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These are harder and denser than alkali metals. They react with water to form alkaline solutions, but they are less reactive than alkali metals.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Locate the alkaline earth metals in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the reactivity of alkaline earth metals with water.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine the pH of the hydroxide solutions of alkaline earth metals.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000018","TOPIC_ID":"vc000018","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000018.jpg","PUBLIC_BANNER_IMG":"vc000018.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000018.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;The elements in Group 2 of the periodic table are called the alkaline earth metals. These are harder and denser than alkali metals. They react with water to form alkaline solutions, but they are less reactive than alkali metals.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Locate the alkaline earth metals in the periodic table.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Compare the reactivity of alkaline earth metals with water.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Determine the pH of the hydroxide solutions of alkaline earth metals.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Group 2: Alkaline Earth Metals","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"673","CATEGORY_ID":"1","CONT_TITLE":"Size-Independent Properties","CONT_SLUG":"size-independent-properties","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThose physical properties which are not affected by the amount of matter present in a substance are called size-independent properties. 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They react with water to form alkaline solutions. These metals are more reactive than alkaline earth metals.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Locate the alkali metals in the periodic table.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify and compare alkali metals based on their hardness and reactivity with water.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Determine the pH of the hydroxide solutions of alkali metals.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Group 1: Alkali Metals","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"653","CATEGORY_ID":"1","CONT_TITLE":"Atomic Models","CONT_SLUG":"atomic-models","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDalton\u2019s atomic theory suggested that the atom was indivisible and indestructible. But after the discovery of electrons and protons inside the atom, this aspect of Dalton\u2019s atomic theory failed. Then, to know how electrons and protons are arranged within an atom, many scientists proposed various atomic models like Thomson\u2019s model, Rutherford\u2019s model, and Bohr\u2019s model.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the structure of an atom proposed by Thomson, Rutherford and Bohr.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict different structures of an atom.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000003","TOPIC_ID":"vc000003","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000003.jpg","PUBLIC_BANNER_IMG":"vc000003.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000003.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/uUSd4UBMRuk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Dalton\u2019s atomic theory suggested that the atom was indivisible and indestructible. But after the discovery of electrons and protons inside the atom, this aspect of Dalton\u2019s atomic theory failed. Then, to know how electrons and protons are arranged within an atom, many scientists proposed various atomic models like Thomson\u2019s model, Rutherford\u2019s model, and Bohr\u2019s model.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe an atom.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Compare the structure of an atom proposed by Thomson, Rutherford and Bohr.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Predict different structures of an atom.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Atomic Models","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"568","CATEGORY_ID":"1","CONT_TITLE":"Ionic Compounds","CONT_SLUG":"ionic-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EIonic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Identify ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Demonstrate the solubility of ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Examine the electrical conductivity of ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200314","TOPIC_ID":"hs200314","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200314.jpg","PUBLIC_BANNER_IMG":"HS200314.jpg","PUBLIC_VIDEO":"pvideo_hs200314.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/rqIx2k9cru4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Ionic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify ionic compounds.\u0026lt;br\u0026gt;- Demonstrate the solubility of ionic compounds.\u0026lt;br\u0026gt;- Examine the electrical conductivity of ionic compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Ionic Compounds","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"508","CATEGORY_ID":"1","CONT_TITLE":"Formation of Ionic Bonds","CONT_SLUG":"formation-of-ionic-bonds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn ionic bond is the electrostatic attraction between two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. Elements in columns 1, 2, and 3 on the periodic chart are likely to form ionic bonds with elements in columns 15, 16, and 17.\u003C\/div\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is an ionic compound. