{"pkgId":"62","subjectId":"818","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":"Cambridge (IGCSE) Curriculum Full Access","PACKAGE_SLUG":"cambridge-igcse-full","PACKAGE_IMG":"file_1354445030_1592481030.png","ADMCOURSE_ID":"215","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","STANDARD_NAME":"Cambridge (IGCSE)","ADMSUBJECT_ID":"818","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","CAT_NAME":"Ionic compounds","CONT_ID":"568","CONT_TITLE":"Ionic Compounds","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EIonic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. 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Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Identify ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Demonstrate the solubility of ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Examine the electrical conductivity of ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200314","TOPIC_ID":"hs200314","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200314.jpg","PUBLIC_BANNER_IMG":"HS200314.jpg","PUBLIC_VIDEO":"pvideo_hs200314.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/rqIx2k9cru4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Ionic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify ionic compounds.\u0026lt;br\u0026gt;- Demonstrate the solubility of ionic compounds.\u0026lt;br\u0026gt;- Examine the electrical conductivity of ionic compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Ionic compounds","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"508","CATEGORY_ID":"1","CONT_TITLE":"Formation of Ionic Bonds","CONT_SLUG":"formation-of-ionic-bonds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn ionic bond is the electrostatic attraction between two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. Elements in columns 1, 2, and 3 on the periodic chart are likely to form ionic bonds with elements in columns 15, 16, and 17.\u003C\/div\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is an ionic compound. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Form ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200432","TOPIC_ID":"hs200432","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200432.jpg","PUBLIC_BANNER_IMG":"HS200432.jpg","PUBLIC_VIDEO":"pvideo_hs200432.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/fuvvXfCCOBg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An ionic bond is the electrostatic attraction between two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. 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They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the intermolecular spaces between particles of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between particles of liquids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200425.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200425","TOPIC_ID":"ms200425","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200425.jpg","PUBLIC_BANNER_IMG":"MS200425.jpg","PUBLIC_VIDEO":"pvideo_ms200425.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xm78b3sjxbI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Liquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the intermolecular spaces between particles of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between particles of liquids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Liquids","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"506","CATEGORY_ID":"1","CONT_TITLE":"Solids","CONT_SLUG":"solids","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESolids are simply the hard substances in which their molecules are tightly packed together. Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the intermolecular spaces between the particles in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between the particles in solids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200424","TOPIC_ID":"ms200424","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200424.jpg","PUBLIC_BANNER_IMG":"MS200424.jpg","PUBLIC_VIDEO":"pvideo_ms200424.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/UusR2XL7IyI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Solids are simply the hard substances in which their molecules are tightly packed together. Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the intermolecular spaces between the particles in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between the particles in solids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Solids","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"505","CATEGORY_ID":"1","CONT_TITLE":"The Difference Between Compounds and Mixtures","CONT_SLUG":"difference-between-compounds-and-mixtures","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Sort compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify compounds and mixtures on the basis of molecular view.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200418.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200418","TOPIC_ID":"hs200418","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200418.jpg","PUBLIC_BANNER_IMG":"HS200418.jpg","PUBLIC_VIDEO":"pvideo_hs200418.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hlxxUVnlQzE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Differentiate between compounds and mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Sort compounds and mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Classify compounds and mixtures on the basis of molecular view.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Difference between compounds and mixtures","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"502","CATEGORY_ID":"1","CONT_TITLE":"Functional Groups","CONT_SLUG":"functional-groups","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA functional group in a substituted hydrocarbon is an atom or group of atoms which gives idea about its properties and functions. Examples of functional groups are hydroxyl, carboxyl, halide and amino group.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different functional groups. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a molecule containing particular functional group. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Name a molecule according to the functional group present in it.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200403","TOPIC_ID":"hs200403","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200403.jpg","PUBLIC_BANNER_IMG":"HS200403.jpg","PUBLIC_VIDEO":"pvideo_hs200403.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/x9qhdxYY1ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A functional group in a substituted hydrocarbon is an atom or group of atoms which gives idea about its properties and functions. Examples of functional groups are hydroxyl, carboxyl, halide and amino group.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify different functional groups.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Construct a molecule containing particular functional group.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Name a molecule according to the functional group present in it.