{"pkgId":"30","subjectId":"1378","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":"Jordan Curriculum Full Access","PACKAGE_SLUG":"jordan-full","PACKAGE_IMG":"file_1402895481_1592480699.png","ADMCOURSE_ID":"393","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","STANDARD_NAME":"Jordan","ADMSUBJECT_ID":"1378","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","CAT_NAME":"\u0627\u0644\u0645\u062c\u0645\u0648\u0639\u0629 \u0627\u0644\u062b\u0627\u0646\u064a\u0629: \u0627\u0644\u0641\u0644\u0632\u0627\u062a \u0627\u0644\u0642\u0644\u0648\u064a\u0629 \u0627\u0644\u0623\u0631\u0636\u064a\u0629.","CONT_ID":"674","CONT_TITLE":"Group 2: Alkaline Earth Metals","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe elements in Group 2 of the periodic table are called the alkaline earth metals. These are harder and denser than alkali metals. 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Semiconductors, such as silicon, have conductivity between that of a conductor and an insulator. Electrical conductivity of a semiconductor increases with an increase in temperature. Semiconductors are found in many electronic devices.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the electrical conductivity of a semiconductor with that of a conductor and an insulator.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the effect of temperature on the conductivity of a semiconductor.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name common objects where semiconductors are used.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000027","TOPIC_ID":"vc000027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000027.jpg","PUBLIC_BANNER_IMG":"vc000027.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/S4OnmsYGcBw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Metals, are good conductors of electricity, while insulators, like diamond, do not conduct electricity, even when heated. Semiconductors, such as silicon, have conductivity between that of a conductor and an insulator. Electrical conductivity of a semiconductor increases with an increase in temperature. Semiconductors are found in many electronic devices.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Compare the electrical conductivity of a semiconductor with that of a conductor and an insulator.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify the effect of temperature on the conductivity of a semiconductor.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Name common objects where semiconductors are used.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0623\u0634\u0628\u0627\u0647 \u0627\u0644\u0645\u0648\u0635\u0644\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"662","CATEGORY_ID":"1","CONT_TITLE":"Group 1: Alkali Metals","CONT_SLUG":"group-1-alkali-metals","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe elements in Group 1 of the periodic table are called the alkali metals. They react with water to form alkaline solutions. These metals are more reactive than alkaline earth metals. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Locate the alkali metals in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and compare alkali metals based on their hardness and reactivity with water.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine the pH of the hydroxide solutions of alkali metals.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000017","TOPIC_ID":"vc000017","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000017.jpg","PUBLIC_BANNER_IMG":"vc000017.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000017.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/m2HCZ-UVDT0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;The elements in Group 1 of the periodic table are called the alkali metals. They react with water to form alkaline solutions. These metals are more reactive than alkaline earth metals.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Locate the alkali metals in the periodic table.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify and compare alkali metals based on their hardness and reactivity with water.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Determine the pH of the hydroxide solutions of alkali metals.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062c\u0645\u0648\u0639\u0629 1: \u0627\u0644\u0641\u0644\u0632\u0627\u062a \u0627\u0644\u0642\u0644\u0648\u064a\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"562","CATEGORY_ID":"1","CONT_TITLE":"Soaps and Detergents","CONT_SLUG":"soaps-and-detergents","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESoaps and detergents are artificial cleansers having cleansing action in water. Their molecules consist of long hydrocarbon chains with one polar end. In this example, when a dirty cloth is soaked in water containing soap\/detergent, the molecules of soap\/detergent gather around the stain and an aggregated particle, called micelle, is formed with oil trapped inside it.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of a soap and a detergent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the cleansing action of soaps and detergents.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the cleaning capacity of soaps and detergents in hard water.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200165","TOPIC_ID":"ss200165","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200165.jpg","PUBLIC_BANNER_IMG":"SS200165.jpg","PUBLIC_VIDEO":"pvideo_ss200165.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1F0sBfrovSE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Soaps and detergents are artificial cleansers having cleansing action in water. Their molecules consist of long hydrocarbon chains with one polar end. In this example, when a dirty cloth is soaked in water containing soap\/detergent, the molecules of soap\/detergent gather around the stain and an aggregated particle, called micelle, is formed with oil trapped inside it.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure of a soap and a detergent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the cleansing action of soaps and detergents.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare the cleaning capacity of soaps and detergents in hard water.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0635\u0627\u0628\u0648\u0646 \u0648\u0627\u0644\u0645\u0646\u0638\u0641\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"507","CATEGORY_ID":"1","CONT_TITLE":"Liquids","CONT_SLUG":"liquids","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELiquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the intermolecular spaces between particles of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between particles of liquids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200425.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200425","TOPIC_ID":"ms200425","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200425.jpg","PUBLIC_BANNER_IMG":"MS200425.jpg","PUBLIC_VIDEO":"pvideo_ms200425.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xm78b3sjxbI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Liquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the intermolecular spaces between particles of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between particles of liquids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0648\u0627\u0626\u0639","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"503","CATEGORY_ID":"1","CONT_TITLE":"Nucleic Acids","CONT_SLUG":"nucleic-acid","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ENucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. Nucleic acid is made up of nucleotides. A nucleotide consists of a sugar, phosphate and nitrogenous base.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what a nucleic acid is.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of a nucleotide.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the different components of RNA and DNA.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a nucleic acid.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200408","TOPIC_ID":"hs200408","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200408.jpg","PUBLIC_BANNER_IMG":"HS200408.jpg","PUBLIC_VIDEO":"pvideo_hs200408.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/L5hwt0XTjzc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Nucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. Nucleic acid is made up of nucleotides. A nucleotide consists of a sugar, phosphate and nitrogenous base.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what a nucleic acid is.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure of a nucleotide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the different components of RNA and DNA.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct a nucleic acid.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062d\u0645\u0636 \u0627\u0644\u0646\u0648\u0648\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"501","CATEGORY_ID":"1","CONT_TITLE":"Naming Hydrocarbons","CONT_SLUG":"naming-hydrocarbons","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EChemical compounds were named as per IUPAC nomenclature in order to avoid duplicate names. IUPAC nomenclature has one set of standardized rules. According to IUPAC system, the IUPAC name of an organic compound may consist of 5 parts that is: \u201cSecondary prefix + Primary prefix + Word root + Primary suffix + Secondary suffix\u201d.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the different parts of the IUPAC name of an organic compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name straight chain hydrocarbons according to the IUPAC guidelines.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Name branched hydrocarbons according to the IUPAC guidelines.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200402","TOPIC_ID":"hs200402","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200402.jpg","PUBLIC_BANNER_IMG":"HS200402.jpg","PUBLIC_VIDEO":"pvideo_hs200402.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/7DPsmbPvpUw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Chemical compounds were named as per IUPAC nomenclature in order to avoid duplicate names. IUPAC nomenclature has one set of standardized rules. According to IUPAC system, the IUPAC name of an organic compound may consist of 5 parts that is: \u201cSecondary prefix + Primary prefix + Word root + Primary suffix + Secondary suffix\u201d.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning Objectives:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the different parts of the IUPAC name of an organic compound.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Name straight chain hydrocarbons according to the IUPAC guidelines.\u0026lt;\/div\u0026gt;- Name branched hydrocarbons according to the IUPAC guidelines.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0633\u0645\u064a\u0629 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u0643\u0631\u0628\u0648\u0646\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"497","CATEGORY_ID":"1","CONT_TITLE":"Physical Changes","CONT_SLUG":"physical-changes","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA physical change is characterized by signs such as: a change in the state of matter, a change in shape and size of the matter, etc. In this type of change, however, the substance remains intact.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the signs of physical changes.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a change is physical or not.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200367","TOPIC_ID":"ms200367","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200367.jpg","PUBLIC_BANNER_IMG":"MS200367.jpg","PUBLIC_VIDEO":"pvideo_ms200367.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/yZRhkU5sZwI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A physical change is characterized by signs such as: a change in the state of matter, a change in shape and size of the matter, etc. In this type of change, however, the substance remains intact.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the signs of physical changes.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a change is physical or not.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u063a\u064a\u0631\u0627\u062a \u0627\u0644\u0641\u064a\u0632\u064a\u0627\u0626\u064a\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"496","CATEGORY_ID":"1","CONT_TITLE":"Testing for Carbon Compounds","CONT_SLUG":"testing-for-carbon-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMost of the food items consumed by us come from living beings and contain carbon compounds such as protein, carbohydrates and lipids. The presence of carbohydrates (starch) in a food sample can be detected using Lugol\u2019s solution as indicator whereas the presence of proteins in a food sample can be detected using Biuret solution as indicator. On the other hand, the presence of lipids in a food sample can be detected using Sudan red solution as indicator.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of Lugol\u2019s test for carbohydrates. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of Biuret test for proteins. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of Sudan red test for lipids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Test for the presence of carbohydrates, proteins and lipids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200335.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200335","TOPIC_ID":"hs200335","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200335.jpg","PUBLIC_BANNER_IMG":"HS200335.jpg","PUBLIC_VIDEO":"pvideo_hs200335.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/M7EHLj525Zs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Most of the food items consumed by us come from living beings and contain carbon compounds such as protein, carbohydrates and lipids. The presence of carbohydrates (starch) in a food sample can be detected using Lugol\u2019s solution as indicator whereas the presence of proteins in a food sample can be detected using Biuret solution as indicator. On the other hand, the presence of lipids in a food sample can be detected using Sudan red solution as indicator.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the process of Lugol\u2019s test for carbohydrates.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe the process of Biuret test for proteins.