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Increasing the concentration of reactants increases collisions between particles, which leads to a higher reaction rate. An increase in pressure compresses the particles into a smaller volume. This increases the frequency of collisions, resulting in an increased reaction rate.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the effects of concentration and pressure on reaction rates.\u003C\/div\u003E","CONT_SLUG":"concentration-pressure-and-reaction-rate","BACKING_FILE":null,"CONT_SRC":null,"CONTTYPE_ID":"9","PUBLIC_IMG":"thumb_vc000039.jpg","PUBLIC_BANNER_IMG":"vc000039.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000039.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Qa_-BWzLeLM","PACKAGE_DOMAIN":"STEM"},"pkgCourses":[{"ADMCOURSE_ID":"121","COURSE_NAME":"\u0627\u0644\u0635\u0641 6","COUNTRY_ID":"278","SHORT_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","ADMSUBJECT_ID":"631","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - 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Increasing the concentration of reactants increases collisions between particles, which leads to a higher reaction rate. An increase in pressure compresses the particles into a smaller volume. This increases the frequency of collisions, resulting in an increased reaction rate.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the effects of concentration and pressure on reaction rates.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000039","TOPIC_ID":"vc000039","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000039.jpg","PUBLIC_BANNER_IMG":"vc000039.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000039.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Qa_-BWzLeLM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Collision theory states that the rate of a reaction depends on successful collisions of reactant molecules. Increasing the concentration of reactants increases collisions between particles, which leads to a higher reaction rate. An increase in pressure compresses the particles into a smaller volume. 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Some of the common functional groups present in organic compounds include -OH, -CHO, -CO, -COOH, C=C, C\u2261C, and halogen. 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Nucleic acid is made up of nucleotides. A nucleotide consists of a sugar, phosphate and nitrogenous base.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what a nucleic acid is.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of a nucleotide.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the different components of RNA and DNA.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a nucleic acid.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200408","TOPIC_ID":"hs200408","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200408.jpg","PUBLIC_BANNER_IMG":"HS200408.jpg","PUBLIC_VIDEO":"pvideo_hs200408.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/L5hwt0XTjzc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Nucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. 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An increase in the speed of collisions increases the collision frequency, and as a result, the rate of the reaction increases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that reaction rates are different for different reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Correlate the rate of reaction to the properties of the particles through collision theory.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200368","TOPIC_ID":"hs200368","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200368.jpg","PUBLIC_BANNER_IMG":"HS200368.jpg","PUBLIC_VIDEO":"pvideo_hs200368.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/toTm_ZvcVRY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The rate of a chemical reaction is the speed at which it occurs. Different reactions happen at different rates.\u0026amp;nbsp; According to collision theory, collisions between reactant molecules having sufficient energy lead to product formation. 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However, the dissolving nature also depends on the charge of the ions in the solution. Non-polar substances have Van der Waals attractions which are weak but present.\u003C\/div\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify water as a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify ethanol as a polar solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify sodium chloride as an ionic solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify hexane as a nonpolar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify pentane as a nonpolar solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a polar solute in a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving an ionic solute in a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200323.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200323","TOPIC_ID":"hs200323","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200323.jpg","PUBLIC_BANNER_IMG":"HS200323.jpg","PUBLIC_VIDEO":"pvideo_hs200323.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hLIZIr9usZ0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Polar solutes tend to dissolve in polar solvents; nonpolar solutes tend to dissolve in nonpolar solvents. However, the dissolving nature also depends on the charge of the ions in the solution.\u0026amp;nbsp;\u0026lt;span style=\u0026quot;color: rgb(38, 50, 56); font-family: Roboto, sans-serif;\u0026quot;\u0026gt;Non-polar substances have Van der Waals attractions which are weak but present.