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A coefficient specifies how many of each molecule are required for a balanced equation. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the terms chemical equation and coefficient.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the law of conservation of mass to describe the characteristics of a balanced chemical equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether or not a chemical equation is balanced.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance a chemical equations.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000037","TOPIC_ID":"vc000037","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000037.jpg","PUBLIC_BANNER_IMG":"vc000037.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000037.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;A chemical equation is the symbolic representation of a chemical reaction. A chemical equation must be balanced according to the Law of Conservation of Mass. In order to balance a chemical equation, the molecular formulas in the equation cannot be altered. A coefficient specifies how many of each molecule are required for a balanced equation.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Define the terms chemical equation and coefficient.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Apply the law of conservation of mass to describe the characteristics of a balanced chemical equation.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Determine whether or not a chemical equation is balanced.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Balance a chemical equations.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0643\u064a\u0641 \u062a\u0632\u0646 \u0627\u0644\u0645\u0639\u0627\u062f\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u061f","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - 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Solutions are homogeneous mixtures. The elements in the compounds are joined by bonds. Some compounds, such as water and sodium chloride, form a solution when mixed together.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the difference between compounds and solutions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- List some common examples of compounds and solutions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000030","TOPIC_ID":"vc000030","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000030.jpg","PUBLIC_BANNER_IMG":"vc000030.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000030.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0E6v-A568h0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;The chemical substances that contain two or more elements that are chemically bonded to one another are called compounds. 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Some of the common functional groups present in organic compounds include -OH, -CHO, -CO, -COOH, C=C, C\u2261C, and halogen. 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IUPAC stands for International Union of Pure Chemistry, an organization responsible for standardizing chemical terminology, such as the naming conventions for organic compounds. According to IUPAC system, the IUPAC name of a hydrocarbon may consist of 3 parts: \u201c Prefix + Root word + Suffix\u201d.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe prefixes, suffixes, and root words.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name straight-chain saturated and unsaturated hydrocarbons.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name branched-chain saturated and unsaturated hydrocarbons.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize hydrocarbons based on the IUPAC name.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000001","TOPIC_ID":"vc000001","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000001.jpg","PUBLIC_BANNER_IMG":"vc000001.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000001.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/6EVY02b5CFA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Organic compounds have a common name, similar to a nickname, and a more formal IUPAC name. IUPAC stands for International Union of Pure Chemistry, an organization responsible for standardizing chemical terminology, such as the naming conventions for organic compounds. According to IUPAC system, the IUPAC name of a hydrocarbon may consist of 3 parts: \u201c Prefix + Root word + Suffix\u201d.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe prefixes, suffixes, and root words.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Name straight-chain saturated and unsaturated hydrocarbons.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Name branched-chain saturated and unsaturated hydrocarbons.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Recognize hydrocarbons based on the IUPAC name.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0648\u0627\u0639\u062f \u062a\u0633\u0645\u064a\u0629 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u0643\u0631\u0628\u0648\u0646\u0627\u062a.","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - 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Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Identify ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Demonstrate the solubility of ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Examine the electrical conductivity of ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200314","TOPIC_ID":"hs200314","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200314.jpg","PUBLIC_BANNER_IMG":"HS200314.jpg","PUBLIC_VIDEO":"pvideo_hs200314.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/rqIx2k9cru4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Ionic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. 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Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the intermolecular spaces between the particles in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between the particles in solids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u0648\u0627\u0645\u062f","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - Grade 11 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 11 - 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\u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Sort compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify compounds and mixtures on the basis of molecular 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The rows in the periodic table are called periods and the columns in the periodic table are called groups.