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If any functional group is present in an organic compound, it is denoted in the compound\u0026#039;s name with either a prefix or a suffix.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe functional groups.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explore how to name molecules with functional groups. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Recognize organic compounds using the IUPAC name.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000002","TOPIC_ID":"vc000002","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000002.jpg","PUBLIC_BANNER_IMG":"vc000002.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000002.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Vnb13VHiLtU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"2143","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Functional groups are a special group of atoms or bonds within molecules that are responsible for the characteristic reactions of those molecules. 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They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the intermolecular spaces between particles of liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between particles of liquids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200425.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200425","TOPIC_ID":"ms200425","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200425.jpg","PUBLIC_BANNER_IMG":"MS200425.jpg","PUBLIC_VIDEO":"pvideo_ms200425.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xm78b3sjxbI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Liquids are nearly incompressible fluids. They take the shape of the container in which they are stored or kept, but they retain constant volume. Thus, liquids are known to have definite volume but indefinite shape. The particles in liquids have a force of attraction between them, but not much energy is required to break this force. Examples of liquids include water, honey etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the intermolecular spaces between particles of liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between particles of liquids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u0648\u0627\u0626\u0639","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"506","CATEGORY_ID":"1","CONT_TITLE":"Solids","CONT_SLUG":"solids","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ESolids are simply the hard substances in which their molecules are tightly packed together. Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the shape and volume of solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the compressibility of solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the intermolecular spaces between the particles in solids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the forces of attraction between the particles in solids.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200424","TOPIC_ID":"ms200424","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200424.jpg","PUBLIC_BANNER_IMG":"MS200424.jpg","PUBLIC_VIDEO":"pvideo_ms200424.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/UusR2XL7IyI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Solids are simply the hard substances in which their molecules are tightly packed together. Unlike liquids or gases, they have a definite shape that is not easy to change. Examples of solids include rock, chalk, etc.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the shape and volume of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the compressibility of solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the intermolecular spaces between the particles in solids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the forces of attraction between the particles in solids.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u0648\u0627\u0645\u062f","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"503","CATEGORY_ID":"1","CONT_TITLE":"Nucleic Acids","CONT_SLUG":"nucleic-acid","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ENucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. Nucleic acid is made up of nucleotides. A nucleotide consists of a sugar, phosphate and nitrogenous base.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what a nucleic acid is.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the structure of a nucleotide.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the different components of RNA and DNA.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a nucleic acid.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200408","TOPIC_ID":"hs200408","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200408.jpg","PUBLIC_BANNER_IMG":"HS200408.jpg","PUBLIC_VIDEO":"pvideo_hs200408.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/L5hwt0XTjzc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Nucleic acids are biomolecules present in living cells, especially DNA (deoxyribonucleic acid) or RNA (ribonucleic acid), whose molecules consist of many nucleotides linked in a long chain. Nucleic acid is made up of nucleotides. 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Examples of functional groups are hydroxyl, carboxyl, halide and amino group.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify different functional groups. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a molecule containing particular functional group. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Name a molecule according to the functional group present in it.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200403","TOPIC_ID":"hs200403","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200403.jpg","PUBLIC_BANNER_IMG":"HS200403.jpg","PUBLIC_VIDEO":"pvideo_hs200403.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/x9qhdxYY1ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;A functional group in a substituted hydrocarbon is an atom or group of atoms which gives idea about its properties and functions. 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However, the dissolving nature also depends on the charge of the ions in the solution. Non-polar substances have Van der Waals attractions which are weak but present.\u003C\/div\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E\u003Cbr\u003E\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify water as a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify ethanol as a polar solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify sodium chloride as an ionic solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify hexane as a nonpolar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify pentane as a nonpolar solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a polar solute in a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving an ionic solute in a polar solvent.