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the process of Sudan red test for lipids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Test for the presence of carbohydrates, proteins and lipids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0643\u0634\u0641 \u0639\u0646 \u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0643\u0631\u0628\u0648\u0646","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"494","CATEGORY_ID":"1","CONT_TITLE":"Like Dissolves Like","CONT_SLUG":"like-dissolves-like","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EPolar solutes tend to dissolve in polar solvents; nonpolar solutes tend to dissolve in nonpolar solvents. However, the dissolving nature also depends on the charge of the ions in the solution. Non-polar substances have Van der Waals attractions which are weak but present.\u003C\/div\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify water as a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify ethanol as a polar solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify sodium chloride as an ionic solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify hexane as a nonpolar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify pentane as a nonpolar solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a polar solute in a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving an ionic solute in a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200323.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200323","TOPIC_ID":"hs200323","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200323.jpg","PUBLIC_BANNER_IMG":"HS200323.jpg","PUBLIC_VIDEO":"pvideo_hs200323.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hLIZIr9usZ0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Polar solutes tend to dissolve in polar solvents; nonpolar solutes tend to dissolve in nonpolar solvents. However, the dissolving nature also depends on the charge of the ions in the solution.\u0026amp;nbsp;\u0026lt;span style=\u0026quot;color: rgb(38, 50, 56); font-family: Roboto, sans-serif;\u0026quot;\u0026gt;Non-polar substances have Van der Waals attractions which are weak but present.\u0026lt;\/span\u0026gt;\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify water as a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify ethanol as a polar solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify sodium chloride as an ionic solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify hexane as a nonpolar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify pentane as a nonpolar solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving a polar solute in a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving an ionic solute in a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062b\u0644 \u064a\u0630\u064a\u0628 \u0627\u0644\u0645\u062b\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"492","CATEGORY_ID":"1","CONT_TITLE":"Covalent Compounds","CONT_SLUG":"covalent-compounds","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA covalent compound is made when two or more nonmetal atoms bond by sharing valence electrons. Covalent compounds have low boiling point, melting point and thermal conductivity. They are insoluble in water and do not conduct electricity.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify what are covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Observe the boiling points of the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Examine the solubility of the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the flame test for the covalent compounds. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the thermal conductivity of the covalent compounds.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200312.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200312","TOPIC_ID":"ms200312","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200312.jpg","PUBLIC_BANNER_IMG":"MS200312.jpg","PUBLIC_VIDEO":"pvideo_ms200312.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/63RXNIt5vA8","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A covalent compound is made when two or more nonmetal atoms bond by sharing valence electrons. Covalent compounds have low boiling point, melting point and thermal conductivity. They are insoluble in water and\u0026amp;nbsp; do not conduct electricity.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026amp;nbsp;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify what are covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Observe the boiling points of the covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Examine the solubility of the covalent compounds.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the flame test for the covalent compounds. \u0026lt;br\u0026gt;\u0026amp;nbsp;- Demonstrate the thermal conductivity of the covalent compounds.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u062a\u0633\u0627\u0647\u0645\u064a\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"491","CATEGORY_ID":"1","CONT_TITLE":"Stable and Unstable Atoms","CONT_SLUG":"stable-and-unstable-atoms","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAtoms become chemically stable by losing or gaining to fill up their outermost electron shell to a configuration nearest to that of a noble gas. Atoms which attain noble gas configuration are non reactive in nature and are called stable atoms. Atoms which do not attain noble gas configuration are reactive in nature and are called unstable atoms.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the conditions for an atom to be stable.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe how an atom can be made stable or unstable.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify stable and unstable atoms.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200310","TOPIC_ID":"hs200310","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200310.jpg","PUBLIC_BANNER_IMG":"HS200310.jpg","PUBLIC_VIDEO":"pvideo_hs200310.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1B18nNgKKDc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Atoms become chemically stable by losing or gaining to fill up their outermost electron shell to a configuration nearest to that of a noble gas. Atoms which attain noble gas configuration are non reactive in nature and are called stable atoms. Atoms which do not attain noble gas configuration are reactive in nature and are called unstable atoms.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the conditions for an atom to be stable.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe how an atom can be made stable or unstable.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify stable and unstable atoms.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0630\u0631\u0627\u062a \u0627\u0644\u0645\u0633\u062a\u0642\u0631\u0629 \u0648\u063a\u064a\u0631 \u0627\u0644\u0645\u0633\u062a\u0642\u0631\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"488","CATEGORY_ID":"1","CONT_TITLE":"Phase Change: Sublimation","CONT_SLUG":"phase-change-sublimation","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe process in which a solid directly changes its state to gas without undergoing the liquid phase is called sublimation. Examples of substances that undergo sublimation are camphor, naphthalene etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define sublimation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of sublimation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify substances that undergo sublimation.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200286.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200286","TOPIC_ID":"ms200286","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200286.jpg","PUBLIC_BANNER_IMG":"MS200286.jpg","PUBLIC_VIDEO":"pvideo_ms200286.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/X1wc5E1F-ic","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The process in which a solid\u0026amp;nbsp; directly changes its state to gas without undergoing the liquid phase is called sublimation. Examples of substances that undergo sublimation are camphor, naphthalene etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define sublimation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of sublimation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify substances that undergo sublimation.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u063a\u064a\u0631 \u062d\u0627\u0644\u0629 \u0627\u0644\u0645\u0627\u062f\u0629: \u0627\u0644\u062a\u0633\u0627\u0645\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"487","CATEGORY_ID":"1","CONT_TITLE":"Phase Changes: Boiling, Evaporation and Condensation","CONT_SLUG":"phase-change-boiling-evaporation-and-condensation","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe change in state of liquid into gas is called vaporization. The process in which the vaporization occurs from the surface of a liquid is called evaporation. Whereas the process in which vaporization occurs within the surface of the liquid is called boiling. The change in state of gas into liquid is called condensation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define evaporation, boiling and condensation. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how liquid state and gaseous state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200285.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200285","TOPIC_ID":"ms200285","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200285.jpg","PUBLIC_BANNER_IMG":"MS200285.jpg","PUBLIC_VIDEO":"pvideo_ms200285.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/B6ArYhP2pRY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The change in state of liquid into gas is called vaporization. The process in which the vaporization occurs from the surface of\u0026amp;nbsp; a liquid is called evaporation. Whereas the process in which vaporization occurs within the surface of the liquid is called boiling. The change in state of gas into liquid is called condensation.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define evaporation, boiling and condensation.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain how liquid state and gaseous state of matter can be interchanged.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u063a\u064a\u0631 \u062d\u0627\u0644\u0629 \u0627\u0644\u0645\u0627\u062f\u0629: \u0627\u0644\u063a\u0644\u064a\u0627\u0646\u060c \u0627\u0644\u062a\u0628\u062e\u0631\u060c \u0627\u0644\u062a\u0643\u062b\u0641","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"486","CATEGORY_ID":"1","CONT_TITLE":"Properties of Gases","CONT_SLUG":"properties-of-gases","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGases do not have definite shape and volume. They attain the shape and volume of the container. Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate that gases do not have definite shape and volume.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Explain that gases occupy the whole space available to them. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe that gases have unlimited diffusibility. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that gases have high compressibility.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200283.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200283","TOPIC_ID":"ms200283","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200283.jpg","PUBLIC_BANNER_IMG":"MS200283.jpg","PUBLIC_VIDEO":"pvideo_ms200283.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/n4tYu4qJMsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Gases do not have definite shape and volume. They attain the shape and volume of the container.\u0026amp;nbsp; Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Illustrate that gases do not have definite shape and volume.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases occupy the whole space available to them.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe that gases have unlimited diffusibility.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases have high compressibility.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0635\u0627\u0626\u0635 \u0627\u0644\u063a\u0627\u0632\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"485","CATEGORY_ID":"1","CONT_TITLE":"Properties of Liquids-Viscosity","CONT_SLUG":"properties-of-liquids-viscosity","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDifferent solutions have different fluidity. The liquid which flows slowly is known to have higher viscosity. The term, viscosity means resistance to flow. It decreases as the liquid becomes warmer. Thus, it can be said that viscosity is temperature dependent.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define viscosity.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare and describe the order of viscosities of different solutions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Complete an experiment to show the effect of temperature on viscosity.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200281","TOPIC_ID":"ss200281","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200281.jpg","PUBLIC_BANNER_IMG":"SS200281.jpg","PUBLIC_VIDEO":"pvideo_ss200281.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/aeAntU_QRps","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Different solutions have different fluidity. The liquid which flows slowly is known to have higher viscosity. The term, viscosity means resistance to flow. It decreases as the liquid becomes warmer. Thus, it can be\u0026amp;nbsp; said that viscosity is temperature dependent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Define viscosity.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Compare and describe the order of viscosities of different solutions.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Complete an experiment to show the effect of temperature on viscosity\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0635\u0627\u0626\u0635 \u0627\u0644\u0633\u0648\u0627\u0626\u0644: \u0627\u0644\u0644\u0632\u0648\u062c\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"482","CATEGORY_ID":"1","CONT_TITLE":"Inhibitors","CONT_SLUG":"inhibitors","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAt times, it is required to prevent certain chemical reactions from occurring. In such cases inhibitors are used to slow down or even stop a chemical reaction. Inhibitors are used in food industry to slow down or inhibit food spoilage.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define an inhibitor.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of an inhibitor on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the use of an inhibitor as a food preservative to slow down or inhibit the reaction that leads to the food item spoiling.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200264.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200264","TOPIC_ID":"ms200264","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200264.jpg","PUBLIC_BANNER_IMG":"MS200264.jpg","PUBLIC_VIDEO":"pvideo_ms200264.