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Form ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200432","TOPIC_ID":"hs200432","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200432.jpg","PUBLIC_BANNER_IMG":"HS200432.jpg","PUBLIC_VIDEO":"pvideo_hs200432.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/fuvvXfCCOBg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An ionic bond is the electrostatic attraction between two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. E\u0026lt;span style=\u0026quot;color: rgb(38, 50, 56); font-family: Roboto, sans-serif;\u0026quot;\u0026gt;lements in columns 1, 2, and 3 on the periodic chart are likely to form ionic bonds with elements in columns 15, 16, and 17.\u0026lt;\/span\u0026gt;\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain what is an ionic compound.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Form ionic compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Formation of Ionic Bonds","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"507","CATEGORY_ID":"1","CONT_TITLE":"Liquids","CONT_SLUG":"liquids","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELiquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the intermolecular spaces between particles of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between particles of liquids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200425.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200425","TOPIC_ID":"ms200425","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200425.jpg","PUBLIC_BANNER_IMG":"MS200425.jpg","PUBLIC_VIDEO":"pvideo_ms200425.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xm78b3sjxbI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Liquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the intermolecular spaces between particles of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between particles of liquids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Liquids","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"504","CATEGORY_ID":"1","CONT_TITLE":"Today\u0027s Periodic Table","CONT_SLUG":"todays-periodic-table","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe Periodic table is the systematic arrangement of 118 elements in the increasing order of their atomic number. The rows in the periodic table are called periods and the columns in the periodic table are called groups.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what groups and periods are.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the criteria for placing elements in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Provide a suitable name for each group.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Arrange elements according to their atomic number.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200413","TOPIC_ID":"hs200413","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200413.jpg","PUBLIC_BANNER_IMG":"HS200413.jpg","PUBLIC_VIDEO":"pvideo_hs200413.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/jnMKcnEqf5o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The Periodic table is the systematic arrangement of 118 elements in the increasing order of their atomic number. The rows in the periodic table are called periods and the columns in the periodic table are called groups.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what groups and periods are.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the criteria for placing elements in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Provide a suitable name for each group.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Arrange elements according to their atomic number.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Today\u0027s Periodic Table","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"486","CATEGORY_ID":"1","CONT_TITLE":"Properties of Gases","CONT_SLUG":"properties-of-gases","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGases do not have definite shape and volume. They attain the shape and volume of the container. Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate that gases do not have definite shape and volume.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Explain that gases occupy the whole space available to them. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe that gases have unlimited diffusibility. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that gases have high compressibility.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200283.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200283","TOPIC_ID":"ms200283","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200283.jpg","PUBLIC_BANNER_IMG":"MS200283.jpg","PUBLIC_VIDEO":"pvideo_ms200283.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/n4tYu4qJMsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Gases do not have definite shape and volume. They attain the shape and volume of the container.\u0026amp;nbsp; Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Illustrate that gases do not have definite shape and volume.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases occupy the whole space available to them.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe that gases have unlimited diffusibility.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases have high compressibility.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Properties of Gases","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"485","CATEGORY_ID":"1","CONT_TITLE":"Properties of Liquids-Viscosity","CONT_SLUG":"properties-of-liquids-viscosity","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDifferent solutions have different fluidity. The liquid which flows slowly is known to have higher viscosity. The term, viscosity means resistance to flow. It decreases as the liquid becomes warmer. Thus, it can be said that viscosity is temperature dependent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define viscosity.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare and describe the order of viscosities of different solutions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Complete an experiment to show the effect of temperature on viscosity.