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To subtract like fractions, simply subtract the numerators and write their difference divided by the common denominator.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify like fractions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Subtract like fractions.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Subtract like fractions","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"543","CATEGORY_ID":"1","CONT_TITLE":"Sales Tax and Total Cost","CONT_SLUG":"sales-tax-and-total-cost","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA sales tax is the money paid to the government, by the service provider, for the sales of certain goods and services. This can be calculated by using the formula: Sales tax = tax rate \u00d7 total cost and, the total cost inclusive of sales tax is calculated by using the formula. Total price (inclusive of sales tax) = total cost + sales tax.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define sales tax. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Relate total cost to sales tax. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply formula for sales tax. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Find total price (inclusive of sales tax) of goods and services.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300148","TOPIC_ID":"ms300148","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300148.jpg","PUBLIC_BANNER_IMG":"MS300148.jpg","PUBLIC_VIDEO":"pvideo_ms300148.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/VFcXdS-PB6w","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A sales tax is the money paid to the government, by the service provider, for the sales of certain goods and services. This can be calculated by using the formula: Sales tax = tax rate \u00d7 total cost and, the total cost inclusive of sales tax is calculated by using the formula. Total\u0026amp;nbsp; price (inclusive of sales tax) = total\u0026amp;nbsp; cost + sales tax.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define sales tax.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Relate total cost to sales tax.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Apply formula for sales tax.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Find total price (inclusive of sales tax) of goods and services.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Sales Tax and Total Cost","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"542","CATEGORY_ID":"1","CONT_TITLE":"Simplification of a Complex Fraction","CONT_SLUG":"simplify-a-complex-fraction","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA complex fraction is a fraction where the numerator, denominator, or both contain a fraction. For example (2\/3)\/(6\/7).\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a complex fraction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Simplify a complex fraction.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300144","TOPIC_ID":"ms300144","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300144.jpg","PUBLIC_BANNER_IMG":"ms300144.jpg","PUBLIC_VIDEO":"pvideo_ms300144.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/AWnDoYUtReM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A complex fraction is a fraction where the numerator, denominator, or both contain a fraction. For example (2\/3)\/(6\/7).\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a complex fraction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Simplify a complex fraction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Simplify a Complex Fraction","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"541","CATEGORY_ID":"1","CONT_TITLE":"Add Like Fractions","CONT_SLUG":"add-like-fractions","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELike fractions are fractions with the same denominator. To add like fractions, simply add the numerators and write the sum divided by common denominator.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Identify like fractions. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Add like fractions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300141","TOPIC_ID":"ms300141","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300141.jpg","PUBLIC_BANNER_IMG":"MS300141.jpg","PUBLIC_VIDEO":"pvideo_ms300141.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BjTi9wmzxsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Like fractions are fractions with the same denominator. To add like fractions, simply add the numerators and write the sum divided by common denominator.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify like fractions.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Add like fractions.\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Add like fractions","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"538","CATEGORY_ID":"1","CONT_TITLE":"Probability of Dependent and Independent Events","CONT_SLUG":"probability-of-dependent-and-independent-events","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETwo events are independent when one event does not affect the probability of another event occurring after it. Whereas, two events are dependent when the occurrence and outcome of one event affects the probability of another event that is occurring after it.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between independent and dependent events.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the formulas for finding the probability of independent and dependent events.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms300137.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300137","TOPIC_ID":"ms300137","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300137.jpg","PUBLIC_BANNER_IMG":"MS300137.jpg","PUBLIC_VIDEO":"pvideo_ms300137.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/sAglw-Q8oLo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"6","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Two events are independent when one event does not affect the probability of another event occurring after it. Whereas, two events are dependent when the occurrence and outcome of one event affects the probability of another event that is occurring after it.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Differentiate between independent and dependent events.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply the formulas for finding the probability of independent and dependent events.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Probability of dependent and independent event","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"Higher Education"},{"CONT_ID":"537","CATEGORY_ID":"1","CONT_TITLE":"Probability of Simple Events","CONT_SLUG":"probability-of-simple-events","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESimple events are events in which one experiment happens at a time and there is a single outcome. The probability of a simple event is denoted by P(E), where E is the event.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the total number of outcomes for an event.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the favorable outcomes of an event.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the probability of an event.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms300135.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300135","TOPIC_ID":"ms300135","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300135.jpg","PUBLIC_BANNER_IMG":"ms300135.jpg","PUBLIC_VIDEO":"pvideo_ms300135.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5SF8zt4RsKA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Simple events are events in which one experiment happens at a time and there is a single outcome. The probability of a simple event is denoted by P(E), where E is the event. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the total number of outcomes for an event.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the favorable outcomes of an event.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Find the probability of an event.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Probability of simple event","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"535","CATEGORY_ID":"1","CONT_TITLE":"Solving Two Step Inequalities","CONT_SLUG":"solve-two-step-inequality","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn inequality is a sentence built from expressions using one or more of the symbols \r\n\u003C,\u003E, \u2264, or \u2265. Two step inequalities means the system of inequalities which can be solved only in two steps.