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"hs200323.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200323","TOPIC_ID":"hs200323","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200323.jpg","PUBLIC_BANNER_IMG":"HS200323.jpg","PUBLIC_VIDEO":"pvideo_hs200323.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/hLIZIr9usZ0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Polar solutes tend to dissolve in polar solvents; nonpolar solutes tend to dissolve in nonpolar solvents. However, the dissolving nature also depends on the charge of the ions in the solution.\u0026amp;nbsp;\u0026lt;span style=\u0026quot;color: rgb(38, 50, 56); font-family: Roboto, sans-serif;\u0026quot;\u0026gt;Non-polar substances have Van der Waals attractions which are weak but present.\u0026lt;\/span\u0026gt;\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify water as a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify ethanol as a polar solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify sodium chloride as an ionic solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify hexane as a nonpolar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify pentane as a nonpolar solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving a polar solute in a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving an ionic solute in a polar solvent.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the process of dissolving a nonpolar solute in a nonpolar solvent.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062b\u0644 \u064a\u0630\u064a\u0628 \u0627\u0644\u0645\u062b\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"486","CATEGORY_ID":"1","CONT_TITLE":"Properties of Gases","CONT_SLUG":"properties-of-gases","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EGases do not have definite shape and volume. They attain the shape and volume of the container. Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to: \u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate that gases do not have definite shape and volume.\u003C\/div\u003E  \r\n\u003Cdiv\u003E- Explain that gases occupy the whole space available to them. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe that gases have unlimited diffusibility. \u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that gases have high compressibility.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":"ms200283.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200283","TOPIC_ID":"ms200283","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200283.jpg","PUBLIC_BANNER_IMG":"MS200283.jpg","PUBLIC_VIDEO":"pvideo_ms200283.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/n4tYu4qJMsk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Gases do not have definite shape and volume. They attain the shape and volume of the container.\u0026amp;nbsp; Gases are highly compressible. They disperse in the available space in response to differences in concentration of gases. This phenomenon is termed as diffusion of gases.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to:\u0026lt;br\u0026gt;\u0026amp;nbsp;- Illustrate that gases do not have definite shape and volume.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases occupy the whole space available to them.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Describe that gases have unlimited diffusibility.\u0026lt;br\u0026gt;\u0026amp;nbsp;- Explain that gases have high compressibility.\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0635\u0627\u0626\u0635 \u0627\u0644\u063a\u0627\u0632\u0627\u062a","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"484","CATEGORY_ID":"1","CONT_TITLE":"Effect of Surface Area on Reaction Rate","CONT_SLUG":"effect-of-surface-area-on-reaction-rate","CONT_TITLE_AR":"","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EWhen a solid lump is subdivided into fine powder, the surface area increases and more particles are exposed for collisions. This results in an increased frequency of collisions and therefore a faster rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to :\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the effect of surface area of solid reactant on rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Illustrate graphically the effect of surface area of solid reactant on rate of reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of increasing surface area on reaction rate using collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply this concept in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200277","TOPIC_ID":"hs200277","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200277.jpg","PUBLIC_BANNER_IMG":"HS200277.jpg","PUBLIC_VIDEO":"pvideo_hs200277.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/m8t8U2eJnj0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"0","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;When a solid lump is subdivided into fine powder, the surface area increases and more particles are exposed for collisions. This results in an increased frequency of collisions and therefore a faster rate of reaction.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;After completing this module, you will be able to :\u0026lt;br\u0026gt;- Identify the effect of surface area of solid reactant on rate of reaction.\u0026lt;br\u0026gt;- Illustrate graphically the effect of surface area of solid reactant on rate of reaction.\u0026lt;br\u0026gt;- Explain the effect of increasing surface area on reaction rate using collision theory.\u0026lt;br\u0026gt;- Apply this concept in practical problems.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0623\u062b\u064a\u0631 \u0645\u0633\u0627\u062d\u0629 \u0627\u0644\u0633\u0637\u062d \u0639\u0644\u0649 \u0645\u0639\u062f\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"369","CATEGORY_ID":"1","CONT_TITLE":"Balancing Redox Reactions","CONT_SLUG":"balancing-redox-reaction","CONT_TITLE_AR":"Balancing Redox Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance oxidation half-reaction and reduction half-reaction separately.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons.\u003C\/div\u003E","CONT_DESC_AR":"In the half-reaction method both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the oxidation and reduction half-reactions in a redox reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance oxidation and reduction half-reactions separately\u0026lt;br \/\u0026gt;\n\u0026amp;bull; balance the overall redox reaction by adding both half-reactions and cancelling electrons","BACKING_FILE":"ss200028.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200028","TOPIC_ID":"ss200028","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200028.jpg","PUBLIC_BANNER_IMG":"SS200028.jpg","PUBLIC_VIDEO":"pvideo_ss200028.