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Examples of liquids include water, honey etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the intermolecular spaces between particles of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between particles of liquids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200425.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200425","TOPIC_ID":"ms200425","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200425.jpg","PUBLIC_BANNER_IMG":"MS200425.jpg","PUBLIC_VIDEO":"pvideo_ms200425.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xm78b3sjxbI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Liquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the intermolecular spaces between particles of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between particles of liquids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0648\u0627\u0626\u0639","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; 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Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the intermolecular spaces between the particles in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between the particles in solids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200424","TOPIC_ID":"ms200424","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200424.jpg","PUBLIC_BANNER_IMG":"MS200424.jpg","PUBLIC_VIDEO":"pvideo_ms200424.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/UusR2XL7IyI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Solids are simply the hard substances in which their molecules are tightly packed together. Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the intermolecular spaces between the particles in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between the particles in solids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u0648\u0627\u0645\u062f","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; 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These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain a decomposition reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200319","TOPIC_ID":"ms200319","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200319.jpg","PUBLIC_BANNER_IMG":"MS200319.jpg","PUBLIC_VIDEO":"pvideo_ms200319.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Dnrhrdmk_RY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain a decomposition reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0627\u0646\u062d\u0644\u0627\u0644","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; 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Covalent compounds have low boiling point, melting point and thermal conductivity. They are insoluble in water and do not conduct electricity.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify what are covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Observe the boiling points of the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Examine the solubility of the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the flame test for the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the thermal conductivity of the covalent compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200312.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200312","TOPIC_ID":"ms200312","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200312.jpg","PUBLIC_BANNER_IMG":"MS200312.jpg","PUBLIC_VIDEO":"pvideo_ms200312.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/63RXNIt5vA8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A covalent compound is made when two or more nonmetal atoms bond by sharing valence electrons. Covalent compounds have low boiling point, melting point and thermal conductivity. 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The change in state of gas into liquid is called condensation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define evaporation, boiling and condensation. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how liquid state and gaseous state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200285.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200285","TOPIC_ID":"ms200285","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200285.jpg","PUBLIC_BANNER_IMG":"MS200285.jpg","PUBLIC_VIDEO":"pvideo_ms200285.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/B6ArYhP2pRY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The change in state of liquid into gas is called vaporization. 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The process in which released hydrogen ions combine with hydroxide ions to form water is called the neutralization reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the ions present in acids and bases.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the neutralization reaction of an acid and a base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Combine ions to perform a neutralization reaction between an acid and a base.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u062a\u0639\u0627\u062f\u0644","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; 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According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0628\u0648\u064a\u0644","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; 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According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. 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The structure of buckyball is similar to that of a football as it also contains hexagonal and pentagonal rings.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the structure of a buckyball, containing 60 carbon atoms.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the hexagonal and pentagonal rings present in the spherical structure of a buckyball.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of a buckyball.\u003C\/div\u003E","CONT_DESC_AR":"Buckyball is an allotrope of carbon containing 60 carbon atoms joined together to form a spherical structure. 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The structure of buckyball is similar to that of a football as it also contains hexagonal and pentagonal rings.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the structure of a buckyball, containing 60 carbon atoms.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the hexagonal and pentagonal rings present in the spherical structure of a buckyball.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of a buckyball.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0643\u0631\u0627\u062a \u0628\u0627\u0643\u064a","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; 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The crystalline structure of graphite consists of layers or sheets of carbon atoms. In these layers, each carbon atom is joined to three other carbon atoms by strong covalent bonds to form hexagonal rings. Various graphite layers are held together by weak Van der Waals forces.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the layered structure of graphite.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the physical properties of graphite.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize the hybridization of carbon atoms in graphite.\u003C\/div\u003E","CONT_DESC_AR":"Crystal of graphite consists of layers or sheets of carbon atoms. In these layers, each carbon atom is joined to three other carbon atoms by strong covalent bonds to form hexagonal rings. Various graphite layers are held together by weak Van der Walls forces.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the layered structure of graphite\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the physical properties of graphite\u0026lt;br \/\u0026gt;\n\u0026amp;bull; recognize the hybridization of carbon atoms in graphite","BACKING_FILE":"ss200048.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200048","TOPIC_ID":"ss200048","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200048.jpg","PUBLIC_BANNER_IMG":"SS200048.jpg","PUBLIC_VIDEO":"pvideo_ss200048.