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200281","TOPIC_ID":"ss200281","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200281.jpg","PUBLIC_BANNER_IMG":"SS200281.jpg","PUBLIC_VIDEO":"pvideo_ss200281.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/aeAntU_QRps","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Different solutions have different fluidity. The liquid which flows slowly is known to have higher viscosity. The term, viscosity means resistance to flow. It decreases as the liquid becomes warmer. Thus, it can be\u0026amp;nbsp; said that viscosity is temperature dependent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Define viscosity.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Compare and describe the order of viscosities of different solutions.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Complete an experiment to show the effect of temperature on viscosity\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Properties of Liquids: Viscosity","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"372","CATEGORY_ID":"1","CONT_TITLE":"Application of VSEPR Theory","CONT_SLUG":"application-of-vsepr-theory","CONT_TITLE_AR":"Application of VSEPR Theory","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence shell electron pair repulsion (VSEPR) theory is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply VSEPR theory to predict the three-dimensional shapes of molecules.\u003C\/div\u003E","CONT_DESC_AR":"Valence shell electron pair repulsion (VSEPR)\u0026amp;nbsp;theory\u0026amp;nbsp;is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n- construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- apply VSEPR theory to predict the three-dimensional shapes of molecules","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200035","TOPIC_ID":"ss200035","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200035.jpg","PUBLIC_BANNER_IMG":"SS200035.jpg","PUBLIC_VIDEO":"pvideo_ss200035.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/gR_7S2Lk39g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Valence shell electron pair repulsion (VSEPR) theory is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply VSEPR theory to predict the three-dimensional shapes of molecules.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Application of VSEPR Theory","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"371","CATEGORY_ID":"1","CONT_TITLE":"VSEPR Theory","CONT_SLUG":"vsepr-theory","CONT_TITLE_AR":"VSEPR Theory","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \u003Cdiv\u003E  \u003Cbr\u003E \u003C\/div\u003E \u003Cdiv\u003EValence shell electron pair repulsion (VSEPR) theory suggests that the electron pairs surrounding the central atom repel each other and tend to occupy such positions around the central atom that minimize this repulsion. According to this theory, the geometry of a molecule depends upon the total number of electron pairs present around the central atom.\u003C\/div\u003E \u003Cdiv\u003E  \u003Cbr\u003E \u003C\/div\u003E \u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \u003Cdiv\u003E  \u003Cbr\u003E \u003C\/div\u003E \u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \u003Cdiv\u003E- Explain valence shell electron pair repulsion (VSEPR) theory.\u003C\/div\u003E \u003Cdiv\u003E- Predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms.\u003C\/div\u003E","CONT_DESC_AR":"According to valence shell electron pair repulsion (VSEPR) theory, the valence electron pairs surrounding an atom mutually repel each other. They adopt an arrangement that minimizes this repulsion, thus determining its molecular geometry. This means that bonding and non-bonding electrons will repel each other as far away as geometrically possible. The number of atoms bonded to a central atom combined with the number of pairs of its non-bonding valence electrons is called its steric number.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain Valence shell electron pair repulsion (VSEPR) theory\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200034","TOPIC_ID":"ss200034","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200034.jpg","PUBLIC_BANNER_IMG":"SS200034.jpg","PUBLIC_VIDEO":"pvideo_ss200034.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RVz4Vp1j4nQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Valence shell electron pair repulsion (VSEPR) theory suggests that the electron pairs surrounding the central atom repel each other and tend to occupy such positions around the central atom that minimize this repulsion. According to this theory, the geometry of a molecule depends upon the total number of electron pairs present around the central atom.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-weight: bold;\u0026quot;\u0026gt;Learning Objectives:\u0026lt;\/span\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain valence shell electron pair repulsion (VSEPR) theory.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"VSEPR Theory","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"369","CATEGORY_ID":"1","CONT_TITLE":"Balancing Redox Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance oxidation half-reaction and reduction half-reaction separately.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Balancing Redox Reaction","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"368","CATEGORY_ID":"1","CONT_TITLE":"Oxidation-Reduction Reactions","CONT_SLUG":"oxidation-reduction-reaction","CONT_TITLE_AR":"Oxidation-Reduction Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoth oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify oxidation-reduction or redox reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidizing and reducing agents in a redox reaction.