{"pkgId":"18","subjectId":"940","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":"Ontario Curriculum Senior Secondary School","PACKAGE_SLUG":"ontario-senior-secondary-school","PACKAGE_IMG":"file_627884782_1589526147.png","ADMCOURSE_ID":"252","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","STANDARD_NAME":"Ontario","ADMSUBJECT_ID":"940","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","CAT_NAME":"Ionic Compounds","CONT_ID":"568","CONT_TITLE":"Ionic Compounds","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EIonic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. 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In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. Elements in columns 1, 2, and 3 on the periodic chart are likely to form ionic bonds with elements in columns 15, 16, and 17.\u003C\/div\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is an ionic compound. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Form ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200432","TOPIC_ID":"hs200432","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200432.jpg","PUBLIC_BANNER_IMG":"HS200432.jpg","PUBLIC_VIDEO":"pvideo_hs200432.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/fuvvXfCCOBg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"0","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An ionic bond is the electrostatic attraction between two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. 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Covalent compounds have low boiling point, melting point and thermal conductivity. They are insoluble in water and\u0026amp;nbsp; do not conduct electricity.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify what are covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Observe the boiling points of the covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Examine the solubility of the covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the flame test for the covalent compounds. \u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the thermal conductivity of the covalent compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Covalent Compounds","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"490","CATEGORY_ID":"1","CONT_TITLE":"Mass Number","CONT_SLUG":"mass-number","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn atom consists of three subatomic particles namely: electrons, protons and neutrons. The mass number of an atom is the sum of the number of protons and the number of neutrons in the nucleus.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define mass number.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mass number of the first 20 elements in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the mass number of any element.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200296","TOPIC_ID":"ms200296","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200296.jpg","PUBLIC_BANNER_IMG":"MS200296.jpg","PUBLIC_VIDEO":"pvideo_ms200296.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BYE0r79sLXE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"0","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An atom consists of three subatomic particles namely: electrons, protons and neutrons. The mass number of an atom is the sum of the number of protons and the number of neutrons in the nucleus.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define mass number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the mass number of the first 20 elements in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the mass number of any element.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Mass Number","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"489","CATEGORY_ID":"1","CONT_TITLE":"Atomic Number","CONT_SLUG":"atomic-number","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn element\u2019s atomic number is the number of protons present in the nucleus of that atom. When you look at an element in the periodic table, the number located in the upper left corner of the square is the atomic number of that element.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define atomic number of an element. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Locate an element\u0026#039;s atomic number in the periodic table. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of electrons present in an atom or ion using its atomic number.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200295","TOPIC_ID":"ms200295","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200295.jpg","PUBLIC_BANNER_IMG":"MS200295.jpg","PUBLIC_VIDEO":"pvideo_ms200295.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/eTGUbyjr8_g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"0","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An element\u2019s atomic number is the number of protons present in the nucleus of that atom. When you look at an element in the periodic table, the number located in the upper left corner of the square is the atomic number of that element.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define atomic number of an element.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Locate an element\u0026#039;s atomic number in the periodic table.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Calculate the number of electrons present in an atom or ion using its atomic number.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Atomic Number","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"398","CATEGORY_ID":"1","CONT_TITLE":"Bases","CONT_SLUG":"bases","CONT_TITLE_AR":"Bases","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EA base is a compound that gives hydroxide ion on ionization. Bases are usually bitter in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define bases.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of bases.\u003C\/div\u003E","CONT_DESC_AR":"A base is a compound that gives hydroxide ion on ionisation. Bases are usually bitter in taste.