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/8SetntZ-6ec","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;In the half-reaction method, both oxidation-half and reduction-half reactions are separated and balanced to get oxidation-half reaction and reduction-half reaction respectively. In the end, both half-reactions are added to obtain a final balanced equation.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;After completing this module, you will be able to:\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Identify the oxidation half-reaction and reduction half-reaction in a redox reaction.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance oxidation half-reaction and reduction half-reaction separately.\u0026lt;\/span\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;span style=\u0026quot;font-size: 13px;\u0026quot;\u0026gt;- Balance the overall redox reaction by adding both the half-reactions and cancelling electrons\u0026lt;\/span\u0026gt;.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0648\u0627\u0632\u0646\u0629 \u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0623\u0643\u0633\u062f\u0629 \u0648\u0627\u0644\u0627\u062e\u062a\u0632\u0627\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - 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Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how solid solutes dissolve in liquid solvents.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the change in the properties of solids when dissolved in liquids.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify solids that can be dissolved in water.\u003C\/div\u003E","CONT_DESC_AR":"Solids that are soluble in a particular liquid when dissolved form homogenous solution. Solids that are insoluble in a particular liquid when dissolved form heterogenous solution.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nAfter playing the simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how solid solute disolves in liquid solvents\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the change in the properties of solids when dissolved in liquids\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify solids that can be dissolved into water","BACKING_FILE":"hs200079.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200079","TOPIC_ID":"hs200079","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200079.jpg","PUBLIC_BANNER_IMG":"hs200079.jpg","PUBLIC_VIDEO":"pvideo_hs200079.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/nGvKBRfZJXk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Solids that are soluble in a particular liquid when dissolved in that liquid, form a homogenous solution. Solids that are insoluble in a particular liquid when dissolved in that liquid form a heterogeneous solution.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how solid solutes dissolve in liquid solvents.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the change in the properties of solids when dissolved in liquids.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify solids that can be dissolved in water.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0630\u0648\u0628\u0627\u0646 \u0627\u0644\u0645\u0648\u0627\u062f \u0627\u0644\u0635\u0644\u0628\u0629 \u0641\u064a \u0627\u0644\u0633\u0648\u0627\u0626\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"275","CATEGORY_ID":"1","CONT_TITLE":"Effect of Temperature on Reaction Rate","CONT_SLUG":"effect-of-temperature-on-reaction-rate","CONT_TITLE_AR":"Effect of Temperature on Reaction Rate","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the increase in the reaction rate with the increase in temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate the effect of temperature on the reaction rate.\u003C\/div\u003E","CONT_DESC_AR":"The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u0026amp;deg; rise in temperature. This increase is mainly due to the increase in the number of collisions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the increase in the reaction rate with the increase in temperature\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate the effect of temperature on the reaction rate\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply the concept in practical problems","BACKING_FILE":"ss200058.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200058","TOPIC_ID":"ss200058","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200058.jpg","PUBLIC_BANNER_IMG":"SS200058.jpg","PUBLIC_VIDEO":"pvideo_ss200058.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/d7IKyDsgrAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The rate of a chemical reaction increases with increase in temperature. For most of the reactions, the rate of reaction becomes nearly double for 10\u00b0 rise in temperature. This increase is mainly due to the increase in the number of collisions of the reactant particles.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the increase in the reaction rate with the increase in temperature.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate the effect of temperature on the reaction rate.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062a\u0623\u062b\u064a\u0631 \u0627\u0644\u062d\u0631\u0627\u0631\u0629 \u0639\u0644\u0649 \u0645\u0639\u062f\u0644 \u0627\u0644\u062a\u0641\u0627\u0639\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"270","CATEGORY_ID":"1","CONT_TITLE":"Boyle\u2019s Law","CONT_SLUG":"boyles-law","CONT_TITLE_AR":"Boyle\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EBoyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the pressure and the volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustration Boyle\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Boyle\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Boyles law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation , you will be able to:\u0026lt;br \/\u0026gt;\n- understand the quantitative relationship between pressure and the volume of a gas\u0026lt;br \/\u0026gt;\n- identify a graphical illustration of Boyles law\u0026lt;br \/\u0026gt;\n- apply Boyles law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200046","TOPIC_ID":"ss200046","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200046.jpg","PUBLIC_BANNER_IMG":"ss200046.jpg","PUBLIC_VIDEO":"pvideo_ss200046.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/K4i5Uy_nk54","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Boyle\u0026#039;s law gives a quantitative relationship between pressure and the volume of a gas. According to this law, at constant temperature, the volume of a given mass of a gas is inversely proportional to its pressure.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the pressure and the volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustration Boyle\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Boyle\u0026#039;s law in practical problems.