a number when used in a multiplication three times, gives that number. Example: 3 \u00d7 3 \u00d7 3 = 27, so the cube root of 27 is 3.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the square root.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the cube root.\u003C\/div\u003E","CONT_DESC_AR":"The square root of a number is a value that, when multiplied by itself, gives the number.\u0026lt;br \/\u0026gt;\nExample: 4 \u0026amp;times; 4 = 16, so the square root of 16 is 4.\u0026lt;br \/\u0026gt;\nSimilarly the cube root of a number is a special value that, when used in a multiplication three times, gives that number. Example: 3 \u0026amp;times; 3 \u0026amp;times; 3 = 27, so the cube root of 27 is 3.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n- identify the square root\u0026lt;br \/\u0026gt;\n- identify the properties of square root\u0026lt;br \/\u0026gt;\n- identify the cube root\u0026lt;br \/\u0026gt;\n- identify the properties of cube root\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ms300084.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300084","TOPIC_ID":"ms300084","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300084.jpg","PUBLIC_BANNER_IMG":"MS300084.jpg","PUBLIC_VIDEO":"pvideo_ms300084.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5rGDhg1xAng","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:35:58","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;h3\u0026gt;Overview:\u0026lt;\/h3\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;The square root of a number is a value that, when multiplied by itself, gives the number. For 4 \u00d7 4 = 16, the square root of 16 will be 4. Similarly, the cube root of a number when used in a multiplication three times, gives that number. 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\u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the term arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of an arithmetic progression.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Insert arithmetic means between two numbers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the nth term formula.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the sum of terms in an arithmetic progression.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vm000007","TOPIC_ID":"vm000007","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vm000007.jpg","PUBLIC_BANNER_IMG":"vm000007.jpg","PUBLIC_VIDEO":"en_us_pvideo_vm000007.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-08-02 12:52:45","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 11:43:06","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;To find the sum of all the n terms of an arithmetic progression, apply the formula for sum of n terms, Sn= (n \/ 2)(2 a + (n - 1) d). the arithmetic mean between two numbers a and b is (a + b) \/ 2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic means between a and b.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Define the term arithmetic progression.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the properties of an arithmetic progression.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Insert arithmetic means between two numbers.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Apply the nth term formula.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Calculate the sum of terms in an arithmetic progression.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Sum of Arithmetic Progression","DISPLAY_NAME":"CBSE - Grade 11 - Mathematics","DISPLAY_NAME_AR":"","SUBJECT_IMG":"","ADMSUBJECT_ID":"882","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"","ADMCOURSE_ID":"198","COURSE_NAME":"Grade 11","COUNTRY_ID":"288","STANDARD_ID":"288","SHORT_NAME":"CBSE","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Ti\u1ebfng Vi\u1ec7t"],"devices":["UmetyVR","WebXR"]}