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Functional groups","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"501","CATEGORY_ID":"1","CONT_TITLE":"Naming Hydrocarbons","CONT_SLUG":"naming-hydrocarbons","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EChemical compounds were named as per IUPAC nomenclature in order to avoid duplicate names. IUPAC nomenclature has one set of standardized rules. According to IUPAC system, the IUPAC name of an organic compound may consist of 5 parts that is: \u201cSecondary prefix + Primary prefix + Word root + Primary suffix + Secondary suffix\u201d.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the different parts of the IUPAC name of an organic compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name straight chain hydrocarbons according to the IUPAC guidelines.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name branched hydrocarbons according to the IUPAC guidelines.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200402","TOPIC_ID":"hs200402","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200402.jpg","PUBLIC_BANNER_IMG":"HS200402.jpg","PUBLIC_VIDEO":"pvideo_hs200402.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/7DPsmbPvpUw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Chemical compounds were named as per IUPAC nomenclature in order to avoid duplicate names. IUPAC nomenclature has one set of standardized rules. According to IUPAC system, the IUPAC name of an organic compound may consist of 5 parts that is: \u201cSecondary prefix + Primary prefix + Word root + Primary suffix + Secondary suffix\u201d.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning Objectives:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the different parts of the IUPAC name of an organic compound.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Name straight chain hydrocarbons according to the IUPAC guidelines.\u0026lt;\/div\u0026gt;- Name branched hydrocarbons according to the IUPAC guidelines.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Naming hydrocarbons","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"496","CATEGORY_ID":"1","CONT_TITLE":"Testing for Carbon Compounds","CONT_SLUG":"testing-for-carbon-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMost of the food items consumed by us come from living beings and contain carbon compounds such as protein, carbohydrates and lipids. The presence of carbohydrates (starch) in a food sample can be detected using Lugol\u2019s solution as indicator whereas the presence of proteins in a food sample can be detected using Biuret solution as indicator. On the other hand, the presence of lipids in a food sample can be detected using Sudan red solution as indicator.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of Lugol\u2019s test for carbohydrates. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of Biuret test for proteins. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of Sudan red test for lipids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Test for the presence of carbohydrates, proteins and lipids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200335.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200335","TOPIC_ID":"hs200335","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200335.jpg","PUBLIC_BANNER_IMG":"HS200335.jpg","PUBLIC_VIDEO":"pvideo_hs200335.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/M7EHLj525Zs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Most of the food items consumed by us come from living beings and contain carbon compounds such as protein, carbohydrates and lipids. The presence of carbohydrates (starch) in a food sample can be detected using Lugol\u2019s solution as indicator whereas the presence of proteins in a food sample can be detected using Biuret solution as indicator. On the other hand, the presence of lipids in a food sample can be detected using Sudan red solution as indicator.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the process of Lugol\u2019s test for carbohydrates.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe the process of Biuret test for proteins.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the process of Sudan red test for lipids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Test for the presence of carbohydrates, proteins and lipids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Testing for carbon compounds","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"495","CATEGORY_ID":"1","CONT_TITLE":"Hydrocarbons","CONT_SLUG":"hydrocarbons","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EHydrocarbons are the molecules that consist of carbon and hydrogen as their constituent atoms. These are classified into three types on the basis of the bond between two carbon atoms: alkanes, alkenes and alkynes.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define hydrocarbons.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify hydrocarbons on the basis of bond type and general formula.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify three different types of hydrocarbons.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200330","TOPIC_ID":"hs200330","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200330.jpg","PUBLIC_BANNER_IMG":"HS200330.jpg","PUBLIC_VIDEO":"pvideo_hs200330.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/LBdZvnxrKy4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Hydrocarbons are the molecules that consist of carbon and hydrogen as their constituent atoms. These are classified into three types on the basis of the bond between two carbon atoms: alkanes, alkenes and alkynes.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define hydrocarbons.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Classify hydrocarbons on the basis of bond type and general formula.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify three different types of hydrocarbons.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Hydrocarbons","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"493","CATEGORY_ID":"1","CONT_TITLE":"Decomposition Reaction","CONT_SLUG":"decomposition-reaction","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain a decomposition reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200319","TOPIC_ID":"ms200319","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200319.jpg","PUBLIC_BANNER_IMG":"MS200319.jpg","PUBLIC_VIDEO":"pvideo_ms200319.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Dnrhrdmk_RY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain a decomposition reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Decomposition reaction","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"492","CATEGORY_ID":"1","CONT_TITLE":"Covalent Compounds","CONT_SLUG":"covalent-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA covalent compound is made when two or more nonmetal atoms bond by sharing valence electrons. Covalent compounds have low boiling point, melting point and thermal conductivity. They are insoluble in water and do not conduct electricity.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify what are covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Observe the boiling points of the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Examine the solubility of the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the flame test for the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the thermal conductivity of the covalent compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200312.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200312","TOPIC_ID":"ms200312","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200312.jpg","PUBLIC_BANNER_IMG":"MS200312.jpg","PUBLIC_VIDEO":"pvideo_ms200312.