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Rates","CONT_SLUG":"reaction-rates","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe rate of a chemical reaction is the speed at which it occurs. Different reactions happen at different rates. According to collision theory, collisions between reactant molecules having sufficient energy lead to product formation. An increase in the speed of collisions increases the collision frequency, and as a result, the rate of the reaction increases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that reaction rates are different for different reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Correlate the rate of reaction to the properties of the particles through collision theory.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200368","TOPIC_ID":"hs200368","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200368.jpg","PUBLIC_BANNER_IMG":"HS200368.jpg","PUBLIC_VIDEO":"pvideo_hs200368.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/toTm_ZvcVRY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The rate of a chemical reaction is the speed at which it occurs. Different reactions happen at different rates.\u0026amp;nbsp; According to collision theory, collisions between reactant molecules having sufficient energy lead to product formation. An increase in the speed of collisions increases the collision frequency, and as a result, the rate of the reaction increases.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain that reaction rates are different for different reactions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Correlate the rate of reaction to the properties of the particles through collision theory.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0639\u062f\u0644\u0627\u062a \u0627\u0644\u062a\u0641\u0627\u0639\u0644","ADMSUBJECT_ID":"669","ADMCOURSE_ID":"155","DISPLAY_NAME":"Jordan - Grade 12 - 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12","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"484","CATEGORY_ID":"1","CONT_TITLE":"Effect of Surface Area on Reaction Rate","CONT_SLUG":"effect-of-surface-area-on-reaction-rate","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWhen a solid lump is subdivided into fine powder, the surface area increases and more particles are exposed for collisions. This results in an increased frequency of collisions and therefore a faster rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to :\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the effect of surface area of solid reactant on rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate graphically the effect of surface area of solid reactant on rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of increasing surface area on reaction rate using collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply this concept in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200277","TOPIC_ID":"hs200277","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200277.jpg","PUBLIC_BANNER_IMG":"HS200277.jpg","PUBLIC_VIDEO":"pvideo_hs200277.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/m8t8U2eJnj0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;When a solid lump is subdivided into fine powder, the surface area increases and more particles are exposed for collisions. 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These are essential molecules for existence of life on earth. 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hydroxide ion on ionization. Bases are usually bitter in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define bases.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of bases.\u003C\/div\u003E","CONT_DESC_AR":"A base is a compound that gives hydroxide ion on ionisation. Bases are usually bitter in taste.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation, you will be able to:\u003C\/br\u003E\r\n\u2022 define bases\u003C\/br\u003E\r\n\u2022 identify the properties of bases","BACKING_FILE":"hs200060.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200060","TOPIC_ID":"hs200060","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200060.jpg","PUBLIC_BANNER_IMG":"HS200060.jpg","PUBLIC_VIDEO":"pvideo_hs200060.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/44_TMLTKv5A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E\u003Cbr\u003E\u003Cdiv\u003EA base is a compound that gives hydroxide ion on ionization. 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A neutral solution like pure water has an equal number of hydronium ions and hydroxide ions, while an acidic solution has more hydronium ions than hydroxide ions, and basic solutions have more hydroxide ions than hydronium ions.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Measure the pH of a strong acid with the help of a pH meter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Measure the pH of a strong base with the help of a pH meter.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a solution is acidic or basic.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the pH of a strong acid.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Calculate the pH of a strong base.\u003C\/div\u003E","CONT_DESC_AR":"An aqueous solution can be acidic, basic or neutral based on the pH of the solution. A neutral solution like pure water has an equal number of hydronium ions and hydroxide ions, while an acidic solution has more hydronium ions than hydroxide ions, and basic solutions have more hydroxide ions than hydronium ions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a solution is acidic, basic or neutral\u0026lt;br \/\u0026gt;\n\u0026amp;bull;\u0026amp;nbsp;calculate the pH of an aqueous solution\u0026lt;br \/\u0026gt;\n\u0026amp;bull;\u0026amp;nbsp;calculate\u0026amp;nbsp;the hydronium ion and hydroxide ion concentrations of an aqueous\u0026amp;nbsp;solution","BACKING_FILE":"ss200071.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200071","TOPIC_ID":"ss200071","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200071.jpg","PUBLIC_BANNER_IMG":"SS200071.jpg","PUBLIC_VIDEO":"pvideo_ss200071.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KOn_tFIwyd4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;An aqueous solution can be acidic, basic or neutral based, on the pH of the solution. 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meter.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify whether a solution is acidic or basic.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Calculate the pH of a strong acid.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Calculate the pH of a strong base\u0026lt;\/span\u0026gt;.