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Solve inequalities in two steps.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300133","TOPIC_ID":"ss300133","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300133.jpg","PUBLIC_BANNER_IMG":"SS300133.jpg","PUBLIC_VIDEO":"pvideo_ss300133.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/bdkNNR5Anr4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;An inequality is a sentence built from expressions using one or more of the symbols \u0026amp;lt;, \u0026amp;gt;, \u2264, or \u2265. Two step inequalities means the system of inequalities which can be solved only in two steps.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objective\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Solve inequalities in two steps.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Solve two step inequality","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"534","CATEGORY_ID":"1","CONT_TITLE":"Addition and Subtraction of Unlike Fractions","CONT_SLUG":"add-and-subtract-unlike-fractions","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EUnlike fractions are the fractions with different denominators. To add or subtract the unlike fractions, first find the least common multiple of the denominators. This gives the equivalent fractions with the same denominators. Then add or subtract the numerators of equivalent fractions having the same denominators.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Identify unlike fractions. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Add unlike fractions. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Subtract unlike fractions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300127","TOPIC_ID":"ms300127","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300127.jpg","PUBLIC_BANNER_IMG":"MS300127.jpg","PUBLIC_VIDEO":"pvideo_ms300127.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/WvHK9dm5kRI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Unlike fractions are the fractions with different denominators. To add or subtract the unlike fractions, first find the least common multiple of the denominators. This gives the equivalent fractions with the same denominators. Then add or subtract the numerators of equivalent fractions having the same denominators.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify unlike fractions.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Add unlike fractions.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Subtract unlike fractions.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Add and subtract unlike fractions","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"533","CATEGORY_ID":"1","CONT_TITLE":"Integers and Absolute Value","CONT_SLUG":"integer-and-absolute-value","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe absolute value of an integer is the numerical positive value without considering the negative or positive sign. On a number line, it is the distance between the number and zero.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify an integer in real life situations.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between positive and negative integers.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define absolute value.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300126","TOPIC_ID":"ms300126","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300126.jpg","PUBLIC_BANNER_IMG":"MS300126.jpg","PUBLIC_VIDEO":"pvideo_ms300126.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/2B_bQ5idEfs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The absolute value of an integer is the numerical positive value without considering the negative or positive sign. On a number line, it is the distance between the number and zero.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define integers.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify an integer in real life situations.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Differentiate between positive and negative integers.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define absolute value.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Integer and absolute value","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"381","CATEGORY_ID":"1","CONT_TITLE":"Fractions and Decimals","CONT_SLUG":"fractions-and-decimals","CONT_TITLE_AR":"Fractions and Decimals","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA fraction represents the part of a whole. To convert a fraction to a decimal, we need to find a number which we can multiply with denominator of that fraction to make it 10, or 100, or 1000, or any 1 followed by 0s. Then multiply both the top and bottom values by that number.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define decimals, mixed numbers, whole numbers, fractions, place values, and expanded form.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the whole number and the fractional parts of a decimal.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize connections between decimal numbers and place values.\u003C\/div\u003E","CONT_DESC_AR":"To convert a fraction to a decimal, find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.\u0026lt;br \/\u0026gt;\nThen multiply both the top and bottom values by that number.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter going through this simulation, you are now able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; recognize and write a fraction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the whole number and the fractional part of a mixed fraction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; compute the place value of digits in a decimal number\u0026lt;br \/\u0026gt;\n\u0026amp;bull; convert a fraction into a decimal.","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300083","TOPIC_ID":"ms300083","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300083.jpg","PUBLIC_BANNER_IMG":"ms300083.jpg","PUBLIC_VIDEO":"pvideo_ms300083.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/jmf66Oggm6I","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A fraction represents the part of a whole. To convert a fraction to a decimal, we need to find a number which we can multiply with denominator of that fraction to make it 10, or 100, or 1000, or any 1 followed by 0s. Then multiply both the top and bottom values by that number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define decimals, mixed numbers, whole numbers, fractions, place values, and expanded form.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the whole number and the fractional parts of a decimal.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Recognize connections between decimal numbers and place values.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Fraction and decimals","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"322","CATEGORY_ID":"1","CONT_TITLE":"Volume and Surface Area of a Cylinder","CONT_SLUG":"volume-and-surface-area-of-cylinder","CONT_TITLE_AR":"Volume and Surface Area of Cylinder","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA right circular cylinder is a closed solid that has two circular bases connected by a curved surface. The curved surface area of a cylinder is the area of its curved surface excluding the base, while total surface area is calculated by adding the areas of curved surface and two circular bases. The volume of a cylinder is calculated by multiplying the area of the base with the height of the cylinder.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive the formula for the curved surface area of a right circular cylinder.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive the formula for the total surface area of a right circular cylinder.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive the formula for the volume of a right circular cylinder.\u003C\/div\u003E","CONT_DESC_AR":"Formula for curved surface area, total surface area and volume of a right circular cylinder.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be able to find that the\u0026lt;br \/\u0026gt;\n\u0026amp;bull; Curved surface area = 2\u0026amp;pi;rh\u0026lt;br \/\u0026gt;\n\u0026amp;bull; Total surface area = 2\u0026amp;pi;r(r+h)\u0026lt;br \/\u0026gt;\n\u0026amp;bull; Volume = \u0026amp;pi;r\u0026amp;sup2;h \u0026amp;nbsp;\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nWhere r is the radius and h is the height of the cylinder.","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300016","TOPIC_ID":"hs300016","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300016.jpg","PUBLIC_BANNER_IMG":"HS300016.jpg","PUBLIC_VIDEO":"pvideo_hs300016.