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/63RXNIt5vA8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A covalent compound is made when two or more nonmetal atoms bond by sharing valence electrons. Covalent compounds have low boiling point, melting point and thermal conductivity. They are insoluble in water and\u0026amp;nbsp; do not conduct electricity.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify what are covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Observe the boiling points of the covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Examine the solubility of the covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the flame test for the covalent compounds. \u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the thermal conductivity of the covalent compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Covalent compounds","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"486","CATEGORY_ID":"1","CONT_TITLE":"Properties of Gases","CONT_SLUG":"properties-of-gases","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGases do not have definite shape and volume. They attain the shape and volume of the container. Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate that gases do not have definite shape and volume.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Explain that gases occupy the whole space available to them. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe that gases have unlimited diffusibility. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that gases have high compressibility.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200283.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200283","TOPIC_ID":"ms200283","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200283.jpg","PUBLIC_BANNER_IMG":"MS200283.jpg","PUBLIC_VIDEO":"pvideo_ms200283.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/n4tYu4qJMsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Gases do not have definite shape and volume. They attain the shape and volume of the container.\u0026amp;nbsp; Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Illustrate that gases do not have definite shape and volume.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases occupy the whole space available to them.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe that gases have unlimited diffusibility.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases have high compressibility.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Properties of gases","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"481","CATEGORY_ID":"1","CONT_TITLE":"Organic Compounds","CONT_SLUG":"organic-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EOrganic compounds are compounds made up of carbon atoms. These are essential molecules for existence of life on earth. These are classified as hydrocarbons, substituted hydrocarbons and biological molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate organic compounds into hydrocarbons, substituted hydrocarbons and biological molecules.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Identify organic compounds through their molecular structure.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200166.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200166","TOPIC_ID":"hs200166","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200166.jpg","PUBLIC_BANNER_IMG":"HS200166.jpg","PUBLIC_VIDEO":"pvideo_hs200166.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/htrsUXDUjU8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Organic compounds are compounds made up of carbon atoms. These are essential molecules for existence of life on earth. These are classified as hydrocarbons, substituted hydrocarbons and biological molecules.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Differentiate organic compounds into hydrocarbons, substituted hydrocarbons and biological molecules.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify organic compounds through their molecular structure.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Organic compounds","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"383","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Using Evaporation","CONT_SLUG":"separating-mixtures-using-evaporation","CONT_TITLE_AR":"Separating Mixtures: Using Evaporation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the evaporation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solutions that can be separated using the evaporation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\n\u0026lt;ol\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;explain the process of evaporation method of separation\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;identify solutions that can be separated using evaporation method of separation\u0026lt;\/li\u0026gt;\n\u0026lt;\/ol\u0026gt;\n","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200064","TOPIC_ID":"ms200064","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200064.jpg","PUBLIC_BANNER_IMG":"MS200064.jpg","PUBLIC_VIDEO":"pvideo_ms200064.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XT6vdYq4BaA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of the evaporation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify solutions that can be separated using the evaporation method of separation.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Separating mixtures: Using evaporation","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"369","CATEGORY_ID":"1","CONT_TITLE":"Balancing Redox Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance oxidation half-reaction and reduction half-reaction separately.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Balancing redox reaction","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"368","CATEGORY_ID":"1","CONT_TITLE":"Oxidation-Reduction Reactions","CONT_SLUG":"oxidation-reduction-reaction","CONT_TITLE_AR":"Oxidation-Reduction Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoth oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify oxidation-reduction or redox reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidizing and reducing agents in a redox reaction.\u003C\/div\u003E","CONT_DESC_AR":"In a redox reaction both oxidation and reduction takes place in a single reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define oxidation-reduction (redox) reactions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidizing and reducing agents in a redox reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200026","TOPIC_ID":"ss200026","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200026.jpg","PUBLIC_BANNER_IMG":"SS200026.jpg","PUBLIC_VIDEO":"pvideo_ss200026.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/frc5RvK7rIk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Both oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify oxidation-reduction or redox reactions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the oxidizing and reducing agents in a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Oxidation-reduction reactions","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"367","CATEGORY_ID":"1","CONT_TITLE":"Distillation","CONT_SLUG":"distillation","CONT_TITLE_AR":"Distillation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDistillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling points, by heating them to a temperature at which one or more fractions of the compound will vaporize.