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Melting point, boiling point, and density are some examples of size-independent properties.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define size-independent properties.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Give examples of size-independent properties.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000073","TOPIC_ID":"vc000073","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000073.jpg","PUBLIC_BANNER_IMG":"vc000073.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000073.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Those physical properties which are not affected by the amount of matter present in a substance are called size-independent properties. Melting point, boiling point, and density are some examples of size-independent properties.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Define size-independent properties.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Give examples of size-independent properties.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0635\u0627\u0626\u0635 \u0644\u0627 \u062a\u0639\u062a\u0645\u062f \u0639\u0644\u0649 \u0627\u0644\u062d\u062c\u0645","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"667","CATEGORY_ID":"1","CONT_TITLE":"Semiconductors","CONT_SLUG":"semiconductors","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMetals, are good conductors of electricity, while insulators, like diamond, do not conduct electricity, even when heated. Semiconductors, such as silicon, have conductivity between that of a conductor and an insulator. Electrical conductivity of a semiconductor increases with an increase in temperature. Semiconductors are found in many electronic devices.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the electrical conductivity of a semiconductor with that of a conductor and an insulator.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the effect of temperature on the conductivity of a semiconductor.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name common objects where semiconductors are used.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000027","TOPIC_ID":"vc000027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000027.jpg","PUBLIC_BANNER_IMG":"vc000027.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/S4OnmsYGcBw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Metals, are good conductors of electricity, while insulators, like diamond, do not conduct electricity, even when heated. Semiconductors, such as silicon, have conductivity between that of a conductor and an insulator. Electrical conductivity of a semiconductor increases with an increase in temperature. Semiconductors are found in many electronic devices.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Compare the electrical conductivity of a semiconductor with that of a conductor and an insulator.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify the effect of temperature on the conductivity of a semiconductor.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Name common objects where semiconductors are used.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0623\u0634\u0628\u0627\u0647 \u0627\u0644\u0645\u0648\u0635\u0644\u0627\u062a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"658","CATEGORY_ID":"1","CONT_TITLE":"Water as a Solvent","CONT_SLUG":"water-as-a-solvent","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWater is a polar covalent compound and has a high dielectric constant, which means that it has strong polarity. Due to strong polarity, most ionic compounds are soluble in water. Water can also dissolve many polar covalent compounds, such as ethanol and sugar. Becuase water is capable of dissolving a variety of substances, it is called a universal solvent. Nonpolar compounds such as oils are not attracted to polar water molecules and do not dissolve in it.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify water as a universal solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify polar solvents, ionic solutes, polar solvents, nonpolar solutes, and nonpolar solvents.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the \u201clike dissolves like\u201d concept.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the suitable solvent for a solute.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000008","TOPIC_ID":"vc000008","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000008.jpg","PUBLIC_BANNER_IMG":"vc000008.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000008.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/S_ojOtCNEOA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Water is a polar covalent compound and has a high dielectric constant, which means that it has strong polarity. Due to strong polarity, most ionic compounds are soluble in water. Water can also dissolve many polar covalent compounds, such as ethanol and sugar. Becuase water is capable of dissolving a variety of substances, it is called a universal solvent. Nonpolar compounds such as oils are not attracted to polar water molecules and do not dissolve in it.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify water as a universal solvent.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify polar solvents, ionic solutes, polar solvents, nonpolar solutes, and nonpolar solvents.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe the \u201clike dissolves like\u201d concept.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Predict the suitable solvent for a solute.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0627\u0621 \u0643\u0645\u0630\u064a\u0628","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"652","CATEGORY_ID":"1","CONT_TITLE":"Functional Groups Naming Conventions","CONT_SLUG":"functional-groups-naming-conventions","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003EFunctional groups are a special group of atoms or bonds within molecules that are responsible for the characteristic reactions of those molecules. Some of the common functional groups present in organic compounds include -OH, -CHO, -CO, -COOH, C=C, C\u2261C, and halogen. If any functional group is present in an organic compound, it is denoted in the compound\u0026#039;s name with either a prefix or a suffix.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe functional groups.