\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0628\u0648\u064a\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"268","CATEGORY_ID":"1","CONT_TITLE":"Charles\u2019s Law","CONT_SLUG":"charles-law","CONT_TITLE_AR":"Charles\u2019s Law","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ECharles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the quantitative relationship between the temperature and volume of a gas.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Graphically illustrate Charles\u0026#039;s law.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Apply Charles\u0026#039;s law in practical problems.\u003C\/div\u003E","CONT_DESC_AR":"Charless law provides a quantitative relationship between volume and the temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the quantitative relationship between temperature and volume of a gas\u0026lt;br \/\u0026gt;\n\u0026amp;bull; graphically illustrate Charles\u0026amp;#39;s law\u0026lt;br \/\u0026gt;\n\u0026amp;bull; apply Charles\u0026amp;#39;s law in practical problems","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200045","TOPIC_ID":"ss200045","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200045.jpg","PUBLIC_BANNER_IMG":"SS200045.jpg","PUBLIC_VIDEO":"pvideo_ss200045.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/SpjYUcmK_Ro","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;Charles\u0026#039;s law provides a quantitative relationship between the volume and temperature of a gas. According to this law, at constant pressure, the volume of a given mass of a gas is directly proportional to its temperature.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the quantitative relationship between the temperature and volume of a gas.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Graphically illustrate Charles\u0026#039;s law.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Apply Charles\u0026#039;s law in practical problems.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0642\u0627\u0646\u0648\u0646 \u0634\u0627\u0631\u0644","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"264","CATEGORY_ID":"1","CONT_TITLE":"Organic Functional Groups","CONT_SLUG":"organic-functional-groups","CONT_TITLE_AR":"Organic Functional Groups","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA functional group is an atom or group of atoms present in a molecule that largely determines its chemical properties. All compounds containing the same functional group display similar chemical reactions and belong to the same class of organic compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define functional groups.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify various functional groups present in organic compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Derive organic compounds containing functional groups from their parent hydrocarbons.\u003C\/div\u003E","CONT_DESC_AR":"A functional group is an atom or group of atoms present in a molecule that largely determines its chemical properties. All compounds containing the same functional group display similar chemical reactions and belong to the same class of organic compounds.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define functional groups\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify various functional groups present in organic compounds\u0026lt;br \/\u0026gt;\n\u0026amp;bull; derive organic compounds containing functional groups from their parent hydrocarbons","BACKING_FILE":"ss200044.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200044","TOPIC_ID":"ss200044","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200044.jpg","PUBLIC_BANNER_IMG":"SS200044.jpg","PUBLIC_VIDEO":"pvideo_ss200044.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/iW10_wefWYQ","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A functional group is an atom or group of atoms present in a molecule that largely determines its chemical properties. All compounds containing the same functional group display similar chemical reactions and belong to the same class of organic compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define functional groups.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify various functional groups present in organic compounds.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Derive organic compounds containing functional groups from their parent hydrocarbons.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062c\u0645\u0648\u0639\u0627\u062a \u0627\u0644\u0648\u0638\u064a\u0641\u064a\u0629 \u0627\u0644\u0639\u0636\u0648\u064a\u0629","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"246","CATEGORY_ID":"1","CONT_TITLE":"Alcohols","CONT_SLUG":"alcohols","CONT_TITLE_AR":"Alcohols","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E  \r\n\u003Cdiv\u003EAlcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the functional group present in alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Write the IUPAC name of an alcohol.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the general formula of a homologous series of alcohols.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u003C\/div\u003E","CONT_DESC_AR":"Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridised carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the functional group present in alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; write the IUPAC name of an alcohol\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the general formula of a homologous series of alcohols\u0026lt;br \/\u0026gt;\n\u0026amp;bull; predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the charge distribution of a methanol molecule using an electrostatic potential map","BACKING_FILE":"ss200055.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200055","TOPIC_ID":"ss200055","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200055.jpg","PUBLIC_BANNER_IMG":"ss200055.jpg","PUBLIC_VIDEO":"pvideo_ss200055.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/J-IuFLRYZjU","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Alcohols are the hydroxy derivatives of aliphatic hydrocarbons. In alcohols, the hydroxyl group is attached to an sp3-hybridized carbon atom. The electrostatic potential map of an alcohol molecule indicates that oxygen atoms of a hydroxy group provide a region of highest electron density due to the presence of lone pairs.\u0026amp;nbsp;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning Objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Identify the functional group present in alcohols.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Write the IUPAC name of an alcohol.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the general formula of a homologous series of alcohols.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Predict the type of hybridization of carbon and oxygen atoms in an alcohol molecule.