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J7nB_OJx5XE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;At times, it is required to prevent certain chemical reactions from occurring. In such cases inhibitors are used to slow down or even stop a chemical reaction. Inhibitors are used in food industry to slow down or inhibit food spoilage.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define an inhibitor.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the effect of an inhibitor on the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the use of an inhibitor as a food preservative to slow down or inhibit the reaction that leads to the food item spoiling.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062b\u0628\u0637\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"383","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Using Evaporation","CONT_SLUG":"separating-mixtures-using-evaporation","CONT_TITLE_AR":"Separating Mixtures: Using Evaporation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the evaporation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solutions that can be separated using the evaporation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\n\u0026lt;ol\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;explain the process of evaporation method of separation\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;identify solutions that can be separated using evaporation method of separation\u0026lt;\/li\u0026gt;\n\u0026lt;\/ol\u0026gt;\n","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200064","TOPIC_ID":"ms200064","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200064.jpg","PUBLIC_BANNER_IMG":"MS200064.jpg","PUBLIC_VIDEO":"pvideo_ms200064.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XT6vdYq4BaA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of the evaporation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify solutions that can be separated using the evaporation method of separation.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0641\u0635\u0644 \u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u0628\u0627\u0633\u062a\u062e\u062f\u0627\u0645 \u0627\u0644\u062a\u0628\u062e\u064a\u0631","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"372","CATEGORY_ID":"1","CONT_TITLE":"Application of VSEPR Theory","CONT_SLUG":"application-of-vsepr-theory","CONT_TITLE_AR":"Application of VSEPR Theory","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence shell electron pair repulsion (VSEPR) theory is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply VSEPR theory to predict the three-dimensional shapes of molecules.\u003C\/div\u003E","CONT_DESC_AR":"Valence shell electron pair repulsion (VSEPR)\u0026amp;nbsp;theory\u0026amp;nbsp;is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n- construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- apply VSEPR theory to predict the three-dimensional shapes of molecules","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200035","TOPIC_ID":"ss200035","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200035.jpg","PUBLIC_BANNER_IMG":"SS200035.jpg","PUBLIC_VIDEO":"pvideo_ss200035.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/gR_7S2Lk39g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Valence shell electron pair repulsion (VSEPR) theory is used in chemistry to predict the three-dimensional shapes of molecules from the number of electron pairs surrounding their central atoms. Molecules can have linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal or pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct molecules having linear, trigonal planar, bent, tetrahedral, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal and pentagonal bipyramidal geometries.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply VSEPR theory to predict the three-dimensional shapes of molecules.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0637\u0628\u064a\u0642\u0627\u062a \u0646\u0638\u0631\u064a\u0629 \u0641\u064a\u0633\u0628\u0631","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"371","CATEGORY_ID":"1","CONT_TITLE":"VSEPR Theory","CONT_SLUG":"vsepr-theory","CONT_TITLE_AR":"VSEPR Theory","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \u003Cdiv\u003E  \u003Cbr\u003E \u003C\/div\u003E \u003Cdiv\u003EValence shell electron pair repulsion (VSEPR) theory suggests that the electron pairs surrounding the central atom repel each other and tend to occupy such positions around the central atom that minimize this repulsion. According to this theory, the geometry of a molecule depends upon the total number of electron pairs present around the central atom.\u003C\/div\u003E \u003Cdiv\u003E  \u003Cbr\u003E \u003C\/div\u003E \u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \u003Cdiv\u003E  \u003Cbr\u003E \u003C\/div\u003E \u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \u003Cdiv\u003E- Explain valence shell electron pair repulsion (VSEPR) theory.\u003C\/div\u003E \u003Cdiv\u003E- Predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms.\u003C\/div\u003E","CONT_DESC_AR":"According to valence shell electron pair repulsion (VSEPR) theory, the valence electron pairs surrounding an atom mutually repel each other. They adopt an arrangement that minimizes this repulsion, thus determining its molecular geometry. This means that bonding and non-bonding electrons will repel each other as far away as geometrically possible. The number of atoms bonded to a central atom combined with the number of pairs of its non-bonding valence electrons is called its steric number.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain Valence shell electron pair repulsion (VSEPR) theory\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200034","TOPIC_ID":"ss200034","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200034.jpg","PUBLIC_BANNER_IMG":"SS200034.jpg","PUBLIC_VIDEO":"pvideo_ss200034.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RVz4Vp1j4nQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Valence shell electron pair repulsion (VSEPR) theory suggests that the electron pairs surrounding the central atom repel each other and tend to occupy such positions around the central atom that minimize this repulsion. According to this theory, the geometry of a molecule depends upon the total number of electron pairs present around the central atom.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-weight: bold;\u0026quot;\u0026gt;Learning Objectives:\u0026lt;\/span\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain valence shell electron pair repulsion (VSEPR) theory.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the geometry of individual molecules from the number of electron pairs surrounding their central atoms.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0646\u0638\u0631\u064a\u0629 \u0641\u064a\u0633\u0628\u0631","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"366","CATEGORY_ID":"1","CONT_TITLE":"Dissolving Solids in Liquids","CONT_SLUG":"dissolving-solids-in-liquids","CONT_TITLE_AR":"Dissolving Solids in Liquids","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESolids that are soluble in a particular liquid when dissolved in that liquid, form a homogenous solution. Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid solutes dissolve in liquid solvents.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the change in the properties of solids when dissolved in liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solids that can be dissolved in water.\u003C\/div\u003E","CONT_DESC_AR":"Solids that are soluble in a particular liquid when dissolved form homogenous solution. Solids that are insoluble in a particular liquid when dissolved form heterogenous solution.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how solid solute disolves in liquid solvents\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the change in the properties of solids when dissolved in liquids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify solids that can be dissolved into water","BACKING_FILE":"hs200079.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200079","TOPIC_ID":"hs200079","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200079.jpg","PUBLIC_BANNER_IMG":"hs200079.jpg","PUBLIC_VIDEO":"pvideo_hs200079.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/nGvKBRfZJXk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Solids that are soluble in a particular liquid when dissolved in that liquid, form a homogenous solution. Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how solid solutes dissolve in liquid solvents.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the change in the properties of solids when dissolved in liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify solids that can be dissolved in water.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0630\u0648\u0628\u0627\u0646 \u0627\u0644\u0645\u0648\u0627\u062f \u0627\u0644\u0635\u0644\u0628\u0629 \u0641\u064a \u0627\u0644\u0633\u0648\u0627\u0626\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"357","CATEGORY_ID":"1","CONT_TITLE":"Methods of Separation","CONT_SLUG":"methods-of-separation","CONT_TITLE_AR":"Methods of Separation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u003C\/div\u003E","CONT_DESC_AR":"Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the separation of ammonium chloride from a mixture of sodium chloride-ammonium chloride by sublimation method\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the separation of acetone from acetone-water solution by distillation method","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200076","TOPIC_ID":"ms200076","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200076.jpg","PUBLIC_BANNER_IMG":"MS200076.jpg","PUBLIC_VIDEO":"pvideo_ms200076.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XFqLqtNsjDQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sublimation is the process in which a solid directly changes to a gaseous state. This solid, which directly changes to a gaseous state, is called a sublimable solid. One example is solid ammonium chloride. We can separate ammonium chloride from a mixture of sodium chloride-ammonium chloride, using this method. The distillation method is best for separating a liquid from a solution. Acetone can be separated from an acetone-water solution using this method.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;- Describe the process of the separation of acetone from an acetone and water solution using the distillation method.\u0026lt;\/div\u0026gt;- Explain the process of the separation of ammonium chloride from a mixture of sodium chloride and ammonium chloride using the sublimation method.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0637\u0631\u0642 \u0627\u0644\u0641\u0635\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"354","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Sedimentation and Decantation","CONT_SLUG":"sedimentation-and-decantation","CONT_TITLE_AR":"Sedimentation and Decantation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation follows sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the sedimentation and decantation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated using the sedimentation and decantation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"Sedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation is followed by sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the process of the sedimentation method of separation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the process of the decantation method of separation\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify mixtures that can be separated using the sedimentation and decantation method of separation","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200065","TOPIC_ID":"ms200065","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200065.jpg","PUBLIC_BANNER_IMG":"MS200065.jpg","PUBLIC_VIDEO":"pvideo_ms200065.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/QR2JTdtNtcQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Sedimentation and decantation methods are used for the separation of insoluble substances which are heavier than liquid. In the sedimentation process, heavier components of the mixture settle on the bottom, due to gravity. Decantation follows sedimentation. The decantation process involves pouring clear, upper liquid out of the container, without disturbing the sediment.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of the sedimentation and decantation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated using the sedimentation and decantation method of separation.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0635\u0628 \u0648\u0627\u0644\u062a\u0631\u0633\u064a\u0628","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"333","CATEGORY_ID":"1","CONT_TITLE":"pH Indicators","CONT_SLUG":"ph-indicators","CONT_TITLE_AR":"pH indicators","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA pH indicator is a halochromic substance that changes color with a change in the pH of a solution. Hence, a pH indicator detects a change in concentration of hydronium ion during a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the change in color of pH indicators at different pH values.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Select an appropriate pH indicator to identify a solution as acidic, basic, or neutral.\u003C\/div\u003E","CONT_DESC_AR":"A pH indicator is a halochromic substance that changes color with a change in the pH of a solution. Hence a pH indicator detects a change concentration of hydronium ion during a chemical reaction.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify colour change of an indicator at different pH values\u0026lt;br \/\u0026gt;\n\u0026amp;bull; select an appropriate pH indicator that can be used to identify a solution as acidic, basic or neutral","BACKING_FILE":"ms200068.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200068","TOPIC_ID":"ms200068","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200068.jpg","PUBLIC_BANNER_IMG":"MS200068.jpg","PUBLIC_VIDEO":"pvideo_ms200068.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/QKXjIrQuCYU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A pH indicator is a halochromic substance that changes color with a change in the pH of a solution. Hence, a pH indicator detects a change in concentration of hydronium ion during a chemical reaction.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the change in color of pH indicators at different pH values.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Select an appropriate pH indicator to identify a solution as acidic, basic, or neutral.