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explore how to name molecules with functional groups. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize organic compounds using the IUPAC name.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000002","TOPIC_ID":"vc000002","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000002.jpg","PUBLIC_BANNER_IMG":"vc000002.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000002.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Vnb13VHiLtU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Functional groups are a special group of atoms or bonds within molecules that are responsible for the characteristic reactions of those molecules. Some of the common functional groups present in organic compounds include -OH, -CHO, -CO, -COOH, C=C, C\u2261C, and halogen. If any functional group is present in an organic compound, it is denoted in the compound\u0026#039;s name with either a prefix or a suffix.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe functional groups.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explore how to name molecules with functional groups.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Recognize organic compounds using the IUPAC name.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0648\u0627\u0639\u062f \u062a\u0633\u0645\u064a\u0629 \u0627\u0644\u0645\u062c\u0645\u0648\u0639\u0627\u062a \u0627\u0644\u0648\u0638\u064a\u0641\u064a\u0629.","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"505","CATEGORY_ID":"1","CONT_TITLE":"The Difference Between Compounds and Mixtures","CONT_SLUG":"difference-between-compounds-and-mixtures","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Sort compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify compounds and mixtures on the basis of molecular view.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200418.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200418","TOPIC_ID":"hs200418","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200418.jpg","PUBLIC_BANNER_IMG":"HS200418.jpg","PUBLIC_VIDEO":"pvideo_hs200418.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hlxxUVnlQzE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Differentiate between compounds and mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Sort compounds and mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Classify compounds and mixtures on the basis of molecular view.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0641\u0631\u0642 \u0628\u064a\u0646 \u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0648\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"503","CATEGORY_ID":"1","CONT_TITLE":"Nucleic Acids","CONT_SLUG":"nucleic-acid","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ENucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. Nucleic acid is made up of nucleotides. A nucleotide consists of a sugar, phosphate and nitrogenous base.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what a nucleic acid is.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of a nucleotide.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the different components of RNA and DNA.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a nucleic acid.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200408","TOPIC_ID":"hs200408","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200408.jpg","PUBLIC_BANNER_IMG":"HS200408.jpg","PUBLIC_VIDEO":"pvideo_hs200408.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/L5hwt0XTjzc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Nucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. Nucleic acid is made up of nucleotides. A nucleotide consists of a sugar, phosphate and nitrogenous base.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what a nucleic acid is.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure of a nucleotide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the different components of RNA and DNA.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct a nucleic acid.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062d\u0645\u0636 \u0627\u0644\u0646\u0648\u0648\u064a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"502","CATEGORY_ID":"1","CONT_TITLE":"Functional Groups","CONT_SLUG":"functional-groups","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA functional group in a substituted hydrocarbon is an atom or group of atoms which gives idea about its properties and functions. Examples of functional groups are hydroxyl, carboxyl, halide and amino group.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different functional groups. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a molecule containing particular functional group. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Name a molecule according to the functional group present in it.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200403","TOPIC_ID":"hs200403","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200403.jpg","PUBLIC_BANNER_IMG":"HS200403.jpg","PUBLIC_VIDEO":"pvideo_hs200403.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/x9qhdxYY1ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A functional group in a substituted hydrocarbon is an atom or group of atoms which gives idea about its properties and functions. Examples of functional groups are hydroxyl, carboxyl, halide and amino group.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify different functional groups.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Construct a molecule containing particular functional group.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Name a molecule according to the functional group present in it.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062c\u0645\u0648\u0639\u0627\u062a \u0627\u0644\u0648\u0638\u064a\u0641\u064a\u0629","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"501","CATEGORY_ID":"1","CONT_TITLE":"Naming Hydrocarbons","CONT_SLUG":"naming-hydrocarbons","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EChemical compounds were named as per IUPAC nomenclature in order to avoid duplicate names. IUPAC nomenclature has one set of standardized rules. According to IUPAC system, the IUPAC name of an organic compound may consist of 5 parts that is: \u201cSecondary prefix + Primary prefix + Word root + Primary suffix + Secondary suffix\u201d.