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of distillation to separate miscible liquid mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify liquids that can be separated by distillation.\u003C\/div\u003E","CONT_DESC_AR":"Distillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling point by heating them to a temperature at which one or more fractions of the compound will vaporize.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the process of distillation to separate miscible liquid mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify liquids that can be separated by distillation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200015","TOPIC_ID":"ss200015","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200015.jpg","PUBLIC_BANNER_IMG":"SS200015.jpg","PUBLIC_VIDEO":"pvideo_ss200015.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0CyfkKB5KG4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Distillation is the separation of a mixture into its component parts, or fractions, separating chemical compounds by their boiling points, by heating them to a temperature at which one or more fractions of the compound will vaporize.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of distillation to separate miscible liquid mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify liquids that can be separated by distillation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Distillation","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"357","CATEGORY_ID":"1","CONT_TITLE":"Methods of Separation","CONT_SLUG":"methods-of-separation","CONT_TITLE_AR":"Methods of Separation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u003C\/div\u003E","CONT_DESC_AR":"Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the separation of ammonium chloride from a mixture of sodium chloride-ammonium chloride by sublimation method\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the separation of acetone from acetone-water solution by distillation method","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200076","TOPIC_ID":"ms200076","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200076.jpg","PUBLIC_BANNER_IMG":"MS200076.jpg","PUBLIC_VIDEO":"pvideo_ms200076.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XFqLqtNsjDQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u0026lt;\/div\u0026gt;- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Methods of separation","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"354","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Sedimentation and Decantation","CONT_SLUG":"sedimentation-and-decantation","CONT_TITLE_AR":"Sedimentation and Decantation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation follows sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the sedimentation and decantation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated using the sedimentation and decantation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"Sedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation is followed by sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the process of the sedimentation method of separation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the process of the decantation method of separation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify mixtures that can be separated using the sedimentation and decantation method of separation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200065","TOPIC_ID":"ms200065","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200065.jpg","PUBLIC_BANNER_IMG":"MS200065.jpg","PUBLIC_VIDEO":"pvideo_ms200065.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/QR2JTdtNtcQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation follows sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of the sedimentation and decantation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated using the sedimentation and decantation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Sedimentation and decantation","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"352","CATEGORY_ID":"1","CONT_TITLE":"Chemical Changes","CONT_SLUG":"chemical-changes","CONT_TITLE_AR":"Chemical Changes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EChemical change is a change in matter in which the substances that make up the matter change into new chemical substances. The physical and chemical properties of the new chemical substances that formed are entirely different. The signs that indicate the formation of a new type of matter include the formation of bubbles or a change in energy, color or odor.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe chemical changes.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the signs that indicate the formation of new types of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the physical and chemical properties of newly formed chemical substances.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a chemical change has occurred or not.\u003C\/div\u003E","CONT_DESC_AR":"Chemical change is a change in matter in which the substances that make up the matter change into new chemical substances. Physical and chemical properties of new chemical substances formed are entirely different. The signs that indicate the formation of a new type of matter include the formation of bubble or a change in energy, colour or odour.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf describe the chemical changes\u0026lt;br \/\u0026gt;\n\u25cf explain the signs that indicate formation of new type of matter\u0026lt;br \/\u0026gt;\n\u25cf compare physical and chemical properties of new\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026amp;nbsp;\u0026amp;nbsp;chemical substances formed\u0026lt;br \/\u0026gt;\n\u25cf identify whether a chemical change has occurred or not","BACKING_FILE":"ms200080.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200080","TOPIC_ID":"ms200080","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200080.jpg","PUBLIC_BANNER_IMG":"MS200080.jpg","PUBLIC_VIDEO":"pvideo_ms200080.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/jM3xFMNR-Bc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Chemical change is a change in matter in which the substances that make up the matter change into new chemical substances. The physical and chemical properties of the new chemical substances that formed are entirely different. The signs that indicate the formation of a new type of matter include the formation of bubbles or a change in energy, color or odor.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe chemical changes.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the signs that indicate the formation of new types of matter.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare the physical and chemical properties of newly formed chemical substances.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a chemical change has occurred or not.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Chemical changes","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"325","CATEGORY_ID":"1","CONT_TITLE":"Atoms and Their Symbols","CONT_SLUG":"atoms-and-their-symbols","CONT_TITLE_AR":"Atoms and Their Symbols","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThere are over a hundred different types of atoms, and these are called elements. Each element has a special name. For example carbon, oxygen and hydrogen are all elements. Each element is given its own chemical symbol, like O for oxygen and Cl for chlorine. Chemical symbols are usually one or two letters long, but sometimes three letters are used.