{"pkgId":"46","subjectId":"648","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":" Full Access \u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","PACKAGE_SLUG":"full-\u0627\u0644\u0645\u0645\u0644\u0643\u0629-\u0627\u0644\u0639\u0631\u0628\u064a\u0629-\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","PACKAGE_IMG":"file_879647053_1592481431.png","ADMCOURSE_ID":"125","COURSE_NAME":"\u0627\u0644\u0635\u0641 10","COUNTRY_ID":"278","STANDARD_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","ADMSUBJECT_ID":"648","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 10 - \u0643\u064a\u0645\u064a\u0627\u0621","DISPLAY_NAME_AR":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 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\r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Sort compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify compounds and mixtures on the basis of molecular view.\u003C\/div\u003E","CONT_SLUG":"difference-between-compounds-and-mixtures","BACKING_FILE":"hs200418.apk","CONT_SRC":null,"CONTTYPE_ID":"9","PUBLIC_IMG":"thumb_HS200418.jpg","PUBLIC_BANNER_IMG":"HS200418.jpg","PUBLIC_VIDEO":"pvideo_hs200418.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hlxxUVnlQzE","PACKAGE_DOMAIN":"STEM"},"pkgCourses":[{"ADMCOURSE_ID":"121","COURSE_NAME":"\u0627\u0644\u0635\u0641 6","COUNTRY_ID":"278","SHORT_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","ADMSUBJECT_ID":"631","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 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Mixtures","CONT_SLUG":"difference-between-compounds-and-mixtures","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA compound is the substance consisting of only one type of molecule throughout its composition, whereas in mixtures two or more than two types of molecules can be observed.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objectives \u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Differentiate between compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Sort compounds and mixtures. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify compounds and mixtures on the basis of molecular 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These reactions often involve an energy source such as heat, light, catalyst or electricity that breaks apart the bonds of compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain a decomposition reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the roles of the different parameters used to initiate and speed up decomposition reactions.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200319","TOPIC_ID":"ms200319","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200319.jpg","PUBLIC_BANNER_IMG":"MS200319.jpg","PUBLIC_VIDEO":"pvideo_ms200319.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Dnrhrdmk_RY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds. 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\u0627\u0644\u0645\u0633\u062a\u0642\u0631\u0629 \u0648\u0627\u0644\u0630\u0631\u0627\u062a \u063a\u064a\u0631 \u0627\u0644\u0645\u0633\u062a\u0642\u0631\u0629 \u0648\u0627\u0644\u0623\u0646\u0648\u0627\u0639 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629 \u0645\u0646 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u062a\u0642\u0648\u0645 \u0648\u062d\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u0639\u0627\u0634\u0631 \u0628\u062c\u0639\u0644 \u0627\u0644\u0637\u0644\u0627\u0628 \u0639\u0644\u0649 \u0645\u0639\u0631\u0641\u0629 \u0628\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0643\u064a\u0645\u0627\u0626\u064a\u0629 \u0627\u0644\u0645\u0631\u062a\u0628\u0637\u0629 \u0628\u062a\u0637\u0628\u064a\u0642\u0627\u062a \u062d\u064a\u0627\u062a\u0647\u0645 \u0627\u0644\u064a\u0648\u0645\u064a\u0629. \u0648\u062a\u0633\u0627\u0647\u0645 \u0647\u0630\u0629 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Atoms which attain noble gas configuration are non reactive in nature and are called stable atoms. Atoms which do not attain noble gas configuration are reactive in nature and are called unstable atoms.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the conditions for an atom to be stable.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe how an atom can be made stable or unstable.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify stable and unstable atoms.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200310","TOPIC_ID":"hs200310","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200310.jpg","PUBLIC_BANNER_IMG":"HS200310.jpg","PUBLIC_VIDEO":"pvideo_hs200310.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1B18nNgKKDc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Atoms become chemically stable by losing or gaining to fill up their outermost electron shell to a configuration nearest to that of a noble gas. Atoms which attain noble gas configuration are non reactive in nature and are called stable atoms. Atoms which do not attain noble gas configuration are reactive in nature and are called unstable atoms.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the conditions for an atom to be stable.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe how an atom can be made stable or unstable.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify stable and unstable atoms.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0630\u0631\u0627\u062a \u0627\u0644\u0645\u0633\u062a\u0642\u0631\u0629 \u0648\u063a\u064a\u0631 \u0627\u0644\u0645\u0633\u062a\u0642\u0631\u0629","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 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The mass number of an atom is the sum of the number of protons and the number of neutrons in the nucleus.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define mass number.