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Pasy8gpnPP0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A right circular cylinder is a closed solid that has two circular bases connected by a curved surface. The curved surface area of a cylinder is the area of its curved surface excluding the base, while total surface area is calculated by adding the areas of curved surface and two circular bases. The volume of a cylinder is calculated by multiplying the area of the base with the height of the cylinder.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive the formula for the curved surface area of a right circular cylinder.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive the formula for the total surface area of a right circular cylinder.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive the formula for the volume of a right circular cylinder.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Volume and surface area of cylinder","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"321","CATEGORY_ID":"1","CONT_TITLE":"Percentage","CONT_SLUG":"percentage","CONT_TITLE_AR":"Percentage","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA percentage is defined as a portion of a whole expressed as a number between 0 and 100 instead of a fraction. The percentage is represented by % sign.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define percentage.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate percentage.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate discount and discounted price.\u003C\/div\u003E","CONT_DESC_AR":"A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, % or the abbreviations pct, pct, sometimes the abbreviation pc is also used. A percentage is a dimensionless number (pure number).\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define percentage\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate percentage\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate discount and discounted price","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300037","TOPIC_ID":"ms300037","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300037.jpg","PUBLIC_BANNER_IMG":"MS300037.jpg","PUBLIC_VIDEO":"pvideo_ms300037.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hOyh3_T4eik","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A percentage is defined as a portion of a whole expressed as a number between 0 and 100 instead of a fraction. The percentage is represented by % sign.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define percentage.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate percentage.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate discount and discounted price.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Percentage","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"282","CATEGORY_ID":"1","CONT_TITLE":"Geometric Sequence and Series","CONT_SLUG":"introduction-to-geometric-sequence","CONT_TITLE_AR":"Introduction to Geometric Sequence","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA sequence of numbers is said to be a geometric sequence if each term after the first term can be obtained by multiplying the previous one by a fixed, non-zero number called the common ratio. For example, the sequence 2, 4, 8, 16, is a geometric sequence with a common ratio of 2.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a geometric sequence.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply a formula for finding the n term.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply a formula for finding the sum of a geometric series.\u003C\/div\u003E","CONT_DESC_AR":"A geometric progression, also known as a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.\u0026lt;br \/\u0026gt;\nFor example, the sequence 2, 6, 18, 54, is a geometric progression with a common ratio of 3.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define geometric sequence\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply a formula for finding the n\u1d57\u02b0 term\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply a formula for finding the sum of a geometric series","BACKING_FILE":"ss300069.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300069","TOPIC_ID":"ss300069","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300069.jpg","PUBLIC_BANNER_IMG":"SS300069.jpg","PUBLIC_VIDEO":"pvideo_ss300069.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/2Q5xiWjT3hs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A sequence of numbers is said to be a geometric sequence if each term after the first term can be obtained by multiplying the previous one by a fixed, non-zero number called the common ratio. For example, the sequence 2, 4, 8, 16, is a geometric sequence with a common ratio of 2.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a geometric sequence.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply a formula for finding the n term.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply a formula for finding the sum of a geometric series.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Introduction to geometric sequence","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"269","CATEGORY_ID":"1","CONT_TITLE":"Normal Distribution","CONT_SLUG":"normal-distribution","CONT_TITLE_AR":"Normal Distribution","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ENormal (or Gaussian) distribution is a very common continuous probability distribution. Normal distributions are important in statistics and are often used in the natural and social sciences to represent real-valued random variables whose distributions are not known.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a normal distribution.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the z-score (z).\u003C\/div\u003E","CONT_DESC_AR":"Normal (or Gaussian) distribution is a very common continuous probability distribution.\u0026lt;br \/\u0026gt;\nNormal distributions are important in statistics and are often used in the natural and social sciences to represent real-valued random variables whose distributions are not known.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be able to identify a normal distribution.","BACKING_FILE":"ss300056.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300056","TOPIC_ID":"ss300056","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300056.jpg","PUBLIC_BANNER_IMG":"SS300056.jpg","PUBLIC_VIDEO":"pvideo_ss300056.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/WBxUGkOgTS4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"6","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Normal (or Gaussian) distribution is a very common continuous probability distribution. Normal distributions are important in statistics and are often used in the natural and social sciences to represent real-valued random variables whose distributions are not known.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify a normal distribution.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the z-score (z).\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Normal Distribution","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"Higher Education"},{"CONT_ID":"267","CATEGORY_ID":"1","CONT_TITLE":"Scatter Plot","CONT_SLUG":"scatter-plot","CONT_TITLE_AR":"Scatter Plot","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EScatter plot is a graph of plotted points that show the relationship between two sets of data. It is defined as a set of points plotted on a horizontal and vertical axis. The graph can depict the extent of correlation between the values of observed quantities or phenomena.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define scatter plot.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define positive and negative associations.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Create a scatter plot.\u003C\/div\u003E","CONT_DESC_AR":"The scatter diagram graphs pairs of numerical data, with one variable on each axis, to look for a relationship between them. Or we can say in a Scatter (XY) Plot the\u0026amp;nbsp;points shows the relationship between two sets of data.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be familiar with\u0026lt;br \/\u0026gt;\n- scatter plot graph","BACKING_FILE":"hs300053.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300053","TOPIC_ID":"hs300053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300053.jpg","PUBLIC_BANNER_IMG":"HS300053.jpg","PUBLIC_VIDEO":"pvideo_hs300053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J9k05vryu-s","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Scatter plot is a graph of plotted points that show the relationship between two sets of data. It is defined as a set of points plotted on a horizontal and vertical axis. The graph can depict the extent of correlation between the values of observed quantities or phenomena.