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify element symbols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write element symbols.\u003C\/div\u003E","CONT_DESC_AR":"There are over a hundred different types of atom, and these are called elements. Each element has a special name. For example carbon, oxygen and hydrogen are all elements. Each element is given its own chemical symbol, like O for oxygen and Cl for chlorine. Chemical symbols are usually one or two letters long, but sometimes three letters are used.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify symbols of the elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write symbols of the elements","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200008","TOPIC_ID":"ms200008","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200008.jpg","PUBLIC_BANNER_IMG":"MS200008.jpg","PUBLIC_VIDEO":"pvideo_ms200008.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/vsVEy0BjH3I","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;There are over a hundred different types of atoms, and these are called elements. Each element has a special name. For example carbon, oxygen and hydrogen are all elements. Each element is given its own chemical symbol, like O for oxygen and Cl for chlorine. Chemical symbols are usually one or two letters long, but sometimes three letters are used.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify element symbols.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Write element symbols.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Atoms and Their Symbols","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"279","CATEGORY_ID":"1","CONT_TITLE":"Structure of Phenol","CONT_SLUG":"structure-of-phenol","CONT_TITLE_AR":"Structure of Phenol","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn phenol, hydroxy functional group is directly attached to the sp2 hybridized carbon atom of the benzene ring. The interaction of six unhybridized 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalized pi-electron clouds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in phenol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the phenol molecule using its electrostatic potential map.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of phenol.\u003C\/div\u003E","CONT_DESC_AR":"In phenol hydroxy functional group is directly attached to the sp2 hybridised carbon atom of the benzene ring. The interaction of six unhybridised 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalised pi-electron clouds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify functional groups present in phenol\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the phenol molecule using an electrostatic potential map\u0026lt;br \/\u0026gt;\n- explain the orbital structure of phenol","BACKING_FILE":"ss200049.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200049","TOPIC_ID":"ss200049","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200049.jpg","PUBLIC_BANNER_IMG":"ss200049.jpg","PUBLIC_VIDEO":"pvideo_ss200049.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/y_oKx7y2T7o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In phenol, hydroxy functional group is directly attached to the sp2 hybridized carbon atom of the benzene ring. The interaction of six unhybridized 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalized pi-electron clouds.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the functional group present in phenol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the charge distribution of the phenol molecule using its electrostatic potential map.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the orbital structure of phenol.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Phenol","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"270","CATEGORY_ID":"1","CONT_TITLE":"Boyle\u2019s Law","CONT_SLUG":"boyles-law","CONT_TITLE_AR":"Boyle\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Boyle\u0027s law","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"268","CATEGORY_ID":"1","CONT_TITLE":"Charles\u2019s Law","CONT_SLUG":"charles-law","CONT_TITLE_AR":"Charles\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECharles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the temperature and volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate Charles\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Charles\u0026#039;s law in practical problems.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Charles\u0027s law","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"262","CATEGORY_ID":"1","CONT_TITLE":"Structure of Benzene","CONT_SLUG":"structure-of-benzene","CONT_TITLE_AR":"Structure of Benzene","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"The molecular formula of benzene is C6H6 Kekule proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2\u0026amp;nbsp;hybridised.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify Kekul\u0026amp;eacute; structures and the modern symbol of benzene\u0026lt;br \/\u0026gt;\n- explain the orbital structure of benzene\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the benzene molecule using its electrostatic potential map","BACKING_FILE":"ss200043.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200043","TOPIC_ID":"ss200043","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200043.jpg","PUBLIC_BANNER_IMG":"SS200043.jpg","PUBLIC_VIDEO":"pvideo_ss200043.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0FPZELqrUf4","DIST":null,"SHOW_ON_HOME":"Y","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;The molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the orbital structure of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of benzene","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"259","CATEGORY_ID":"1","CONT_TITLE":"Aromatic Compounds","CONT_SLUG":"aromatic-compound","CONT_TITLE_AR":"Aromatic Compound","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EH\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the criteria for aromaticity described by H\u00fcckel.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether a molecule is aromatic or not by investigating its structure.\u003C\/div\u003E","CONT_DESC_AR":"Huckel postulated that planar cyclic conjugated polyenes containing delocalised (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6\u0026amp;pi; electrons and is aromatic.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the criteria for aromaticity described by Huckel\u0026lt;br \/\u0026gt;\n\u0026amp;bull; determine whether a molecule is aromatic or not by investigating its structure","BACKING_FILE":"ss200042.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200042","TOPIC_ID":"ss200042","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200042.jpg","PUBLIC_BANNER_IMG":"SS200042.jpg","PUBLIC_VIDEO":"pvideo_ss200042.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/N7AnvZ7Qtqw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;H\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the criteria for aromaticity described by H\u00fcckel.