\u003C\/div\u003E","CONT_DESC_AR":"In a redox reaction both oxidation and reduction takes place in a single reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define oxidation-reduction (redox) reactions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidizing and reducing agents in a redox reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200026","TOPIC_ID":"ss200026","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200026.jpg","PUBLIC_BANNER_IMG":"SS200026.jpg","PUBLIC_VIDEO":"pvideo_ss200026.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/frc5RvK7rIk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Both oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify oxidation-reduction or redox reactions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the oxidizing and reducing agents in a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Oxidation-Reduction Reactions","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"262","CATEGORY_ID":"1","CONT_TITLE":"Structure of Benzene","CONT_SLUG":"structure-of-benzene","CONT_TITLE_AR":"Structure of Benzene","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"The molecular formula of benzene is C6H6 Kekule proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2\u0026amp;nbsp;hybridised.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify Kekul\u0026amp;eacute; structures and the modern symbol of benzene\u0026lt;br \/\u0026gt;\n- explain the orbital structure of benzene\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the benzene molecule using its electrostatic potential map","BACKING_FILE":"ss200043.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200043","TOPIC_ID":"ss200043","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200043.jpg","PUBLIC_BANNER_IMG":"SS200043.jpg","PUBLIC_VIDEO":"pvideo_ss200043.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0FPZELqrUf4","DIST":null,"SHOW_ON_HOME":"Y","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;The molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the orbital structure of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Benzene","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"259","CATEGORY_ID":"1","CONT_TITLE":"Aromatic Compounds","CONT_SLUG":"aromatic-compound","CONT_TITLE_AR":"Aromatic Compound","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EH\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the criteria for aromaticity described by H\u00fcckel.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether a molecule is aromatic or not by investigating its structure.\u003C\/div\u003E","CONT_DESC_AR":"Huckel postulated that planar cyclic conjugated polyenes containing delocalised (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6\u0026amp;pi; electrons and is aromatic.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the criteria for aromaticity described by Huckel\u0026lt;br \/\u0026gt;\n\u0026amp;bull; determine whether a molecule is aromatic or not by investigating its structure","BACKING_FILE":"ss200042.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200042","TOPIC_ID":"ss200042","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200042.jpg","PUBLIC_BANNER_IMG":"SS200042.jpg","PUBLIC_VIDEO":"pvideo_ss200042.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/N7AnvZ7Qtqw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;H\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the criteria for aromaticity described by H\u00fcckel.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Determine whether a molecule is aromatic or not by investigating its structure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Aromatic Compound","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"242","CATEGORY_ID":"1","CONT_TITLE":"Titration of a Strong Acid with a Strong Base","CONT_SLUG":"titration-of-a-strong-acid-with-a-strong-base","CONT_TITLE_AR":"Titration of a Strong Acid with a Strong Base","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETitration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the detailed procedure for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the laboratory setup for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the application of the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Extrapolate the graph for the titration of a strong acid with a strong base.\u003C\/div\u003E","CONT_DESC_AR":"Strong acid-strong base titration is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the detailed procedure for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the laboratory setup for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the application of titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; extrapolate the graph for the titration of a strong acid with a strong base","BACKING_FILE":"ss200032.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200032","TOPIC_ID":"ss200032","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200032.jpg","PUBLIC_BANNER_IMG":"SS200032.jpg","PUBLIC_VIDEO":"pvideo_ss200032.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/R4ghDnAEBuo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Titration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the detailed procedure for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the laboratory setup for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the application of the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Extrapolate the graph for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Titration of a Strong acid with a Strong Base","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"234","CATEGORY_ID":"1","CONT_TITLE":"Calculating the Oxidation Number","CONT_SLUG":"calculating-oxidation-number","CONT_TITLE_AR":"Calculating Oxidation Number","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFor calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define oxidation number.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assign oxidation number to different elements in a chemical species.