{"pkgId":"19","subjectId":"1182","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":"Universal Curriculum Library Full Access","PACKAGE_SLUG":"ucl-new-full","PACKAGE_IMG":"file_1653208394_1592480219.png","ADMCOURSE_ID":"347","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","STANDARD_NAME":"UCL-New","ADMSUBJECT_ID":"1182","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","CAT_NAME":"How to Balance Chemical Equations","CONT_ID":"675","CONT_TITLE":"How to Balance Chemical Equations","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA chemical equation is the symbolic representation of a chemical reaction. A chemical equation must be balanced according to the Law of Conservation of Mass. In order to balance a chemical equation, the molecular formulas in the equation cannot be altered. 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A chemical equation must be balanced according to the Law of Conservation of Mass. In order to balance a chemical equation, the molecular formulas in the equation cannot be altered. A coefficient specifies how many of each molecule are required for a balanced equation. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the terms chemical equation and coefficient.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the law of conservation of mass to describe the characteristics of a balanced chemical equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether or not a chemical equation is balanced.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance a chemical equations.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000037","TOPIC_ID":"vc000037","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000037.jpg","PUBLIC_BANNER_IMG":"vc000037.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000037.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;A chemical equation is the symbolic representation of a chemical reaction. A chemical equation must be balanced according to the Law of Conservation of Mass. In order to balance a chemical equation, the molecular formulas in the equation cannot be altered. A coefficient specifies how many of each molecule are required for a balanced equation.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Define the terms chemical equation and coefficient.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Apply the law of conservation of mass to describe the characteristics of a balanced chemical equation.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Determine whether or not a chemical equation is balanced.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Balance a chemical equations.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"How to Balance Chemical Equations","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"493","CATEGORY_ID":"1","CONT_TITLE":"Decomposition Reaction","CONT_SLUG":"decomposition-reaction","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain a decomposition reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200319","TOPIC_ID":"ms200319","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200319.jpg","PUBLIC_BANNER_IMG":"MS200319.jpg","PUBLIC_VIDEO":"pvideo_ms200319.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Dnrhrdmk_RY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"0","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain a decomposition reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Decomposition Reaction","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"484","CATEGORY_ID":"1","CONT_TITLE":"Effect of Surface Area on Reaction Rate","CONT_SLUG":"effect-of-surface-area-on-reaction-rate","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWhen a solid lump is subdivided into fine powder, the surface area increases and more particles are exposed for collisions. This results in an increased frequency of collisions and therefore a faster rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to :\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the effect of surface area of solid reactant on rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate graphically the effect of surface area of solid reactant on rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of increasing surface area on reaction rate using collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply this concept in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200277","TOPIC_ID":"hs200277","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200277.jpg","PUBLIC_BANNER_IMG":"HS200277.jpg","PUBLIC_VIDEO":"pvideo_hs200277.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/m8t8U2eJnj0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"0","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;When a solid lump is subdivided into fine powder, the surface area increases and more particles are exposed for collisions. This results in an increased frequency of collisions and therefore a faster rate of reaction.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to :\u0026lt;br\u0026gt;- Identify the effect of surface area of solid reactant on rate of reaction.\u0026lt;br\u0026gt;- Illustrate graphically the effect of surface area of solid reactant on rate of reaction.\u0026lt;br\u0026gt;- Explain the effect of increasing surface area on reaction rate using collision theory.\u0026lt;br\u0026gt;- Apply this concept in practical problems.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Effect of Surface Area on Reaction Rate","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"482","CATEGORY_ID":"1","CONT_TITLE":"Inhibitors","CONT_SLUG":"inhibitors","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAt times, it is required to prevent certain chemical reactions from occurring. In such cases inhibitors are used to slow down or even stop a chemical reaction. Inhibitors are used in food industry to slow down or inhibit food spoilage.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define an inhibitor.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of an inhibitor on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the use of an inhibitor as a food preservative to slow down or inhibit the reaction that leads to the food item spoiling.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200264.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200264","TOPIC_ID":"ms200264","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200264.jpg","PUBLIC_BANNER_IMG":"MS200264.jpg","PUBLIC_VIDEO":"pvideo_ms200264.