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the different parts of the IUPAC name of an organic compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name straight chain hydrocarbons according to the IUPAC guidelines.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name branched hydrocarbons according to the IUPAC guidelines.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200402","TOPIC_ID":"hs200402","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200402.jpg","PUBLIC_BANNER_IMG":"HS200402.jpg","PUBLIC_VIDEO":"pvideo_hs200402.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/7DPsmbPvpUw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Chemical compounds were named as per IUPAC nomenclature in order to avoid duplicate names. IUPAC nomenclature has one set of standardized rules. According to IUPAC system, the IUPAC name of an organic compound may consist of 5 parts that is: \u201cSecondary prefix + Primary prefix + Word root + Primary suffix + Secondary suffix\u201d.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning Objectives:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the different parts of the IUPAC name of an organic compound.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Name straight chain hydrocarbons according to the IUPAC guidelines.\u0026lt;\/div\u0026gt;- Name branched hydrocarbons according to the IUPAC guidelines.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0633\u0645\u064a\u0629 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u0643\u0631\u0628\u0648\u0646\u0627\u062a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"496","CATEGORY_ID":"1","CONT_TITLE":"Testing for Carbon Compounds","CONT_SLUG":"testing-for-carbon-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMost of the food items consumed by us come from living beings and contain carbon compounds such as protein, carbohydrates and lipids. The presence of carbohydrates (starch) in a food sample can be detected using Lugol\u2019s solution as indicator whereas the presence of proteins in a food sample can be detected using Biuret solution as indicator. On the other hand, the presence of lipids in a food sample can be detected using Sudan red solution as indicator.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of Lugol\u2019s test for carbohydrates. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of Biuret test for proteins. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of Sudan red test for lipids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Test for the presence of carbohydrates, proteins and lipids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200335.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200335","TOPIC_ID":"hs200335","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200335.jpg","PUBLIC_BANNER_IMG":"HS200335.jpg","PUBLIC_VIDEO":"pvideo_hs200335.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/M7EHLj525Zs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Most of the food items consumed by us come from living beings and contain carbon compounds such as protein, carbohydrates and lipids. The presence of carbohydrates (starch) in a food sample can be detected using Lugol\u2019s solution as indicator whereas the presence of proteins in a food sample can be detected using Biuret solution as indicator. On the other hand, the presence of lipids in a food sample can be detected using Sudan red solution as indicator.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the process of Lugol\u2019s test for carbohydrates.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe the process of Biuret test for proteins.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the process of Sudan red test for lipids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Test for the presence of carbohydrates, proteins and lipids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0643\u0634\u0641 \u0639\u0646 \u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0643\u0631\u0628\u0648\u0646","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"488","CATEGORY_ID":"1","CONT_TITLE":"Phase Change: Sublimation","CONT_SLUG":"phase-change-sublimation","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe process in which a solid directly changes its state to gas without undergoing the liquid phase is called sublimation. Examples of substances that undergo sublimation are camphor, naphthalene etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define sublimation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of sublimation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify substances that undergo sublimation.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200286.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200286","TOPIC_ID":"ms200286","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200286.jpg","PUBLIC_BANNER_IMG":"MS200286.jpg","PUBLIC_VIDEO":"pvideo_ms200286.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/X1wc5E1F-ic","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The process in which a solid\u0026amp;nbsp; directly changes its state to gas without undergoing the liquid phase is called sublimation. Examples of substances that undergo sublimation are camphor, naphthalene etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define sublimation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of sublimation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify substances that undergo sublimation.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u063a\u064a\u0631 \u062d\u0627\u0644\u0629 \u0627\u0644\u0645\u0627\u062f\u0629: \u0627\u0644\u062a\u0633\u0627\u0645\u064a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"486","CATEGORY_ID":"1","CONT_TITLE":"Properties of Gases","CONT_SLUG":"properties-of-gases","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGases do not have definite shape and volume. They attain the shape and volume of the container. Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate that gases do not have definite shape and volume.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Explain that gases occupy the whole space available to them. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe that gases have unlimited diffusibility. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that gases have high compressibility.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200283.