\u003C\/div\u003E","CONT_DESC_AR":"While calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation you will be able to:\u003C\/br\u003E\r\n\u2022 define oxidation number\u003C\/br\u003E\r\n\u2022 assign the oxidation number to different elements in a chemical species","BACKING_FILE":"ss200027.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200027","TOPIC_ID":"ss200027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200027.jpg","PUBLIC_BANNER_IMG":"SS200027.jpg","PUBLIC_VIDEO":"pvideo_ss200027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Jf7BP10vSVM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define oxidation number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assign oxidation number to different elements in a chemical species.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Calculating Oxidation Number","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"224","CATEGORY_ID":"1","CONT_TITLE":"Structure of Alkynes","CONT_SLUG":"structure-of-alkynes","CONT_TITLE_AR":"Structure of Alkynes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAlkynes are hydrocarbons that contain at least one carbon-carbon triple bond. Each carbon atoms in alkyne making a triple bond is sp hybridized. Hence alkynes contain both sigma and pi-bond. Ethyne is the simplest hydrocarbon, with chemical formula C2H2.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify an alkyne molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure and hybridization of the simplest alkyne molecule, ethyne.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe bonding and hybridization in alkynes.\u003C\/div\u003E","CONT_DESC_AR":"Alkynes are hydrocarbons that contain at least one carbon-carbon triple bond. Each carbon atoms in alkyne making a triple bond is sp hybridized. Hence alkynes contain both sigma and pi-bond. Ethyne is the simplest hydrocarbon, with chemical formulae C2H2.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify an alkyne molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the structure and hybridisation of the simplest alkyne molecule, ethyne\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe bonding and hybridisation in alkynes","BACKING_FILE":"ss200009.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200009","TOPIC_ID":"ss200009","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200009.jpg","PUBLIC_BANNER_IMG":"SS200009.jpg","PUBLIC_VIDEO":"pvideo_ss200009.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EGv4LSMdQwo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Alkynes are hydrocarbons that contain at least one carbon-carbon triple bond. Each carbon atoms in alkyne making a triple bond is sp hybridized. Hence alkynes contain both sigma and pi-bond. Ethyne is the simplest hydrocarbon, with chemical formula C2H2.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify an alkyne molecule.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure and hybridization of the simplest alkyne molecule, ethyne.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe bonding and hybridization in alkynes.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Alkynes","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"220","CATEGORY_ID":"1","CONT_TITLE":"Structure of Alkenes","CONT_SLUG":"structure-of-alkenes","CONT_TITLE_AR":"Structure of Alkenes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAlkenes are hydrocarbons that contain at least one carbon-carbon double bond. Each of the carbon atoms in alkene making a double bond is sp\u00b2 hybridized. Hence alkenes contain both sigma and pi-bond. Ethene is the simplest hydrocarbon, with a chemical formula of C2H4.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify an alkene molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure and hybridization of the simplest alkene molecule, ethene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe bonding and hybridization in alkenes.\u003C\/div\u003E","CONT_DESC_AR":"Alkenes are hydrocarbons that contain at least one carbon-carbon double bond. Each of the carbon atoms in alkene making a double bond is sp2 hybridized. Hence alkenes contain both sigma and pi-bond. Ethene is the simplest hydrocarbon, with a chemical formula of C2H4.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify an alkene molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the structure and hybridisation of the simplest alkene molecule, ethene\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the bonding and hybridisation in alkenes","BACKING_FILE":"ss200005.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200005","TOPIC_ID":"ss200005","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200005.jpg","PUBLIC_BANNER_IMG":"SS200005.jpg","PUBLIC_VIDEO":"pvideo_ss200005.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/z4Tr-o6KRBs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Alkenes are hydrocarbons that contain at least one carbon-carbon double bond. Each of the carbon atoms in alkene making a double bond is sp\u00b2 hybridized. Hence alkenes contain both sigma and pi-bond. Ethene is the simplest hydrocarbon, with a chemical formula of C2H4.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify an alkene molecule.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe the structure and hybridization of the simplest alkene molecule, ethene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe bonding and hybridization in alkenes.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Alkenes","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"217","CATEGORY_ID":"1","CONT_TITLE":"Structure of Alkanes","CONT_SLUG":"structure-of-alkanes","CONT_TITLE_AR":"Structure of Alkanes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAlkanes are hydrocarbons that contain only a single bond. All the carbon atoms in an alkane are sp3 hybridized. Hence only a sigma bond is found in alkanes. Methane is the simplest hydrocarbon with a chemical formula of CH4.