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J7nB_OJx5XE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"0","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;At times, it is required to prevent certain chemical reactions from occurring. In such cases inhibitors are used to slow down or even stop a chemical reaction. Inhibitors are used in food industry to slow down or inhibit food spoilage.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define an inhibitor.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the effect of an inhibitor on the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the use of an inhibitor as a food preservative to slow down or inhibit the reaction that leads to the food item spoiling.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Inhibitors","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"369","CATEGORY_ID":"1","CONT_TITLE":"Balancing Redox Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance oxidation half-reaction and reduction half-reaction separately.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Balancing Redox Reaction","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"368","CATEGORY_ID":"1","CONT_TITLE":"Oxidation-Reduction Reactions","CONT_SLUG":"oxidation-reduction-reaction","CONT_TITLE_AR":"Oxidation-Reduction Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoth oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify oxidation-reduction or redox reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidizing and reducing agents in a redox reaction.\u003C\/div\u003E","CONT_DESC_AR":"In a redox reaction both oxidation and reduction takes place in a single reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define oxidation-reduction (redox) reactions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidizing and reducing agents in a redox reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200026","TOPIC_ID":"ss200026","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200026.jpg","PUBLIC_BANNER_IMG":"SS200026.jpg","PUBLIC_VIDEO":"pvideo_ss200026.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/frc5RvK7rIk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Both oxidation and reduction take place in a singe reaction, called a redox reaction. The chemical species undergoing oxidation is called an oxidant or reducing agent. The chemical species undergoing reduction is called a reductant or oxidizing agent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify oxidation-reduction or redox reactions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the oxidizing and reducing agents in a redox reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Oxidation-reduction Reactions","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"275","CATEGORY_ID":"1","CONT_TITLE":"Effect of Temperature on Reaction Rate","CONT_SLUG":"effect-of-temperature-on-reaction-rate","CONT_TITLE_AR":"Effect of Temperature on Reaction Rate","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the increase in the reaction rate with the increase in temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate the effect of temperature on the reaction rate.\u003C\/div\u003E","CONT_DESC_AR":"The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u0026amp;deg; rise in temperature. This increase is mainly due to the increase in the number of collisions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the increase in the reaction rate with the increase in temperature\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate the effect of temperature on the reaction rate\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the concept in practical problems","BACKING_FILE":"ss200058.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200058","TOPIC_ID":"ss200058","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200058.jpg","PUBLIC_BANNER_IMG":"SS200058.jpg","PUBLIC_VIDEO":"pvideo_ss200058.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/d7IKyDsgrAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the increase in the reaction rate with the increase in temperature.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate the effect of temperature on the reaction rate.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Effect of Temperature on Reaction Rate","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"234","CATEGORY_ID":"1","CONT_TITLE":"Calculating the Oxidation Number","CONT_SLUG":"calculating-oxidation-number","CONT_TITLE_AR":"Calculating Oxidation Number","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFor calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define oxidation number.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assign oxidation number to different elements in a chemical species.\u003C\/div\u003E","CONT_DESC_AR":"While calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation you will be able to:\u003C\/br\u003E\r\n\u2022 define oxidation number\u003C\/br\u003E\r\n\u2022 assign the oxidation number to different elements in a chemical species","BACKING_FILE":"ss200027.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200027","TOPIC_ID":"ss200027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200027.jpg","PUBLIC_BANNER_IMG":"SS200027.jpg","PUBLIC_VIDEO":"pvideo_ss200027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Jf7BP10vSVM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define oxidation number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assign oxidation number to different elements in a chemical species.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Calculating Oxidation Number","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"213","CATEGORY_ID":"1","CONT_TITLE":"Catalysts","CONT_SLUG":"catalysts","CONT_TITLE_AR":"Catalysts","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define catalyst.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of a catalyst on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how a catalyst increases the rate of a chemical reaction.\u003C\/div\u003E","CONT_DESC_AR":"A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define catalyst\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain effect of catalyst on the rate of a chemical reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how a catalyst increases the rate of a chemical reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200020","TOPIC_ID":"ss200020","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200020.jpg","PUBLIC_BANNER_IMG":"ss200020.jpg","PUBLIC_VIDEO":"pvideo_ss200020.