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0643\u0648\u0627\u0634\u0641 \u0627\u0644\u0623\u0633 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u062c\u064a\u0646\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"279","CATEGORY_ID":"1","CONT_TITLE":"Structure of Phenol","CONT_SLUG":"structure-of-phenol","CONT_TITLE_AR":"Structure of Phenol","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn phenol, hydroxy functional group is directly attached to the sp2 hybridized carbon atom of the benzene ring. The interaction of six unhybridized 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalized pi-electron clouds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in phenol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the phenol molecule using its electrostatic potential map.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of phenol.\u003C\/div\u003E","CONT_DESC_AR":"In phenol hydroxy functional group is directly attached to the sp2 hybridised carbon atom of the benzene ring. The interaction of six unhybridised 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalised pi-electron clouds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify functional groups present in phenol\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the phenol molecule using an electrostatic potential map\u0026lt;br \/\u0026gt;\n- explain the orbital structure of phenol","BACKING_FILE":"ss200049.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200049","TOPIC_ID":"ss200049","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200049.jpg","PUBLIC_BANNER_IMG":"ss200049.jpg","PUBLIC_VIDEO":"pvideo_ss200049.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/y_oKx7y2T7o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In phenol, hydroxy functional group is directly attached to the sp2 hybridized carbon atom of the benzene ring. The interaction of six unhybridized 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalized pi-electron clouds.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the functional group present in phenol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the charge distribution of the phenol molecule using its electrostatic potential map.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the orbital structure of phenol.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0641\u064a\u0646\u0648\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"270","CATEGORY_ID":"1","CONT_TITLE":"Boyle\u2019s Law","CONT_SLUG":"boyles-law","CONT_TITLE_AR":"Boyle\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0628\u0648\u064a\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"268","CATEGORY_ID":"1","CONT_TITLE":"Charles\u2019s Law","CONT_SLUG":"charles-law","CONT_TITLE_AR":"Charles\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECharles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the temperature and volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate Charles\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Charles\u0026#039;s law in practical problems.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0634\u0627\u0631\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"264","CATEGORY_ID":"1","CONT_TITLE":"Organic Functional Groups","CONT_SLUG":"organic-functional-groups","CONT_TITLE_AR":"Organic Functional Groups","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA functional group is an atom or group of atoms present in a molecule that largely determines its chemical properties. All compounds containing the same functional group display similar chemical reactions and belong to the same class of organic compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define functional groups.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify various functional groups present in organic compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive organic compounds containing functional groups from their parent hydrocarbons.\u003C\/div\u003E","CONT_DESC_AR":"A functional group is an atom or group of atoms present in a molecule that largely determines its chemical properties. All compounds containing the same functional group display similar chemical reactions and belong to the same class of organic compounds.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define functional groups\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify various functional groups present in organic compounds\u0026lt;br \/\u0026gt;\n\u0026amp;bull; derive organic compounds containing functional groups from their parent hydrocarbons","BACKING_FILE":"ss200044.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200044","TOPIC_ID":"ss200044","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200044.jpg","PUBLIC_BANNER_IMG":"SS200044.jpg","PUBLIC_VIDEO":"pvideo_ss200044.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/iW10_wefWYQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A functional group is an atom or group of atoms present in a molecule that largely determines its chemical properties. All compounds containing the same functional group display similar chemical reactions and belong to the same class of organic compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define functional groups.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify various functional groups present in organic compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive organic compounds containing functional groups from their parent hydrocarbons.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062c\u0645\u0648\u0639\u0627\u062a \u0627\u0644\u0648\u0638\u064a\u0641\u064a\u0629 \u0627\u0644\u0639\u0636\u0648\u064a\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"255","CATEGORY_ID":"1","CONT_TITLE":"Structure of Diamond","CONT_SLUG":"structure-of-diamond","CONT_TITLE_AR":"Structure of Diamond","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EDiamond is a covalent solid in which the carbon atoms are linked together by covalent bonds to give a three dimensional structure. Due to the presence of a strong network of covalent bonds, diamond is very hard and possesses an extremely high melting point.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the three dimensional structure of a diamond.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize the type of hybridization of the carbon atoms in a diamond.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the physical properties of a diamond.\u003C\/div\u003E","CONT_DESC_AR":"Diamond is a covalent solid in which the carbon atoms are linked together by covalent bonds to give a three dimensional structure. Due to the presence of a strong network of covalent bonds, diamond is very hard and possesses an extremely high melting point.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the three dimensional structure of a diamond\u0026lt;br \/\u0026gt;\n\u0026amp;bull; recognize the type of hybridization of the carbon atoms in a diamond\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the physical properties of a diamond","BACKING_FILE":"ss200073.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200073","TOPIC_ID":"ss200073","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200073.jpg","PUBLIC_BANNER_IMG":"SS200073.jpg","PUBLIC_VIDEO":"pvideo_ss200073.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Cnz1zrnl_2U","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Diamond is a covalent solid in which the carbon atoms are linked together by covalent bonds to give a three dimensional structure. Due to the presence of a strong network of covalent bonds, diamond is very hard and possesses an extremely high melting point.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the three dimensional structure of a diamond.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Recognize the type of hybridization of the carbon atoms in a diamond.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the physical properties of a diamond.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0623\u0644\u0645\u0627\u0633","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"253","CATEGORY_ID":"1","CONT_TITLE":"Buckyballs","CONT_SLUG":"buckyballs","CONT_TITLE_AR":"Buckyballs","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBuckyball is an allotrope of carbon containing 60 carbon atoms joined together to form a spherical structure. The structure of buckyball is similar to that of a football as it also contains hexagonal and pentagonal rings.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the structure of a buckyball, containing 60 carbon atoms.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the hexagonal and pentagonal rings present in the spherical structure of a buckyball.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of a buckyball.\u003C\/div\u003E","CONT_DESC_AR":"Buckyball is an allotrope of carbon containing 60 carbon atoms joined together to form a spherical structure. The structure of buckyball is similar to that of a football as it also contains hexagonal and pentagonal rings.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the structure of a buckyball, containing 60 carbon atoms\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the hexagonal and pentagonal rings present in the spherical structure of a buckyball\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of a buckyball","BACKING_FILE":"ss200056.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200056","TOPIC_ID":"ss200056","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200056.jpg","PUBLIC_BANNER_IMG":"SS200056.jpg","PUBLIC_VIDEO":"pvideo_ss200056.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EAci6nWM9Q0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Buckyball is an allotrope of carbon containing 60 carbon atoms joined together to form a spherical structure. The structure of buckyball is similar to that of a football as it also contains hexagonal and pentagonal rings.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the structure of a buckyball, containing 60 carbon atoms.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the hexagonal and pentagonal rings present in the spherical structure of a buckyball.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of a buckyball.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0643\u0631\u0627\u062a \u0628\u0627\u0643\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"250","CATEGORY_ID":"1","CONT_TITLE":"The Structure of Graphite","CONT_SLUG":"structure-of-graphite","CONT_TITLE_AR":"Structure of Graphite","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGraphite is a crystalline allotrope of carbon. The crystalline structure of graphite consists of layers or sheets of carbon atoms. In these layers, each carbon atom is joined to three other carbon atoms by strong covalent bonds to form hexagonal rings. Various graphite layers are held together by weak Van der Waals forces.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the layered structure of graphite.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the physical properties of graphite.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize the hybridization of carbon atoms in graphite.\u003C\/div\u003E","CONT_DESC_AR":"Crystal of graphite consists of layers or sheets of carbon atoms. In these layers, each carbon atom is joined to three other carbon atoms by strong covalent bonds to form hexagonal rings. Various graphite layers are held together by weak Van der Walls forces.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the layered structure of graphite\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the physical properties of graphite\u0026lt;br \/\u0026gt;\n\u0026amp;bull; recognize the hybridization of carbon atoms in graphite","BACKING_FILE":"ss200048.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200048","TOPIC_ID":"ss200048","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200048.jpg","PUBLIC_BANNER_IMG":"SS200048.jpg","PUBLIC_VIDEO":"pvideo_ss200048.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/gq2NqZsYfUs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Graphite is a crystalline allotrope of carbon. The crystalline structure of graphite consists of layers or sheets of carbon atoms. In these layers, each carbon atom is joined to three other carbon atoms by strong covalent bonds to form hexagonal rings. Various graphite layers are held together by weak Van der Waals forces.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the layered structure of graphite.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the physical properties of graphite.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Recognize the hybridization of carbon atoms in graphite.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u062c\u0631\u0627\u0641\u064a\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"247","CATEGORY_ID":"1","CONT_TITLE":"Allotropes of Carbon","CONT_SLUG":"allotropes-of-carbon","CONT_TITLE_AR":"Allotropes of Carbon","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe element carbon can exist in different physical forms called the allotropes of carbon. Three examples of carbon allotropes are: diamond, graphite, and buckyball. The physical properties of these allotropes are quite different due to the different arrangements of carbon atoms in their crystals.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify various allotropes of carbon.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the different arrangements of the carbon atoms in diamond, graphite, and buckyball.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the physical properties of diamond, graphite, and buckyball.\u003C\/div\u003E","CONT_DESC_AR":"The element carbon exists in three physical forms called the allotropes of carbon. Diamond, graphite and buckyball are the three allotropes of carbon. The physical properties of these allotropes are quite different due to the different arrangements of carbon atoms in their crystals.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the three allotropes of carbon\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain different arrangements of carbon atoms in diamond, graphite and buckyball\u0026lt;br \/\u0026gt;\n\u0026amp;bull; compare the physical properties of diamond, graphite and buckyball","BACKING_FILE":"ss200047.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200047","TOPIC_ID":"ss200047","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200047.jpg","PUBLIC_BANNER_IMG":"SS200047.jpg","PUBLIC_VIDEO":"pvideo_ss200047.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EoiR4OnSF40","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The element carbon can exist in different physical forms called the allotropes of carbon. Three examples of carbon allotropes are: diamond, graphite, and buckyball. The physical properties of these allotropes are quite different due to the different arrangements of carbon atoms in their crystals.