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mass number of the first 20 elements in the periodic table.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the mass number of any element.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200296","TOPIC_ID":"ms200296","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200296.jpg","PUBLIC_BANNER_IMG":"MS200296.jpg","PUBLIC_VIDEO":"pvideo_ms200296.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BYE0r79sLXE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An atom consists of three subatomic particles namely: electrons, protons and neutrons. 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"489","CATEGORY_ID":"1","CONT_TITLE":"Atomic Number","CONT_SLUG":"atomic-number","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn element\u2019s atomic number is the number of protons present in the nucleus of that atom. When you look at an element in the periodic table, the number located in the upper left corner of the square is the atomic number of that element.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define atomic number of an element. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Locate an element\u0026#039;s atomic number in the periodic table. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of electrons present in an atom or ion using its atomic number.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200295","TOPIC_ID":"ms200295","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200295.jpg","PUBLIC_BANNER_IMG":"MS200295.jpg","PUBLIC_VIDEO":"pvideo_ms200295.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/eTGUbyjr8_g","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An element\u2019s atomic number is the number of protons present in the nucleus of that atom. When you look at an element in the periodic table, the number located in the upper left corner of the square is the atomic number of that element.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define atomic number of an element.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Locate an element\u0026#039;s atomic number in the periodic table.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Calculate the number of electrons present in an atom or ion using its atomic number.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0639\u062f\u062f \u0627\u0644\u0630\u0631\u064a","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - 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\u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u062a\u0642\u0648\u0645 \u0648\u062d\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u0639\u0627\u0634\u0631 \u0628\u062c\u0639\u0644 \u0627\u0644\u0637\u0644\u0627\u0628 \u0639\u0644\u0649 \u0645\u0639\u0631\u0641\u0629 \u0628\u0627\u0644\u0645\u0641\u0627\u0647\u064a\u0645 \u0627\u0644\u0643\u064a\u0645\u0627\u0626\u064a\u0629 \u0627\u0644\u0645\u0631\u062a\u0628\u0637\u0629 \u0628\u062a\u0637\u0628\u064a\u0642\u0627\u062a \u062d\u064a\u0627\u062a\u0647\u0645 \u0627\u0644\u064a\u0648\u0645\u064a\u0629. \u0648\u062a\u0633\u0627\u0647\u0645 \u0647\u0630\u0629 \u0627\u0644\u0648\u062d\u062f\u0627\u062a \u0641\u064a \u0641\u0647\u0645 \u0623\u0641\u0636\u0644  \u0644\u0645\u0648\u0627\u0636\u064a\u0639 \u0645\u062b\u0644 \u0627\u0644\u062a\u063a\u064a\u0631\u0627\u062a \u0627\u0644\u0641\u064a\u0632\u064a\u0627\u0626\u064a\u0629 (\u0643\u0627\u0644\u0627\u0646\u0635\u0647\u0627\u0631 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"488","CATEGORY_ID":"1","CONT_TITLE":"Phase Change: Sublimation","CONT_SLUG":"phase-change-sublimation","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe process in which a solid directly changes its state to gas without undergoing the liquid phase is called sublimation. Examples of substances that undergo sublimation are camphor, naphthalene etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define sublimation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of sublimation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify substances that undergo sublimation.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200286.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200286","TOPIC_ID":"ms200286","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200286.jpg","PUBLIC_BANNER_IMG":"MS200286.jpg","PUBLIC_VIDEO":"pvideo_ms200286.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/X1wc5E1F-ic","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The process in which a solid\u0026amp;nbsp; directly changes its state to gas without undergoing the liquid phase is called sublimation. Examples of substances that undergo sublimation are camphor, naphthalene etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define sublimation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the process of sublimation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify substances that undergo sublimation.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u063a\u064a\u0631 \u062d\u0627\u0644\u0629 \u0627\u0644\u0645\u0627\u062f\u0629: \u0627\u0644\u062a\u0633\u0627\u0645\u064a","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 10 - 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"487","CATEGORY_ID":"1","CONT_TITLE":"Phase Changes: Boiling, Evaporation and Condensation","CONT_SLUG":"phase-change-boiling-evaporation-and-condensation","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe change in state of liquid into gas is called vaporization. The process in which the vaporization occurs from the surface of a liquid is called evaporation. Whereas the process in which vaporization occurs within the surface of the liquid is called boiling. The change in state of gas into liquid is called condensation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define evaporation, boiling and condensation. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how liquid state and gaseous state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200285.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200285","TOPIC_ID":"ms200285","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200285.jpg","PUBLIC_BANNER_IMG":"MS200285.jpg","PUBLIC_VIDEO":"pvideo_ms200285.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/B6ArYhP2pRY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The change in state of liquid into gas is called vaporization. The process in which the vaporization occurs from the surface of\u0026amp;nbsp; a liquid is called evaporation. Whereas the process in which vaporization occurs within the surface of the liquid is called boiling. 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The law states that mass cannot be formed or destroyed. Mass remains constant before and after a change.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the law of conservation of mass.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate the law of conservation of mass in physical changes.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate the law of conservation of mass in chemical changes.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200273","TOPIC_ID":"ms200273","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200273.jpg","PUBLIC_BANNER_IMG":"MS200273.jpg","PUBLIC_VIDEO":"pvideo_ms200273.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SRqPI8TJjuM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Physical and chemical changes follow the law of conservation of mass. The law states that mass cannot be formed or destroyed. Mass remains constant before and after a change.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the law of conservation of mass.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Illustrate the law of conservation of mass in physical changes.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Illustrate the law of conservation of mass in chemical changes.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0628\u0642\u0627\u0621 \u0627\u0644\u0645\u0627\u062f\u0629","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 10 - 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In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the process of the evaporation method of separation.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solutions that can be separated using the evaporation method of separation.\u003C\/div\u003E","CONT_DESC_AR":"The evaporation method of separation is used for the separation of soluble solids and solvents. In this separation method, a solution is heated until the solvent evaporates, leaving behind a solid residue.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\n\u0026lt;ol\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;explain the process of evaporation method of separation\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;identify solutions that can be separated using evaporation method of separation\u0026lt;\/li\u0026gt;\n\u0026lt;\/ol\u0026gt;\n","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200064","TOPIC_ID":"ms200064","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200064.jpg","PUBLIC_BANNER_IMG":"MS200064.jpg","PUBLIC_VIDEO":"pvideo_ms200064.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/XT6vdYq4BaA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The evaporation method of separation is used for the separation of soluble solids and solvents. 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Atoms are made up of three subatomic particles: electrons, protons and neutrons. Protons and neutrons are present in a small, dense nucleus at the center of the atom. The positively charged nucleus is surrounded by negatively charged electrons.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define an atom.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe subatomic particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the subatomic particles that are present in the nucleus.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the subatomic particles that revolve around the nucleus.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a model of an atom.\u003C\/div\u003E","CONT_DESC_AR":"An atom is the smallest particle that makes up all matter. Atoms are made up of three subatomic particles: electrons, protons and neutrons. Protons and neutrons are present a in a small, dense nucleus at the center of the atom. The positively charged nucleus is surrounded by negatively charged electrons.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\n\u0026lt;ol\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;define an atom\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;describe subatomic particles\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;explain subatomic particles that are present in the nucleus\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;explain subatomic particle that revolve around the nucleus\u0026lt;\/li\u0026gt;\n\t\u0026lt;li value=\u0026quot;NaN\u0026quot;\u0026gt;construct the model of an atom\u0026lt;\/li\u0026gt;\n\u0026lt;\/ol\u0026gt;\n","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200081","TOPIC_ID":"ms200081","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200081.jpg","PUBLIC_BANNER_IMG":"MS200081.jpg","PUBLIC_VIDEO":"pvideo_ms200081.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Y31lr9Sup5A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An atom is the smallest particle that defines an element. Atoms are made up of three subatomic particles: electrons, protons and neutrons. Protons and neutrons are present in a small, dense nucleus at the center of the atom. The positively charged nucleus is surrounded by negatively charged electrons.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define an atom.