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify alkane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the structure of an alkane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe bonding and hybridization in alkanes.\u003C\/div\u003E","CONT_DESC_AR":"Alkanes are hydrocarbons that contain only a single bond. All the carbon atoms in an alkane are sp3 hybridized. Hence only a sigma bond is found in alkanes. Methane is the simplest hydrocarbon with a chemical formula of CH4.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify an alkane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the structure of an alkane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the bonding and hybridisation in alkanes","BACKING_FILE":"ss200002.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200002","TOPIC_ID":"ss200002","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200002.jpg","PUBLIC_BANNER_IMG":"SS200002.jpg","PUBLIC_VIDEO":"pvideo_ss200002.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/PsksVs8o8hg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Alkanes are hydrocarbons that contain only a single bond. All the carbon atoms in an alkane are sp3 hybridized. Hence only a sigma bond is found in alkanes. Methane is the simplest hydrocarbon with a chemical formula of CH4.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify alkane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the structure of an alkane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe bonding and hybridization in alkanes.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Alkanes","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"211","CATEGORY_ID":"1","CONT_TITLE":"Factors Affecting Equilibria","CONT_SLUG":"factors-affecting-equilibria","CONT_TITLE_AR":"Factors Affecting Equilibria","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAccording to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u003C\/div\u003E","CONT_DESC_AR":"According to Le Chateliers principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain, when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change","BACKING_FILE":"ss200017.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200017","TOPIC_ID":"ss200017","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200017.jpg","PUBLIC_BANNER_IMG":"SS200017.jpg","PUBLIC_VIDEO":"pvideo_ss200017.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KtndjzIHD3A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;According to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Factors Affecting Equilibrium","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"204","CATEGORY_ID":"1","CONT_TITLE":"Aufbau Principle","CONT_SLUG":"aufbau-principle","CONT_TITLE_AR":"Aufbau principle","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the ground state of the atoms, electrons first occupy the lowest energy orbital available to them and once the lower energy orbitals are filled, the electron can enter into higher energy orbital. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the energy order of the orbitals in an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Arrange the electrons in different orbitals in order of increasing energy.\u003C\/div\u003E","CONT_DESC_AR":"In the ground state of the atoms, electrons first occupy the lowest energy orbital available to them and once the lower energy orbitals are filled, the electron can enter into higher energy orbital.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the energy order of the orbitals\u0026lt;br \/\u0026gt;\n\u0026amp;bull; arrange the electrons in different orbitals in order of increasing energy","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200014","TOPIC_ID":"ss200014","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200014.jpg","PUBLIC_BANNER_IMG":"ss200014.jpg","PUBLIC_VIDEO":"pvideo_ss200014.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/TGDXQNbFyOs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;In the ground state of the atoms, electrons first occupy the lowest energy orbital available to them and once the lower energy orbitals are filled, the electron can enter into higher energy orbital.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the energy order of the orbitals in an atom.\u0026lt;div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Arrange the electrons in different orbitals in order of increasing energy.\u0026lt;div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Aufbau Principle","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"200","CATEGORY_ID":"1","CONT_TITLE":"Structure of the Atom","CONT_SLUG":"structure-of-the-atom","CONT_TITLE_AR":"Structure of the Atom","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EEvery atom is made of a nucleus consisting of protons and neutrons. The nucleus is surrounded by electrons. Protons and electrons are oppositely charged, and neutrons have no charge. Thus the nucleus of an atom is positively charged.\u003C\/div\u003E \r\n\u003Cdiv\u003EOverall, an atom is electrically neutral because it has the same number of electrons as protons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the structure of an atom proposed by J. J. Thomson.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the structure of an atom proposed by Rutherford.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the structure of an atom proposed by Niels Bohr.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the quantum mechanical model of an atom.\u003C\/div\u003E","CONT_DESC_AR":"In atoms, electrons which are found in the outermost shell are generally known as valence electrons and the number of valence electrons determines the valency of an atom.\u0026lt;br \/\u0026gt;\nThe valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electron.\u0026lt;br \/\u0026gt;\nAnd the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from the number eight.