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/gq2NqZsYfUs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Graphite is a crystalline allotrope of carbon. The crystalline structure of graphite consists of layers or sheets of carbon atoms. In these layers, each carbon atom is joined to three other carbon atoms by strong covalent bonds to form hexagonal rings. Various graphite layers are held together by weak Van der Waals forces.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the layered structure of graphite.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the physical properties of graphite.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Recognize the hybridization of carbon atoms in graphite.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a 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00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define oxidation number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assign oxidation number to different elements in a 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This principle is applicable to both physical as well as chemical equilibrium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u003C\/div\u003E","CONT_DESC_AR":"According to Le Chateliers principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. 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Acids are usually sour in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objective:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- List some common acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of acids.\u003C\/div\u003E","CONT_DESC_AR":"An acid is a compound that gives hydronium ions on ionisation. Acids are usually sour in taste.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; list some common acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the properties of acids","BACKING_FILE":"hs200059.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200059","TOPIC_ID":"hs200059","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200059.jpg","PUBLIC_BANNER_IMG":"HS200059.jpg","PUBLIC_VIDEO":"pvideo_hs200059.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1DN17OR4aBk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An acid is a chemical species that donates protons or hydrogen ions and\/or accepts electrons. Acids are usually sour in taste.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objective\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- List some common acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify the properties of acids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0623\u062d\u0645\u0627\u0636","ADMSUBJECT_ID":"622","ADMCOURSE_ID":"133","DISPLAY_NAME":"UAE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"UAE - Grade 11 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646\u0026nbsp; \u0627\u0644\u0645\u0639\u0631\u0641\u0629 \u0627\u0644\u0639\u0645\u064a\u0642\u0629 \u0644\u0645\u0648\u0636\u0648\u0639\u0627\u062a \u0645\u062e\u062a\u0644\u0641\u0629. \u0641\u0641\u064a \u0647\u0630\u0647 \u0627\u0644\u0648\u062d\u062f\u0627\u062a \u064a\u062a\u0639\u0631\u0641\u0026nbsp; \u0627\u0644\u0637\u0644\u0627\u0628\u0026nbsp; \u0639\u0644\u0649 \u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0648\u062a\u0643\u0648\u064a\u0646 \u0627\u0644\u0623\u064a\u0648\u0646\u0627\u062a \u0648\u0627\u0644\u0637\u0631\u0642 \u0627\u0644\u062d\u062f\u064a\u062b\u0629 \u0644\u062d\u0633\u0627\u0628 \u0639\u062f\u062f \u0627\u0644\u062a\u0623\u0643\u0633\u062f \u0648\u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629 \u0648\u0633\u0644\u0648\u0643 \u0627\u0644\u063a\u0627\u0632\u0627\u062a \u0648\u0641\u0642\u064b\u0627 \u0644\u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644\u060c \u0643\u0630\u0644\u0643 \u064a\u062a\u0639\u0631\u0641 \u0639\u0644\u0649 \u062d\u0627\u0644\u0627\u062a \u0627\u0644\u0645\u0627\u062f\u0629 \u0648\u0627\u0644\u0645\u0642\u0627\u0631\u0646\u0629 \u0628\u064a\u0646\u0647\u0627 \u0628\u0627\u0633\u062a\u062e\u062f\u0627\u0645 \u0645\u0639\u0627\u064a\u064a\u0631 \u0645\u062e\u062a\u0644\u0641\u0629.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u062a\u0633\u0627\u0639\u062f \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062d\u0627\u062f\u064a \u0639\u0634\u0631 \u0639\u0644\u0649 \u062a\u0645\u0643\u064a\u0646 \u0627\u0644\u0637\u0644\u0627\u0628 \u0645\u0646  \u0627\u0644\u0645\u0639\u0631\u0641\u0629 \u0627\u0644\u0639\u0645\u064a\u0642\u0629 \u0644\u0645\u0648\u0636\u0648\u0639\u0627\u062a \u0645\u062e\u062a\u0644\u0641\u0629. \u0641\u0641\u064a \u0647\u0630\u0647 \u0627\u0644\u0648\u062d\u062f\u0627\u062a \u064a\u062a\u0639\u0631\u0641  \u0627\u0644\u0637\u0644\u0627\u0628  \u0639\u0644\u0649 \u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0648\u062a\u0643\u0648\u064a\u0646 \u0627\u0644\u0623\u064a\u0648\u0646\u0627\u062a \u0648\u0627\u0644\u0637\u0631\u0642 \u0627\u0644\u062d\u062f\u064a\u062b\u0629 \u0644\u062d\u0633\u0627\u0628 \u0639\u062f\u062f \u0627\u0644\u062a\u0623\u0643\u0633\u062f \u0648\u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629 \u0648\u0633\u0644\u0648\u0643 \u0627\u0644\u063a\u0627\u0632\u0627\u062a \u0648\u0641\u0642\u064b\u0627 \u0644\u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644\u060c \u0643\u0630\u0644\u0643 \u064a\u062a\u0639\u0631\u0641 \u0639\u0644\u0649 \u062d\u0627\u0644\u0627\u062a \u0627\u0644\u0645\u0627\u062f\u0629 \u0648\u0627\u0644\u0645\u0642\u0627\u0631\u0646\u0629 \u0628\u064a\u0646\u0647\u0627 \u0628\u0627\u0633\u062a\u062e\u062f\u0627\u0645 \u0645\u0639\u0627\u064a\u064a\u0631 \u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_IMG":"uae_grade11_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"277","SHORT_NAME":"UAE","DOMAIN_NAME":"STEM"},{"CONT_ID":"154","CATEGORY_ID":"1","CONT_TITLE":"Combustion Reactions","CONT_SLUG":"combustion-reactions","CONT_TITLE_AR":"Combustion reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define a combustion reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the combustion of propane and oxygen.\u003C\/div\u003E","CONT_DESC_AR":"A combustion reaction is a major class of chemical reactions. Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. In the more general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. 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The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. 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On the other hand, when a solid matter loses heat, it causes a process called freezing. In freezing, the motion of atoms or molecules slows down.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define melting and freezing.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid state and liquid state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"If solid matter gains enough heat, it changes state from solid to liquid, causing melting. 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These are all made up of particles, but the behaviors of these particles differ in the three states. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of particles in different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the characteristics of particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Gases, liquids and solids are all made up of particles, but the behaviors of these particles differ in the three phases. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- explain the characteristics of particles of different states of matter\u0026lt;br \/\u0026gt;\n- compare the characteristics of particles of matter\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200016","TOPIC_ID":"ms200016","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200016.jpg","PUBLIC_BANNER_IMG":"MS200016.jpg","PUBLIC_VIDEO":"pvideo_ms200016.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5PRBv9scvUo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;The three common states of matter are: gases, liquids, and solids. 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a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- identify the single displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- demonstrate the single displacement reaction\u0026lt;br 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