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what groups and periods are.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the criteria for placing elements in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Provide a suitable name for each group.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Arrange elements according to their atomic number.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a \u0627\u0644\u062d\u062f\u064a\u062b","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - Grade 11 - Chemistry","DISPLAY_NAME_AR":"Jordan - 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These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain a decomposition reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200319","TOPIC_ID":"ms200319","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200319.jpg","PUBLIC_BANNER_IMG":"MS200319.jpg","PUBLIC_VIDEO":"pvideo_ms200319.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Dnrhrdmk_RY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. 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The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify oxidation-reduction or redox reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidizing and reducing agents in a redox reaction.\u003C\/div\u003E","CONT_DESC_AR":"In a redox reaction both oxidation and reduction takes place in a single reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define oxidation-reduction (redox) reactions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidizing and reducing agents in a redox reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200026","TOPIC_ID":"ss200026","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200026.jpg","PUBLIC_BANNER_IMG":"SS200026.jpg","PUBLIC_VIDEO":"pvideo_ss200026.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/frc5RvK7rIk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Both oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify oxidation-reduction or redox reactions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the oxidizing and reducing agents in a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0623\u0643\u0633\u062f\u0629 \u0648\u0627\u0644\u0627\u062e\u062a\u0632\u0627\u0644","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - 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Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"The molecular formula of benzene is C6H6 Kekule proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2\u0026amp;nbsp;hybridised.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify Kekul\u0026amp;eacute; structures and the modern symbol of benzene\u0026lt;br \/\u0026gt;\n- explain the orbital structure of benzene\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the benzene molecule using its electrostatic potential map","BACKING_FILE":"ss200043.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200043","TOPIC_ID":"ss200043","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200043.jpg","PUBLIC_BANNER_IMG":"SS200043.jpg","PUBLIC_VIDEO":"pvideo_ss200043.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0FPZELqrUf4","DIST":null,"SHOW_ON_HOME":"Y","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;The molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the orbital structure of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0628\u0646\u0632\u064a\u0646","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - 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An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the criteria for aromaticity described by H\u00fcckel.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether a molecule is aromatic or not by investigating its structure.\u003C\/div\u003E","CONT_DESC_AR":"Huckel postulated that planar cyclic conjugated polyenes containing delocalised (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6\u0026amp;pi; electrons and is aromatic.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the criteria for aromaticity described by Huckel\u0026lt;br \/\u0026gt;\n\u0026amp;bull; determine whether a molecule is aromatic or not by investigating its structure","BACKING_FILE":"ss200042.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200042","TOPIC_ID":"ss200042","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200042.jpg","PUBLIC_BANNER_IMG":"SS200042.jpg","PUBLIC_VIDEO":"pvideo_ss200042.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/N7AnvZ7Qtqw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;H\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the criteria for aromaticity described by H\u00fcckel.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Determine whether a molecule is aromatic or not by investigating its structure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - Grade 11 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0634\u0631\u062d \u0648\u062d\u062f\u0627\u062a \u0627\u0644\u0645\u0633\u062a\u0648\u0649 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a \u0627\u0644\u062d\u062f\u064a\u062b \u0648\u0627\u0644\u0623\u0637\u064a\u0627\u0641 \u0627\u0644\u0630\u0631\u064a\u0629\u060c \u0648\u0627\u0644\u0637\u064a\u0641 \u0627\u0644\u0643\u0647\u0631\u0648\u0645\u063a\u0646\u0627\u0637\u064a\u0633\u064a\u060c \u0648\u0627\u0644\u062a\u0637\u0648\u0631\u0627\u062a \u0627\u0644\u062a\u064a \u0623\u062f\u062a \u0625\u0644\u0649 \u0646\u0645\u0648\u0630\u062c \u0628\u0648\u0631 \u0627\u0644\u0630\u0631\u064a. \u062a\u0631\u0643\u0651\u0650\u0632 \u0647\u0630\u0647 \u0627\u0644\u0648\u062d\u062f\u0627\u062a \u0623\u064a\u0636\u064b\u0627 \u0639\u0644\u0649 \u0627\u0644\u0639\u0648\u0627\u0645\u0644 \u0627\u0644\u0645\u0624\u062b\u0631\u0629 \u0639\u0644\u0649 \u0627\u0644\u0630\u0648\u0628\u0627\u0646\u060c \u0648\u062a\u0631\u0643\u064a\u0632 \u0627\u0644\u0645\u062d\u0644\u0648\u0644 \u0648\u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u0627\u0644\u0627\u062a\u0632\u0627\u0646 \u0648\u0627\u0644\u062a\u0631\u0627\u0628\u0637 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0648\u0627\u0644\u062a\u0631\u0627\u0643\u064a\u0628 \u0627\u0644\u062c\u0632\u064a\u0626\u064a\u0629\u060c \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0639\u0636\u0648\u064a\u0629 \u0645\u062b\u0644 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u0643\u0631\u0628\u0648\u0646\u0627\u062a.