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0623\u0633 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u062c\u064a\u0646\u064a \u0644\u0644\u0645\u062d\u0644\u0648\u0644.","ADMSUBJECT_ID":"669","ADMCOURSE_ID":"155","DISPLAY_NAME":"Jordan - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 12 - 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Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance oxidation half-reaction and reduction half-reaction separately.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0648\u0627\u0632\u0646\u0629 \u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0623\u0643\u0633\u062f\u0629 \u0648\u0627\u0644\u0627\u062e\u062a\u0632\u0627\u0644","ADMSUBJECT_ID":"669","ADMCOURSE_ID":"155","DISPLAY_NAME":"Jordan - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u0646\u064f\u0638\u0651\u0650\u0645\u062a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0644\u0644\u0645\u0633\u062a\u0648\u0649 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 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\u0628\u0627\u0644\u0642\u0627\u0639\u062f\u0629.\u003Cbr\u003E","SUBJECT_DESC_AR":"\u0646\u064f\u0638\u0651\u0650\u0645\u062a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0644\u0644\u0645\u0633\u062a\u0648\u0649 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \u0637\u064f\u0628\u0651\u0650\u0642\u062a \u062e\u0635\u0627\u0626\u0635 \u0627\u0644\u062f\u064a\u0646\u0627\u0645\u0643\u064a\u0629 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0648\u0627\u0644\u062e\u0648\u0627\u0635 \u0627\u0644\u062d\u0631\u0643\u064a\u0629\u060c \u0648\u0627\u0644\u0633\u0645\u0627\u062a \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a 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\u0627\u0644\u0645\u0631\u0643\u0628\u0627\u062a \u0627\u0644\u0639\u0636\u0648\u064a\u0629 \u0648\u0627\u0644\u0643\u0648\u0627\u0634\u0641 \u0648\u0627\u0644\u0645\u062d\u0627\u0644\u064a\u0644 \u0627\u0644\u0645\u0646\u0638\u0651\u064e\u0645\u0629 \u0648\u0645\u0639\u0627\u064a\u0631\u0629 \u0627\u0644\u062d\u0645\u0636 \u0628\u0627\u0644\u0642\u0627\u0639\u062f\u0629.","SUBJECT_IMG":"jordan_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"356","CATEGORY_ID":"1","CONT_TITLE":"The pH Scale","CONT_SLUG":"the-ph-scale","CONT_TITLE_AR":"The pH Scale","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe pH scale ranges from 0 to 14. Aqueous solutions with a pH of less than 7 are acidic. Aqueous solutions with pH more than 7 are basic. Aqueous solutions with a pH exactly equal to 7 are neutral. Acidity increases as the solution move below 7, with pH 1 being the most acidic. Basicity increases as the solution move above 7, with pH 14 being the most basic.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the pH scale.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare different acids, bases and neutral solutions on the pH scale.\u003C\/div\u003E","CONT_DESC_AR":"The pH scale ranges from 0 to 14. Aqueous solutions with a pH of less than 7 are acidic. Aqueous solutions with pH more than 7 are basic. Aqueous solutions with a pH exactly equal to 7 are neutral. Acidity increases as we move below 7, with pH 1 being the most acidic. Basicity increases as we move above 7, with pH 14 being the most basic.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define the pH scale\u0026lt;br \/\u0026gt;\n\u0026amp;bull; compare different acids, bases and neutral solutions in a pH scale","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200067","TOPIC_ID":"ms200067","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200067.jpg","PUBLIC_BANNER_IMG":"MS200067.jpg","PUBLIC_VIDEO":"pvideo_ms200067.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/9cl_CJSsVww","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The pH scale ranges from 0 to 14. Aqueous solutions with a pH of less than 7 are acidic. Aqueous solutions with pH more than 7 are basic. Aqueous solutions with a pH exactly equal to 7 are neutral. Acidity increases as the solution move below 7, with pH 1 being the most acidic. Basicity increases as the solution move above 7, with pH 14 being the most basic.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the pH scale.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Compare different acids, bases and neutral solutions on the pH scale.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0642\u064a\u0627\u0633 \u0627\u0644\u0623\u0633 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u062c\u064a\u0646\u064a","ADMSUBJECT_ID":"669","ADMCOURSE_ID":"155","DISPLAY_NAME":"Jordan - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u0646\u064f\u0638\u0651\u0650\u0645\u062a \u0648\u062d\u062f\u0627\u062a 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level is a numeric scale used to specify the acidity or basicity of an aqueous solution. Solutions with a pH less than 7 are acidic and solutions with a pH greater than 7 are basic. Pure water is neutral, at pH 7, being neither an acid nor a base.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the difference between acidic, basic, and neutral solutions on the basis of their pH value.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Classify solutions as acidic or basic based on their pH values.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the relationship between hydronium ion concentration and pH value.\u003C\/div\u003E","CONT_DESC_AR":"The pH level is a numeric scale used to specify the acidity or basicity of an aqueous solution. Solutions with a pH less than 7 are acidic and solutions with a pH greater than 7 are basic. Pure water is neutral, at pH 7, being neither an acid nor a base.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define the pH of an aqueous solution and its importance\u0026lt;br \/\u0026gt;\n\u0026amp;bull; memorize the application of pH\u0026lt;br \/\u0026gt;\n\u0026amp;bull; calculate pH for a given concentration of hydronium ion","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200066","TOPIC_ID":"ms200066","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200066.jpg","PUBLIC_BANNER_IMG":"MS200066.jpg","PUBLIC_VIDEO":"pvideo_ms200066.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/OFZ9pgaM2so","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;The pH level is a numeric scale used to specify the acidity or basicity of an aqueous solution. Solutions with a pH less than 7 are acidic and solutions with a pH greater than 7 are basic. Pure water is neutral, at pH 7, being neither an acid nor a base.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the difference between acidic, basic, and neutral solutions on the basis of their pH value.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Classify solutions as acidic or basic based on their pH values.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the relationship between hydronium ion concentration and pH value.