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe subatomic particles.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the subatomic particles that are present in the nucleus.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the subatomic particles that revolve around the nucleus.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct a model of an atom.\u0026lt;\/div\u0026gt;\u0026lt;ol\u0026gt;\r\n\u0026lt;\/ol\u0026gt;\r\n","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0630\u0631\u0629","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 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The physical and chemical properties of the new chemical substances that formed are entirely different. The signs that indicate the formation of a new type of matter include the formation of bubbles or a change in energy, color or odor.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe chemical changes.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the signs that indicate the formation of new types of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the physical and chemical properties of newly formed chemical substances.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a chemical change has occurred or not.\u003C\/div\u003E","CONT_DESC_AR":"Chemical change is a change in matter in which the substances that make up the matter change into new chemical substances. Physical and chemical properties of new chemical substances formed are entirely different. The signs that indicate the formation of a new type of matter include the formation of bubble or a change in energy, colour or odour.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf describe the chemical changes\u0026lt;br \/\u0026gt;\n\u25cf explain the signs that indicate formation of new type of matter\u0026lt;br \/\u0026gt;\n\u25cf compare physical and chemical properties of new\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026amp;nbsp;\u0026amp;nbsp;chemical substances formed\u0026lt;br \/\u0026gt;\n\u25cf identify whether a chemical change has occurred or not","BACKING_FILE":"ms200080.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200080","TOPIC_ID":"ms200080","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200080.jpg","PUBLIC_BANNER_IMG":"MS200080.jpg","PUBLIC_VIDEO":"pvideo_ms200080.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/jM3xFMNR-Bc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Chemical change is a change in matter in which the substances that make up the matter change into new chemical substances. 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A hydrogen atom has three known isotopes: hydrogen, deuterium and tritium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define isotopes. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify isotopes of different elements. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the number of protons and neutrons in different isotopes.\u003C\/div\u003E","CONT_DESC_AR":"Isotopes of an element have the same number of protons and electrons, but a different number of neutrons. A hydrogen atom has three known isotopes: \u0026amp;nbsp;hydrogen, deuterium and tritium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define isotopes\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify isotopes of different elements\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate the number of protons and neutrons in different isotopes","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200024","TOPIC_ID":"hs200024","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200024.jpg","PUBLIC_BANNER_IMG":"HS200024.jpg","PUBLIC_VIDEO":"pvideo_hs200024.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/f4sZdLZU03k","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Isotopes are atoms that have the same number of protons and electrons, but a different number of neutrons. 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For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define a synthesis reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the synthesis reaction of magnesium oxide.\u003C\/div\u003E","CONT_DESC_AR":"A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic. An example of a synthesis reaction is the formation of water from hydrogen and oxygen.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define a synthesis reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate the synthesis reaction of magnesium oxide","BACKING_FILE":"hs200021.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200021","TOPIC_ID":"hs200021","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200021.jpg","PUBLIC_BANNER_IMG":"HS200021.jpg","PUBLIC_VIDEO":"pvideo_hs200021.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5RK8BgMSqAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance. For example, when magnesium ribbon is burnt in air, it combines with oxygen to form magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define a synthesis reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate the synthesis reaction of magnesium oxide.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0627\u062a\u062d\u0627\u062f","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 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The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. For example, when propane combines with oxygen, it produces heat and light.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify and define a combustion reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the combustion of propane and oxygen.\u003C\/div\u003E","CONT_DESC_AR":"A combustion reaction is a major class of chemical reactions. Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. In the more general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. Combustion is an exothermic reaction, so it releases heat.