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define scatter plot.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define positive and negative associations.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Create a scatter plot.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Scatter Plot","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"254","CATEGORY_ID":"1","CONT_TITLE":"Solving Systems of Equations in Two Variables","CONT_SLUG":"solving-system-of-equations-in-two-variables","CONT_TITLE_AR":"Solving System of Equations in Two Variables","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA linear equation in two variable is defined as a first-degree equation that can be written in the form ax + by = c, where both a and b are not equal to zero and a, b, and c are real numbers. The graph of any equation of this form is a straight line.To solve the system of equations graphically, first of all we graph both the lines and then find the point of intersection. If the lines intersect at only one point, it is known as unique solutions. If the line coincides with each other, then they have infinitely many solutions and if the two lines are parallel, then no solution exists for those equations.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Solve a linear equation in two variables using the graphical method.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate and construct a unique solution.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate and construct infinitely many solutions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate and construct no solution.\u003C\/div\u003E","CONT_DESC_AR":"Solving systems of equations with two variables.\u003C\/br\u003E\r\nA system of a linear equation is comprised of two or more equations, used to find a common solution to the equations.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nAt the end of this simulation, you will be able to:\u003C\/br\u003E\r\n\u2022 solve linear equation in two variable using graphical method\u003C\/br\u003E\r\n\u2022 differentiate and construct unique solution\u003C\/br\u003E\r\n\u2022 differentiate and construct infinitely many solution\u003C\/br\u003E\r\n\u2022 differentiate and construct no solution","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300076","TOPIC_ID":"hs300076","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300076.jpg","PUBLIC_BANNER_IMG":"hs300076.jpg","PUBLIC_VIDEO":"pvideo_hs300076.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/tc7Z4gGoOwU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A linear equation in two variable is defined as a first-degree equation that can be written in the form ax + by = c, where both a and b are not equal to zero and \u0026amp;nbsp;a, b, and c are real numbers. The graph of any equation of this form is a straight line.To solve the system of equations graphically, first of all we graph both the lines and then find the point of intersection. If the lines intersect at only one point, it is known as unique solutions. If the line coincides with each other, then they have infinitely many solutions and if the two lines are parallel, then no solution exists for those equations.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Solve a linear equation in two variables using the graphical method.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Differentiate and construct a unique solution.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Differentiate and construct infinitely many solutions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Differentiate and construct no solution.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Solving system of equations in two variables","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"237","CATEGORY_ID":"1","CONT_TITLE":"Polygons","CONT_SLUG":"polygons","CONT_TITLE_AR":"Polygons","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA polygon is a two dimensional closed shape formed with straight lines. Triangles, quadrilaterals, pentagons, and hexagons are some of its examples. The first suffix in the name of a polygons tells about the number of sides that the polygon have. For example, in triangle, \u0026#039;tri\u0026#039; means 3 sides.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify polygons and non polygons.\u003C\/div\u003E","CONT_DESC_AR":"A polygon is any 2-dimensional shape formed with straight lines. Triangles, quadrilaterals, pentagons, and hexagons are all examples of\u0026amp;nbsp;polygons. The name tells you how many sides the shape has. For example, a triangle has three sides, and a quadrilateral has four sides.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\n\u0026lt;p\u0026gt;\u0026lt;br \/\u0026gt;\nAt the end of simulation you will be able to identify polygons.\u0026lt;\/p\u0026gt;\n","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300041","TOPIC_ID":"ms300041","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300041.jpg","PUBLIC_BANNER_IMG":"MS300041.jpg","PUBLIC_VIDEO":"pvideo_ms300041.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hZrn_cF9g30","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A polygon is a two dimensional closed shape formed with straight lines. Triangles, quadrilaterals, pentagons, and hexagons are some of its examples. The first suffix in the name of a polygons tells about the number of sides that the polygon have. For example, in triangle, \u0026#039;tri\u0026#039; means 3 sides.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objective\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify polygons and non polygons.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\r\n","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Polygons","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"235","CATEGORY_ID":"1","CONT_TITLE":"Circle","CONT_SLUG":"circle","CONT_TITLE_AR":"Circle","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA circle is defined as a round closed figure whose boundary consists of points equidistant from a fixed point.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIts radius is the line connecting the center to the outer boundary of circle and diameter is twice of the radius. The circumference of a circle is defined as the outer boundary of circle. The formula for calculating circumference is 2\u03c0r and for calculating area is \u03c0r\u00b2.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAt the end of this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a circle.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define the radius and diameter of a circle.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the circumference and the area of a circle.\u003C\/div\u003E","CONT_DESC_AR":"Circle : - A round closed figure whose boundary consists of points equidistant from a fixed point.\u0026lt;br \/\u0026gt;\nRadius : - Line connecting the centre to the outer boundary of circle.\u0026lt;br \/\u0026gt;\nDiameter : - Twice of the radius is diameter of the circle.\u0026lt;br \/\u0026gt;\nCircumference: - Outer boundary of circle.\u0026lt;br \/\u0026gt;\nFormula to calculate circumference is 2\u0026amp;pi;r\u0026lt;br \/\u0026gt;\nArea \u0026amp;nbsp;: - Formula for finding area of circle is \u0026amp;pi;r\u0026lt;sup\u0026gt;2\u0026lt;\/sup\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a circle\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the radius and diameter of a circle\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the circumference and area of a circle","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300042","TOPIC_ID":"ms300042","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300042.jpg","PUBLIC_BANNER_IMG":"MS300042.jpg","PUBLIC_VIDEO":"pvideo_ms300042.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xKAEF2qfW3g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;A circle is defined as a round closed figure whose boundary consists of points equidistant from a fixed point.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Its radius is the line connecting the center to the outer boundary of circle and diameter is twice of the radius. The circumference of a circle is defined as the outer boundary of circle. The formula for calculating circumference is 2\u03c0r and for calculating area is \u03c0r\u00b2.