\u0026lt;\/span\u0026gt;\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify water as a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify ethanol as a polar solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify sodium chloride as an ionic solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify hexane as a nonpolar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify pentane as a nonpolar solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving a polar solute in a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving an ionic solute in a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062b\u0644 \u064a\u0630\u064a\u0628 \u0627\u0644\u0645\u062b\u0644","ADMSUBJECT_ID":"650","ADMCOURSE_ID":"127","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 12 - \u0643\u064a\u0645\u064a\u0627\u0621","DISPLAY_NAME_AR":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 12 - 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"398","CATEGORY_ID":"1","CONT_TITLE":"Bases","CONT_SLUG":"bases","CONT_TITLE_AR":"Bases","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EA base is a compound that gives hydroxide ion on ionization. Bases are usually bitter in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define bases.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of bases.\u003C\/div\u003E","CONT_DESC_AR":"A base is a compound that gives hydroxide ion on ionisation. Bases are usually bitter in taste.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation, you will be able to:\u003C\/br\u003E\r\n\u2022 define bases\u003C\/br\u003E\r\n\u2022 identify the properties of bases","BACKING_FILE":"hs200060.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200060","TOPIC_ID":"hs200060","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200060.jpg","PUBLIC_BANNER_IMG":"HS200060.jpg","PUBLIC_VIDEO":"pvideo_hs200060.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/44_TMLTKv5A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\u003Cbr\u003E\u003Cdiv\u003EA base is a compound that gives hydroxide ion on ionization. Bases are usually bitter in taste.\u003C\/div\u003E\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E\u003Cdiv\u003E\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E\u003Cdiv\u003E- Define bases.\u003C\/div\u003E\u003Cdiv\u003E- Identify the properties of bases.\u003C\/div\u003E\u003C\/div\u003E","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0642\u0648\u0627\u0639\u062f","ADMSUBJECT_ID":"650","ADMCOURSE_ID":"127","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 12 - \u0643\u064a\u0645\u064a\u0627\u0621","DISPLAY_NAME_AR":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"370","CATEGORY_ID":"1","CONT_TITLE":"pH of a Solution","CONT_SLUG":"ph-of-a-solution","CONT_TITLE_AR":"pH of a Solution","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn aqueous solution can be acidic, basic or neutral based, on the pH of the solution. 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\u0627\u0644\u0646\u0648\u0648\u064a.","SUBJECT_IMG":"ksa_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"\u0627\u0644\u0635\u0641 12","COUNTRY_ID":"278","SHORT_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"369","CATEGORY_ID":"1","CONT_TITLE":"Balancing Redox Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. 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\u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"366","CATEGORY_ID":"1","CONT_TITLE":"Dissolving Solids in Liquids","CONT_SLUG":"dissolving-solids-in-liquids","CONT_TITLE_AR":"Dissolving Solids in Liquids","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESolids that are soluble in a particular liquid when dissolved in that liquid, form a homogenous solution. Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid solutes dissolve in liquid solvents.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the change in the properties of solids when dissolved in liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solids that can be dissolved in water.\u003C\/div\u003E","CONT_DESC_AR":"Solids that are soluble in a particular liquid when dissolved form homogenous solution. 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Solutions with a pH less than 7 are acidic and solutions with a pH greater than 7 are basic. Pure water is neutral, at pH 7, being neither an acid nor a base.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the difference between acidic, basic, and neutral solutions on the basis of their pH value.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify solutions as acidic or basic based on their pH values.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the relationship between hydronium ion concentration and pH value.\u003C\/div\u003E","CONT_DESC_AR":"The pH level is a numeric scale used to specify the acidity or basicity of an aqueous solution. Solutions with a pH less than 7 are acidic and solutions with a pH greater than 7 are basic. Pure water is neutral, at pH 7, being neither an acid nor a base.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define the pH of an aqueous solution and its importance\u0026lt;br \/\u0026gt;\n\u0026amp;bull; memorize the application of pH\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate pH for a given concentration of hydronium ion","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200066","TOPIC_ID":"ms200066","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200066.jpg","PUBLIC_BANNER_IMG":"MS200066.jpg","PUBLIC_VIDEO":"pvideo_ms200066.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/OFZ9pgaM2so","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The pH level is a numeric scale used to specify the acidity or basicity of an aqueous solution. Solutions with a pH less than 7 are acidic and solutions with a pH greater than 7 are basic. Pure water is neutral, at pH 7, being neither an acid nor a base.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the difference between acidic, basic, and neutral solutions on the basis of their pH value.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Classify solutions as acidic or basic based on their pH values.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the relationship between hydronium ion concentration and pH value.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0627 \u0647\u0648 \u0627\u0644\u0623\u0633 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u062c\u064a\u0646\u064a\u061f","ADMSUBJECT_ID":"650","ADMCOURSE_ID":"127","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 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Alkalies dissociate in water and release hydroxide ions. The process in which released hydrogen ions combine with hydroxide ions to form water is called the neutralization reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the ions present in acids and bases.