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u25cf explain what is a combustion reaction\u0026lt;br \/\u0026gt;\n\u25cf demonstrate combustion reaction of propane and oxygen\u0026lt;br \/\u0026gt;\n\u25cf identify a combustion reaction","BACKING_FILE":"hs200022.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200022","TOPIC_ID":"hs200022","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200022.jpg","PUBLIC_BANNER_IMG":"HS200022.jpg","PUBLIC_VIDEO":"pvideo_hs200022.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Wl8vJ7nbNbY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A combustion reaction is a type of chemical reaction in which a combustible substance reacts with oxygen to produce energy, in the form of heat and light. The presence of oxygen as one of the reactants is vital for a reaction to be a combustion reaction. 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For example, pure iron would only contain iron atoms, pure water would only contain molecules of water.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define substances.\u003C\/div\u003E \r\n\u003Cdiv\u003E- List elements as metals, nonmetals, or metalloids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify substances as elements or compounds.\u003C\/div\u003E","CONT_DESC_AR":"Pure substances are made of only one type of atom or only one type of molecule. 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"93","CATEGORY_ID":"1","CONT_TITLE":"Homogeneous Mixtures","CONT_SLUG":"homogeneous-mixtures","CONT_TITLE_AR":"Homogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is homogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is homogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200054","TOPIC_ID":"ms200054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200054.jpg","PUBLIC_BANNER_IMG":"MS200054.jpg","PUBLIC_VIDEO":"pvideo_ms200054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/elFGPE_TZxk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the properties of homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify whether a mixture is homogeneous or not.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u0627\u0644\u0645\u062a\u062c\u0627\u0646\u0633\u0629","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 10 - 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"85","CATEGORY_ID":"1","CONT_TITLE":"Heterogeneous Mixtures","CONT_SLUG":"heterogeneous-mixtures","CONT_TITLE_AR":"Heterogeneous Mixtures","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is heterogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is heterogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200053","TOPIC_ID":"ms200053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200053.jpg","PUBLIC_BANNER_IMG":"MS200053.jpg","PUBLIC_VIDEO":"pvideo_ms200053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BrPP-a75tI0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe heterogeneous mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of heterogeneous mixtures.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a mixture is heterogeneous or not.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u063a\u064a\u0631 \u0627\u0644\u0645\u062a\u062c\u0627\u0646\u0633\u0629","ADMSUBJECT_ID":"648","ADMCOURSE_ID":"125","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 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10","COUNTRY_ID":"278","SHORT_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"62","CATEGORY_ID":"1","CONT_TITLE":"Separating Mixtures: Using Magnets","CONT_SLUG":"separating-mixtures-using-magnets","CONT_TITLE_AR":"Separating Mixtures: Using Magnets","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EMixtures containing substances that are attracted by magnets can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only the iron is attracted to the magnet.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the procedure to separate the constituents of a mixture that are attracted toward a magnet.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the mixtures whose constituents can be separated by using a magnet.\u003C\/div\u003E","CONT_DESC_AR":"Mixtures containing substances that get attracted to magnet can be separated using a magnet. 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On the other hand, when a solid matter loses heat, it causes a process called freezing. In freezing, the motion of atoms or molecules slows down.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define melting and freezing.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid state and liquid state of matter can be interchanged.\u003C\/div\u003E","CONT_DESC_AR":"If solid matter gains enough heat, it changes state from solid to liquid, causing melting. 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On the other hand, when a solid matter loses heat, it causes a process called freezing. 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Particles of various types of matter have different characteristics. The particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003EBut, the particles of liquids are free to move. The particles in a gas have a high amount of energy, which makes it very easy to break apart gas particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different states of matter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the characteristics of the particles of matter.\u003C\/div\u003E","CONT_DESC_AR":"Matter exists in three states: solid, liquid, and gas.\u003C\/br\u003E\r\nParticles of various types of matter have different characteristics.\u003C\/br\u003E\r\nThe particles in solids are packed very closely. The spaces between the particles of liquids are almost the same as in solids.\u003C\/br\u003E\r\nBut, the particles of liquids are free to move. 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