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation, you will be able to:\u003C\/br\u003E\r\n\u2022 define bases\u003C\/br\u003E\r\n\u2022 identify the properties of bases","BACKING_FILE":"hs200060.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200060","TOPIC_ID":"hs200060","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200060.jpg","PUBLIC_BANNER_IMG":"HS200060.jpg","PUBLIC_VIDEO":"pvideo_hs200060.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/44_TMLTKv5A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\u003Cbr\u003E\u003Cdiv\u003EA base is a compound that gives hydroxide ion on ionization. Bases are usually bitter in taste.\u003C\/div\u003E\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E\u003Cdiv\u003E\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\u003Cdiv\u003E- Define bases.\u003C\/div\u003E\u003Cdiv\u003E- Identify the properties of bases.\u003C\/div\u003E\u003C\/div\u003E","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Bases","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"366","CATEGORY_ID":"1","CONT_TITLE":"Dissolving Solids in Liquids","CONT_SLUG":"dissolving-solids-in-liquids","CONT_TITLE_AR":"Dissolving Solids in Liquids","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESolids that are soluble in a particular liquid when dissolved in that liquid, form a homogenous solution. Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid solutes dissolve in liquid solvents.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the change in the properties of solids when dissolved in liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solids that can be dissolved in water.\u003C\/div\u003E","CONT_DESC_AR":"Solids that are soluble in a particular liquid when dissolved form homogenous solution. Solids that are insoluble in a particular liquid when dissolved form heterogenous solution.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how solid solute disolves in liquid solvents\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the change in the properties of solids when dissolved in liquids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify solids that can be dissolved into water","BACKING_FILE":"hs200079.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200079","TOPIC_ID":"hs200079","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200079.jpg","PUBLIC_BANNER_IMG":"hs200079.jpg","PUBLIC_VIDEO":"pvideo_hs200079.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/nGvKBRfZJXk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Solids that are soluble in a particular liquid when dissolved in that liquid, form a homogenous solution. Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how solid solutes dissolve in liquid solvents.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the change in the properties of solids when dissolved in liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify solids that can be dissolved in water.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Dissolving Solids in Liquids","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"326","CATEGORY_ID":"1","CONT_TITLE":"Neutralization Reactions","CONT_SLUG":"neutralization-reaction","CONT_TITLE_AR":"Neutralization Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAcids dissociate in water and release hydrogen ions. Alkalies dissociate in water and release hydroxide ions. The process in which released hydrogen ions combine with hydroxide ions to form water is called the neutralization reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the ions present in acids and bases.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the neutralization reaction of an acid and a base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Combine ions to perform a neutralization reaction between an acid and a base.\u003C\/div\u003E","CONT_DESC_AR":"Acids dissociate in water and release hydrogen ions. Alkalies dissociate in water and release hydroxide ions. The process in which released hydrogen ions combine with hydroxide ions to form water is called the neutralisation reaction.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;middot; identify the ions present in acids and bases\u0026lt;br \/\u0026gt;\n\u0026amp;middot; demonstrate the neutralisation reaction of an acid and a base\u0026lt;br \/\u0026gt;\n\u0026amp;middot; combine ions to perform a neutralisation reaction between an acid and a base","BACKING_FILE":"hs200001.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200001","TOPIC_ID":"hs200001","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200001.jpg","PUBLIC_BANNER_IMG":"HS200001.jpg","PUBLIC_VIDEO":"pvideo_hs200001.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/QesxBXOtRF4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"0","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Acids dissociate in water and release hydrogen ions. Alkalies dissociate in water and release hydroxide ions. The process in which released hydrogen ions combine with hydroxide ions to form water is called the neutralization reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the ions present in acids and bases.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the neutralization reaction of an acid and a base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Combine ions to perform a neutralization reaction between an acid and a base.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Neutralization Reaction","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"270","CATEGORY_ID":"1","CONT_TITLE":"Boyle\u2019s Law","CONT_SLUG":"boyles-law","CONT_TITLE_AR":"Boyle\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Boyle\u0027s Law","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"268","CATEGORY_ID":"1","CONT_TITLE":"Charles\u2019s Law","CONT_SLUG":"charles-law","CONT_TITLE_AR":"Charles\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECharles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the temperature and volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate Charles\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Charles\u0026#039;s law in practical problems.