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200283","TOPIC_ID":"ms200283","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200283.jpg","PUBLIC_BANNER_IMG":"MS200283.jpg","PUBLIC_VIDEO":"pvideo_ms200283.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/n4tYu4qJMsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Gases do not have definite shape and volume. They attain the shape and volume of the container.\u0026amp;nbsp; Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Illustrate that gases do not have definite shape and volume.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases occupy the whole space available to them.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe that gases have unlimited diffusibility.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases have high compressibility.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0635\u0627\u0626\u0635 \u0627\u0644\u063a\u0627\u0632\u0627\u062a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"485","CATEGORY_ID":"1","CONT_TITLE":"Properties of Liquids-Viscosity","CONT_SLUG":"properties-of-liquids-viscosity","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDifferent solutions have different fluidity. The liquid which flows slowly is known to have higher viscosity. The term, viscosity means resistance to flow. It decreases as the liquid becomes warmer. Thus, it can be said that viscosity is temperature dependent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define viscosity.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare and describe the order of viscosities of different solutions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Complete an experiment to show the effect of temperature on viscosity.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200281","TOPIC_ID":"ss200281","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200281.jpg","PUBLIC_BANNER_IMG":"SS200281.jpg","PUBLIC_VIDEO":"pvideo_ss200281.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/aeAntU_QRps","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Different solutions have different fluidity. The liquid which flows slowly is known to have higher viscosity. The term, viscosity means resistance to flow. It decreases as the liquid becomes warmer. Thus, it can be\u0026amp;nbsp; said that viscosity is temperature dependent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Define viscosity.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Compare and describe the order of viscosities of different solutions.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Complete an experiment to show the effect of temperature on viscosity\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0635\u0627\u0626\u0635 \u0627\u0644\u0633\u0648\u0627\u0626\u0644: \u0627\u0644\u0644\u0632\u0648\u062c\u0629","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"483","CATEGORY_ID":"1","CONT_TITLE":"Conservation of Mass","CONT_SLUG":"conservation-of-mass","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EPhysical and chemical changes follow the law of conservation of mass. The law states that mass cannot be formed or destroyed. Mass remains constant before and after a change.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the law of conservation of mass.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate the law of conservation of mass in physical changes.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate the law of conservation of mass in chemical changes.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200273","TOPIC_ID":"ms200273","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200273.jpg","PUBLIC_BANNER_IMG":"MS200273.jpg","PUBLIC_VIDEO":"pvideo_ms200273.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SRqPI8TJjuM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Physical and chemical changes follow the law of conservation of mass. The law states that mass cannot be formed or destroyed. Mass remains constant before and after a change.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the law of conservation of mass.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Illustrate the law of conservation of mass in physical changes.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Illustrate the law of conservation of mass in chemical changes.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0628\u0642\u0627\u0621 \u0627\u0644\u0645\u0627\u062f\u0629","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"482","CATEGORY_ID":"1","CONT_TITLE":"Inhibitors","CONT_SLUG":"inhibitors","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAt times, it is required to prevent certain chemical reactions from occurring. In such cases inhibitors are used to slow down or even stop a chemical reaction. Inhibitors are used in food industry to slow down or inhibit food spoilage.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define an inhibitor.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of an inhibitor on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the use of an inhibitor as a food preservative to slow down or inhibit the reaction that leads to the food item spoiling.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200264.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200264","TOPIC_ID":"ms200264","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200264.jpg","PUBLIC_BANNER_IMG":"MS200264.jpg","PUBLIC_VIDEO":"pvideo_ms200264.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J7nB_OJx5XE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;At times, it is required to prevent certain chemical reactions from occurring. In such cases inhibitors are used to slow down or even stop a chemical reaction. Inhibitors are used in food industry to slow down or inhibit food spoilage.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define an inhibitor.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the effect of an inhibitor on the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the use of an inhibitor as a food preservative to slow down or inhibit the reaction that leads to the food item spoiling.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062b\u0628\u0637\u0627\u062a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"481","CATEGORY_ID":"1","CONT_TITLE":"Organic Compounds","CONT_SLUG":"organic-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EOrganic compounds are compounds made up of carbon atoms. These are essential molecules for existence of life on earth. These are classified as hydrocarbons, substituted hydrocarbons and biological molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate organic compounds into hydrocarbons, substituted hydrocarbons and biological molecules.