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0627 \u0647\u0648 \u0627\u0644\u0623\u0633 \u0627\u0644\u0647\u064a\u062f\u0631\u0648\u062c\u064a\u0646\u064a\u061f","ADMSUBJECT_ID":"669","ADMCOURSE_ID":"155","DISPLAY_NAME":"Jordan - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 12 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For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the increase in the reaction rate with the increase in temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate the effect of temperature on the reaction rate.\u003C\/div\u003E","CONT_DESC_AR":"The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u0026amp;deg; rise in temperature. This increase is mainly due to the increase in the number of collisions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the increase in the reaction rate with the increase in temperature\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate the effect of temperature on the reaction rate\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the concept in practical problems","BACKING_FILE":"ss200058.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200058","TOPIC_ID":"ss200058","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200058.jpg","PUBLIC_BANNER_IMG":"SS200058.jpg","PUBLIC_VIDEO":"pvideo_ss200058.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/d7IKyDsgrAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the increase in the reaction rate with the increase in temperature.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate the effect of temperature on the reaction rate.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0623\u062b\u064a\u0631 \u0627\u0644\u062d\u0631\u0627\u0631\u0629 \u0639\u0644\u0649 \u0645\u0639\u062f\u0644 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Molecular models are used for better visualization and perception of 3D structures of organic molecules.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain various structural representations such as molecular formula, structural formula, and bond-line formula used to represent organic compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain ball and stick models and space filling models of organic compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Compare the molecular formula, structural formula, bond-line formula, and ball and stick model.\u003C\/div\u003E","CONT_DESC_AR":"Various structural representations used to represent organic compounds include complete structural formula, bond-line structural formula and polygon formula. 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In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the IUPAC name of an alcohol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the general formula of a homologous series of alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridised carbon atom. 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Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the detailed procedure for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the laboratory setup for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the application of the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Extrapolate the graph for the titration of a strong acid with a strong base.\u003C\/div\u003E","CONT_DESC_AR":"Strong acid-strong base titration is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the detailed procedure for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the laboratory setup for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the application of titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; extrapolate the graph for the titration of a strong acid with a strong base","BACKING_FILE":"ss200032.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200032","TOPIC_ID":"ss200032","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200032.jpg","PUBLIC_BANNER_IMG":"SS200032.jpg","PUBLIC_VIDEO":"pvideo_ss200032.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/R4ghDnAEBuo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Titration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the detailed procedure for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the laboratory setup for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the application of the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Extrapolate the graph for the titration of a strong acid with a strong 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In electrolysis, electrical energy is used to carry out a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the components used to construct an electrolytic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the working principle of an electrolytic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the applications of electrolytic cells.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct an electrolytic cell.\u003C\/div\u003E","CONT_DESC_AR":"The apparatus in which electrolysis is carried out is called electrolytic cell. 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We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the relation between the standard cell potential and the feasibility of a cell reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the conditions where a galvanic cell reaction is feasible.\u003C\/div\u003E","CONT_DESC_AR":"For a Galvanic cell reaction to be feasible the standard cell potential must be positive. We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the relation between the standard cell potential and the feasibility of a cell reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the conditions where a galvanic cell reaction is feasible","BACKING_FILE":"ss200037.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200037","TOPIC_ID":"ss200037","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200037.jpg","PUBLIC_BANNER_IMG":"SS200037.jpg","PUBLIC_VIDEO":"pvideo_ss200037.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/peQvICwZjAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For a galvanic cell reaction to be feasible, the standard cell potential must be positive. We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the relation between the standard cell potential and the feasibility of a cell reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the conditions where a galvanic cell reaction is feasible.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0625\u0645\u0643\u0627\u0646\u064a\u0629 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u062e\u0644\u064a\u0629 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In a galvanic cell, the metal which is more reactive is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of galvanic cells.