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the structure of an atom proposed by J. J. Thomson\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the structure of an atom proposed by Rutherford\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the structure of an atom proposed by Neils Bohr\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the quantum mechanical model of an atom\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ss200006.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200006","TOPIC_ID":"ss200006","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200006.jpg","PUBLIC_BANNER_IMG":"SS200006.jpg","PUBLIC_VIDEO":"pvideo_ss200006.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/oGc6JdkYAwY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Every atom is made of a nucleus consisting of protons and neutrons. The nucleus is surrounded by electrons. Protons and electrons are oppositely charged, and neutrons have no charge. Thus the nucleus of an atom is positively charged.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Overall, an atom is electrically neutral because it has the same number of electrons as protons.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the structure of an atom proposed by J. J. Thomson.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the structure of an atom proposed by Rutherford.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the structure of an atom proposed by Niels Bohr.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the quantum mechanical model of an atom.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of the Atom","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"192","CATEGORY_ID":"1","CONT_TITLE":"Structure of Methane","CONT_SLUG":"structure-of-methane","CONT_TITLE_AR":"Structure of Methane","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the molecular formula of methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the hybridization of the carbon atom in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the tetrahedral structure of methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of covalent bonds present in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the C-H bond length and the H-C-H bond angle in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the electrostatic potential map of methane.\u003C\/div\u003E","CONT_DESC_AR":"A methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the molecular formula of methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the hybridisation of the carbon atom in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the tetrahedral structure of methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of covalent bonds present in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the C-H bond length and the H-C-H bond angle in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the electrostatic potential map of methane","BACKING_FILE":"hs200078.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200078","TOPIC_ID":"hs200078","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200078.jpg","PUBLIC_BANNER_IMG":"HS200078.jpg","PUBLIC_VIDEO":"pvideo_hs200078.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KyIxUUo8mzg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Write the molecular formula of methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the hybridization of the carbon atom in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the tetrahedral structure of methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the number of covalent bonds present in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the C-H bond length and the H-C-H bond angle in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the electrostatic potential map of methane.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Methane","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"169","CATEGORY_ID":"1","CONT_TITLE":"Lewis Dot Structures","CONT_SLUG":"lewis-dot-structures","CONT_TITLE_AR":"Lewis dot Structures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u003C\/div\u003E","CONT_DESC_AR":"Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u0026amp;rsquo;s chemical symbol.Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain steps involved in writing Lewis dot structures of atoms and molecules\u0026lt;br \/\u0026gt;\n\u0026amp;bull; draw Lewis dot structures of atoms and molecules","BACKING_FILE":"hs200069.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200069","TOPIC_ID":"hs200069","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200069.jpg","PUBLIC_BANNER_IMG":"HS200069.jpg","PUBLIC_VIDEO":"pvideo_hs200069.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/W0V5VQ3PcC4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Lewis Dot Structures","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"},{"CONT_ID":"148","CATEGORY_ID":"1","CONT_TITLE":"Periodic Trends-Atomic Radii","CONT_SLUG":"periodic-trends-atomic-radii","CONT_TITLE_AR":"Periodic Trends: Atomic Radii","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe atomic radius of a chemical element is the distance from the center of the nucleus to the outmost boundary of the surrounding cloud of electrons. On moving left to right in the periodic table, the atomic radius decreases with the atomic number. Down the group, the atomic radius increases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the trends of atomic radii in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the atomic radii of the elements.\u003C\/div\u003E","CONT_DESC_AR":"The atomic radius of a chemical element is the distance from the center of the nucleus to the boundary of the surrounding cloud of electrons. On moving left to right in the periodic table, the atomic radius decreases with the atomic number. Down the group, the atomic radius increases in conjunction to the atomic number.