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;At the end of this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a circle.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and define the radius and diameter of a circle.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the circumference and the area of a circle.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Circle","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"225","CATEGORY_ID":"1","CONT_TITLE":"Area Related to Circle","CONT_SLUG":"area-related-to-circles","CONT_TITLE_AR":"Area Related to Circles","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA sector is the part of a circle enclosed by two radii and an intercepted arc of that circle. The segment of a circle is the region bounded by a chord. An annulus is a flat ring shaped object. To find the area of an annulus, a sector, and a segment we actually need to find the fractional part of the area of the entire circle.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the area of a sector.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the area of a segment.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the area of an annulus.\u003C\/div\u003E","CONT_DESC_AR":"When finding the area of an annulus, sector, and segment you are actually finding a fractional part of the area of the entire circle.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nAt the end of this simulation, you will be able to apply the formula of:\u003C\/br\u003E\r\n\u2022 the area of a sector\u003C\/br\u003E\r\n\u2022 the area of a segment\u003C\/br\u003E\r\n\u2022 the area of an annulus","BACKING_FILE":"hs300020.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300020","TOPIC_ID":"hs300020","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300020.jpg","PUBLIC_BANNER_IMG":"HS300020.jpg","PUBLIC_VIDEO":"pvideo_hs300020.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/z4XP6Ift0Yc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A sector is the part of a circle enclosed by two radii and an intercepted arc of that circle. The segment of a circle is the region bounded by a chord. An annulus is a flat ring shaped object. To find the area of an annulus, a sector, and a segment we actually need to find the fractional part of the area of the entire circle.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Find the area of a sector.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Find the area of a segment.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Find the area of an annulus.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Area related to circles","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"218","CATEGORY_ID":"1","CONT_TITLE":"Direct Variation","CONT_SLUG":"direct-variation","CONT_TITLE_AR":"Direct Variation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDirect variation is the relationship between two variables in which one is a constant multiple of the other. In other words, we can say when one variable changes the other changes in proportion to the first. If b is directly proportional to a, the equation is of the form b = ka (where k is a constant).\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to :\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the concept of direct variation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify direct variation.\u003C\/div\u003E","CONT_DESC_AR":"A relationship between two variables in which one is a constant multiple of the other. In particular, when one variable changes the other changes in proportion to the first. If b is directly proportional to a, the equation is of the form b = ka (where k is a constant)\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nAt the end of this simulation, you will:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; know the concept of direct variation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify direct variation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300077","TOPIC_ID":"ms300077","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300077.jpg","PUBLIC_BANNER_IMG":"ms300077.jpg","PUBLIC_VIDEO":"pvideo_ms300077.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ccOglkJsAqI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Direct variation is the relationship between two variables in which one is a constant multiple of the other. In other words, we can say when one variable changes the other changes in proportion to the first. If b is directly proportional to a, the equation is of the form b = ka (where k is a constant).\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to :\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the concept of direct variation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify direct variation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Direct variation","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"214","CATEGORY_ID":"1","CONT_TITLE":"Regression and Correlation","CONT_SLUG":"regression-and-correlation","CONT_TITLE_AR":"Regression and Correlation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ERegression analysis involves identifying the relationship between a dependent variable and one or more independent variables. A model of this relationship is hypothesized, and estimates of the parameter values are then used to develop an estimated regression equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define regression and correlation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the formulas for regression and correlation in real life.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the formula for finding the equation of a line.\u003C\/div\u003E","CONT_DESC_AR":"Regression analysis involves identifying the relationship between a dependent variable and one or more independent variables.\u0026lt;br \/\u0026gt;\nA model of this relationship is hypothesized, and estimates of the parameter values are used to develop an estimated regression equation.\u0026lt;br \/\u0026gt;\nRegression and correlation formulas and their usage in finding the equation of a line.\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nLearning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nin this topic you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define regression and correlation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the formulas for regression and correlation in real life\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the formula for finding the equation of a line\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ss300070.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300070","TOPIC_ID":"ss300070","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300070.jpg","PUBLIC_BANNER_IMG":"SS300070.jpg","PUBLIC_VIDEO":"pvideo_ss300070.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/USFehzuvA7o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"6","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Regression analysis involves identifying the relationship between a dependent variable and one or more independent variables. A model of this relationship is hypothesized, and estimates of the parameter values are then used to develop an estimated regression equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define regression and correlation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply the formulas for regression and correlation in real life.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply the formula for finding the equation of a line.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Regression and correlation","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"Higher Education"},{"CONT_ID":"210","CATEGORY_ID":"1","CONT_TITLE":"Simple Interest","CONT_SLUG":"simple-interest","CONT_TITLE_AR":"Simple Interest","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESimple interest is defined as the interest that is calculated on an original sum of money by multiplying the principal amount with rate of interest and time period.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define simple interest.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Use the formula to calculate simple interest.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the simple interest formula to calculate the interest on loans and mutual funds.\u003C\/div\u003E","CONT_DESC_AR":"Simple interest is a quick method of calculating the interest charged on a loan.\u0026lt;br \/\u0026gt;\nSimple interest is determined by multiplying the interest rate by the principal and by the number of days that elapse between payments.