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Explain the charge distribution of a methanol molecule using an electrostatic potential map.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0643\u062d\u0648\u0644\u0627\u062a","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"245","CATEGORY_ID":"1","CONT_TITLE":"Boiling Point Elevation","CONT_SLUG":"boiling-point-elevation","CONT_TITLE_AR":"Boiling Point Elevation","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe boiling point of a solution is always higher than that of the pure solvent. This increase is called the elevation in boiling point.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Theoretically calculate the boiling point elevation of a solution containing a non-volatile solute.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Experimentally calculate the boiling point of a solution containing a non-volatile solute.\u003C\/div\u003E","CONT_DESC_AR":"The boiling point of a solution is always higher than that of the pure solvent. This increase is called the elevation in boiling point.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation,\u0026amp;nbsp;you will\u0026amp;nbsp;be able to:\u0026lt;br \/\u0026gt;\n\u25cf theoretically calculate the boiling point elevation of a solution containing non-volatile solute\u0026lt;br \/\u0026gt;\n\u25cf experimentally calculate the boiling point of a solution containing non-volatile solute","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200072","TOPIC_ID":"ss200072","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200072.jpg","PUBLIC_BANNER_IMG":"SS200072.jpg","PUBLIC_VIDEO":"pvideo_ss200072.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/5bMUwIPeFKE","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The boiling point of a solution is always higher than that of the pure solvent. This increase is called the elevation in boiling point.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Theoretically calculate the boiling point elevation of a solution containing a non-volatile solute.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Experimentally calculate the boiling point of a solution containing a non-volatile solute.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0627\u0631\u062a\u0641\u0627\u0639 \u0641\u064a \u062f\u0631\u062c\u0629 \u0627\u0644\u063a\u0644\u064a\u0627\u0646","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"242","CATEGORY_ID":"1","CONT_TITLE":"Titration of a Strong Acid with a Strong Base","CONT_SLUG":"titration-of-a-strong-acid-with-a-strong-base","CONT_TITLE_AR":"Titration of a Strong Acid with a Strong Base","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003ETitration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the detailed procedure for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the laboratory setup for the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the application of the titration of a strong acid with a strong base.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Extrapolate the graph for the titration of a strong acid with a strong base.\u003C\/div\u003E","CONT_DESC_AR":"Strong acid-strong base titration is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the detailed procedure for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the laboratory setup for the titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the application of titration of a strong acid with a strong base\u0026lt;br \/\u0026gt;\n\u0026amp;bull; extrapolate the graph for the titration of a strong acid with a strong base","BACKING_FILE":"ss200032.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200032","TOPIC_ID":"ss200032","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200032.jpg","PUBLIC_BANNER_IMG":"SS200032.jpg","PUBLIC_VIDEO":"pvideo_ss200032.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/R4ghDnAEBuo","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Titration of a strong acid with a strong base is used to determine the concentration of unknown acid by titrating it with a strong base of known concentration. Both the strong acid and the strong base are completely neutralized at an equivalence point, giving a pH of 7.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the detailed procedure for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the laboratory setup for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the application of the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Extrapolate the graph for the titration of a strong acid with a strong base.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0645\u0639\u0627\u064a\u0631\u0629 \u062d\u0645\u0636 \u0642\u0648\u064a \u0645\u0639 \u0642\u0627\u0639\u062f\u0629 \u0642\u0648\u064a\u0629","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"240","CATEGORY_ID":"1","CONT_TITLE":"Electrolytic Cell","CONT_SLUG":"electrolytic-cell","CONT_TITLE_AR":"Electrolytic Cell","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EThe apparatus in which electrolysis is carried out is called electrolytic cell. In electrolysis, electrical energy is used to carry out a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the components used to construct an electrolytic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the working principle of an electrolytic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the applications of electrolytic cells.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct an electrolytic cell.\u003C\/div\u003E","CONT_DESC_AR":"The apparatus in which electrolysis is carried out is called electrolytic cell. In electrolysis, electrical energy is used to carry out a chemical reaction.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the equipment used in an electrolytic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; construct an electrolytic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the principle of electrolytic cell function\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the applications of electrolytic cells","BACKING_FILE":"ss200023.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200023","TOPIC_ID":"ss200023","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200023.jpg","PUBLIC_BANNER_IMG":"SS200023.jpg","PUBLIC_VIDEO":"pvideo_ss200023.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/VbY5Y80n-NI","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;The apparatus in which electrolysis is carried out is called electrolytic cell. In electrolysis, electrical energy is used to carry out a chemical reaction.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the components used to construct an electrolytic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the working principle of an electrolytic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the applications of electrolytic cells.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct an electrolytic cell.