{"pkgId":"38","subjectId":"783","fullwidthLayout":false,"contentData":{"PACKAGE_NAME":"Qatar Curriculum Full Access","PACKAGE_SLUG":"qatar-full","PACKAGE_IMG":"file_828164100_1592480838.png","ADMCOURSE_ID":"169","COURSE_NAME":"Grade 12","COUNTRY_ID":"283","STANDARD_NAME":"Qatar","ADMSUBJECT_ID":"783","DISPLAY_NAME":"Qatar - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Qatar - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","CAT_NAME":"\u0628\u0642\u0627\u0621 \u0627\u0644\u0645\u0627\u062f\u0629","CONT_ID":"483","CONT_TITLE":"Conservation of Mass","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EPhysical and chemical changes follow the law of conservation of mass. The law states that mass cannot be formed or destroyed. 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The interaction of six unhybridized 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalized pi-electron clouds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in phenol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the phenol molecule using its electrostatic potential map.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of phenol.\u003C\/div\u003E","CONT_DESC_AR":"In phenol hydroxy functional group is directly attached to the sp2 hybridised carbon atom of the benzene ring. 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The interaction of six unhybridized 2pz orbitals of carbon atoms of the benzene ring leads to the formation of delocalized pi-electron clouds.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the functional group present in phenol.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the charge distribution of the phenol molecule using its electrostatic potential map.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the orbital structure of phenol.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0641\u064a\u0646\u0648\u0644","ADMSUBJECT_ID":"783","ADMCOURSE_ID":"169","DISPLAY_NAME":"Qatar - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Qatar - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_DESC_AR":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"283","SHORT_NAME":"Qatar","DOMAIN_NAME":"STEM"},{"CONT_ID":"270","CATEGORY_ID":"1","CONT_TITLE":"Boyle\u2019s Law","CONT_SLUG":"boyles-law","CONT_TITLE_AR":"Boyle\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-03 10:59:33","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0628\u0648\u064a\u0644","ADMSUBJECT_ID":"783","ADMCOURSE_ID":"169","DISPLAY_NAME":"Qatar - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Qatar - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_DESC_AR":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"283","SHORT_NAME":"Qatar","DOMAIN_NAME":"STEM"},{"CONT_ID":"268","CATEGORY_ID":"1","CONT_TITLE":"Charles\u2019s Law","CONT_SLUG":"charles-law","CONT_TITLE_AR":"Charles\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECharles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-03 10:59:33","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the temperature and volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate Charles\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Charles\u0026#039;s law in practical problems.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0634\u0627\u0631\u0644","ADMSUBJECT_ID":"783","ADMCOURSE_ID":"169","DISPLAY_NAME":"Qatar - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Qatar - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_DESC_AR":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"283","SHORT_NAME":"Qatar","DOMAIN_NAME":"STEM"},{"CONT_ID":"262","CATEGORY_ID":"1","CONT_TITLE":"Structure of Benzene","CONT_SLUG":"structure-of-benzene","CONT_TITLE_AR":"Structure of Benzene","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the orbital structure of benzene.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"The molecular formula of benzene is C6H6 Kekule proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2\u0026amp;nbsp;hybridised.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n- identify Kekul\u0026amp;eacute; structures and the modern symbol of benzene\u0026lt;br \/\u0026gt;\n- explain the orbital structure of benzene\u0026lt;br \/\u0026gt;\n- explain the charge distribution of the benzene molecule using its electrostatic potential map","BACKING_FILE":"ss200043.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200043","TOPIC_ID":"ss200043","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200043.jpg","PUBLIC_BANNER_IMG":"SS200043.jpg","PUBLIC_VIDEO":"pvideo_ss200043.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/0FPZELqrUf4","DIST":null,"SHOW_ON_HOME":"Y","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-03 10:59:33","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;The molecular formula of benzene is C6H6. Kekul\u00e9 proposed that six carbon atoms of benzene are joined to each other by alternate single and double bonds to form a hexagonal ring. The orbital structure of benzene suggests that each carbon atom in benzene ring is sp2 hybridized.\u0026amp;nbsp;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\r\n\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify Kekul\u00e9 structures and the modern symbol of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the orbital structure of benzene.