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define simple interest\u0026lt;br \/\u0026gt;\n\u0026amp;bull; use the formula to calculate simple interest\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the simple interest formula to calculate the interest on loans and mutual funds","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300067","TOPIC_ID":"ms300067","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300067.jpg","PUBLIC_BANNER_IMG":"ms300067.jpg","PUBLIC_VIDEO":"pvideo_ms300067.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/eXZS6L1ft4Y","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Simple interest is defined as the interest that is calculated on an original sum of money by multiplying the principal amount with rate of interest and time period.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define simple interest.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Use the formula to calculate simple interest.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply the simple interest formula to calculate the interest on loans and mutual funds.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Simple Interest","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"207","CATEGORY_ID":"1","CONT_TITLE":"Solving a System of Inequalities Graphically","CONT_SLUG":"solving-system-of-inequalities-graphically","CONT_TITLE_AR":"Solving System of Inequalities Graphically","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA linear inequality is an inequality which involves a linear function. A linear inequality contains one of the symbols of inequality: \u003C is less than, \u003E is greater than, \u2264 is less than or equal to, \u2265 is greater than or equal to. Linear inequality in two variables can be solved in a similar manner as we solve linear inequality.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the concept of inequality.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Distinguish between graphs of inequalities.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Solve a system of linear inequalities graphically.\u003C\/div\u003E","CONT_DESC_AR":"A linear inequality is an inequality which involves a linear function.\u003C\/br\u003E\r\nA linear inequality contains one of the symbols of inequality: \u003C is less than, \u003E is greater than, \u2264 is less than or equal to.\u003C\/br\u003E\r\nLinear inequality in two variables can be solved in a similar manner as we solve system of linear equations.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation,you will be able to:\u003C\/br\u003E\r\n\u2022 explain the concept of inequality\u003C\/br\u003E\r\n\u2022 distinguish between the graphs of inequalities\u003C\/br\u003E\r\n\u2022 solve the system of linear inequalities graphically","BACKING_FILE":"ss300049.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300049","TOPIC_ID":"ss300049","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300049.jpg","PUBLIC_BANNER_IMG":"SS300049.jpg","PUBLIC_VIDEO":"pvideo_ss300049.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/H6wES_wtrQ4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A linear inequality is an inequality which involves a linear function. A linear inequality contains one of the symbols of inequality: \u0026amp;lt; is less than, \u0026amp;gt; is greater than, \u2264 is less than or equal to, \u2265 is greater than or equal to. Linear inequality in two variables can be solved in a similar manner as we solve linear inequality.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the concept of inequality.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Distinguish between graphs of inequalities.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Solve a system of linear inequalities graphically.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Solving system of inequalities graphically","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"205","CATEGORY_ID":"1","CONT_TITLE":"Probability","CONT_SLUG":"probability","CONT_TITLE_AR":"Probability","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EProbability is defined as the chance that something is likely to happen. This is defined as the ratio of favorable cases to the total number of cases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define probability.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between favorable cases and unfavorable cases.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply the formula for finding probability.\u003C\/div\u003E","CONT_DESC_AR":"Probability is the quality or state of being probable; the extent to which something is likely to happen, or be the case. This is defined as the ratio of favourable cases to the total number of cases.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this topic you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define probability\u0026lt;br \/\u0026gt;\n\u0026amp;bull; differentiate between favourable cases and unfavourable cases\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the formula for finding probability","BACKING_FILE":"hs300017.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs300017","TOPIC_ID":"hs300017","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS300017.jpg","PUBLIC_BANNER_IMG":"HS300017.jpg","PUBLIC_VIDEO":"pvideo_hs300017.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/DTJVgsSfs4M","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Probability is defined as the chance that something is likely to happen. This is defined as the ratio of favorable cases to the total number of cases.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define probability.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Differentiate between favorable cases and unfavorable cases.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply the formula for finding probability.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Probability","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"198","CATEGORY_ID":"1","CONT_TITLE":"Ratio","CONT_SLUG":"ratio","CONT_TITLE_AR":"Ratio","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA ratio is defined as the relationship between two groups or amounts that expresses how much an amount or group is bigger than the other.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain ratios.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify equivalent ratios.\u003C\/div\u003E","CONT_DESC_AR":"A ratio is the quantitative relationship between two amounts showing the number of times one value contains or is contained within the other activity to find equal ratios.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of simulation you will learn about ratios.","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300036","TOPIC_ID":"ms300036","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300036.jpg","PUBLIC_BANNER_IMG":"ms300036.jpg","PUBLIC_VIDEO":"pvideo_ms300036.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/kxaGcnXZL7A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A ratio is defined as the relationship between two groups or amounts that expresses how much an amount or group is bigger than the other.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain ratios.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify equivalent ratios.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Ratio","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"197","CATEGORY_ID":"1","CONT_TITLE":"Sum of Arithmetic Sequence and Series","CONT_SLUG":"sum-of-arithmetic-sequence-and-series","CONT_TITLE_AR":"Sum of Arithmetic Sequence and Series","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETo find the sum of all arithmetic sequences, we apply the formula for sum of n terms, Sn= (n\/2)(2a+(n-1000)d).\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the formula for the sum of \u0026#039;n\u0026#039; terms.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assess the application of the sum of \u0026#039;n\u0026#039; terms in the real world.\u003C\/div\u003E","CONT_DESC_AR":"To find the sum of all arithmetic sequences, we apply the formula for sum of n terms, Sn= n\/2(2a+(n-1)d).\u0026lt;br \/\u0026gt;\nLearn the application of the sum of (n) terms in the real world.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this topic you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the formula for the sum of n terms\u0026lt;br \/\u0026gt;\n\u0026amp;bull; assess the application of the sum of n terms in the real world","BACKING_FILE":"ss300043.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300043","TOPIC_ID":"ss300043","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300043.jpg","PUBLIC_BANNER_IMG":"SS300043.jpg","PUBLIC_VIDEO":"pvideo_ss300043.