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EpkHrhW2Xxc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define catalyst.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the effect of a catalyst on the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how a catalyst increases the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Catalysts","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"157","CATEGORY_ID":"1","CONT_TITLE":"Synthesis Reactions","CONT_SLUG":"synthesis-reactions","CONT_TITLE_AR":"Synthesis reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a synthesis reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the synthesis reaction of magnesium oxide.\u003C\/div\u003E","CONT_DESC_AR":"A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic. An example of a synthesis reaction is the formation of water from hydrogen and oxygen.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a synthesis reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate the synthesis reaction of magnesium oxide","BACKING_FILE":"hs200021.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200021","TOPIC_ID":"hs200021","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200021.jpg","PUBLIC_BANNER_IMG":"HS200021.jpg","PUBLIC_VIDEO":"pvideo_hs200021.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5RK8BgMSqAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a synthesis reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the synthesis reaction of magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Synthesis Reactions","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"154","CATEGORY_ID":"1","CONT_TITLE":"Combustion Reactions","CONT_SLUG":"combustion-reactions","CONT_TITLE_AR":"Combustion reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define a combustion reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the combustion of propane and oxygen.\u003C\/div\u003E","CONT_DESC_AR":"A combustion reaction is a major class of chemical reactions. Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. In the more general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. Combustion is an exothermic reaction, so it releases heat.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf explain what is a combustion reaction\u0026lt;br \/\u0026gt;\n\u25cf demonstrate combustion reaction of propane and oxygen\u0026lt;br \/\u0026gt;\n\u25cf identify a combustion reaction","BACKING_FILE":"hs200022.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200022","TOPIC_ID":"hs200022","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200022.jpg","PUBLIC_BANNER_IMG":"HS200022.jpg","PUBLIC_VIDEO":"pvideo_hs200022.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Wl8vJ7nbNbY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 08:53:46","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and define a combustion reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the combustion of propane and oxygen.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Combustion Reactions","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"150","CATEGORY_ID":"1","CONT_TITLE":"Double Displacement Reactions","CONT_SLUG":"double-displacement-reaction","CONT_TITLE_AR":"Double displacement reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able 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\/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 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sodium chloride.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Double Displacement Reaction","ADMSUBJECT_ID":"1182","ADMCOURSE_ID":"347","DISPLAY_NAME":"","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemical Reactions","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":null,"SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"High School Chemistry","COUNTRY_ID":"335","SHORT_NAME":"UCL-New","DOMAIN_NAME":"STEM"},{"CONT_ID":"51","CATEGORY_ID":"1","CONT_TITLE":"Single Displacement Reaction","CONT_SLUG":"single-displacement-reaction","CONT_TITLE_AR":"Single Displacement Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a single displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate a single displacement reaction.\u003C\/div\u003E","CONT_DESC_AR":"A single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- identify the single displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- demonstrate the single displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200003","TOPIC_ID":"ms200003","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200003.jpg","PUBLIC_BANNER_IMG":"MS200003.jpg","PUBLIC_VIDEO":"pvideo_ms200003.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/o6-pPsqJirE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-05-03 00:00:00","CREATED_BY":"1","UPDATED_ON":"2020-02-05 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A chemical equation must be balanced according to the Law of Conservation of Mass. In order to balance a chemical equation, the molecular formulas in the equation cannot be altered. A coefficient specifies how many of each molecule are required for a balanced equation. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the terms chemical equation and coefficient.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the law of conservation of mass to describe the characteristics of a balanced chemical equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether or not a chemical equation is balanced.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance a chemical equations.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000037","TOPIC_ID":"vc000037","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000037.jpg","PUBLIC_BANNER_IMG":"vc000037.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000037.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-07-04 07:05:11","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 10:21:59","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;A chemical equation is the symbolic representation of a chemical reaction. A chemical equation must be balanced according to the Law of Conservation of Mass. In order to balance a chemical equation, the molecular formulas in the equation cannot be altered. 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