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062e\u0644\u064a\u0629 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\u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"234","CATEGORY_ID":"1","CONT_TITLE":"Calculating the Oxidation Number","CONT_SLUG":"calculating-oxidation-number","CONT_TITLE_AR":"Calculating Oxidation Number","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFor calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define oxidation number.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Assign oxidation number to different elements in a chemical species.\u003C\/div\u003E","CONT_DESC_AR":"While calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u003C\/br\u003E\u003C\/br\u003E\r\n\u003Cstrong\u003ELearning Objectives\u003C\/strong\u003E\u003C\/br\u003E\u003C\/br\u003E\r\nIn this simulation you will be able to:\u003C\/br\u003E\r\n\u2022 define oxidation number\u003C\/br\u003E\r\n\u2022 assign the oxidation number to different elements in a chemical species","BACKING_FILE":"ss200027.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200027","TOPIC_ID":"ss200027","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200027.jpg","PUBLIC_BANNER_IMG":"SS200027.jpg","PUBLIC_VIDEO":"pvideo_ss200027.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Jf7BP10vSVM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For calculating the oxidation number, we calculate the number of electrons lost, gained or shared by an element in a chemical species.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define oxidation number.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Assign oxidation number to different elements in a chemical species.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u062d\u0633\u0627\u0628 \u0639\u062f\u062f \u0627\u0644\u062a\u0623\u0643\u0633\u062f","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - 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\u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"229","CATEGORY_ID":"1","CONT_TITLE":"Feasibility of a Galvanic Cell","CONT_SLUG":"feasibility-of-galvanic-cell","CONT_TITLE_AR":"Feasibility of Galvanic cell","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EFor a galvanic cell reaction to be feasible, the standard cell potential must be positive. We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the relation between the standard cell potential and the feasibility of a cell reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the conditions where a galvanic cell reaction is feasible.\u003C\/div\u003E","CONT_DESC_AR":"For a Galvanic cell reaction to be feasible the standard cell potential must be positive. We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the relation between the standard cell potential and the feasibility of a cell reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the conditions where a galvanic cell reaction is feasible","BACKING_FILE":"ss200037.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200037","TOPIC_ID":"ss200037","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200037.jpg","PUBLIC_BANNER_IMG":"SS200037.jpg","PUBLIC_VIDEO":"pvideo_ss200037.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/peQvICwZjAA","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;For a galvanic cell reaction to be feasible, the standard cell potential must be positive. We can determine the feasibility of a cell reaction by calculating the standard cell potential from standard electrode potential data.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe the relation between the standard cell potential and the feasibility of a cell reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the conditions where a galvanic cell reaction is feasible.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0625\u0645\u0643\u0627\u0646\u064a\u0629 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0627\u0644\u062e\u0644\u064a\u0629 \u0627\u0644\u062c\u0644\u0641\u0627\u0646\u064a\u0629","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"227","CATEGORY_ID":"1","CONT_TITLE":"Galvanic Cell","CONT_SLUG":"galvanic-cell","CONT_TITLE_AR":"Galvanic Cell","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. In a galvanic cell, the metal which is more reactive is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of galvanic cells.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify the components used to construct a galvanic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Construct a galvanic cell.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe how a galvanic cell functions.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the importance of a salt bridge in a galvanic cell.\u003C\/div\u003E","CONT_DESC_AR":"A Galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. In a Galvanic cell the more reactive metal is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of Galvanic cells.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify the pieces of equipment used to construct a galvanic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; construct a galvanic cell\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe how a galvanic cell functions\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe the importance of a salt bridge in a galvanic cell","BACKING_FILE":"ss200010.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200010","TOPIC_ID":"ss200010","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200010.jpg","PUBLIC_BANNER_IMG":"SS200010.jpg","PUBLIC_VIDEO":"pvideo_ss200010.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/xfKUW6Cwxn4","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A galvanic cell is an electrochemical cell that converts chemical energy into electrical energy. In a galvanic cell, the metal which is more reactive is taken as anode and the less reactive metal is taken as cathode. Electric batteries are examples of galvanic cells.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify the components used to construct a galvanic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Construct a galvanic cell.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe how a galvanic cell functions.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;-\u0026amp;nbsp;\u0026lt;span style=\u0026quot;color: rgb(0, 0, 0); font-family: Arial; white-space: pre-wrap;\u0026quot;\u0026gt;Explain the importance of a salt bridge in a galvanic cell\u0026lt;\/span\u0026gt;.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062e\u0644\u064a\u0629 \u0627\u0644\u062c\u0644\u0641\u0627\u0646\u064a\u0629","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"213","CATEGORY_ID":"1","CONT_TITLE":"Catalysts","CONT_SLUG":"catalysts","CONT_TITLE_AR":"Catalysts","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define catalyst.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the effect of a catalyst on the rate of a chemical reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain how a catalyst increases the rate of a chemical reaction.