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Identify organic compounds through their molecular structure.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200166.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200166","TOPIC_ID":"hs200166","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200166.jpg","PUBLIC_BANNER_IMG":"HS200166.jpg","PUBLIC_VIDEO":"pvideo_hs200166.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/htrsUXDUjU8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Organic compounds are compounds made up of carbon atoms. These are essential molecules for existence of life on earth. These are classified as hydrocarbons, substituted hydrocarbons and biological molecules.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Differentiate organic compounds into hydrocarbons, substituted hydrocarbons and biological molecules.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify organic compounds through their molecular structure.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062b\u0628\u0637\u0627\u062a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"372","CATEGORY_ID":"1","CONT_TITLE":"Application of VSEPR Theory","CONT_SLUG":"application-of-vsepr-theory","CONT_TITLE_AR":"Application of VSEPR Theory","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence shell electron pair repulsion (VSEPR) theory is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply VSEPR theory to predict the three-dimensional shapes of molecules.\u003C\/div\u003E","CONT_DESC_AR":"Valence shell electron pair repulsion (VSEPR)\u0026amp;nbsp;theory\u0026amp;nbsp;is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n- construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- apply VSEPR theory to predict the three-dimensional shapes of molecules","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200035","TOPIC_ID":"ss200035","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200035.jpg","PUBLIC_BANNER_IMG":"SS200035.jpg","PUBLIC_VIDEO":"pvideo_ss200035.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/gR_7S2Lk39g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Valence shell electron pair repulsion (VSEPR) theory is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply VSEPR theory to predict the three-dimensional shapes of molecules.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0637\u0628\u064a\u0642\u0627\u062a \u0646\u0638\u0631\u064a\u0629 \u0641\u064a\u0633\u0628\u0631","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"369","CATEGORY_ID":"1","CONT_TITLE":"Balancing Redox Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance oxidation half-reaction and reduction half-reaction separately.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0648\u0627\u0632\u0646\u0629 \u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0623\u0643\u0633\u062f\u0629 \u0648\u0627\u0644\u0627\u062e\u062a\u0632\u0627\u0644","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"367","CATEGORY_ID":"1","CONT_TITLE":"Distillation","CONT_SLUG":"distillation","CONT_TITLE_AR":"Distillation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDistillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling points, by heating them to a temperature at which one or more fractions of the compound will vaporize.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of distillation to separate miscible liquid mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify liquids that can be separated by distillation.\u003C\/div\u003E","CONT_DESC_AR":"Distillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling point by heating them to a temperature at which one or more fractions of the compound will vaporize.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the process of distillation to separate miscible liquid mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify liquids that can be separated by distillation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200015","TOPIC_ID":"ss200015","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200015.jpg","PUBLIC_BANNER_IMG":"SS200015.jpg","PUBLIC_VIDEO":"pvideo_ss200015.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0CyfkKB5KG4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Distillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling points, by heating them to a temperature at which one or more fractions of the compound will vaporize.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of distillation to separate miscible liquid mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify liquids that can be separated by distillation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0627\u0644\u062a\u0642\u0637\u064a\u0631","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"357","CATEGORY_ID":"1","CONT_TITLE":"Methods of Separation","CONT_SLUG":"methods-of-separation","CONT_TITLE_AR":"Methods of Separation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u003C\/div\u003E","CONT_DESC_AR":"Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the separation of ammonium chloride from a mixture of sodium chloride-ammonium chloride by sublimation method\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the separation of acetone from acetone-water solution by distillation method","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200076","TOPIC_ID":"ms200076","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200076.jpg","PUBLIC_BANNER_IMG":"MS200076.jpg","PUBLIC_VIDEO":"pvideo_ms200076.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XFqLqtNsjDQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u0026lt;\/div\u0026gt;- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0637\u0631\u0642 \u0627\u0644\u0641\u0635\u0644","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"354","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Sedimentation and Decantation","CONT_SLUG":"sedimentation-and-decantation","CONT_TITLE_AR":"Sedimentation and Decantation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation follows sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the sedimentation and decantation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated using the sedimentation and decantation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"Sedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation is followed by sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the process of the sedimentation method of separation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the process of the decantation method of separation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify mixtures that can be separated using the sedimentation and decantation method of separation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200065","TOPIC_ID":"ms200065","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200065.jpg","PUBLIC_BANNER_IMG":"MS200065.jpg","PUBLIC_VIDEO":"pvideo_ms200065.