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Determine whether a molecule is aromatic or not by investigating its structure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Aromatic Compound","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"246","CATEGORY_ID":"1","CONT_TITLE":"Alcohols","CONT_SLUG":"alcohols","CONT_TITLE_AR":"Alcohols","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAlcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the IUPAC name of an alcohol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the general formula of a homologous series of alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridised carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the functional group present in alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the IUPAC name of an alcohol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the general formula of a homologous series of alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the charge distribution of a methanol molecule using an electrostatic potential map","BACKING_FILE":"ss200055.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200055","TOPIC_ID":"ss200055","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200055.jpg","PUBLIC_BANNER_IMG":"ss200055.jpg","PUBLIC_VIDEO":"pvideo_ss200055.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J-IuFLRYZjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify the functional group present in alcohols.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Write the IUPAC name of an alcohol.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the general formula of a homologous series of alcohols.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Alcohols","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"234","CATEGORY_ID":"1","CONT_TITLE":"Calculating the Oxidation Number","CONT_SLUG":"calculating-oxidation-number","CONT_TITLE_AR":"Calculating Oxidation Number","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFor calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define oxidation number.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assign oxidation number to different elements in a chemical species.\u003C\/div\u003E","CONT_DESC_AR":"While calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation you will be able to:\u003C\/br\u003E\r\n\u2022 define oxidation number\u003C\/br\u003E\r\n\u2022 assign the oxidation number to different elements in a chemical species","BACKING_FILE":"ss200027.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200027","TOPIC_ID":"ss200027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200027.jpg","PUBLIC_BANNER_IMG":"SS200027.jpg","PUBLIC_VIDEO":"pvideo_ss200027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Jf7BP10vSVM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define oxidation number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assign oxidation number to different elements in a chemical species.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Calculating Oxidation number","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"192","CATEGORY_ID":"1","CONT_TITLE":"Structure of Methane","CONT_SLUG":"structure-of-methane","CONT_TITLE_AR":"Structure of Methane","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the molecular formula of methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the hybridization of the carbon atom in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the tetrahedral structure of methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of covalent bonds present in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the C-H bond length and the H-C-H bond angle in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the electrostatic potential map of methane.\u003C\/div\u003E","CONT_DESC_AR":"A methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the molecular formula of methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the hybridisation of the carbon atom in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the tetrahedral structure of methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of covalent bonds present in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the C-H bond length and the H-C-H bond angle in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the electrostatic potential map of methane","BACKING_FILE":"hs200078.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200078","TOPIC_ID":"hs200078","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200078.jpg","PUBLIC_BANNER_IMG":"HS200078.jpg","PUBLIC_VIDEO":"pvideo_hs200078.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KyIxUUo8mzg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Write the molecular formula of methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the hybridization of the carbon atom in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the tetrahedral structure of methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the number of covalent bonds present in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the C-H bond length and the H-C-H bond angle in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the electrostatic potential map of methane.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Methane","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"178","CATEGORY_ID":"1","CONT_TITLE":"Structure of Ethanal","CONT_SLUG":"structure-of-ethanal","CONT_TITLE_AR":"Structure of Ethanal","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EEthanal is commonly known as acetaldehyde. It is an aldehyde molecule containing two carbon atoms. Ethanal has five single bonds and one carbon-oxygen double bond.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the structure of ethanal.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in ethanal.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the types of covalent bonds present in ethanal.\u003C\/div\u003E","CONT_DESC_AR":"Ethanal is commonly known as acetaldehyde. It is an aldehyde molecule containing two carbon atoms. Ethanal has five single bonds and one carbon-oxygen double bond.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the structure of ethanal\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the functional group present in ethanal\u0026lt;br \/\u0026gt;\n\u0026amp;bull; compare the molecular formula, structural formula, bond-line formula, and ball and stick model","BACKING_FILE":"hs200038.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200038","TOPIC_ID":"hs200038","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200038.jpg","PUBLIC_BANNER_IMG":"HS200038.jpg","PUBLIC_VIDEO":"pvideo_hs200038.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/OCIqGn4fCMc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Ethanal is commonly known as acetaldehyde. It is an aldehyde molecule containing two carbon atoms. Ethanal has five single bonds and one carbon-oxygen double bond.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the structure of ethanal.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the functional group present in ethanal.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the types of covalent bonds present in ethanal.