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u062a\u0634\u0631\u062d \u0648\u062d\u062f\u0627\u062a \u0627\u0644\u0645\u0633\u062a\u0648\u0649 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a \u0627\u0644\u062d\u062f\u064a\u062b \u0648\u0627\u0644\u0623\u0637\u064a\u0627\u0641 \u0627\u0644\u0630\u0631\u064a\u0629\u060c \u0648\u0627\u0644\u0637\u064a\u0641 \u0627\u0644\u0643\u0647\u0631\u0648\u0645\u063a\u0646\u0627\u0637\u064a\u0633\u064a\u060c \u0648\u0627\u0644\u062a\u0637\u0648\u0631\u0627\u062a \u0627\u0644\u062a\u064a \u0623\u062f\u062a \u0625\u0644\u0649 \u0646\u0645\u0648\u0630\u062c \u0628\u0648\u0631 \u0627\u0644\u0630\u0631\u064a. \u062a\u0631\u0643\u0651\u0650\u0632 \u0647\u0630\u0647 \u0627\u0644\u0648\u062d\u062f\u0627\u062a \u0623\u064a\u0636\u064b\u0627 \u0639\u0644\u0649 \u0627\u0644\u0639\u0648\u0627\u0645\u0644 \u0627\u0644\u0645\u0624\u062b\u0631\u0629 \u0639\u0644\u0649 \u0627\u0644\u0630\u0648\u0628\u0627\u0646\u060c \u0648\u062a\u0631\u0643\u064a\u0632 \u0627\u0644\u0645\u062d\u0644\u0648\u0644 \u0648\u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u0627\u0644\u0627\u062a\u0632\u0627\u0646 \u0648\u0627\u0644\u062a\u0631\u0627\u0628\u0637 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0648\u0627\u0644\u062a\u0631\u0627\u0643\u064a\u0628 \u0627\u0644\u062c\u0632\u064a\u0626\u064a\u0629\u060c \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0639\u0636\u0648\u064a\u0629 \u0645\u062b\u0644 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u0643\u0631\u0628\u0648\u0646\u0627\u062a.","SUBJECT_IMG":"jordan_grade11_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"246","CATEGORY_ID":"1","CONT_TITLE":"Alcohols","CONT_SLUG":"alcohols","CONT_TITLE_AR":"Alcohols","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAlcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the IUPAC name of an alcohol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the general formula of a homologous series of alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridised carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the functional group present in alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the IUPAC name of an alcohol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the general formula of a homologous series of alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the charge distribution of a methanol molecule using an electrostatic potential map","BACKING_FILE":"ss200055.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200055","TOPIC_ID":"ss200055","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200055.jpg","PUBLIC_BANNER_IMG":"ss200055.jpg","PUBLIC_VIDEO":"pvideo_ss200055.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J-IuFLRYZjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. 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chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A double displacement reaction is a type of chemical reaction in which two 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The shell nearest to the nucleus has the least energy and subsequent shells have progressively more energy. Electrons first occupy lowest-energy shell, subsequent shells are occupied according to increasing order of energy. The maximum number of electrons that can be accommodated in any energy level is given by 2n\u00b2 where n is the number of the energy level, such as 1, 2, 3, 4...\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the rules for filling electrons in different atomic shells.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Arrange electrons in different atomic shells up to first 20 elements.\u003C\/div\u003E","CONT_DESC_AR":"Electrons are arranged in energy levels, or shells, around the nucleus of an atom. The shell nearest the nucleus has the least energy and subsequent shells have progressively more energy. The electron first occupy the lowest-energy shell, subsequent shells are occupied according to increasing order of energy. 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The shell nearest to the nucleus has the least energy and subsequent shells have progressively more energy. Electrons first occupy lowest-energy shell, subsequent shells are occupied according to increasing order of energy. The maximum number of electrons that can be accommodated in any energy level is given by 2n\u00b2 where n is the number of the energy level, such as 1, 2, 3, 4...\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the rules for filling electrons in different atomic shells.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Arrange electrons in different atomic shells up to first 20 elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0648\u0632\u064a\u0639 \u0627\u0644\u0625\u0644\u0643\u062a\u0631\u0648\u0646\u064a \u0641\u064a \u0645\u0633\u062a\u0648\u064a\u0627\u062a \u0627\u0644\u0637\u0627\u0642\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629","ADMSUBJECT_ID":"668","ADMCOURSE_ID":"154","DISPLAY_NAME":"Jordan - 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For example, pure iron would only contain iron atoms, pure water would only contain molecules of water.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define substances.\u003C\/div\u003E \r\n\u003Cdiv\u003E- List elements as metals, nonmetals, or metalloids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify substances as elements or compounds.\u003C\/div\u003E","CONT_DESC_AR":"Pure substances are made of only one type of atom or only one type of molecule. For example, pure iron would only contain iron atoms, pure water would only contain molecules of water.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define substances\u0026lt;br \/\u0026gt;\n\u0026amp;bull; list elements as metals, non-metals, or metalloids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; classify substances as elements or compounds","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200063","TOPIC_ID":"ms200063","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200063.jpg","PUBLIC_BANNER_IMG":"MS200063.jpg","PUBLIC_VIDEO":"pvideo_ms200063.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/n7IFb3_C2SY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:00:38","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Pure substances are made of only one type of atom or only one type of molecule. 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\r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECompounds with the same molecular formula but different structures are called structural isomers. 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