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/QR2JTdtNtcQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation follows sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of the sedimentation and decantation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated using the sedimentation and decantation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0635\u0628 \u0648\u0627\u0644\u062a\u0631\u0633\u064a\u0628","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"213","CATEGORY_ID":"1","CONT_TITLE":"Catalysts","CONT_SLUG":"catalysts","CONT_TITLE_AR":"Catalysts","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define catalyst.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of a catalyst on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how a catalyst increases the rate of a chemical reaction.\u003C\/div\u003E","CONT_DESC_AR":"A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define catalyst\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain effect of catalyst on the rate of a chemical reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how a catalyst increases the rate of a chemical reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200020","TOPIC_ID":"ss200020","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200020.jpg","PUBLIC_BANNER_IMG":"ss200020.jpg","PUBLIC_VIDEO":"pvideo_ss200020.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EpkHrhW2Xxc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define catalyst.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the effect of a catalyst on the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how a catalyst increases the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062d\u0641\u0632\u0627\u062a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"181","CATEGORY_ID":"1","CONT_TITLE":"Rutherford\u0027s Atomic Model","CONT_SLUG":"rutherfords-atomic-model","CONT_TITLE_AR":"Rutherford\u2019s Atomic model","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAccording to Rutherford\u2019s atomic model, the atom consists of two parts. First is the nucleus which is very small in size and carries a positive charge, and in which the entire mass of the atom is concentrated. The second part is the extra nuclear part, in which negatively charged electrons revolve around the nucleus on fixed circular paths.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of an atom according to Rutherford\u0026#039;s atomic model.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Rutherford\u0026#039;s model of an atom.\u003C\/div\u003E","CONT_DESC_AR":"According to Rutherfords atomic model, the atom consists of two parts\u003Cbr\u003E\n1. Nucleus, very small in size, carries a positive charge and in which the entire mass of the atom is concentrated\u0026lt;br \/\u0026gt;\n2. Extra nuclear part, in which negatively charged electrons revolve around the nucleus on fixed circular paths\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the structure of an atom according\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;to Rutherford\u0026amp;#39;s atomic model\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify Rutherford\u0026amp;#39;s model of atom\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"hs200040.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200040","TOPIC_ID":"hs200040","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200040.jpg","PUBLIC_BANNER_IMG":"HS200040.jpg","PUBLIC_VIDEO":"pvideo_hs200040.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/YyEDbnJd0lc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;According to Rutherford\u2019s atomic model, the atom consists of two parts. First is the nucleus which is very small in size and\u0026amp;nbsp; carries a positive charge, and in which the entire mass of the atom is concentrated. The second part is the extra nuclear part, in which negatively charged electrons revolve around the nucleus on fixed circular paths.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure of an atom according\u0026amp;nbsp; to Rutherford\u0026#039;s atomic model.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify Rutherford\u0026#039;s model of an atom.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0646\u0645\u0648\u0630\u062c \u0631\u0632\u0631\u0641\u0648\u0631\u062f \u0627\u0644\u0630\u0631\u064a","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"173","CATEGORY_ID":"1","CONT_TITLE":"Valence Electrons","CONT_SLUG":"valence-electrons","CONT_TITLE_AR":"Valence Electrons","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the outermost shell of an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Count the number of valence electrons present in an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u003C\/div\u003E","CONT_DESC_AR":"Valence electrons are the electrons present in the outermost shell of an atom. The number of valence electrons in the atoms of groups 1,2 and 13 to 18 equals the ones digit of the group members.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- identify outermost shell of an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- count valence electrons present in an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- predict the number of valence electrons in the atoms of groups 1, 2 and 13 to 18 using periodic table\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"hs200070.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200070","TOPIC_ID":"hs200070","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200070.jpg","PUBLIC_BANNER_IMG":"HS200070.jpg","PUBLIC_VIDEO":"pvideo_hs200070.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ksLodK-mJ8c","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Valence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify the outermost shell of an atom.