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Ethanal","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"175","CATEGORY_ID":"1","CONT_TITLE":"Structure of Ethanol","CONT_SLUG":"structure-of-ethanol","CONT_TITLE_AR":"Structure of Ethanol","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EEthanol is commonly known as ethyl alcohol. It is an alcohol molecule containing the hydoxy functional group. An ethanol molecule has eight single bonds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify functional groups present in ethanol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain types of covalent bonds present in ethanol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in ethanol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain charge distribution of an ethanol molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Ethanol is commonly known as ethyl alcohol. It is an alcohol molecule containing the hydoxy functional group. An ethanol molecule has eight single bonds.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify functional groups present in ethanol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain types of covalent bonds present in ethanol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the type of hybridization of carbon and oxygen atoms in an ethanol molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain charge distribution of an ethanol molecule using its electrostatic potential map","BACKING_FILE":"hs200074.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200074","TOPIC_ID":"hs200074","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200074.jpg","PUBLIC_BANNER_IMG":"HS200074.jpg","PUBLIC_VIDEO":"pvideo_hs200074.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/NdG5hheY5ok","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Ethanol is commonly known as ethyl alcohol. It is an alcohol molecule containing the hydoxy functional group. An ethanol molecule has eight single bonds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify functional groups present in ethanol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain types of covalent bonds present in ethanol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the type of hybridization of carbon and oxygen atoms in ethanol molecule.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain charge distribution of an ethanol molecule using its electrostatic potential map.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Structure of Ethanol","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"173","CATEGORY_ID":"1","CONT_TITLE":"Valence Electrons","CONT_SLUG":"valence-electrons","CONT_TITLE_AR":"Valence Electrons","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the outermost shell of an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Count the number of valence electrons present in an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u003C\/div\u003E","CONT_DESC_AR":"Valence electrons are the electrons present in the outermost shell of an atom. The number of valence electrons in the atoms of groups 1,2 and 13 to 18 equals the ones digit of the group members.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- identify outermost shell of an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- count valence electrons present in an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- predict the number of valence electrons in the atoms of groups 1, 2 and 13 to 18 using periodic table\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"hs200070.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200070","TOPIC_ID":"hs200070","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200070.jpg","PUBLIC_BANNER_IMG":"HS200070.jpg","PUBLIC_VIDEO":"pvideo_hs200070.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ksLodK-mJ8c","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Valence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify the outermost shell of an atom.\u0026lt;br\u0026gt;- Count the number of valence electrons present in an atom.\u0026lt;br\u0026gt;- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Valence electrons","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"169","CATEGORY_ID":"1","CONT_TITLE":"Lewis Dot Structures","CONT_SLUG":"lewis-dot-structures","CONT_TITLE_AR":"Lewis dot Structures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u003C\/div\u003E","CONT_DESC_AR":"Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u0026amp;rsquo;s chemical symbol.Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain steps involved in writing Lewis dot structures of atoms and molecules\u0026lt;br \/\u0026gt;\n\u0026amp;bull; draw Lewis dot structures of atoms and molecules","BACKING_FILE":"hs200069.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200069","TOPIC_ID":"hs200069","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200069.jpg","PUBLIC_BANNER_IMG":"HS200069.jpg","PUBLIC_VIDEO":"pvideo_hs200069.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/W0V5VQ3PcC4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Lewis dot structures","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"157","CATEGORY_ID":"1","CONT_TITLE":"Synthesis Reactions","CONT_SLUG":"synthesis-reactions","CONT_TITLE_AR":"Synthesis reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a synthesis reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the synthesis reaction of magnesium oxide.\u003C\/div\u003E","CONT_DESC_AR":"A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic. An example of a synthesis reaction is the formation of water from hydrogen and oxygen.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a synthesis reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate the synthesis reaction of magnesium oxide","BACKING_FILE":"hs200021.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200021","TOPIC_ID":"hs200021","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200021.jpg","PUBLIC_BANNER_IMG":"HS200021.jpg","PUBLIC_VIDEO":"pvideo_hs200021.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5RK8BgMSqAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a synthesis reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the synthesis reaction of magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Synthesis reactions","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"154","CATEGORY_ID":"1","CONT_TITLE":"Combustion Reactions","CONT_SLUG":"combustion-reactions","CONT_TITLE_AR":"Combustion reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define a combustion reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the combustion of propane and oxygen.\u003C\/div\u003E","CONT_DESC_AR":"A combustion reaction is a major class of chemical reactions. Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. In the more general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. Combustion is an exothermic reaction, so it releases heat.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf explain what is a combustion reaction\u0026lt;br \/\u0026gt;\n\u25cf demonstrate combustion reaction of propane and oxygen\u0026lt;br \/\u0026gt;\n\u25cf identify a combustion reaction","BACKING_FILE":"hs200022.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200022","TOPIC_ID":"hs200022","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200022.jpg","PUBLIC_BANNER_IMG":"HS200022.jpg","PUBLIC_VIDEO":"pvideo_hs200022.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Wl8vJ7nbNbY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and define a combustion reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the combustion of propane and oxygen.