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate the neutralization reaction of an acid and a base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Combine ions to perform a neutralization reaction between an acid and a base.\u003C\/div\u003E","CONT_DESC_AR":"Acids dissociate in water and release hydrogen ions. Alkalies dissociate in water and release hydroxide ions. The process in which released hydrogen ions combine with hydroxide ions to form water is called the neutralisation reaction.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;middot; identify the ions present in acids and bases\u0026lt;br \/\u0026gt;\n\u0026amp;middot; demonstrate the neutralisation reaction of an acid and a base\u0026lt;br \/\u0026gt;\n\u0026amp;middot; combine ions to perform a neutralisation reaction between an acid and a base","BACKING_FILE":"hs200001.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200001","TOPIC_ID":"hs200001","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200001.jpg","PUBLIC_BANNER_IMG":"HS200001.jpg","PUBLIC_VIDEO":"pvideo_hs200001.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/QesxBXOtRF4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Acids dissociate in water and release hydrogen ions. 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For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the increase in the reaction rate with the increase in temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate the effect of temperature on the reaction rate.\u003C\/div\u003E","CONT_DESC_AR":"The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u0026amp;deg; rise in temperature. This increase is mainly due to the increase in the number of collisions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the increase in the reaction rate with the increase in temperature\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate the effect of temperature on the reaction rate\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the concept in practical problems","BACKING_FILE":"ss200058.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200058","TOPIC_ID":"ss200058","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200058.jpg","PUBLIC_BANNER_IMG":"SS200058.jpg","PUBLIC_VIDEO":"pvideo_ss200058.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/d7IKyDsgrAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the increase in the reaction rate with the increase in temperature.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate the effect of temperature on the reaction rate.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0623\u062b\u064a\u0631 \u0627\u0644\u062d\u0631\u0627\u0631\u0629 \u0639\u0644\u0649 \u0645\u0639\u062f\u0644 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In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the IUPAC name of an alcohol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the general formula of a homologous series of alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridised carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the functional group present in alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the IUPAC name of an alcohol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the general formula of a homologous series of alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the charge distribution of a methanol molecule using an electrostatic potential map","BACKING_FILE":"ss200055.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200055","TOPIC_ID":"ss200055","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200055.jpg","PUBLIC_BANNER_IMG":"ss200055.jpg","PUBLIC_VIDEO":"pvideo_ss200055.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J-IuFLRYZjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. 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This increase is called the elevation in boiling point.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Theoretically calculate the boiling point elevation of a solution containing a non-volatile solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Experimentally calculate the boiling point of a solution containing a non-volatile solute.\u003C\/div\u003E","CONT_DESC_AR":"The boiling point of a solution is always higher than that of the pure solvent. 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We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the relation between the standard cell potential and the feasibility of a cell reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the conditions where a galvanic cell reaction is feasible.\u003C\/div\u003E","CONT_DESC_AR":"For a Galvanic cell reaction to be feasible the standard cell potential must be positive. 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In a galvanic cell, the metal which is more reactive is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of galvanic cells.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the components used to construct a galvanic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a galvanic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe how a galvanic cell functions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the importance of a salt bridge in a galvanic cell.\u003C\/div\u003E","CONT_DESC_AR":"A Galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. In a Galvanic cell the more reactive metal is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of Galvanic cells.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the pieces of equipment used to construct a galvanic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; construct a galvanic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe how a galvanic cell functions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the importance of a salt bridge in a galvanic cell","BACKING_FILE":"ss200010.