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation, you will be able to:\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the valency of elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the placement of elements in the periodic table using valency","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200012","TOPIC_ID":"hs200012","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200012.jpg","PUBLIC_BANNER_IMG":"hs200012.jpg","PUBLIC_VIDEO":"pvideo_hs200012.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/InBee94xfgk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The atomic radius of a chemical element is the distance from the center of the nucleus to the outmost boundary of the surrounding cloud of electrons. On moving left to right in the periodic table, the atomic radius decreases with the atomic number. 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The valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electrons. And the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from number eight.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the valency of an element using the number of valence electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine the valency of an element with the help of its position in the periodic table.\u003C\/div\u003E","CONT_DESC_AR":"In the atoms, the electrons which are found in the outermost shell are generally known as valence electrons and the number of valence electrons determines the valency of an atom.\u0026amp;nbsp;The valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electron.\u0026amp;nbsp;And the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from number eight.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning objectives\u0026amp;nbsp;\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation, you will be able to:\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the valency of elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the placement of elements in the periodic table using valency","BACKING_FILE":"hs200011.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200011","TOPIC_ID":"hs200011","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200011.jpg","PUBLIC_BANNER_IMG":"hs200011.jpg","PUBLIC_VIDEO":"pvideo_hs200011.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XV474BAXvVQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-07-23 09:59:55","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the atoms, the electrons which are found in the outermost shell are generally known as valence electrons and the number of valence electrons determines the valency of an atom. The valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electrons. And the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from number eight.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the valency of an element using the number of valence electrons.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Determine the valency of an element with the help of its position in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Periodic Trends: Valency","ADMSUBJECT_ID":"1339","ADMCOURSE_ID":"382","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"342","SHORT_NAME":"ICSE","DOMAIN_NAME":"STEM"}],"levelObject":["Benzene","Molecular Formula Of Benzene","C6H6","Kekul\u00e9 Structures","Orbital Structure Of Benzene","Modern Symbol Of Benzene","Electrostatic Potential Map Of Benzene","\u03c3-Bond Framework Of Benzene Molecule","\u03c0-electron Cloud","Sp2 Hybridised Orbital","Electron Density"],"contData":{"CONT_ID":"262","CATEGORY_ID":"1","CONT_TITLE":"Structure of Benzene","CONT_SLUG":"structure-of-benzene","CONT_TITLE_AR":"Structure of Benzene","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"The molecular formula of benzene is C6H6 Kekule proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2\u0026amp;nbsp;hybridised.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify Kekul\u0026amp;eacute; structures and the modern symbol of benzene\u0026lt;br \/\u0026gt;\n- explain the orbital structure of benzene\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the benzene molecule using its electrostatic potential map","BACKING_FILE":"ss200043.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200043","TOPIC_ID":"ss200043","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200043.jpg","PUBLIC_BANNER_IMG":"SS200043.jpg","PUBLIC_VIDEO":"pvideo_ss200043.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0FPZELqrUf4","DIST":"AF,AX,AL,DZ,AS,AD,AO,AI,AQ,AG,AR,AM,AW,AU,AT,AZ,BS,BH,BD,BB,BY,BE,BZ,BJ,BM,BT,BO,BQ,BA,BW,BV,BR,IO,BN,BG,BF,BI,KH,CM,CA,CV,KY,CF,TD,CL,CN,CX,CC,CO,KM,CG,CK,CR,CI,HR,CU,CW,CY,CZ,CD,DK,DJ,DM,DO,EC,EG,SV,GQ,ER,EE,ET,FK,FO,FJ,FI,FR,GF,PF,TF,GA,GM,GE,DE,GH,GI,GR,GL,GD,GP,GU,GT,GG,GN,GW,GY,HT,HM,HN,HK,HU,IS,IN,ID,IR,IQ,IE,IM,IT,JM,JP,JE,JO,KZ,KE,KI,XK,KW,KG,LA,LV,LB,LS,LR,LY,LI,LT,LU,MO,MK,MG,MW,MY,MV,ML,MT,MH,MQ,MR,MU,YT,MX,FM,MD,MC,MN,ME,MS,MA,MZ,MM,NA,NR,NP,NL,NC,NZ,NI,NE,NG,NU,NF,KP,MP,NO,OM,PK,PW,PS,PA,PG,PY,PE,PH,PN,PL,PT,PR,QA,RE,RO,RU,RW,BL,SH,KN,LC,MF,PM,VC,WS,SM,ST,SA,SN,RS,SC,SL,SG,SX,SK,SI,SB,SO,ZA,GS,KR,SS,ES,LK,SD,SR,SJ,SZ,SE,CH,SY,TW,TJ,TZ,TH,TL,TG,TK,TO,TT,TN,TR,TM,TC,TV,UG,UA,AE,GB,US,UM,UY,UZ,VU,VA,VE,VN,VG,VI,WF,EH,YE,ZM,ZW","SHOW_ON_HOME":"Y","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":"0","CREATED_ON":"2017-01-22 09:03:21","CREATED_BY":"1","UPDATED_ON":"2024-10-08 10:45:17","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;The molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the orbital structure of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of benzene","DISPLAY_NAME":"NGSS New - Middle School - Physical Science","DISPLAY_NAME_AR":"NGSS New - Middle School - Physical Science","SUBJECT_IMG":"569.jpg","ADMSUBJECT_ID":"569","SUBJECT_NAME":"Physical Science","SUBJECT_NAME_AR":"Physical Science","ADMCOURSE_ID":"191","COURSE_NAME":"Middle School","COUNTRY_ID":"287","STANDARD_ID":"287","SHORT_NAME":"NGSS","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u4e2d\u6587","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Portugu\u00eas ","Ti\u1ebfng Vi\u1ec7t"],"devices":["UmetyVR","WebXR"]}