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify various allotropes of carbon.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the different arrangements of the carbon atoms in diamond, graphite, and buckyball.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare the physical properties of diamond, graphite, and buckyball.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u062a\u0622\u0635\u0644\u0627\u062a \u0627\u0644\u0643\u0631\u0628\u0648\u0646.","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"245","CATEGORY_ID":"1","CONT_TITLE":"Boiling Point Elevation","CONT_SLUG":"boiling-point-elevation","CONT_TITLE_AR":"Boiling Point Elevation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe boiling point of a solution is always higher than that of the pure solvent. This increase is called the elevation in boiling point.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Theoretically calculate the boiling point elevation of a solution containing a non-volatile solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Experimentally calculate the boiling point of a solution containing a non-volatile solute.\u003C\/div\u003E","CONT_DESC_AR":"The boiling point of a solution is always higher than that of the pure solvent. This increase is called the elevation in boiling point.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation,\u0026amp;nbsp;you will\u0026amp;nbsp;be able to:\u0026lt;br \/\u0026gt;\n\u25cf theoretically calculate the boiling point elevation of a solution containing non-volatile solute\u0026lt;br \/\u0026gt;\n\u25cf experimentally calculate the boiling point of a solution containing non-volatile solute","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200072","TOPIC_ID":"ss200072","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200072.jpg","PUBLIC_BANNER_IMG":"SS200072.jpg","PUBLIC_VIDEO":"pvideo_ss200072.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5bMUwIPeFKE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The boiling point of a solution is always higher than that of the pure solvent. This increase is called the elevation in boiling point.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Theoretically calculate the boiling point elevation of a solution containing a non-volatile solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Experimentally calculate the boiling point of a solution containing a non-volatile solute.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0627\u0631\u062a\u0641\u0627\u0639 \u0641\u064a \u062f\u0631\u062c\u0629 \u0627\u0644\u063a\u0644\u064a\u0627\u0646","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"224","CATEGORY_ID":"1","CONT_TITLE":"Structure of Alkynes","CONT_SLUG":"structure-of-alkynes","CONT_TITLE_AR":"Structure of Alkynes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAlkynes are hydrocarbons that contain at least one carbon-carbon triple bond. Each carbon atoms in alkyne making a triple bond is sp hybridized. Hence alkynes contain both sigma and pi-bond. Ethyne is the simplest hydrocarbon, with chemical formula C2H2.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify an alkyne molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure and hybridization of the simplest alkyne molecule, ethyne.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe bonding and hybridization in alkynes.\u003C\/div\u003E","CONT_DESC_AR":"Alkynes are hydrocarbons that contain at least one carbon-carbon triple bond. Each carbon atoms in alkyne making a triple bond is sp hybridized. Hence alkynes contain both sigma and pi-bond. Ethyne is the simplest hydrocarbon, with chemical formulae C2H2.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify an alkyne molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the structure and hybridisation of the simplest alkyne molecule, ethyne\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe bonding and hybridisation in alkynes","BACKING_FILE":"ss200009.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200009","TOPIC_ID":"ss200009","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200009.jpg","PUBLIC_BANNER_IMG":"SS200009.jpg","PUBLIC_VIDEO":"pvideo_ss200009.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EGv4LSMdQwo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Alkynes are hydrocarbons that contain at least one carbon-carbon triple bond. Each carbon atoms in alkyne making a triple bond is sp hybridized. Hence alkynes contain both sigma and pi-bond. Ethyne is the simplest hydrocarbon, with chemical formula C2H2.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify an alkyne molecule.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure and hybridization of the simplest alkyne molecule, ethyne.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe bonding and hybridization in alkynes.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0623\u0644\u0643\u0627\u064a\u0646\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"220","CATEGORY_ID":"1","CONT_TITLE":"Structure of Alkenes","CONT_SLUG":"structure-of-alkenes","CONT_TITLE_AR":"Structure of Alkenes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAlkenes are hydrocarbons that contain at least one carbon-carbon double bond. Each of the carbon atoms in alkene making a double bond is sp\u00b2 hybridized. Hence alkenes contain both sigma and pi-bond. Ethene is the simplest hydrocarbon, with a chemical formula of C2H4.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify an alkene molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure and hybridization of the simplest alkene molecule, ethene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe bonding and hybridization in alkenes.\u003C\/div\u003E","CONT_DESC_AR":"Alkenes are hydrocarbons that contain at least one carbon-carbon double bond. Each of the carbon atoms in alkene making a double bond is sp2 hybridized. Hence alkenes contain both sigma and pi-bond. Ethene is the simplest hydrocarbon, with a chemical formula of C2H4.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify an alkene molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the structure and hybridisation of the simplest alkene molecule, ethene\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the bonding and hybridisation in alkenes","BACKING_FILE":"ss200005.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200005","TOPIC_ID":"ss200005","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200005.jpg","PUBLIC_BANNER_IMG":"SS200005.jpg","PUBLIC_VIDEO":"pvideo_ss200005.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/z4Tr-o6KRBs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Alkenes are hydrocarbons that contain at least one carbon-carbon double bond. Each of the carbon atoms in alkene making a double bond is sp\u00b2 hybridized. Hence alkenes contain both sigma and pi-bond. Ethene is the simplest hydrocarbon, with a chemical formula of C2H4.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify an alkene molecule.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe the structure and hybridization of the simplest alkene molecule, ethene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe bonding and hybridization in alkenes.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0623\u0644\u0643\u064a\u0646\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"211","CATEGORY_ID":"1","CONT_TITLE":"Factors Affecting Equilibria","CONT_SLUG":"factors-affecting-equilibria","CONT_TITLE_AR":"Factors Affecting Equilibria","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAccording to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u003C\/div\u003E","CONT_DESC_AR":"According to Le Chateliers principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain, when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change","BACKING_FILE":"ss200017.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200017","TOPIC_ID":"ss200017","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200017.jpg","PUBLIC_BANNER_IMG":"SS200017.jpg","PUBLIC_VIDEO":"pvideo_ss200017.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KtndjzIHD3A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;According to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0627\u0644\u0639\u0648\u0627\u0645\u0644 \u0627\u0644\u0645\u0624\u062b\u0631\u0629 \u0639\u0644\u0649 \u0627\u0644\u0627\u062a\u0632\u0627\u0646","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"204","CATEGORY_ID":"1","CONT_TITLE":"Aufbau Principle","CONT_SLUG":"aufbau-principle","CONT_TITLE_AR":"Aufbau principle","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the ground state of the atoms, electrons first occupy the lowest energy orbital available to them and once the lower energy orbitals are filled, the electron can enter into higher energy orbital. \u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the energy order of the orbitals in an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Arrange the electrons in different orbitals in order of increasing energy.\u003C\/div\u003E","CONT_DESC_AR":"In the ground state of the atoms, electrons first occupy the lowest energy orbital available to them and once the lower energy orbitals are filled, the electron can enter into higher energy orbital.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the energy order of the orbitals\u0026lt;br \/\u0026gt;\n\u0026amp;bull; arrange the electrons in different orbitals in order of increasing energy","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200014","TOPIC_ID":"ss200014","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200014.jpg","PUBLIC_BANNER_IMG":"ss200014.jpg","PUBLIC_VIDEO":"pvideo_ss200014.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/TGDXQNbFyOs","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;In the ground state of the atoms, electrons first occupy the lowest energy orbital available to them and once the lower energy orbitals are filled, the electron can enter into higher energy orbital.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the energy order of the orbitals in an atom.\u0026lt;div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Arrange the electrons in different orbitals in order of increasing energy.\u0026lt;div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0645\u0628\u062f\u0623 \u0623\u0648\u0641\u0628\u0627\u0648","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"192","CATEGORY_ID":"1","CONT_TITLE":"Structure of Methane","CONT_SLUG":"structure-of-methane","CONT_TITLE_AR":"Structure of Methane","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the molecular formula of methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the hybridization of the carbon atom in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the tetrahedral structure of methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of covalent bonds present in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the C-H bond length and the H-C-H bond angle in methane.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the electrostatic potential map of methane.\u003C\/div\u003E","CONT_DESC_AR":"A methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the molecular formula of methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the hybridisation of the carbon atom in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the tetrahedral structure of methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of covalent bonds present in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the C-H bond length and the H-C-H bond angle in methane\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the electrostatic potential map of methane","BACKING_FILE":"hs200078.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200078","TOPIC_ID":"hs200078","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200078.jpg","PUBLIC_BANNER_IMG":"HS200078.jpg","PUBLIC_VIDEO":"pvideo_hs200078.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KyIxUUo8mzg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A methane molecule contains one carbon and four hydrogen atoms. The four hydrogen atoms in methane molecule spread out evenly around the carbon atom, leading to the tetrahedral structure.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Write the molecular formula of methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the hybridization of the carbon atom in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the tetrahedral structure of methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the number of covalent bonds present in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the C-H bond length and the H-C-H bond angle in methane.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the electrostatic potential map of methane.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0645\u064a\u062b\u0627\u0646","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"181","CATEGORY_ID":"1","CONT_TITLE":"Rutherford\u0027s Atomic Model","CONT_SLUG":"rutherfords-atomic-model","CONT_TITLE_AR":"Rutherford\u2019s Atomic model","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAccording to Rutherford\u2019s atomic model, the atom consists of two parts. First is the nucleus which is very small in size and carries a positive charge, and in which the entire mass of the atom is concentrated. The second part is the extra nuclear part, in which negatively charged electrons revolve around the nucleus on fixed circular paths.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of an atom according to Rutherford\u0026#039;s atomic model.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Rutherford\u0026#039;s model of an atom.\u003C\/div\u003E","CONT_DESC_AR":"According to Rutherfords atomic model, the atom consists of two parts\u003Cbr\u003E\n1. Nucleus, very small in size, carries a positive charge and in which the entire mass of the atom is concentrated\u0026lt;br \/\u0026gt;\n2. Extra nuclear part, in which negatively charged electrons revolve around the nucleus on fixed circular paths\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the structure of an atom according\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;to Rutherford\u0026amp;#39;s atomic model\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify Rutherford\u0026amp;#39;s model of atom\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"hs200040.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200040","TOPIC_ID":"hs200040","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200040.jpg","PUBLIC_BANNER_IMG":"HS200040.jpg","PUBLIC_VIDEO":"pvideo_hs200040.