\u0026lt;br\u0026gt;- Count the number of valence electrons present in an atom.\u0026lt;br\u0026gt;- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0625\u0644\u0643\u062a\u0631\u0648\u0646\u0627\u062a \u0627\u0644\u062a\u0643\u0627\u0641\u0624","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"64","CATEGORY_ID":"1","CONT_TITLE":"Separation by Filtration","CONT_SLUG":"separation-by-filtration","CONT_TITLE_AR":"Separation by Filtration","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWater-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure of filtration using filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated by filtration.\u003C\/div\u003E","CONT_DESC_AR":"Liquid mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand water mixture as sand cannot permeate filter paper.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- describe the procedure of filtration using filter paper\u0026lt;br \/\u0026gt;\n- identify mixtures that can be separated by filtration\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200051","TOPIC_ID":"ms200051","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200051.jpg","PUBLIC_BANNER_IMG":"MS200051.jpg","PUBLIC_VIDEO":"pvideo_ms200051.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RZS1h0l5xjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Water-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the procedure of filtration using filter paper.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated by filtration.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0641\u0635\u0644 \u0628\u0627\u0644\u062a\u0631\u0634\u064a\u062d","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"62","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Using Magnets","CONT_SLUG":"separating-mixtures-using-magnets","CONT_TITLE_AR":"Separating Mixtures: Using Magnets","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMixtures containing substances that are attracted by magnets can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only the iron is attracted to the magnet.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure to separate the constituents of a mixture that are attracted toward a magnet.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mixtures whose constituents can be separated by using a magnet.\u003C\/div\u003E","CONT_DESC_AR":"Mixtures containing substances that get attracted to magnet can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only iron attracts\u0026amp;nbsp;to the magnet.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- describe the procedure of separating the constituents of a mixture with the help of a magnet\u0026lt;br \/\u0026gt;\n- identify the mixtures whose constituents can be\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;separated by using a magnet","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200036","TOPIC_ID":"ms200036","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200036.jpg","PUBLIC_BANNER_IMG":"MS200036.jpg","PUBLIC_VIDEO":"pvideo_ms200036.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/--Vd1at4aWc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Mixtures containing substances that are attracted by magnets can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only the iron is attracted to the magnet.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the procedure to separate the constituents of a mixture that are attracted toward a magnet.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the mixtures whose constituents can be separated by using a magnet.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0641\u0635\u0644 \u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u0628\u0627\u0633\u062a\u062e\u062f\u0627\u0645 \u0627\u0644\u0645\u063a\u0627\u0646\u0637","ADMSUBJECT_ID":"1400","ADMCOURSE_ID":"403","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"56","CATEGORY_ID":"1","CONT_TITLE":"States of Matter","CONT_SLUG":"states-of-matter","CONT_TITLE_AR":"States of Matter","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMatter exists in three states: solid, liquid, and gas. Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003EBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of the particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Matter exists in three states: solid, liquid, and gas.\u003C\/br\u003E\r\nParticles of various types of matter have different characteristics.\u003C\/br\u003E\r\nThe particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/br\u003E\r\nBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives:\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation, you will be able to:\u003C\/br\u003E\r\n- identify different states of matter\u003C\/br\u003E\r\n- explain the characteristics of particles of matter","BACKING_FILE":"ms200013.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200013","TOPIC_ID":"ms200013","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200013.jpg","PUBLIC_BANNER_IMG":"MS200013.jpg","PUBLIC_VIDEO":"pvideo_ms200013.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/IjS0e_2CV6o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-10-01 07:03:02","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Matter exists in three states: solid, liquid, and gas. Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;But, the particles of liquids are free to move. 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Melting point, boiling point, and density are some examples of size-independent properties.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define size-independent properties.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Give examples of size-independent properties.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000073","TOPIC_ID":"vc000073","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000073.jpg","PUBLIC_BANNER_IMG":"vc000073.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000073.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-07-04 07:01:50","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 10:53:19","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Those physical properties which are not affected by the amount of matter present in a substance are called size-independent properties. 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