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200010","TOPIC_ID":"ss200010","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200010.jpg","PUBLIC_BANNER_IMG":"SS200010.jpg","PUBLIC_VIDEO":"pvideo_ss200010.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xfKUW6Cwxn4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. 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Electric batteries are examples of galvanic cells.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the components used to construct a galvanic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct a galvanic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe how a galvanic cell functions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;-\u0026amp;nbsp;\u0026lt;span style=\u0026quot;color: rgb(0, 0, 0); font-family: Arial; white-space: pre-wrap;\u0026quot;\u0026gt;Explain the importance of a salt bridge in a galvanic 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\r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAccording to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u003C\/div\u003E","CONT_DESC_AR":"According to Le Chateliers principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. 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This principle is applicable to both physical as well as chemical equilibrium.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0627\u0644\u0639\u0648\u0627\u0645\u0644 \u0627\u0644\u0645\u0624\u062b\u0631\u0629 \u0639\u0644\u0649 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Acids are usually sour in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objective:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- List some common acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of acids.\u003C\/div\u003E","CONT_DESC_AR":"An acid is a compound that gives hydronium ions on ionisation. Acids are usually sour in taste.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; list some common acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the properties of acids","BACKING_FILE":"hs200059.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200059","TOPIC_ID":"hs200059","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200059.jpg","PUBLIC_BANNER_IMG":"HS200059.jpg","PUBLIC_VIDEO":"pvideo_hs200059.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1DN17OR4aBk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An acid is a chemical species that donates protons or hydrogen ions and\/or accepts electrons. Acids are usually sour in taste.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objective\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- List some common acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify the properties of acids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0623\u062d\u0645\u0627\u0636","ADMSUBJECT_ID":"650","ADMCOURSE_ID":"127","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 12 - \u0643\u064a\u0645\u064a\u0627\u0621","DISPLAY_NAME_AR":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 12 - 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chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium 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homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is homogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is homogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200054","TOPIC_ID":"ms200054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200054.jpg","PUBLIC_BANNER_IMG":"MS200054.jpg","PUBLIC_VIDEO":"pvideo_ms200054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/elFGPE_TZxk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents. \u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain the properties of homogeneous mixtures.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify whether a mixture is homogeneous or not.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u0627\u0644\u0645\u062a\u062c\u0627\u0646\u0633\u0629","ADMSUBJECT_ID":"650","ADMCOURSE_ID":"127","DISPLAY_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629 - \u0627\u0644\u0635\u0641 12 - 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In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is heterogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is heterogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200053","TOPIC_ID":"ms200053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200053.jpg","PUBLIC_BANNER_IMG":"MS200053.jpg","PUBLIC_VIDEO":"pvideo_ms200053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BrPP-a75tI0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"0000-00-00 00:00:00","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. 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\u0627\u0644\u0646\u0648\u0648\u064a.","SUBJECT_IMG":"ksa_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"\u0627\u0644\u0635\u0641 12","COUNTRY_ID":"278","SHORT_NAME":"\u0627\u0644\u0645\u0645\u0644\u0643\u0629 \u0627\u0644\u0639\u0631\u0628\u064a\u0629 \u0627\u0644\u0633\u0639\u0648\u062f\u064a\u0629","DOMAIN_NAME":"STEM"},{"CONT_ID":"51","CATEGORY_ID":"1","CONT_TITLE":"Single Displacement Reaction","CONT_SLUG":"single-displacement-reaction","CONT_TITLE_AR":"Single Displacement Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E 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This increases the frequency of collisions, resulting in an increased reaction rate.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the effects of concentration and pressure on reaction rates.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000039","TOPIC_ID":"vc000039","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000039.jpg","PUBLIC_BANNER_IMG":"vc000039.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000039.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Qa_-BWzLeLM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-07-04 06:35:37","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 11:51:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Collision theory states that the rate of a reaction depends on successful collisions of reactant molecules. 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