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/YyEDbnJd0lc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;According to Rutherford\u2019s atomic model, the atom consists of two parts. First is the nucleus which is very small in size and\u0026amp;nbsp; carries a positive charge, and in which the entire mass of the atom is concentrated. The second part is the extra nuclear part, in which negatively charged electrons revolve around the nucleus on fixed circular paths.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the structure of an atom according\u0026amp;nbsp; to Rutherford\u0026#039;s atomic model.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify Rutherford\u0026#039;s model of an atom.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0646\u0645\u0648\u0630\u062c \u0631\u0632\u0631\u0641\u0648\u0631\u062f \u0627\u0644\u0630\u0631\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"178","CATEGORY_ID":"1","CONT_TITLE":"Structure of Ethanal","CONT_SLUG":"structure-of-ethanal","CONT_TITLE_AR":"Structure of Ethanal","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EEthanal is commonly known as acetaldehyde. It is an aldehyde molecule containing two carbon atoms. Ethanal has five single bonds and one carbon-oxygen double bond.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the structure of ethanal.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in ethanal.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the types of covalent bonds present in ethanal.\u003C\/div\u003E","CONT_DESC_AR":"Ethanal is commonly known as acetaldehyde. It is an aldehyde molecule containing two carbon atoms. Ethanal has five single bonds and one carbon-oxygen double bond.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the structure of ethanal\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the functional group present in ethanal\u0026lt;br \/\u0026gt;\n\u0026amp;bull; compare the molecular formula, structural formula, bond-line formula, and ball and stick model","BACKING_FILE":"hs200038.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200038","TOPIC_ID":"hs200038","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200038.jpg","PUBLIC_BANNER_IMG":"HS200038.jpg","PUBLIC_VIDEO":"pvideo_hs200038.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/OCIqGn4fCMc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Ethanal is commonly known as acetaldehyde. It is an aldehyde molecule containing two carbon atoms. Ethanal has five single bonds and one carbon-oxygen double bond.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the structure of ethanal.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the functional group present in ethanal.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the types of covalent bonds present in ethanal.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0625\u064a\u062b\u0627\u0646\u0627\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"175","CATEGORY_ID":"1","CONT_TITLE":"Structure of Ethanol","CONT_SLUG":"structure-of-ethanol","CONT_TITLE_AR":"Structure of Ethanol","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EEthanol is commonly known as ethyl alcohol. It is an alcohol molecule containing the hydoxy functional group. An ethanol molecule has eight single bonds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify functional groups present in ethanol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain types of covalent bonds present in ethanol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in ethanol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain charge distribution of an ethanol molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Ethanol is commonly known as ethyl alcohol. It is an alcohol molecule containing the hydoxy functional group. An ethanol molecule has eight single bonds.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify functional groups present in ethanol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain types of covalent bonds present in ethanol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the type of hybridization of carbon and oxygen atoms in an ethanol molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain charge distribution of an ethanol molecule using its electrostatic potential map","BACKING_FILE":"hs200074.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200074","TOPIC_ID":"hs200074","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200074.jpg","PUBLIC_BANNER_IMG":"HS200074.jpg","PUBLIC_VIDEO":"pvideo_hs200074.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/NdG5hheY5ok","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Ethanol is commonly known as ethyl alcohol. It is an alcohol molecule containing the hydoxy functional group. An ethanol molecule has eight single bonds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify functional groups present in ethanol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain types of covalent bonds present in ethanol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the type of hybridization of carbon and oxygen atoms in ethanol molecule.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain charge distribution of an ethanol molecule using its electrostatic potential map.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0625\u064a\u062b\u0627\u0646\u0648\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"173","CATEGORY_ID":"1","CONT_TITLE":"Valence Electrons","CONT_SLUG":"valence-electrons","CONT_TITLE_AR":"Valence Electrons","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EValence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the outermost shell of an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Count the number of valence electrons present in an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u003C\/div\u003E","CONT_DESC_AR":"Valence electrons are the electrons present in the outermost shell of an atom. The number of valence electrons in the atoms of groups 1,2 and 13 to 18 equals the ones digit of the group members.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- identify outermost shell of an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- count valence electrons present in an atom\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n- predict the number of valence electrons in the atoms of groups 1, 2 and 13 to 18 using periodic table\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":"hs200070.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200070","TOPIC_ID":"hs200070","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200070.jpg","PUBLIC_BANNER_IMG":"HS200070.jpg","PUBLIC_VIDEO":"pvideo_hs200070.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/ksLodK-mJ8c","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Valence electrons are the electrons present in the outermost shell of an atom. Since they are involved in the formation of a molecule, they decide the valency of the atom.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;- Identify the outermost shell of an atom.\u0026lt;br\u0026gt;- Count the number of valence electrons present in an atom.\u0026lt;br\u0026gt;- Predict the number of valence electrons in the atoms of groups 1, 2, and 13 to 18 using the periodic table.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0625\u0644\u0643\u062a\u0631\u0648\u0646\u0627\u062a \u0627\u0644\u062a\u0643\u0627\u0641\u0624","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"169","CATEGORY_ID":"1","CONT_TITLE":"Lewis Dot Structures","CONT_SLUG":"lewis-dot-structures","CONT_TITLE_AR":"Lewis dot Structures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ELewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u003C\/div\u003E","CONT_DESC_AR":"Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u0026amp;rsquo;s chemical symbol.Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons.\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain steps involved in writing Lewis dot structures of atoms and molecules\u0026lt;br \/\u0026gt;\n\u0026amp;bull; draw Lewis dot structures of atoms and molecules","BACKING_FILE":"hs200069.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200069","TOPIC_ID":"hs200069","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200069.jpg","PUBLIC_BANNER_IMG":"HS200069.jpg","PUBLIC_VIDEO":"pvideo_hs200069.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/W0V5VQ3PcC4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Lewis dot structures of atoms are the representations that show valence electrons as dots around the element\u2019s chemical symbol. Lewis dot structures of molecules are the representations that show the bonding between atoms and lone pairs of electrons. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the steps to represent the \u0026#039;Lewis dot structure\u0026#039; of different atoms and molecules.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Draw the \u0026#039;Lewis dot structures\u0026#039; of atoms and molecules.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0631\u0643\u064a\u0628 \u0644\u0648\u064a\u0633 \u0627\u0644\u0646\u0642\u0637\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"167","CATEGORY_ID":"1","CONT_TITLE":"Isoelectronic Species","CONT_SLUG":"isoelectronic-species","CONT_TITLE_AR":"Isoelectronic species","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsoelectronic species have the same number of electrons or a similar electronic configuration, and similar structure. Isoelectronic species can be atoms, ions or molecules. Neon (Ne) atoms and Sodium ion (Na\u207a) are isoelectronic, as both contain 10 electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isoelectronic species.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isoelectronic species of different elements.\u003C\/div\u003E","CONT_DESC_AR":"Isoelectronic species have the same number of electrons or a similar electronic configuration and similar structure. Isoelectronic species can be atoms, ions or molecules. Ne atoms and Na+ ions are isoelectronic, as both contain 10 electrons.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation, you will be able to:\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isoelectronic species\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isoelectronic species of different elements","BACKING_FILE":"hs200052.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200052","TOPIC_ID":"hs200052","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200052.jpg","PUBLIC_BANNER_IMG":"HS200052.jpg","PUBLIC_VIDEO":"pvideo_hs200052.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/IJ7J0l0OUZg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isoelectronic species have the same number of electrons or a similar electronic configuration, and similar structure. Isoelectronic species can be atoms, ions or molecules. Neon (Ne) atoms and Sodium ion (Na\u0026lt;span style=\u0026quot;color: rgb(38, 50, 56); font-family: Roboto, sans-serif;\u0026quot;\u0026gt;\u207a\u0026lt;\/span\u0026gt;) are isoelectronic, as both contain 10 electrons.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isoelectronic species.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isoelectronic species of different elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u0645\u062a\u0633\u0627\u0648\u064a\u0629 \u0625\u0644\u0643\u062a\u0631\u0648\u0646\u064a\u0651\u064b\u0627","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"165","CATEGORY_ID":"1","CONT_TITLE":"Isotones","CONT_SLUG":"isotones","CONT_TITLE_AR":"Isotones","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsotones are atoms that have the same number of neutrons but a different number of protons. Boron-12 and carbon-13 are isotones, as both of them contain 7 neutrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAt the end of this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isotones.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isotones of different elements.\u003C\/div\u003E","CONT_DESC_AR":"Isotones have the same number of neutrons but a different number of protons. Boron-12 and carbon-13 are isotones, as both of them contain 7 neutrons.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isotones\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isotones of different elements","BACKING_FILE":"hs200050.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200050","TOPIC_ID":"hs200050","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200050.jpg","PUBLIC_BANNER_IMG":"HS200050.jpg","PUBLIC_VIDEO":"pvideo_hs200050.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RNhrWFaUeqQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isotones are atoms that have the same number of neutrons but a different number of protons. Boron-12 and carbon-13 are isotones, as both of them contain 7 neutrons.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;At the end of this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isotones.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isotones of different elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0623\u064a\u0632\u0648\u062a\u0648\u0646\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"162","CATEGORY_ID":"1","CONT_TITLE":"Isobars","CONT_SLUG":"isobars","CONT_TITLE_AR":"Isobars","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsobars are atoms that have the same mass number, but a different atomic number. Hence isobars have the same number of nuclides, but a different number of protons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isobars.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isobars of different elements.\u003C\/div\u003E","CONT_DESC_AR":"Isobars have the same mass number, but a different atomic number. Hence isobars have the same number of nuclides, but a different number of protons.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isobars\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isobars of different elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of protons and neutrons in different isobars","BACKING_FILE":"hs200025.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200025","TOPIC_ID":"hs200025","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200025.jpg","PUBLIC_BANNER_IMG":"HS200025.jpg","PUBLIC_VIDEO":"pvideo_hs200025.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/LOlP2PuVudo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isobars are atoms that have the same mass number, but a different atomic number. Hence isobars have the same number of nuclides, but a different number of protons.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isobars.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isobars of different elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u062a\u0633\u0627\u0648\u064a\u0627\u062a \u0627\u0644\u0643\u062a\u0644","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"159","CATEGORY_ID":"1","CONT_TITLE":"Isotopes","CONT_SLUG":"isotopes","CONT_TITLE_AR":"Isotopes","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIsotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: hydrogen, deuterium and tritium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isotopes. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isotopes of different elements. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of protons and neutrons in different isotopes.\u003C\/div\u003E","CONT_DESC_AR":"Isotopes of an element have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: \u0026amp;nbsp;hydrogen, deuterium and tritium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isotopes\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isotopes of different elements\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of protons and neutrons in different isotopes","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200024","TOPIC_ID":"hs200024","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200024.jpg","PUBLIC_BANNER_IMG":"HS200024.jpg","PUBLIC_VIDEO":"pvideo_hs200024.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/f4sZdLZU03k","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes:\u0026amp;nbsp; hydrogen, deuterium and tritium.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define isotopes.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify isotopes of different elements.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the number of protons and neutrons in different isotopes.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0646\u0638\u0627\u0626\u0631","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"157","CATEGORY_ID":"1","CONT_TITLE":"Synthesis Reactions","CONT_SLUG":"synthesis-reactions","CONT_TITLE_AR":"Synthesis reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a synthesis reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the synthesis reaction of magnesium oxide.\u003C\/div\u003E","CONT_DESC_AR":"A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic. An example of a synthesis reaction is the formation of water from hydrogen and oxygen.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a synthesis reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate the synthesis reaction of magnesium oxide","BACKING_FILE":"hs200021.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200021","TOPIC_ID":"hs200021","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200021.jpg","PUBLIC_BANNER_IMG":"HS200021.jpg","PUBLIC_VIDEO":"pvideo_hs200021.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5RK8BgMSqAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a synthesis reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the synthesis reaction of magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0627\u062a\u062d\u0627\u062f","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"154","CATEGORY_ID":"1","CONT_TITLE":"Combustion Reactions","CONT_SLUG":"combustion-reactions","CONT_TITLE_AR":"Combustion reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define a combustion reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the combustion of propane and oxygen.\u003C\/div\u003E","CONT_DESC_AR":"A combustion reaction is a major class of chemical reactions. Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. In the more general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. Combustion is an exothermic reaction, so it releases heat.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf explain what is a combustion reaction\u0026lt;br \/\u0026gt;\n\u25cf demonstrate combustion reaction of propane and oxygen\u0026lt;br \/\u0026gt;\n\u25cf identify a combustion reaction","BACKING_FILE":"hs200022.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200022","TOPIC_ID":"hs200022","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200022.jpg","PUBLIC_BANNER_IMG":"HS200022.jpg","PUBLIC_VIDEO":"pvideo_hs200022.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Wl8vJ7nbNbY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify and define a combustion reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the combustion of propane and oxygen.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0627\u062d\u062a\u0631\u0627\u0642","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"148","CATEGORY_ID":"1","CONT_TITLE":"Periodic Trends-Atomic Radii","CONT_SLUG":"periodic-trends-atomic-radii","CONT_TITLE_AR":"Periodic Trends: Atomic Radii","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe atomic radius of a chemical element is the distance from the center of the nucleus to the outmost boundary of the surrounding cloud of electrons. On moving left to right in the periodic table, the atomic radius decreases with the atomic number. Down the group, the atomic radius increases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the trends of atomic radii in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the atomic radii of the elements.\u003C\/div\u003E","CONT_DESC_AR":"The atomic radius of a chemical element is the distance from the center of the nucleus to the boundary of the surrounding cloud of electrons. On moving left to right in the periodic table, the atomic radius decreases with the atomic number. Down the group, the atomic radius increases in conjunction to the atomic number.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation, you will be able to:\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the valency of elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the placement of elements in the periodic table using valency","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200012","TOPIC_ID":"hs200012","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200012.jpg","PUBLIC_BANNER_IMG":"hs200012.jpg","PUBLIC_VIDEO":"pvideo_hs200012.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/InBee94xfgk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The atomic radius of a chemical element is the distance from the center of the nucleus to the outmost boundary of the surrounding cloud of electrons. On moving left to right in the periodic table, the atomic radius decreases with the atomic number. Down the group, the atomic radius increases.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Predict the trends of atomic radii in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare the atomic radii of the elements.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0646\u0635\u0641 \u0627\u0644\u0642\u0637\u0631 \u0627\u0644\u0630\u0631\u064a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"146","CATEGORY_ID":"1","CONT_TITLE":"Periodic Trends-Valency","CONT_SLUG":"periodic-trends-valency","CONT_TITLE_AR":"Periodic Trends: Valency","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the atoms, the electrons which are found in the outermost shell are generally known as valence electrons and the number of valence electrons determines the valency of an atom. The valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electrons. And the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from number eight.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the valency of an element using the number of valence electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine the valency of an element with the help of its position in the periodic table.\u003C\/div\u003E","CONT_DESC_AR":"In the atoms, the electrons which are found in the outermost shell are generally known as valence electrons and the number of valence electrons determines the valency of an atom.\u0026amp;nbsp;The valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electron.\u0026amp;nbsp;And the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from number eight.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning objectives\u0026amp;nbsp;\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation, you will be able to:\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the valency of elements\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the placement of elements in the periodic table using valency","BACKING_FILE":"hs200011.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200011","TOPIC_ID":"hs200011","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200011.jpg","PUBLIC_BANNER_IMG":"hs200011.jpg","PUBLIC_VIDEO":"pvideo_hs200011.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XV474BAXvVQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the atoms, the electrons which are found in the outermost shell are generally known as valence electrons and the number of valence electrons determines the valency of an atom. The valency of atoms of 1st, 2nd, 13th and 14th group elements are generally given as the number of valence electrons. And the valency of 15th to 18th group elements can be calculated by subtracting the number of valence electrons from number eight.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the valency of an element using the number of valence electrons.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Determine the valency of an element with the help of its position in the periodic table.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0627\u0644\u062a\u0643\u0627\u0641\u0624","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"96","CATEGORY_ID":"1","CONT_TITLE":"The Molecule","CONT_SLUG":"the-molecules","CONT_TITLE_AR":"The Molecule","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA molecule is a group of atoms bonded together. Molecules can be monatomic, diatomic or polyatomic on the basis of the number of atoms present in them.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the atomicity of different molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify monoatomic, diatomic and polyatomic molecules.\u003C\/div\u003E","CONT_DESC_AR":"A molecule is a group of atoms bonded together. Molecules can be monoatomic, diatomic or polyatomic on the basis of the number of atoms present in them.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define molecules\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate atomicity of a molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify monoatomic, diatomic and polyatomic molecules","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200077","TOPIC_ID":"ms200077","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200077.jpg","PUBLIC_BANNER_IMG":"MS200077.jpg","PUBLIC_VIDEO":"pvideo_ms200077.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/-MxyzLjRApc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A molecule is a group of atoms bonded together. Molecules can be monatomic, diatomic or polyatomic on the basis of the number of atoms present in them.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define molecules.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Calculate the atomicity of different molecules.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify monoatomic, diatomic and polyatomic molecules.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u0632\u064a\u0626\u0627\u062a","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"93","CATEGORY_ID":"1","CONT_TITLE":"Homogeneous Mixtures","CONT_SLUG":"homogeneous-mixtures","CONT_TITLE_AR":"Homogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is homogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is homogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200054","TOPIC_ID":"ms200054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200054.jpg","PUBLIC_BANNER_IMG":"MS200054.jpg","PUBLIC_VIDEO":"pvideo_ms200054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/elFGPE_TZxk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the properties of homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify whether a mixture is homogeneous or not.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u0627\u0644\u0645\u062a\u062c\u0627\u0646\u0633\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"85","CATEGORY_ID":"1","CONT_TITLE":"Heterogeneous Mixtures","CONT_SLUG":"heterogeneous-mixtures","CONT_TITLE_AR":"Heterogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is heterogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is heterogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200053","TOPIC_ID":"ms200053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200053.jpg","PUBLIC_BANNER_IMG":"MS200053.jpg","PUBLIC_VIDEO":"pvideo_ms200053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BrPP-a75tI0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe heterogeneous mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of heterogeneous mixtures.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a mixture is heterogeneous or not.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u063a\u064a\u0631 \u0627\u0644\u0645\u062a\u062c\u0627\u0646\u0633\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"69","CATEGORY_ID":"1","CONT_TITLE":"Endothermic Reactions","CONT_SLUG":"endothermic-reactions","CONT_TITLE_AR":"Endothermic Reactions","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EHeat is absorbed from the surrounding area during an endothermic reaction. The temperature of the surrounding area decreases after the completion of an endothermic reaction. Photosynthesis is an example of an endothermic reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define an endothermic reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the condition that makes a chemical reaction endothermic.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate an endothermic reaction.\u003C\/div\u003E","CONT_DESC_AR":"Heat is absorbed from the surrounding area during an endothermic reaction. The temperature of the surrounding area decreases after the completion of an endothermic reaction. Photosynthesis is an example of an endothermic reaction.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- define an endothermic reaction\u0026lt;br \/\u0026gt;\n- identify the condition that makes a chemical reaction endothermic\u0026lt;br \/\u0026gt;\n- demonstrate an endothermic reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200030","TOPIC_ID":"ms200030","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200030.jpg","PUBLIC_BANNER_IMG":"MS200030.jpg","PUBLIC_VIDEO":"pvideo_ms200030.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SoWCbiufVDg","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Heat is absorbed from the surrounding area during an endothermic reaction. The temperature of the surrounding area decreases after the completion of an endothermic reaction. Photosynthesis is an example of an endothermic reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define an endothermic reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the condition that makes a chemical reaction endothermic.