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/FBQUvWlgIWw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;To find the sum of all arithmetic sequences, we apply the formula for sum of n terms,\u0026amp;nbsp; S\u0026lt;span style=\u0026quot;font-size: 9.75px; line-height: 0; position: relative; vertical-align: baseline; bottom: -0.25em; color: rgb(0, 77, 64); font-family: \u0026amp;quot;Open Sans\u0026amp;quot;, \u0026amp;quot;Lucida Sans\u0026amp;quot;, sans-serif; text-align: justify;\u0026quot;\u0026gt;n\u0026lt;\/span\u0026gt;= (n\/2)(2a+(n-1)d).\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the formula for the sum of \u0026#039;n\u0026#039; terms.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assess the application of the sum of \u0026#039;n\u0026#039; terms in the real world.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Sum of Arithmetic sequence and series","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"187","CATEGORY_ID":"1","CONT_TITLE":"Median, Mode, Mean \u0026 Range","CONT_SLUG":"mean-mode-median-and-range-of-ungrouped-data","CONT_TITLE_AR":"Mean, Mode, Median, and Range of Ungrouped Data","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMean is defined as the average of a set of numbers that can be calculated by adding all the numbers and dividing the sum by the total number of terms. Median is defined as the middle value in a given set of numbers. To find the median, list all the numbers in increasing or decreasing order. The mode is the value that occurs most frequently in a given set of numbers. Range is the difference between the lowest and highest values in a given set of numbers.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the median of ungrouped data.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mode of ungrouped data.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mean of ungrouped data.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the range of ungrouped data.\u003C\/div\u003E","CONT_DESC_AR":"The mean is the average, where you add up all the numbers and then divide by the sum of numbers. The median is the middle value in this list of numbers. To find the median, \u0026amp;nbsp;numbers need to be listed in ascending or descending order.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this topic you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; know and identify the median of ungrouped data\u0026lt;br \/\u0026gt;\n\u0026amp;bull; know and identify the mode of ungrouped data\u0026lt;br \/\u0026gt;\n\u0026amp;bull; know and identify the mean of ungrouped data\u0026lt;br \/\u0026gt;\n\u0026amp;bull; know and identify the range of ungrouped data","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300031","TOPIC_ID":"ms300031","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300031.jpg","PUBLIC_BANNER_IMG":"MS300031.jpg","PUBLIC_VIDEO":"pvideo_ms300031.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/S2taGqPcih0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Mean is defined as the average of a set of numbers that can be calculated by adding all the numbers and dividing the sum by the total number of terms. Median is defined as the middle value in a given set of numbers. To find the median, list all the numbers in increasing or decreasing order. The mode is the value that occurs most frequently in a given set of numbers.\u0026amp;nbsp;Range is the difference between the lowest and highest values in a given set of numbers.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the median of ungrouped data.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the mode of ungrouped data.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the mean of ungrouped data.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the range of ungrouped data.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Mean, Mode, Median, and range of ungrouped data","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"183","CATEGORY_ID":"1","CONT_TITLE":"Introduction to Arithmetic Sequence","CONT_SLUG":"introduction-to-arithmetic-sequence-and-series","CONT_TITLE_AR":"Introduction to Arithmetic Sequence and Series","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn arithmetic sequence is a sequence in which the successive terms have common differences. With the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, an = a+(n-1)d. Arithmetic mean between two numbers is a+b\/2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic mean between a and b.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assess arithmetic sequence and series.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply a formula for arithmetic sequence and series.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the concept of arithmetic sequence and series.\u003C\/div\u003E","CONT_DESC_AR":"An arithmetic sequence is a sequence in which the successive terms have common differences.\u0026lt;br \/\u0026gt;\nWith the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, an = a+(n-1)d. Arithmetic mean between two numbers is a+b\/2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic mean between a and b.\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\nLearning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; assess arithmetic sequence and series\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply a formula for arithmetic sequence and series\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the concept of arithmetic sequence and series\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ss300002.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss300002","TOPIC_ID":"ss300002","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS300002.jpg","PUBLIC_BANNER_IMG":"ss300002.jpg","PUBLIC_VIDEO":"pvideo_ss300002.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/A8TSAmwj-ac","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;An arithmetic sequence is a sequence in which the successive terms have common differences. With the first term (a), common difference (d) and (n) number of terms, we can find the last term using the formula, a\u0026lt;span style=\u0026quot;font-size: 9.75px; line-height: 0; position: relative; vertical-align: baseline; bottom: -0.25em; color: rgb(0, 77, 64); font-family: \u0026amp;quot;Open Sans\u0026amp;quot;, \u0026amp;quot;Lucida Sans\u0026amp;quot;, sans-serif; text-align: justify;\u0026quot;\u0026gt;n\u0026lt;\/span\u0026gt;\u0026amp;nbsp;= a+(n-1)d. Arithmetic mean between two numbers is a+b\/2 and if the sequence is a, A1, A2, A3, A4, b then A1, A2, A3, A4 are four arithmetic mean between a and b.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assess arithmetic sequence and series.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply a formula for arithmetic sequence and series.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the concept of arithmetic sequence and series.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Introduction to Arithmetic sequence and series","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"182","CATEGORY_ID":"1","CONT_TITLE":"Pythagorean Theorem","CONT_SLUG":"pythagorean-theorem","CONT_TITLE_AR":"Pythagorean Theorem","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EPythagorean theorem states that the square of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the other two sides in a right triangle. By using this theorem, we can find the length of unknown side if any two side lengths are given.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the Pythagorean theorem.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Use the Pythagorean theorem to find the side lengths of a right triangle.\u003C\/div\u003E","CONT_DESC_AR":"Pythagoras theorem is a fundamental relationship in Euclidean geometry among the three sides of a right triangle.\u0026lt;br \/\u0026gt;\nIt states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define the Pythagorean theorem\u0026lt;br \/\u0026gt;\n\u0026amp;bull; use the Pythagorean theorem to find the lengths of the sides of right triangles\u0026lt;br \/\u0026gt;\n\u0026amp;bull; use the Pythagorean theorem to find the areas of right triangles\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the Pythagorean theorem to find the perimeter and area of triangles on a grid","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300029","TOPIC_ID":"ms300029","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300029.jpg","PUBLIC_BANNER_IMG":"ms300029.jpg","PUBLIC_VIDEO":"pvideo_ms300029.