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Charles\u0027s Law","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"242","CATEGORY_ID":"1","CONT_TITLE":"Titration of a Strong Acid with a Strong Base","CONT_SLUG":"titration-of-a-strong-acid-with-a-strong-base","CONT_TITLE_AR":"Titration of a Strong Acid with a Strong Base","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETitration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the detailed procedure for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the laboratory setup for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the application of the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Extrapolate the graph for the titration of a strong acid with a strong base.\u003C\/div\u003E","CONT_DESC_AR":"Strong acid-strong base titration is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the detailed procedure for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the laboratory setup for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the application of titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; extrapolate the graph for the titration of a strong acid with a strong base","BACKING_FILE":"ss200032.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200032","TOPIC_ID":"ss200032","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200032.jpg","PUBLIC_BANNER_IMG":"SS200032.jpg","PUBLIC_VIDEO":"pvideo_ss200032.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/R4ghDnAEBuo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Titration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the detailed procedure for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the laboratory setup for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the application of the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Extrapolate the graph for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Titration of a Strong Acid with a Strong Base","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"188","CATEGORY_ID":"1","CONT_TITLE":" Acids","CONT_SLUG":"acids","CONT_TITLE_AR":"The Acid","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn acid is a chemical species that donates protons or hydrogen ions and\/or accepts electrons. Acids are usually sour in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objective:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- List some common acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of acids.\u003C\/div\u003E","CONT_DESC_AR":"An acid is a compound that gives hydronium ions on ionisation. Acids are usually sour in taste.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; list some common acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the properties of acids","BACKING_FILE":"hs200059.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200059","TOPIC_ID":"hs200059","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200059.jpg","PUBLIC_BANNER_IMG":"HS200059.jpg","PUBLIC_VIDEO":"pvideo_hs200059.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1DN17OR4aBk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An acid is a chemical species that donates protons or hydrogen ions and\/or accepts electrons. Acids are usually sour in taste.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objective\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- List some common acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify the properties of acids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Acids","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"169","CATEGORY_ID":"1","CONT_TITLE":"Lewis Dot Structures","CONT_SLUG":"lewis-dot-structures","CONT_TITLE_AR":"Lewis dot Structures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u003C\/div\u003E","CONT_DESC_AR":"Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u0026amp;rsquo;s chemical symbol.Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain steps involved in writing Lewis dot structures of atoms and molecules\u0026lt;br \/\u0026gt;\n\u0026amp;bull; draw Lewis dot structures of atoms and molecules","BACKING_FILE":"hs200069.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200069","TOPIC_ID":"hs200069","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200069.jpg","PUBLIC_BANNER_IMG":"HS200069.jpg","PUBLIC_VIDEO":"pvideo_hs200069.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/W0V5VQ3PcC4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Lewis Dot Structures","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"159","CATEGORY_ID":"1","CONT_TITLE":"Isotopes","CONT_SLUG":"isotopes","CONT_TITLE_AR":"Isotopes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: hydrogen, deuterium and tritium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isotopes. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isotopes of different elements. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of protons and neutrons in different isotopes.\u003C\/div\u003E","CONT_DESC_AR":"Isotopes of an element have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: \u0026amp;nbsp;hydrogen, deuterium and tritium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isotopes\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isotopes of different elements\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of protons and neutrons in different isotopes","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200024","TOPIC_ID":"hs200024","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200024.jpg","PUBLIC_BANNER_IMG":"HS200024.jpg","PUBLIC_VIDEO":"pvideo_hs200024.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/f4sZdLZU03k","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes:\u0026amp;nbsp; hydrogen, deuterium and tritium.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isotopes.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isotopes of different elements.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the number of protons and neutrons in different isotopes.