\u003C\/div\u003E","CONT_DESC_AR":"A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; define catalyst\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain effect of catalyst on the rate of a chemical reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain how a catalyst increases the rate of a chemical reaction","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200020","TOPIC_ID":"ss200020","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200020.jpg","PUBLIC_BANNER_IMG":"ss200020.jpg","PUBLIC_VIDEO":"pvideo_ss200020.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/EpkHrhW2Xxc","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Enzymes are naturally occurring catalysts responsible for many essential biochemical reactions.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Define catalyst.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the effect of a catalyst on the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain how a catalyst increases the rate of a chemical reaction.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062d\u0641\u0632\u0627\u062a","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"211","CATEGORY_ID":"1","CONT_TITLE":"Factors Affecting Equilibria","CONT_SLUG":"factors-affecting-equilibria","CONT_TITLE_AR":"Factors Affecting Equilibria","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAccording to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u003C\/div\u003E","CONT_DESC_AR":"According to Le Chateliers principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objective\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain, when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change","BACKING_FILE":"ss200017.apk","FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ss200017","TOPIC_ID":"ss200017","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_SS200017.jpg","PUBLIC_BANNER_IMG":"SS200017.jpg","PUBLIC_VIDEO":"pvideo_ss200017.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/KtndjzIHD3A","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;According to Le Chatelier\u2019s principle, if there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change. This principle is applicable to both physical as well as chemical equilibrium.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain that when there is any change in the factors that affect the equilibrium condition of the system, the system will counteract or reduce the effect of the overall change.\u0026lt;\/div\u0026gt;\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u062c\u062f\u0648\u0644 \u0627\u0644\u062f\u0648\u0631\u064a: \u0627\u0644\u0639\u0648\u0627\u0645\u0644 \u0627\u0644\u0645\u0624\u062b\u0631\u0629 \u0639\u0644\u0649 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\u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"150","CATEGORY_ID":"1","CONT_TITLE":"Double Displacement Reactions","CONT_SLUG":"double-displacement-reaction","CONT_TITLE_AR":"Double displacement reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain what is double displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of silver nitrate and sodium chloride.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide.\u003C\/div\u003E","CONT_DESC_AR":"A double displacement reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain what is double displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of silver nitrate and sodium chloride\u0026lt;br \/\u0026gt;\n\u0026amp;bull; demonstrate double displacement reaction of copper(II) chloride with sodium hydroxide","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.hs200019","TOPIC_ID":"hs200019","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_HS200019.jpg","PUBLIC_BANNER_IMG":"HS200019.jpg","PUBLIC_VIDEO":"pvideo_hs200019.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/cSoNIBkflKY","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;div\u0026gt;Overview:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;A double displacement reaction is a type of chemical reaction in which two compounds react by an exchange of cations and anions to form two new compounds.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;Learning Objectives:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain what is double displacement reaction.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Demonstrate double displacement reaction of silver nitrate and 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\u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 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\r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EIn homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of homogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is homogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. This kind of mixture has a uniform composition and has no visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of homogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is homogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200054","TOPIC_ID":"ms200054","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200054.jpg","PUBLIC_BANNER_IMG":"MS200054.jpg","PUBLIC_VIDEO":"pvideo_ms200054.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/elFGPE_TZxk","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In homogeneous mixtures, substances are completely mixed together and are indistinguishable from one another. 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In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Explain the properties of heterogeneous mixtures.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify whether a mixture is heterogeneous or not.\u003C\/div\u003E","CONT_DESC_AR":"substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;bull; describe heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; explain the properties of heterogeneous mixtures\u0026lt;br \/\u0026gt;\n\u0026amp;bull; identify whether a mixture is heterogeneous or not","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":"","MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.ms200053","TOPIC_ID":"ms200053","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_MS200053.jpg","PUBLIC_BANNER_IMG":"MS200053.jpg","PUBLIC_VIDEO":"pvideo_ms200053.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/BrPP-a75tI0","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"0000-00-00 00:00:00","CREATED_BY":"1","UPDATED_ON":"2017-12-29 10:52:47","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"Overview:\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;In heterogeneous mixtures, substances remain separate. In these mixtures, one substance is spread throughout another substance as small particles, droplets or bubbles. This kind of mixture has visible boundaries of separation between the various constituents.