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate an endothermic reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0645\u0627\u0635\u0629 \u0644\u0644\u062d\u0631\u0627\u0631\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"67","CATEGORY_ID":"1","CONT_TITLE":"Exothermic Reactions","CONT_SLUG":"exothermic-reaction","CONT_TITLE_AR":"Exothermic Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EHeat is released to the surrounding area during an exothermic reaction. The temperature of the surrounding area increases after the completion of an exothermic reaction. The burning of coal is an example of an exothermic reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define an exothermic reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the condition that makes a chemical reaction exothermic.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate an exothermic reaction.\u003C\/div\u003E","CONT_DESC_AR":"Heat is liberated to the surrounding area during an exothermic reaction. The temperature of the surrounding area increases after the completion of an exothermic reaction. The burning of coal is an example of an exothermic reaction.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- define an exothermic reaction\u0026lt;br \/\u0026gt;\n- identify the condition that makes a chemical reaction exothermic\u0026lt;br \/\u0026gt;\n- demonstrate an exothermic reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200029","TOPIC_ID":"ms200029","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200029.jpg","PUBLIC_BANNER_IMG":"MS200029.jpg","PUBLIC_VIDEO":"pvideo_ms200029.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5gweNe56g-A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Heat is released to the surrounding area during an exothermic reaction. The temperature of the surrounding area increases after the completion of an exothermic reaction. The burning of coal is an example of an exothermic reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define an exothermic reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the condition that makes a chemical reaction exothermic.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate an exothermic reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0637\u0627\u0631\u062f\u0629 \u0644\u0644\u062d\u0631\u0627\u0631\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"64","CATEGORY_ID":"1","CONT_TITLE":"Separation by Filtration","CONT_SLUG":"separation-by-filtration","CONT_TITLE_AR":"Separation by Filtration","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWater-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure of filtration using filter paper.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify mixtures that can be separated by filtration.\u003C\/div\u003E","CONT_DESC_AR":"Liquid mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand water mixture as sand cannot permeate filter paper.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAt the end of the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- describe the procedure of filtration using filter paper\u0026lt;br \/\u0026gt;\n- identify mixtures that can be separated by filtration\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200051","TOPIC_ID":"ms200051","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200051.jpg","PUBLIC_BANNER_IMG":"MS200051.jpg","PUBLIC_VIDEO":"pvideo_ms200051.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/RZS1h0l5xjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Water-based mixtures containing solid substances can be separated by using a filter paper. We can separate sand from a sand-water mixture as sand cannot permeate into the filter paper.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the procedure of filtration using filter paper.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify mixtures that can be separated by filtration.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0641\u0635\u0644 \u0628\u0627\u0644\u062a\u0631\u0634\u064a\u062d","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"62","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Using Magnets","CONT_SLUG":"separating-mixtures-using-magnets","CONT_TITLE_AR":"Separating Mixtures: Using Magnets","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMixtures containing substances that are attracted by magnets can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only the iron is attracted to the magnet.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure to separate the constituents of a mixture that are attracted toward a magnet.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mixtures whose constituents can be separated by using a magnet.\u003C\/div\u003E","CONT_DESC_AR":"Mixtures containing substances that get attracted to magnet can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only iron attracts\u0026amp;nbsp;to the magnet.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- describe the procedure of separating the constituents of a mixture with the help of a magnet\u0026lt;br \/\u0026gt;\n- identify the mixtures whose constituents can be\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;separated by using a magnet","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200036","TOPIC_ID":"ms200036","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200036.jpg","PUBLIC_BANNER_IMG":"MS200036.jpg","PUBLIC_VIDEO":"pvideo_ms200036.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/--Vd1at4aWc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Mixtures containing substances that are attracted by magnets can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only the iron is attracted to the magnet.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the procedure to separate the constituents of a mixture that are attracted toward a magnet.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the mixtures whose constituents can be separated by using a magnet.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0641\u0635\u0644 \u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u0628\u0627\u0633\u062a\u062e\u062f\u0627\u0645 \u0627\u0644\u0645\u063a\u0627\u0646\u0637","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"59","CATEGORY_ID":"1","CONT_TITLE":"Phase Change: Melting and Freezing","CONT_SLUG":"phase-change-melting-and-freezing","CONT_TITLE_AR":"Phase Change-Melting and Freezing","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIf a solid matter gains enough heat, it changes its state from solid to liquid, causing melting. On the other hand, when a solid matter loses heat, it causes a process called freezing. In freezing, the motion of atoms or molecules slows down.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define melting and freezing.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid state and liquid state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"If solid matter gains enough heat, it changes state from solid to liquid, causing melting. The inverse of melting is called freezing, changing from a liquid state to solid, in which atoms and molecules lose heat and come together, slowing down motion.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- Define melting and freezing\u0026lt;br \/\u0026gt;\n- Explain how a solid state and liquid state of matter can be interchanged","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200018","TOPIC_ID":"ms200018","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200018.jpg","PUBLIC_BANNER_IMG":"MS200018.jpg","PUBLIC_VIDEO":"pvideo_ms200018.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/_wM6VCKEABQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;If a solid matter gains enough heat, it changes its state from solid to liquid, causing melting. On the other hand, when a solid matter loses heat, it causes a process called freezing. In freezing, the motion of atoms or molecules slows down.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define melting and freezing.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how solid state and liquid state of matter can be interchanged.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u063a\u064a\u0631\u0627\u062a \u0627\u0644\u062d\u0627\u0644\u0629: \u0627\u0644\u0627\u0646\u0635\u0647\u0627\u0631 \u0648\u0627\u0644\u062a\u062c\u0645\u062f","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"57","CATEGORY_ID":"1","CONT_TITLE":"Comparing Solid, Liquid, and Gas","CONT_SLUG":"comparing-solid-liquid-and-gases","CONT_TITLE_AR":"Comparing Solid, Liquid and Gases","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe three common states of matter are: gases, liquids, and solids. These are all made up of particles, but the behaviors of these particles differ in the three states. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of particles in different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the characteristics of particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Gases, liquids and solids are all made up of particles, but the behaviors of these particles differ in the three phases. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation you will be able to:\u0026lt;br \/\u0026gt;\n- explain the characteristics of particles of different states of matter\u0026lt;br \/\u0026gt;\n- compare the characteristics of particles of matter\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200016","TOPIC_ID":"ms200016","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200016.jpg","PUBLIC_BANNER_IMG":"MS200016.jpg","PUBLIC_VIDEO":"pvideo_ms200016.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5PRBv9scvUo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;The three common states of matter are: gases, liquids, and solids. These are all made up of particles, but the behaviors of these particles differ in the three states. Gases are well separated with no regular arrangement, liquids are close together with no regular arrangement, and solids are tightly packed, usually in a regular pattern.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the characteristics of particles in different states of matter.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare the characteristics of particles of matter.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0642\u0627\u0631\u0646 \u0628\u064a\u0646 \u0627\u0644\u0645\u0648\u0627\u062f \u0627\u0644\u0635\u0644\u0628\u0629 \u0648\u0627\u0644\u0633\u0627\u0626\u0644\u0629 \u0648\u0627\u0644\u063a\u0627\u0632\u064a\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"56","CATEGORY_ID":"1","CONT_TITLE":"States of Matter","CONT_SLUG":"states-of-matter","CONT_TITLE_AR":"States of Matter","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMatter exists in three states: solid, liquid, and gas. Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003EBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of the particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Matter exists in three states: solid, liquid, and gas.\u003C\/br\u003E\r\nParticles of various types of matter have different characteristics.\u003C\/br\u003E\r\nThe particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/br\u003E\r\nBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives:\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation, you will be able to:\u003C\/br\u003E\r\n- identify different states of matter\u003C\/br\u003E\r\n- explain the characteristics of particles of matter","BACKING_FILE":"ms200013.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200013","TOPIC_ID":"ms200013","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200013.jpg","PUBLIC_BANNER_IMG":"MS200013.jpg","PUBLIC_VIDEO":"pvideo_ms200013.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/IjS0e_2CV6o","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2019-09-17 06:37:58","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Matter exists in three states: solid, liquid, and gas. Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;But, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify different states of matter.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the characteristics of the particles of matter.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062d\u0627\u0644\u0627\u062a \u0627\u0644\u0645\u0627\u062f\u0629","ADMSUBJECT_ID":"1378","ADMCOURSE_ID":"393","DISPLAY_NAME":"Chemistry","DISPLAY_NAME_AR":"","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"","SUBJECT_DESC":"Description","SUBJECT_DESC_AR":"","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Additional Topics","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"}],"levelObject":[],"contData":{"CONT_ID":"674","CATEGORY_ID":"1","CONT_TITLE":"Group 2: Alkaline Earth Metals","CONT_SLUG":"group-2-alkaline-earth-metals","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe elements in Group 2 of the periodic table are called the alkaline earth metals. These are harder and denser than alkali metals. They react with water to form alkaline solutions, but they are less reactive than alkali metals.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E  \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Locate the alkaline earth metals in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the reactivity of alkaline earth metals with water.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine the pH of the hydroxide solutions of alkaline earth metals.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000018","TOPIC_ID":"vc000018","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000018.jpg","PUBLIC_BANNER_IMG":"vc000018.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000018.mp4","PUBLIC_VIDEO_URL":null,"DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-07-04 07:03:45","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 11:01:06","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;The elements in Group 2 of the periodic table are called the alkaline earth metals. These are harder and denser than alkali metals. They react with water to form alkaline solutions, but they are less reactive than alkali metals.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives::\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Locate the alkaline earth metals in the periodic table.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Compare the reactivity of alkaline earth metals with water.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Determine the pH of the hydroxide solutions of alkaline earth metals.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Group 2: Alkaline Earth Metals","DISPLAY_NAME":"CBSE - Grade 11 - Chemistry","DISPLAY_NAME_AR":"CBSE - Grade 11 - Chemistry","SUBJECT_IMG":"570.jpg","ADMSUBJECT_ID":"570","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","ADMCOURSE_ID":"198","COURSE_NAME":"Grade 11","COUNTRY_ID":"288","STANDARD_ID":"288","SHORT_NAME":"CBSE","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Ti\u1ebfng Vi\u1ec7t"],"devices":["UmetyVR","WebXR"]}