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Isotopes","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"157","CATEGORY_ID":"1","CONT_TITLE":"Synthesis Reactions","CONT_SLUG":"synthesis-reactions","CONT_TITLE_AR":"Synthesis reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a synthesis reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the synthesis reaction of magnesium oxide.\u003C\/div\u003E","CONT_DESC_AR":"A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic. An example of a synthesis reaction is the formation of water from hydrogen and oxygen.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a synthesis reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate the synthesis reaction of magnesium oxide","BACKING_FILE":"hs200021.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200021","TOPIC_ID":"hs200021","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200021.jpg","PUBLIC_BANNER_IMG":"HS200021.jpg","PUBLIC_VIDEO":"pvideo_hs200021.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5RK8BgMSqAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a synthesis reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the synthesis reaction of magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Synthesis Reactions","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"154","CATEGORY_ID":"1","CONT_TITLE":"Combustion Reactions","CONT_SLUG":"combustion-reactions","CONT_TITLE_AR":"Combustion reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define a combustion reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the combustion of propane and oxygen.\u003C\/div\u003E","CONT_DESC_AR":"A combustion reaction is a major class of chemical reactions. Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. In the more general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. Combustion is an exothermic reaction, so it releases heat.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf explain what is a combustion reaction\u0026lt;br \/\u0026gt;\n\u25cf demonstrate combustion reaction of propane and oxygen\u0026lt;br \/\u0026gt;\n\u25cf identify a combustion reaction","BACKING_FILE":"hs200022.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200022","TOPIC_ID":"hs200022","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200022.jpg","PUBLIC_BANNER_IMG":"HS200022.jpg","PUBLIC_VIDEO":"pvideo_hs200022.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Wl8vJ7nbNbY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and define a combustion reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the combustion of propane and oxygen.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Combustion Reactions","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"150","CATEGORY_ID":"1","CONT_TITLE":"Double Displacement Reactions","CONT_SLUG":"double-displacement-reaction","CONT_TITLE_AR":"Double displacement reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is double displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what is double displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Double Displacement Reaction","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"57","CATEGORY_ID":"1","CONT_TITLE":"Comparing Solid, Liquid, and Gas","CONT_SLUG":"comparing-solid-liquid-and-gases","CONT_TITLE_AR":"Comparing Solid, Liquid and Gases","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe three common states of matter are: gases, liquids, and solids. These are all made up of particles, but the behaviors of these particles differ in the three states. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of particles in different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the characteristics of particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Gases, liquids and solids are all made up of particles, but the behaviors of these particles differ in the three phases. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- explain the characteristics of particles of different states of matter\u0026lt;br \/\u0026gt;\n- compare the characteristics of particles of matter\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200016","TOPIC_ID":"ms200016","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200016.jpg","PUBLIC_BANNER_IMG":"MS200016.jpg","PUBLIC_VIDEO":"pvideo_ms200016.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5PRBv9scvUo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;The three common states of matter are: gases, liquids, and solids. These are all made up of particles, but the behaviors of these particles differ in the three states. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the characteristics of particles in different states of matter.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare the characteristics of particles of matter.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Comparing Solid, Liquid and Gases","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"56","CATEGORY_ID":"1","CONT_TITLE":"States of Matter","CONT_SLUG":"states-of-matter","CONT_TITLE_AR":"States of Matter","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMatter exists in three states: solid, liquid, and gas. Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003EBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of the particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Matter exists in three states: solid, liquid, and gas.\u003C\/br\u003E\r\nParticles of various types of matter have different characteristics.\u003C\/br\u003E\r\nThe particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/br\u003E\r\nBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives:\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation, you will be able to:\u003C\/br\u003E\r\n- identify different states of matter\u003C\/br\u003E\r\n- explain the characteristics of particles of matter","BACKING_FILE":"ms200013.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200013","TOPIC_ID":"ms200013","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200013.jpg","PUBLIC_BANNER_IMG":"MS200013.jpg","PUBLIC_VIDEO":"pvideo_ms200013.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/IjS0e_2CV6o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Matter exists in three states: solid, liquid, and gas. Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;But, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify different states of matter.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the characteristics of the particles of matter.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"States of Matter","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"52","CATEGORY_ID":"1","CONT_TITLE":"Reactivity Series of Metals","CONT_SLUG":"reactivity-series-of-metals","CONT_TITLE_AR":"Reactivity Series of Metals","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the reactivity series of metals, the most reactive metal is placed at the top and the least reactive element at the bottom. Each element in the reactivity series can be replaced from a compound by any of the elements above it.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe why metals are arranged in a reactivity series.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the order of metals in a reactivity series.\u003C\/div\u003E","CONT_DESC_AR":"In the reactivity series of metals, the most reactive metal is placed at the top and the least reactive element at the bottom.\u0026amp;nbsp;Each element in the reactivity series can be replaced from a compound by any of the elements above it.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter watching the video, you will be able to:\u0026lt;br \/\u0026gt;\n- describe why metals are arranged in a reactivity series\u0026lt;br \/\u0026gt;\n- explain the reactivity order of metals","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200007","TOPIC_ID":"ms200007","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200007.jpg","PUBLIC_BANNER_IMG":"MS200007.jpg","PUBLIC_VIDEO":"pvideo_ms200007.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5T6IVD0FbAw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;In the reactivity series of metals, the most reactive metal is placed at the top and the least reactive element at the bottom. Each element in the reactivity series can be replaced from a compound by any of the elements above it.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe why metals are arranged in a reactivity series.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the order of metals in a reactivity series.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Reactivity Series of Metals","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"},{"CONT_ID":"51","CATEGORY_ID":"1","CONT_TITLE":"Single Displacement Reaction","CONT_SLUG":"single-displacement-reaction","CONT_TITLE_AR":"Single Displacement Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a single displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate a single displacement reaction.\u003C\/div\u003E","CONT_DESC_AR":"A single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- identify the single displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- demonstrate the single displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200003","TOPIC_ID":"ms200003","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200003.jpg","PUBLIC_BANNER_IMG":"MS200003.jpg","PUBLIC_VIDEO":"pvideo_ms200003.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/o6-pPsqJirE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-09-05 11:32:57","CREATED_BY":"1","UPDATED_ON":"2018-09-06 09:01:24","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;A single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a single displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate a single displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Single Displacement Reaction","ADMSUBJECT_ID":"940","ADMCOURSE_ID":"252","DISPLAY_NAME":"Ontario - Grade 11 - Chemistry: University Preparation","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry: University Preparation","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 11","COUNTRY_ID":"316","SHORT_NAME":"Ontario","DOMAIN_NAME":"STEM"}],"levelObject":["Compounds","Solubility","Electrical Conductivity","Miscible"],"contData":{"CONT_ID":"568","CATEGORY_ID":"1","CONT_TITLE":"Ionic Compounds","CONT_SLUG":"ionic-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EIonic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\r\n \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Identify ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Demonstrate the solubility of ionic compounds.\u003C\/div\u003E\r\n \r\n\u003Cdiv\u003E- Examine the electrical conductivity of ionic compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200314","TOPIC_ID":"hs200314","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200314.jpg","PUBLIC_BANNER_IMG":"HS200314.jpg","PUBLIC_VIDEO":"pvideo_hs200314.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/rqIx2k9cru4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2017-10-06 05:54:22","CREATED_BY":"0","UPDATED_ON":"2024-10-08 09:57:40","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Ionic compounds consist of positively charged cations and negatively charged anions. Ionic compounds are solid at room temperature. They are brittle in nature. These compounds are highly soluble in water and conduct electricity in aqueous state only.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify ionic compounds.\u0026lt;br\u0026gt;- Demonstrate the solubility of ionic compounds.\u0026lt;br\u0026gt;- Examine the electrical conductivity of ionic compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Ionic compounds","DISPLAY_NAME":"NGSS New - Middle School - Physical Science","DISPLAY_NAME_AR":"NGSS New - Middle School - Physical Science","SUBJECT_IMG":"569.jpg","ADMSUBJECT_ID":"569","SUBJECT_NAME":"Physical Science","SUBJECT_NAME_AR":"Physical Science","ADMCOURSE_ID":"191","COURSE_NAME":"Middle School","COUNTRY_ID":"287","STANDARD_ID":"287","SHORT_NAME":"NGSS","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u4e2d\u6587","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Polski","Ti\u1ebfng Vi\u1ec7t","\ud55c\uad6d\uc5b4"],"devices":["UmetyVR","WebXR"]}