\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;Learning objectives\u0026lt;br\u0026gt;\u0026lt;br\u0026gt;\u0026lt;div\u0026gt;After completing this module, you will be able to:\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Describe heterogeneous mixtures.\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Explain the properties of heterogeneous mixtures.\u0026amp;nbsp;\u0026lt;\/div\u0026gt;\u0026lt;div\u0026gt;- Identify whether a mixture is heterogeneous or not.\u0026lt;\/div\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"\u0627\u0644\u0645\u062e\u0627\u0644\u064a\u0637 \u063a\u064a\u0631 \u0627\u0644\u0645\u062a\u062c\u0627\u0646\u0633\u0629","ADMSUBJECT_ID":"706","ADMCOURSE_ID":"148","DISPLAY_NAME":"Bahrain - Grade 12 - Chemistry","DISPLAY_NAME_AR":"Bahrain - Grade 12 - Chemistry","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","SUBJECT_DESC":"\u003Cdiv\u003E\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621.\u0026nbsp;\u003C\/div\u003E\u003Cdiv\u003E\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c \u0627\u0644\u062d\u0631\u0643\u064a\u0629 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629\u060c \u0648\u062c\u0648\u0627\u0646\u0628 \u0627\u0644\u0643\u0647\u0631\u0648\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629 \u0627\u0644\u062a\u064a \u062a\u0645 \u062a\u0637\u0628\u064a\u0642\u0647\u0627 \u0639\u0644\u0649 \u0627\u0644\u062a\u0641\u0627\u0639\u0644\u0627\u062a \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0626\u064a\u0629. \u0648\u0627\u0644\u062a\u064a \u064a\u062c\u0628 \u0623\u0646 \u062a\u064f\u0641\u064a\u062f \u0627\u0644\u0637\u0644\u0627\u0628 \u0641\u064a \u0641\u0647\u0645 \u0633\u0628\u0628 \u062d\u062f\u0648\u062b \u062a\u0641\u0627\u0639\u0644 \u0645\u0639\u064a\u0646\u060c \u0648\u0633\u0628\u0628 \u0638\u0647\u0648\u0631 \u062e\u0627\u0635\u064a\u0629 \u0645\u0639\u064a\u0646\u0629 \u0628\u0648\u0627\u0633\u0637\u0629 \u0627\u0644\u0646\u0648\u0627\u062a\u062c.\u003C\/div\u003E","SUBJECT_DESC_AR":"\u062a\u0645 \u062a\u0646\u0638\u064a\u0645 \u0648\u064e\u062d\u064e\u062f\u0627\u062a \u0627\u0644\u0635\u0641 \u0627\u0644\u062b\u0627\u0646\u064a \u0639\u0634\u0631 \u062d\u0648\u0644 \u0642\u0648\u0627\u0646\u064a\u0646 \u0648\u0645\u0628\u0627\u062f\u0626 \u0627\u0644\u0643\u064a\u0645\u064a\u0627\u0621. \r\n\u0627\u0644\u062f\u064a\u0646\u0627\u0645\u064a\u0643\u0627 \u0627\u0644\u062d\u0631\u0627\u0631\u064a\u0629\u060c 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\u0627\u0644\u0646\u0648\u0627\u062a\u062c.","SUBJECT_IMG":"bahrain_grade12_chemistry.jpg","SUBJECT_BANNER_IMG":null,"SUBJECT_PRICE":null,"IS_FEATURED":"N","COURSE_NAME":"Grade 12","COUNTRY_ID":"280","SHORT_NAME":"Bahrain","DOMAIN_NAME":"STEM"},{"CONT_ID":"51","CATEGORY_ID":"1","CONT_TITLE":"Single Displacement Reaction","CONT_SLUG":"single-displacement-reaction","CONT_TITLE_AR":"Single Displacement Reaction","CONT_DESC":"\u003Ch3\u003EOverview:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EA single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Identify a single displacement reaction.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Demonstrate a single displacement reaction.\u003C\/div\u003E","CONT_DESC_AR":"A single displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\n\u0026lt;strong\u0026gt;Learning Objectives:\u0026lt;\/strong\u0026gt;\u0026lt;br \/\u0026gt;\n\u0026lt;br \/\u0026gt;\nIn this simulation, you will be able to:\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- identify the single displacement reaction\u0026lt;br \/\u0026gt;\n\u0026amp;nbsp;- demonstrate the single displacement reaction\u0026lt;br 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Increasing the concentration of reactants increases collisions between particles, which leads to a higher reaction rate. An increase in pressure compresses the particles into a smaller volume. This increases the frequency of collisions, resulting in an increased reaction rate.\u003C\/div\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Ch3\u003ELearning Objectives:\u003C\/h3\u003E \r\n\u003Cdiv\u003E \r\n \u003Cbr\u003E \r\n\u003C\/div\u003E \r\n\u003Cdiv\u003EAfter completing this module, you will be able to:\u003C\/div\u003E \r\n\u003Cdiv\u003E- Define collision theory.\u003C\/div\u003E \r\n\u003Cdiv\u003E- Describe the effects of concentration and pressure on reaction rates.\u003C\/div\u003E","CONT_DESC_AR":"","BACKING_FILE":null,"FILE_UID":null,"SCORM_COURSE_ID":null,"CONT_SRC":null,"MOD_FILES":null,"FOLDER_NAME":null,"CONTTYPE_ID":"9","ANDROID_PKG":"com.umety.vr.vc000039","TOPIC_ID":"vc000039","IS_PUBLISH":"Y","IS_PUBLIC":"Y","CONT_PRICE":null,"PUBLIC_IMG":"thumb_vc000039.jpg","PUBLIC_BANNER_IMG":"vc000039.jpg","PUBLIC_VIDEO":"en_us_pvideo_vc000039.mp4","PUBLIC_VIDEO_URL":"https:\/\/youtu.be\/Qa_-BWzLeLM","DIST":null,"SHOW_ON_HOME":"N","CONTROLLER_REQUIRED":"Y","DOMAIN":"3","CONCEPT":"0","STATUS":"A","EXPIRY_DAYS":null,"CREATED_ON":"2018-07-04 06:35:37","CREATED_BY":"2143","UPDATED_ON":"2024-10-08 11:51:20","UPDATED_BY":"2","CONT_ORDER":"0","X_ROTATION":null,"Y_ROTATION":null,"Z_ROTATION":null,"BG_COLOR":"0x000000","X_POSITION":null,"Y_POSITION":null,"Z_POSITION":null,"TEMP_DESC":"\u0026lt;p\u0026gt;Overview:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Collision theory states that the rate of a reaction depends on successful collisions of reactant molecules. Increasing the concentration of reactants increases collisions between particles, which leads to a higher reaction rate. An increase in pressure compresses the particles into a smaller volume. This increases the frequency of collisions, resulting in an increased reaction rate.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;Learning objectives:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;\u0026lt;br\u0026gt;\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;After completing this module, you will be able to:\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Define collision theory.\u0026lt;\/p\u0026gt;\u0026lt;p\u0026gt;- Describe the effects of concentration and pressure on reaction rates.\u0026lt;\/p\u0026gt;","IS_ANALYTICS":"Y","VR_ENABLE":"Y","VR_SESSION_ENABLE":"Y","YOUTUBE_URL":null,"CONT_TYPE":"VR Module","CAT_NAME":"Concentration, Pressure and Reaction Rates","DISPLAY_NAME":"CBSE - Grade 12 - Chemistry","DISPLAY_NAME_AR":"CBSE - Grade 12 - Chemistry","SUBJECT_IMG":"573.jpg","ADMSUBJECT_ID":"573","SUBJECT_NAME":"Chemistry","SUBJECT_NAME_AR":"Chemistry","ADMCOURSE_ID":"199","COURSE_NAME":"Grade 12","COUNTRY_ID":"288","STANDARD_ID":"288","SHORT_NAME":"CBSE","LANG_ID":null,"LOCALE_TITLE":null,"LOCALE_DESC":null,"DIR":null,"LANG_NAME":null,"DOMAIN_NAME":"STEM","DOMAIN_DESC":"STEM"},"checkLang":["English - US","\u0639\u0631\u0628\u064a","Espa\u00f1ol","Ti\u1ebfng Vi\u1ec7t","\ud55c\uad6d\uc5b4"],"devices":["UmetyVR","WebXR"]}