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Combustion reactions","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"150","CATEGORY_ID":"1","CONT_TITLE":"Double Displacement Reactions","CONT_SLUG":"double-displacement-reaction","CONT_TITLE_AR":"Double displacement reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is double displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what is double displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Double displacement reaction","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"96","CATEGORY_ID":"1","CONT_TITLE":"The Molecule","CONT_SLUG":"the-molecules","CONT_TITLE_AR":"The Molecule","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA molecule is a group of atoms bonded together. Molecules can be monatomic, diatomic or polyatomic on the basis of the number of atoms present in them.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the atomicity of different molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify monoatomic, diatomic and polyatomic molecules.\u003C\/div\u003E","CONT_DESC_AR":"A molecule is a group of atoms bonded together. Molecules can be monoatomic, diatomic or polyatomic on the basis of the number of atoms present in them.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define molecules\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate atomicity of a molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify monoatomic, diatomic and polyatomic molecules","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200077","TOPIC_ID":"ms200077","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200077.jpg","PUBLIC_BANNER_IMG":"MS200077.jpg","PUBLIC_VIDEO":"pvideo_ms200077.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/-MxyzLjRApc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A molecule is a group of atoms bonded together. Molecules can be monatomic, diatomic or polyatomic on the basis of the number of atoms present in them.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define molecules.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the atomicity of different molecules.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify monoatomic, diatomic and polyatomic molecules.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"The Molecules","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"93","CATEGORY_ID":"1","CONT_TITLE":"Homogeneous Mixtures","CONT_SLUG":"homogeneous-mixtures","CONT_TITLE_AR":"Homogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is homogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is homogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200054","TOPIC_ID":"ms200054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200054.jpg","PUBLIC_BANNER_IMG":"MS200054.jpg","PUBLIC_VIDEO":"pvideo_ms200054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/elFGPE_TZxk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the properties of homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify whether a mixture is homogeneous or not.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Homogeneous mixtures","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"85","CATEGORY_ID":"1","CONT_TITLE":"Heterogeneous Mixtures","CONT_SLUG":"heterogeneous-mixtures","CONT_TITLE_AR":"Heterogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is heterogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is heterogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200053","TOPIC_ID":"ms200053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200053.jpg","PUBLIC_BANNER_IMG":"MS200053.jpg","PUBLIC_VIDEO":"pvideo_ms200053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BrPP-a75tI0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe heterogeneous mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of heterogeneous mixtures.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a mixture is heterogeneous or not.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Heterogeneous mixtures","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"64","CATEGORY_ID":"1","CONT_TITLE":"Separation by Filtration","CONT_SLUG":"separation-by-filtration","CONT_TITLE_AR":"Separation by Filtration","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWater-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure of filtration using filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated by filtration.\u003C\/div\u003E","CONT_DESC_AR":"Liquid mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand water mixture as sand cannot permeate filter paper.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- describe the procedure of filtration using filter paper\u0026lt;br \/\u0026gt;\n- identify mixtures that can be separated by filtration\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200051","TOPIC_ID":"ms200051","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200051.jpg","PUBLIC_BANNER_IMG":"MS200051.jpg","PUBLIC_VIDEO":"pvideo_ms200051.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RZS1h0l5xjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-19 06:14:17","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Water-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the procedure of filtration using filter paper.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated by filtration.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Separation by filtration","ADMSUBJECT_ID":"818","ADMCOURSE_ID":"215","DISPLAY_NAME":"Cambridge - Secondary - Stage - 8 - Chemistry","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 8 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"Chemistry","SUBJECT_DESC_AR":"Chemistry","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 8","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"}],"levelObject":["Compounds","Solubility","Electrical Conductivity","Miscible"],"contData":{"CONT_ID":"568","CATEGORY_ID":"1","CONT_TITLE":"Ionic Compounds","CONT_SLUG":"ionic-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EIonic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Identify ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Demonstrate the solubility of ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Examine the electrical conductivity of ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200314","TOPIC_ID":"hs200314","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200314.jpg","PUBLIC_BANNER_IMG":"HS200314.jpg","PUBLIC_VIDEO":"pvideo_hs200314.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/rqIx2k9cru4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2017-10-06 05:54:22","CREATED_BY":"0","UPDATED_ON":"2024-10-08 09:57:40","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Ionic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify ionic compounds.\u0026lt;br\u0026gt;- Demonstrate the solubility of ionic compounds.\u0026lt;br\u0026gt;- Examine the electrical conductivity of ionic compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Ionic compounds","DISPLAY_NAME":"NGSS New - Middle School - Physical Science","DISPLAY_NAME_AR":"NGSS New - Middle School - Physical Science","SUBJECT_IMG":"569.jpg","ADMSUBJECT_ID":"569","SUBJECT_NAME":"Physical Science","SUBJECT_NAME_AR":"Physical Science","ADMCOURSE_ID":"191","COURSE_NAME":"Middle School","COUNTRY_ID":"287","STANDARD_ID":"287","SHORT_NAME":"NGSS","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u4e2d\u6587","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Polski","Ti\u1ebfng Vi\u1ec7t","\ud55c\uad6d\uc5b4"],"devices":["UmetyVR","WebXR"]}