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the components used to construct a galvanic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a galvanic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe how a galvanic cell functions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the importance of a salt bridge in a galvanic cell.\u003C\/div\u003E","CONT_DESC_AR":"A Galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. In a Galvanic cell the more reactive metal is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of Galvanic cells.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the pieces of equipment used to construct a galvanic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; construct a galvanic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe how a galvanic cell functions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the importance of a salt bridge in a galvanic cell","BACKING_FILE":"ss200010.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200010","TOPIC_ID":"ss200010","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200010.jpg","PUBLIC_BANNER_IMG":"SS200010.jpg","PUBLIC_VIDEO":"pvideo_ss200010.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xfKUW6Cwxn4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. In a galvanic cell, the metal which is more reactive is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of galvanic cells.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the components used to construct a galvanic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct a galvanic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe how a galvanic cell functions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;-\u0026amp;nbsp;\u0026lt;span style=\u0026quot;color: rgb(0, 0, 0); font-family: Arial; white-space: pre-wrap;\u0026quot;\u0026gt;Explain the importance of a salt bridge in a galvanic 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Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define catalyst.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of a catalyst on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how a catalyst increases the rate of a chemical reaction.\u003C\/div\u003E","CONT_DESC_AR":"A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define catalyst\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain effect of catalyst on the rate of a chemical reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how a catalyst increases the rate of a chemical reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200020","TOPIC_ID":"ss200020","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200020.jpg","PUBLIC_BANNER_IMG":"ss200020.jpg","PUBLIC_VIDEO":"pvideo_ss200020.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EpkHrhW2Xxc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. 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12","COUNTRY_ID":"281","SHORT_NAME":"Jordan","DOMAIN_NAME":"STEM"},{"CONT_ID":"188","CATEGORY_ID":"1","CONT_TITLE":" Acids","CONT_SLUG":"acids","CONT_TITLE_AR":"The Acid","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAn acid is a chemical species that donates protons or hydrogen ions and\/or accepts electrons. Acids are usually sour in taste.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning objective:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Define acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- List some common acids. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the properties of acids.\u003C\/div\u003E","CONT_DESC_AR":"An acid is a compound that gives hydronium ions on ionisation. Acids are usually sour in taste.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; list some common acids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the properties of acids","BACKING_FILE":"hs200059.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200059","TOPIC_ID":"hs200059","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200059.jpg","PUBLIC_BANNER_IMG":"HS200059.jpg","PUBLIC_VIDEO":"pvideo_hs200059.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/1DN17OR4aBk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;An acid is a chemical species that donates protons or hydrogen ions and\/or accepts electrons. Acids are usually sour in taste.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objective\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Define acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- List some common acids.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Identify the properties of acids.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0623\u062d\u0645\u0627\u0636","ADMSUBJECT_ID":"669","ADMCOURSE_ID":"155","DISPLAY_NAME":"Jordan - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Jordan - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u0646\u064f\u0638\u0651\u0650\u0645\u062a \u0648\u062d\u062f\u0627\u062a \u0645\u0627\u062f\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621 \u0644\u0644\u0645\u0633\u062a\u0648\u0649 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 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anions to form two new compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is double displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 11:02:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what is double displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- 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\r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a single displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate a single displacement reaction.\u003C\/div\u003E","CONT_DESC_AR":"A single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able 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Increasing the concentration of reactants increases collisions between particles, which leads to a higher reaction rate. An increase in pressure compresses the particles into a smaller volume. This increases the frequency of collisions, resulting in an increased reaction rate.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the effects of concentration and pressure on reaction rates.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000039","TOPIC_ID":"vc000039","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000039.jpg","PUBLIC_BANNER_IMG":"vc000039.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000039.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Qa_-BWzLeLM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-07-04 06:35:37","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 11:51:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Collision theory states that the rate of a reaction depends on successful collisions of reactant molecules. 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