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/73FuqeMHDv4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Pythagorean theorem states that the square of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the other two sides in a right triangle. By using this theorem, we can find the length of unknown side if any two side lengths are given.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the Pythagorean theorem.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Use the Pythagorean theorem to find the side lengths of a right triangle.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Pythagorean Theorem","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"25","CATEGORY_ID":"1","CONT_TITLE":"Finding Square Root and Cube Root","CONT_SLUG":"finding-square-root-and-cube-root","CONT_TITLE_AR":"Finding Square root and Cube root","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe square root of a number is a value that, when multiplied by itself, gives the number. For 4 \u00d7 4 = 16, the square root of 16 will be 4. Similarly, the cube root of a number when used in a multiplication three times, gives that number. Example: 3 \u00d7 3 \u00d7 3 = 27, so the cube root of 27 is 3.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the square root.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Find the cube root.\u003C\/div\u003E","CONT_DESC_AR":"The square root of a number is a value that, when multiplied by itself, gives the number.\u0026lt;br \/\u0026gt;\nExample: 4 \u0026amp;times; 4 = 16, so the square root of 16 is 4.\u0026lt;br \/\u0026gt;\nSimilarly the cube root of a number is a special value that, when used in a multiplication three times, gives that number. Example: 3 \u0026amp;times; 3 \u0026amp;times; 3 = 27, so the cube root of 27 is 3.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n- identify the square root\u0026lt;br \/\u0026gt;\n- identify the properties of square root\u0026lt;br \/\u0026gt;\n- identify the cube root\u0026lt;br \/\u0026gt;\n- identify the properties of cube root\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"ms300084.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300084","TOPIC_ID":"ms300084","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300084.jpg","PUBLIC_BANNER_IMG":"MS300084.jpg","PUBLIC_VIDEO":"pvideo_ms300084.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5rGDhg1xAng","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;h3\u0026gt;Overview:\u0026lt;\/h3\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;The square root of a number is a value that, when multiplied by itself, gives the number. For 4 \u00d7 4 = 16, the square root of 16 will be 4. Similarly, the cube root of a number when used in a multiplication three times, gives that number. Example: 3 \u00d7 3 \u00d7 3 = 27, so the cube root of 27 is 3.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;h3\u0026gt;Learning Objectives:\u0026lt;\/h3\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Find the square root.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Find the cube root.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Finding Square root \u0026 cube root","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"},{"CONT_ID":"18","CATEGORY_ID":"1","CONT_TITLE":"Proportion","CONT_SLUG":"proportion","CONT_TITLE_AR":"Proportion","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EA proportion is defined as a notation used to represent that the two ratios are equal. It can be written in two ways: two equal fractions, or, using a colon, a:b = c:d.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explore and identify proportion.\u003C\/div\u003E","CONT_DESC_AR":"A proportion is a name we give to a statement that two ratios are equal.\u003C\/br\u003E\r\nIt can be written in two ways: two equal fractions, or, using a colon, a:b = c:d.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objective:\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\n- At the end of this simulation you will be able to explore and identify proportion.","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300060","TOPIC_ID":"ms300060","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300060.jpg","PUBLIC_BANNER_IMG":"ms300060.jpg","PUBLIC_VIDEO":"pvideo_ms300060.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/OIo9FigGb3A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-12 04:59:15","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;h3\u0026gt;Overview:\u0026lt;\/h3\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;A proportion is defined as a notation used to represent that the two ratios are equal. It can be written in two ways: two equal fractions, or, using a colon, a:b = c:d.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;h3\u0026gt;Learning Objectives:\u0026lt;\/h3\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explore and identify proportion.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Proportion","ADMSUBJECT_ID":"809","ADMCOURSE_ID":"216","DISPLAY_NAME":"Cambridge - Secondary - Stage - 9 - Mathematics","DISPLAY_NAME_AR":"Cambridge - Secondary - Stage - 9 - Mathematics","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","SUBJECT_DESC":"Mathematics","SUBJECT_DESC_AR":"Mathematics","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Secondary - Stage - 9","COUNTRY_ID":"296","SHORT_NAME":"Cambridge (IGCSE)","DOMAIN_NAME":"STEM"}],"levelObject":["Histogram","Bars","Frequency Table","Graphing Histogram","Class Intervals","Types Of Histograms"],"contData":{"CONT_ID":"556","CATEGORY_ID":"1","CONT_TITLE":"Histogram","CONT_SLUG":"histogram","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA histogram is a graph that is formed by using rectangles whose area is proportional to the frequency of a variable and whose width is equal to the class interval. It is similar to a bar graph. The only difference is that there is no gap in the class intervals or we can say, the intervals are continuous here.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a histogram.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the use of histograms in real life situations.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Interpret a histogram.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Create a histogram.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms300200.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms300200","TOPIC_ID":"ms300200","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS300200.jpg","PUBLIC_BANNER_IMG":"ms300200.jpg","PUBLIC_VIDEO":"pvideo_ms300200.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/moUWon8HrF0","DIST":"AF,AX,AL,DZ,AS,AD,AO,AI,AG,AR,AM,AW,AU,AT,AZ,BS,BH,BD,BB,BY,BE,BZ,BJ,BM,BT,BO,BQ,BA,BW,BR,IO,BN,BG,BF,BI,KH,CM,CA,KY,CF,TD,CL,CN,CX,CC,CO,KM,CG,CR,HR,CU,CW,CY,CZ,CD,DK,DJ,DM,DO,EC,EG,SV,GQ,ER,EE,ET,FK,FJ,FI,FR,GF,PF,GA,GM,GE,DE,GH,GI,GR,GL,GD,GP,GU,GT,GG,GN,GW,GY,HT,HN,HK,HU,IS,IN,ID,IR,IQ,IE,IM,IT,JM,JP,JE,JO,KZ,KE,KI,XK,KW,KG,LA,LV,LB,LS,LR,LY,LI,LT,LU,MO,MK,MG,MW,MY,MV,ML,MT,MH,MQ,MR,MU,YT,MX,FM,MD,MC,MN,ME,MS,MA,MZ,MM,NA,NR,NP,NL,NC,NZ,NI,NE,NG,NU,NF,KP,MP,NO,OM,PK,PW,PS,PA,PG,PY,PE,PH,PN,PL,PT,PR,QA,RE,RO,RU,RW,BL,SH,KN,LC,MF,PM,VC,WS,SM,ST,SA,SN,RS,SC,SL,SG,SX,SK,SI,SB,SO,ZA,GS,KR,SS,ES,LK,SD,SR,SJ,SZ,SE,CH,SY,TW,TJ,TZ,TH,TL,TG,TK,TO,TT,TN,TR,TM,TC,TV,UG,UA,AE,GB,US,UY,UZ,VU,VA,VE,VN,WF,YE,ZM,ZW","SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2017-10-06 05:40:39","CREATED_BY":"0","UPDATED_ON":"2024-10-08 08:51:16","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A histogram is a graph that is formed by using rectangles whose area is proportional to the frequency of a variable and whose width is equal to the class interval. It is similar to a bar graph. The only difference is that there is no gap in the class intervals or we can say, the intervals are continuous here.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Define a histogram.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the use of histograms in real life situations.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Interpret a histogram.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Create a histogram.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Histogram","DISPLAY_NAME":"NGSS New - Middle School - Mathematics","DISPLAY_NAME_AR":"NGSS New - Middle School - Mathematics","SUBJECT_IMG":"559.jpg","ADMSUBJECT_ID":"559","SUBJECT_NAME":"Mathematics","SUBJECT_NAME_AR":"Mathematics","ADMCOURSE_ID":"191","COURSE_NAME":"Middle School","COUNTRY_ID":"287","STANDARD_ID":"287","SHORT_NAME":"NGSS","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u4e2d\u6587","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Ti\u1ebfng Vi\u1ec7t"],"devices":["UmetyVR","WebXR"]}