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of the benzene molecule using its electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0628\u0646\u0627\u0626\u064a \u0644\u0644\u0628\u0646\u0632\u064a\u0646","ADMSUBJECT_ID":"783","ADMCOURSE_ID":"169","DISPLAY_NAME":"Qatar - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Qatar - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_DESC_AR":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"283","SHORT_NAME":"Qatar","DOMAIN_NAME":"STEM"},{"CONT_ID":"259","CATEGORY_ID":"1","CONT_TITLE":"Aromatic Compounds","CONT_SLUG":"aromatic-compound","CONT_TITLE_AR":"Aromatic Compound","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EH\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the criteria for aromaticity described by H\u00fcckel.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Determine whether a molecule is aromatic or not by investigating its structure.\u003C\/div\u003E","CONT_DESC_AR":"Huckel postulated that planar cyclic conjugated polyenes containing delocalised (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6\u0026amp;pi; electrons and is aromatic.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the criteria for aromaticity described by Huckel\u0026lt;br \/\u0026gt;\n\u0026amp;bull; determine whether a molecule is aromatic or not by investigating its structure","BACKING_FILE":"ss200042.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200042","TOPIC_ID":"ss200042","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200042.jpg","PUBLIC_BANNER_IMG":"SS200042.jpg","PUBLIC_VIDEO":"pvideo_ss200042.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/N7AnvZ7Qtqw","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-01-03 10:59:33","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;H\u00fcckel postulated that planar cyclic conjugated polyenes containing delocalized (4n+2) pi-electrons are called aromatic compounds. An example is the benzene molecule, which has 6 \u03c0 electrons is aromatic.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the criteria for aromaticity described by H\u00fcckel.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Determine whether a molecule is aromatic or not by investigating its structure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629","ADMSUBJECT_ID":"783","ADMCOURSE_ID":"169","DISPLAY_NAME":"Qatar - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Qatar - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_DESC_AR":"\u064a\u062a\u0639\u0644\u0645 \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0628\u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u0645\u0641\u0627\u0647\u064a\u0645 \u0645\u062b\u0644 \u0628\u0642\u0627\u0621 \u0627\u0644\u0643\u062a\u0644\u0629 \u062e\u0644\u0627\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u060c \u0642\u0648\u0627\u0646\u064a\u0646 \u0628\u0648\u064a\u0644 \u0648\u0634\u0627\u0631\u0644 \u0648\u062a\u0631\u0643\u064a\u0628 \u0627\u0644\u0641\u064a\u0646\u0648\u0644 \u0648\u0627\u0644\u0628\u0646\u0632\u064a\u0646 \u0648\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0623\u0631\u0648\u0645\u0627\u062a\u064a\u0629 \u0627\u0644\u0645\u062e\u062a\u0644\u0641\u0629.","SUBJECT_IMG":"","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"283","SHORT_NAME":"Qatar","DOMAIN_NAME":"STEM"}],"levelObject":{"0":"Mass","1":"Substance","2":"Law Of Conservation Of Mass","3":"Precipitate","4":"Reactants And Products","8":"Chemical Equation And Reaction"},"contData":{"CONT_ID":"483","CATEGORY_ID":"1","CONT_TITLE":"Conservation of Mass","CONT_SLUG":"conservation-of-mass","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EPhysical and chemical changes follow the law of conservation of mass. The law states that mass cannot be formed or destroyed. Mass remains constant before and after a change.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the law of conservation of mass.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate the law of conservation of mass in physical changes.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate the law of conservation of mass in chemical changes.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200273","TOPIC_ID":"ms200273","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200273.jpg","PUBLIC_BANNER_IMG":"MS200273.jpg","PUBLIC_VIDEO":"pvideo_ms200273.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SRqPI8TJjuM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2017-10-05 12:13:33","CREATED_BY":"0","UPDATED_ON":"2024-10-08 09:00:16","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Physical and chemical changes follow the law of conservation of mass. The law states that mass cannot be formed or destroyed. Mass remains constant before and after a change.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the law of conservation of mass.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Illustrate the law of conservation of mass in physical changes.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Illustrate the law of conservation of mass in chemical changes.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Conservation of mass","DISPLAY_NAME":"NGSS New - Middle School - Physical Science","DISPLAY_NAME_AR":"NGSS New - Middle School - Physical Science","SUBJECT_IMG":"569.jpg","ADMSUBJECT_ID":"569","SUBJECT_NAME":"Physical Science","SUBJECT_NAME_AR":"Physical Science","ADMCOURSE_ID":"191","COURSE_NAME":"Middle School","COUNTRY_ID":"287","STANDARD_ID":"287","SHORT_NAME":"NGSS","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u4e2d\u6587","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Portugu\u00eas ","Ti\u1ebfng Vi\u1ec7t"],"devices":["UmetyVR","WebXR"]}